Pattern matching String

Hi,
I want to do pattern matching using String. Here is my requirement.
String file_name = (String)hash.get("DOCNAME"));
file_name = file_name.replace("'","285745@");
So, whereever I have '(apostrophe) I will replace it with pattern "285745@" and then at another jsp where I get this request parameter I do reverse as follows:
String docname = (String)request.getParameter("doc_name").replace("285745@","'");
Now I know replace function is not going to do this. It is just a indicative, for you to know what I want to achieve. which other java function / method i can implement to get the desired result.
thanks,
sa pa

Similar Messages

Pattern matching in sql scripts

Hi All,
I am trying to run some queries for database maintainence and to find out the number of rows inserted in a table on a day. These queries would be stored in a .sql file and a scheduler will trigger these files are regular intervals.
Amongst these queries , one query that we generally exceute in sql command line is:
select component, count(*) from test where timestamp like '%2010-11-30%' group by component order by count(*) desc;
This query gives me a list of components and the number of rows they inserted in 'test' table on a particular day. To fetch the data inserted on a particular day we manually give current date inside pattern matching string -> e.g where timestamp like '%2010-11-30%'
How can I use pattern matching (as in the above query) in my sql script. How can I fetch the current date and use it in the above sql for pattern matching.
Please help.

Assuming your timestamp column has a proper data type like DATE or TIMESTAMP then you should compare dates with dates or timestamps with timestamps. Not timesatamp with a string.
example
select component, count(*) cnt
from test
where timestamp>= trunc(sysdate)
and timestamp < trunc(sysdate) /* this line is only needed if you have timestamps in the future */
group by component
order by cnt desc;If your column is of the datatype timestamp then use SYSTIMESTAMP instead of SYSDATE.

Pattern matching in String

Hi,
I want to do pattern matching using String. Here is my requirement.
String file_name = (String)hash.get("DOCNAME"));
file_name = file_name.replace("'","285745@");
So, whereever I have '(apostrophe) I will replace it with pattern "285745@" and then at another jsp where I get this request parameter I do reverse as follows:
String docname = (String)request.getParameter("doc_name").replace("285745@","'");
Now I know replace function is not going to do this. It is just a indicative, for you to know what I want to achieve. which other java function / method i can implement to get the desired result.
thanks,
pp

String file_name = (String)hash.get("DOCNAME"));
file_name = file_name.replace("'","285745@");The problem here is that String.replace() operates only on char arguments, you cannot replace entire substrings with it.
The String.replaceAll() method, on the other hand, operates on regular expressions. In many common cases (those in which the substring you want to find contains no characters with special meaning to the regular expression processor) you can use it exactly as you would String.replace() except that it operates on substrings.
But regular expressions are much more powerful than that. The javadoc for the "Pattern" class has some information on how to use them. There is also a tutorial at http://java.sun.com/docs/books/tutorial/extra/regex/intro.html which you might find helpful.
In the 1.4 edition of Java there is no longer any need to screw around with while loops and StringBuffers. Nearly any text processing operation can be done with regular expressions.

Pattern matching a string

I'm trying to pattern match a string in java which has the following syntax:
ENSMUS followed by one character which can be anything followed by 11 digits.
I've done this in javascript using the following regex:
var regex = /^ENSMUS(\w{1})(\d{11})$/;I'm slightly confused by the Java equivalent (having looked at the Pattern class in the API). Could anyone lend a hand please?

ENSMUS followed by one character which can be
anything followed by 11 digits.
String s = ...
boolean b = s.matches("ENSMUS.\\d{11}");Note that when matching an entire String, you don't
need to provide a beginning (^) and end ($) in your
regex. Also, you said "any character", this is not
\w, but a . (a period). \w is a "word character".So I assume if it was a word character it would be
String s = ...
boolean b = s.matches("ENSMUS\\w{1}\\d{11}");I'll try it and see what happens. Thanks

A regular expressin problem: String.matches & the pair of Pattern & Matcher

I observe this problem when working on pattern match for Z5Z-5Z5, Z5Z 5Z5 or Z5Z5Z5.
When I use the match method of the String class, the correct pattern will yield true with
!str.matches("^[A-Za-z]\\d[A-Za-z]\\s?|-?\\d[A-Za-z]\\d$").
When I use the pair classes of regex:
Pattern p = Pattern.compile("^[A-Za-z]\\d[A-Za-z]\\s?|-?\\d[A-Za-z]\\d$");
Matcher m = p.matcher(str);
a string of "v7u h4e" (two blank spaces in between) can pass the !m.find().
Have anyone else experienced the same situation?
Do I use them right, or bugs?
Thanks for your input.
v.

