Path in ZIP Files

I have a program that compresses files into a ZIP File.
How do you get the data extractable in something like WinZip and how do you get Ride of the Path in WinZip?

Well what I'm trying to do is use the class files in java.util.zip.* to make a program that compresses files into a ZIP Archive. I figured out the question you didn't understand. What I'm trying to do right now is get the data in the archive extractable. When I open my archive that I created with my program, WinZip says that the enties are there. When I try to extract them WinZip crashes. I used a code that is something like this:
ZipOutputStream zos = new ZipOutputStream(new FileOutputStream(outzip));
int q = 0;
for (q = 0; q < infile.length; q++) {
FileInputStream in = new FileInputStream(infile[q]);
size = in.available();
byte b[] = new byte[size];
in.read(b);
File f = new File(infile[q]);
ZipEntry ze = new ZipEntry(f.getPath());
zos.setLevel(9);
ze.setTime(f.lastModified());
zos.putNextEntry(ze);
zos.write(b);
zos.closeEntry();
in.close();
zos.flush();
zos.close();
Infile is an array of file names in the form of strings. Then the program loops through them strings turning each into a file so that it is written without a path name (which wa part of my last problem) into the zip file.

Similar Messages

  • Keeping paths when zipping files

    Hi,
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    I've managed to get all the files into one zip, but when I unzip it (winzip), all the paths are gone ...
    any ideas that can help me to keep them?

    if you use winzip, you can just highlight all the directories/files you want in it and right click (add to zip), and all the paths will be kept.

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    Sorry, I want the path to be like: "\db\data.data"

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                   ZipEntry ze = null;
                   File ff = null;
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                             byte[] buf = new byte[1024];
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    Nothing to do with the resource path....thats fine. Use the code below.....most likely this will fix it.......
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        try
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          ZipEntry ze = null;
          File ff = null;
          while ( ( ze = zis.getNextEntry() ) != null )
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            ff = new File( "C:\\your_path\\" + ze.getName() );
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            else
              fos = new FileOutputStream( ff );
              byte[] buf = new byte[1024];
              int len;
              while ( ( len = zis.read( buf ) ) > 0 )
                fos.write( buf, 0, len );
              fos.close();
              System.out.println( "wrote file " + ff.getPath() + " success=" + ff.exists() );
          zis.close();
        catch( Exception ex )
          ex.printStackTrace();
        finally
          try { zis.close(); }catch(Exception ex){}
          try { fos.close(); }catch(Exception ex){}
        }

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             **************String files[] = f.list();**************
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    out.close();
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    I'll admit i took 1 look at that reply an thought "thats stupid that wont work"...
    then a second look an though "actually, i should work i cant believe i didnt think of that"
    Anyways i tried it and it did work
    How are the duke dollars awarded, cos u should have them ordinary_guy
    cheers!

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        IMPORTING
          buffer       = lv_content
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          binary_tab   = lt_data
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          OTHERS       = 2.
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          lang    = sy-langu
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      SPLIT lv_tmp AT '\' INTO lv_tmp_file lv_tmp.
      CALL FUNCTION 'STRING_REVERSE'
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          string  = lv_tmp_file
          lang    = sy-langu
        IMPORTING
          rstring = lv_tmp_file.
      lv_upfilename = lv_tmp_file.
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      lv_zip_content   = lo_zip->save( ).
    * Conver the xstring content to binary
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          buffer        = lv_zip_content
        IMPORTING
          output_length = lv_size
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            filename     = p_down
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          CHANGING
            data_tab     = lt_data
          EXCEPTIONS
            OTHERS       = 24 ).
    Regards,
    Rich Heilman

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