This is why I wish regex references would list the
operator precedence. What do you mean? My regex reference does show that right under the section called "Operators" in the second chapter.
Maybe you need to update your references and buy "Programming Perl"? :)
I think there are only three
levels of precedence, but it needs to be crystal clear
that | has the lowest precedence (even lower than
putting two tokens together!) and often needs
parentheses: "\w\d|\s\w" means "(\w\d)|(\s\w)", not
"\w(\d|\s)\w".Actually for that particular operator it is pretty consistent. It is always very low. Even when I was introduced to the theory of regex's in school the precedence was lower than everything else.

Pattern matching in Strings

Hi,
I need some help using pattern matching in strings .. this is what i need to do ..
if given a string of this format
String tempNotes="07/07/05 3:42 PM - 65. Java forum test 07/01/05 5:11 PM - 62. Trying regualt Expressions";I need to extract the number(s) after the time .. in the above case would be 65,62 .
The string might have more than one line of the above format .. can some one help me with this .
I tried using regular expressions .. I am pretty new to Regex's tried this
String regex="\\d(2)/\\d(2)/\\d(2)\\s\\d+:\\d(2)\\sP|AM\\s-";
Pattern p= Pattern.compile(regex);
Matcher m1 = p.matcher(tempNotes);
if(m1.find()){
System.out.println("Num = "+tempNotes.substring(m1.end()+1,m1.end()+3));
} I am totally lost .. can someone help me with this please. I need to extract all the numbers after the time .
Thanks in advance.

I see two major problems with that regex. First, you're using parentheses where you should be using braces - "\\d{2}", not "\\d(2)". Second, you need to need to limit the scope of the alternation: "(?:P|A)M", or better, use a character class instead: "[PA]M". As it is, the vbar is splitting the whole regex into two alternatives. Also, you can use a capturing group to extract the number.
String regex="\\d{2}/\\d{2}/\\d{2}\\s\\d+:\\d{2}\\s[AP]M\\s-\\s+(\\d+)";
Pattern p= Pattern.compile(regex);
Matcher m1 = p.matcher(tempNotes);
while (m1.find()) {
System.out.println("Num = " + m1.group(1));
}

Regular Expressions (Pattern/Matcher) --- Help

Hi,
I have an regex i.e. Pattern.compile("([0-9])D([0-9])'?(?:([0-9]+)\")?([NSEW])").{code}
It has to exactly match the input e.g *45D15'34"N*
I need to retrieve the values based on grouping.
Group1 = 45 (degree value)
Group2 = 15 (minutes value)
Group3 = 34 (seconds value) ----> this is a non-capturing group
Group4 = N (directions)
The regex works fine for most of longitude/latitude value but I get a StackOverFlow for some. There is a known bug on this http://bugs.sun.com/bugdatabase/view_bug.do?bug_id=5050507
According to the bug report, they have said that are many different regex that can trigger the stack overflow....even though the length of my input is not as long as the one posted on the bug report.
I was wondering if anyone could suggest a different way of writing the regex above to avoid the stack over flow.
Thank you in advance

Hi,
I missed the '+' in my original regex Pattern.compile("([0-9]+)D([0-9]+)'?(?:([0-9]+)\")?([NSEW])"){code}.
I have also tried {code} Pattern.compile("(\\d+)D(\\d+)'?(?:(\\d+)\")?([NSEW])");And, the other 2 expressions as suggested by you.
The problem happens when Durham Lat=35D52N Lon=78D47W value is selected from a Jtree(the values are parsed from a xml file to the tree - the xml file has a bout 800 longitude/latitude elements for different cities in the US). It does not happen for other values and If I increment the degree or min by, then the expression works. I am not sure how else i could re-write this exp.
Below is the snippet of the xml file:
<State name="NORTH CAROLINA">
            <City name="Asheville AP"     Lat="35D26'N"     Lon="82D32'W"/>
            <City name="Charlotte AP"     Lat="35D13'N"     Lon="80D56'W"/>
            <City name="Durham"     Lat="35D52'N"     Lon="78D47'W"/>
            <City name="Elizabeth City AP"     Lat="36D16'N"     Lon="76D11'W"/>
            <City name="Fayetteville, Pope AFB" Lat="35D10'N"     Lon="79D01'W"/>
            <City name="Goldsboro,Seymour-Johnson"     Lat="35D20'N"     Lon="77D58'W"/>
            <City name="Greensboro AP (S)"     Lat="36D05'N"     Lon="79D57'W"/>
            <City name="Greenville"     Lat="35D37'N"     Lon="77D25'W"/>
            <City name="Henderson"     Lat="36D22'N"     Lon="78D25'W"/>
            <City name="Hickory"     Lat="35D45'N"     Lon="81D23'W"/>
            <City name="Jacksonville"     Lat="34D50'N"     Lon="77D37'W"/>
            <City name="Lumberton"     Lat="34D37'N"     Lon="79D04'W"/>
            <City name="New Bern AP"     Lat="35D05'N"     Lon="77D03'W"/>
            <City name="Raleigh/Durham AP (S)"     Lat="35D52'N"     Lon="78D47'W"/>
            <City name="Rocky Mount"     Lat="35D58'N"     Lon="77D48'W"/>
            <City name="Wilmington AP"     Lat="34D16'N"     Lon="77D55'W"/>
            <City name="Winston-Salem AP"     Lat="36D08'N"     Lon="80D13'W"/>
        </State>
public final class GeoLine {
    /* Enum for the possible directions of longitude and latitude*/
    public enum Direction {
        N, S, E, W;
        public boolean isLongitude() {
            return (this == E || this == W);
        public boolean isLatitude() {
            return (this == N || this == S);
        public Direction getCanonicalDirection() {
            if (this == S) {
                return Direction.N;
            } else if (this == W) {
                return Direction.E;
            } else {
                return this;
    private final int degree;
    private final int minute;
    private final int second;
    private final Direction dir;
    /* Recognizes longitude and latitude values that has degrees, minutes and seconds i.e. "45D15'34"N
    * or "45D1534"N. The single-quotes for the minutes is optional. And, for the moment we do not support seconds
    * validation although ilog library returns the longitude/latitude with second when NEs and Sub-networks are
    * dragged and dropped on the map.*/
private static final Pattern PATTERN = Pattern.compile("([0-9]+)D([0-9]+)'?(?:([0-9]+)\")?([NSEW])");
    public GeoLine(int degree, int minute, Direction dir) {
        this(degree, minute, 0, dir);
    public GeoLine(int degree, int minute, int second, Direction dir) {
        Log.logInfo(getClass().getSimpleName(), "PAU degree: " + degree + " minute: " + minute + " second: " + second + " direction: " + dir);
        verifyLongitudeLatitude(degree, dir);
        verifyMinute(degree, minute, dir);
        this.degree = degree;
        this.minute = minute;
        this.second = second;
        if (this.degree == 0 && this.minute == 0 && this.second == 0) {
            this.dir = dir.getCanonicalDirection();
        } else {
            this.dir = dir;
    public Direction getDirection() {
        return dir;
    public int getMinute() {
        return minute;
    public int getDegree() {
        return degree;
    public int getSecond() {
        return second;
    public static GeoLine parseLine(String location) {
        * Matcher class will throw java.lang.NullPointerException if a null location
        * is passed, null location validation is not needed.
        Matcher m = PATTERN.matcher(location);
        if(m.matches()) {
            int deg;
            int min;
            int second;
            Direction direction;
            deg = Integer.parseInt(m.group(1));
            min = Integer.parseInt(m.group(2));
            if (m.group(3) == null) {
                second = 0;
            } else {
                second = Integer.parseInt(m.group(3));
            direction = Direction.valueOf(m.group(4));
            return new GeoLine(deg, min, second, direction);
        } else {
            throw new IllegalArgumentException("Invalid location value. Expected format XXDXX'XX\"[NSEW] " + location);
    private void verifyMinute(int deg, int min, Direction direction) {
        /* This validation is to make sure that minute does not exceed 0 if maximum value for latitude == 90
        * or longitude == 180 is specified */
        int maxDeg = direction.isLatitude() ? 90 : 180;
        if(min < 0 || min > 59) {
           throw new NumberFormatException("Minutes is out of range. Value should be less than 60: " + min);
        if (deg == maxDeg && min > 0) {
            throw new NumberFormatException("Degree value " + deg + "D" + direction + " cannot have minute exceeding 0: " + min);
    private void verifyLongitudeLatitude(int valDeg, Direction valDir) {
           int max = valDir.isLatitude() ? 90 : 180;
           if(valDeg < 0 || valDeg > max) {
                throw new NumberFormatException("Degree " + valDeg + valDir + " is invalid");
    public final boolean isLongitude() {
        return dir.isLongitude();
    public final boolean isLatitude() {
        return dir.isLatitude();
    @Override
    public final String toString(){
        if(minute < 10){
            return degree + "D0" + minute + dir;
        } else {
            return degree + "D" + minute + dir;
    @Override
    public boolean equals(Object obj) {
        if (obj instanceof GeoLine) {
            GeoLine other = (GeoLine) obj;
                return (this.degree == other.degree && this.minute == other.minute && this.second == other.second && this.dir == other.dir);
        return false;
    @Override
    public int hashCode() {
        int result = 17;
        result = result * 37 + degree;
        result = result * 37 + minute;
        result = result * 37 + second;
        result = result * 37 + dir.hashCode();
        return result;
}Thank you again.

Who knows how to output some text once labview detects something I want using pattern matching(Vision assistant)?

who knows how to output some text once labview detects something I want using pattern matching(Vision assistant)?
The text is something like"Yes, this is a coin"
Thanks!

I attached a SubVI which I used to place an overlay next to a Pattern, found by a Pattern Match before:
As you can see, you simply pass the image reference and the Array of Matches to the VI along with the String you want to have as an overlay next to the Match.
I also modified your VI a bit, but didn't test it. I created an Array of clusters, each elment containing the template path along with the respective text.
Please note that this is just a hint!
Christian
Attachments:
suggestion.vi ‏146 KB
Overlay_Txt.vi ‏24 KB

Pattern matching problme - not getting desired result.

Hi,
According my program , If 'san' is in 'sangeetha', then it should display "hello".
but I am getting only 'hi'
Why ? any idea?
<%@ page import="java.util.regex.Pattern"%>
<%
if(Pattern.matches("san", "sangeetha"))
out.println("hello");
else
out.println("hi");
%>
Result : Hi

sangee wrote:
Hi,
According my program , If 'san' is in 'sangeetha', then it should display "hello".No, that isn't what your patten say. You should read about regular expressions and learn how to use them, or switch to String.indexOf or contains.
Kaj

Pattern matching for range of numbers

I am facing problem in using a pattern like [200-300] to match any number in the range 200 and 300 inclusive. I wrote following code:
public class RangeTest {
     public static void main(String[] args) {
          String pat = "[100-200]";
          String input = "100";
          // incpat.replace("[", "\\[");
          // incpat.replace("]", "\\]");
          System.out.println("Pattern" + pat);
          Pattern pattern = Pattern.compile(pat);
          Matcher matcher = pattern.matcher(input);
          if (matcher.matches()) {
               System.out.println("EPC Matched:" + input + " and pattern:"              +matcher.pattern());
}and tested it for different values of input , it's not working. I tried even giving escape characters for "[" and "]" (commented code). Can i use pattern matching in this case.
Please help me.
Regards,
Prashanth

I am facing problem in using a pattern like[200-300] to match any number in
the range 200 and 300 inclusive.Try this one: "(2\d\d)|(300)".
kind regards,
Jos
ps. Waiting for Sabre to jump in telling me that the
parentheses aren't needed ;-)The parentheses aren't needed Jos! :-)

Regular expression and pattern matching/replacing

I have a list of key words. It has around 1000 key word now but can grow to 5000 keywords.
My web application displays lot of texts which are stored in the database. My requirement is to scan each text for the occurance of any of the above keywords. If any keyword is present I have to replace that with some custom values, before showing it to the user.
I was thinking of using using regular expression for replacing the keyword in the text using matcher.replaceAll method as follows:
Pattern pattern = Pattern.compile(patternStr);
Matcher matcher = pattern.matcher(inputStr);
String output = matcher.replaceAll(replacementStr);
But My pattern string will have around 5000 keywords with the 'OR' Logical Operator like- keyword1| keyword2 I keyword3 | ..........
Will such a big pattern string adversly affect the performance? What can I do to speed up the performance? (Since my keyword list is not static i would prefer to do the replacement just before showing the text to the user)
Any suggestions are most welcome.

I don't think a pure regex approach would be that slow, but it would be a maintenance nightmare. I think a combined regex/table-lookup approach would be best: use a regex to identify potential keywords, then look them up in the table to confirm. For instance, to find all Java keywords you could use the regex "\\b[a-z]{2,12}+\\b" to filter out anything that can't possibility be a keyword.
What are you going to replace the keywords with? Will it vary depending on which keyword is found? If so, you'll have to use a table--and you won't be able to use the replaceAll method, because it can't handle dynamically generated replacement values. You would have to use the lower-level appendReplacement and appendTail method instead.

Pattern Matching problems

Hi people,
I'm having a slight problem with pattern matching. What I need to do is find if my pattern is a given string an return the end index.
Here's my string:
<TD>Some text</TD>
I need to find everything between the 2 anchor tags. (In this case "Some text"). The query string parameters are the only thing that can change.
Here's what I've tried:
Pattern pattern = Pattern.compile("<a href=\"/cgi-bin/dir/program.cgi?PARAM1=[0-9]&PARAM2=[0-9]*\"onmouseover=\"window.status='';return true;\">");
Matcher matcher = pattern.matcher(myString);
if ( matcher.find() ) {
System.out.println(matcher.end());
System.out.println(myString.substring(matcher.end(), myString.toLowerCase().indexOf("</a>",matcher.end())));
}Of course I've tried a lot of other things. I've also googled to try to find some examples but to no avail.
Thanks for any help.

Just change your Patterne. It will work. The '?' character is being considered as a pattern matching character, while you want it as it is. Use \\ before '?' character.
Pattern pattern = Pattern.compile("<a href=\"/cgi-bin/dir/program.cgi\\?PARAM1=[0-9]&PARAM2=[0-9]*\"onmouseover=\"window.status='';return true;\">");
Hope it helps.

Saving Pattern matching information to an array

I am using imaqLearnPattern function to create a template image. According the IMAQ documentation, the pattern matching information is "appended" to the image. But when I try to call the imaqImageToArray function on this template image, it does not give me any pattern matching information. Is there any way, that I can save the template data into an array? I do not want to use the imaqWriteVisionFile function because I want the data in an array format and not saved in a file.
Thanks.

Normally you cannot save this information without this function. This information saved in *.png file. This format have a possibilities for saving "user data", and this fact used by IMAQ Vision. Theoretically you can extract this information from *.png into array (format of png is a well known format), but what can you do with this information afterwards? You cannot load this information separately without IMAQ Read Image and Vision Info.vi, because (pretty sure) this function allocated memory for Vision Info before loading, but you not able to do this. You can make this only if you know internal representation of IMAQ image in memory. How organized common parameters, such as width, height, pixel pointer, resolution, linewidth - not very complicated (IMAQ Image -
a cluster of string and pointer to appropriate structure), but where placed vision info - not very easy.
Better, fastest and easyest way - to use IMAQ Write Image and Vision Info.vi.
with best regards

Latin 1 supplement for Pattern matching

Hi All,
I am trying to pattern match a string with the following pattern:
"\\p{InLatin1Supplement}+"(want to allow only characters in Latin 1 Supplement charset)
However I get java.util.regex.PatternSyntaxException: Unknown character family {Latin1Supplement}Please suggest what should be the proper string for the pattern.
Thank you !!

Hm, have your checked Blocks-3.txt, as it says in the javadocs?
"Unicode blocks and categories are written with the \p and \P constructs as in Perl. \p{prop} matches if the input has the property prop, while \P{prop} does not match if the input has that property. Blocks are specified with the prefix In, as in InMongolian. Categories may be specified with the optional prefix Is: Both \p{L} and \p{IsL} denote the category of Unicode letters. Blocks and categories can be used both inside and outside of a character class.
The supported blocks and categories are those of The Unicode Standard, Version 3.0. The block names are those defined in Chapter 14 and in the file Blocks-3.txt of the Unicode Character Database except that the spaces are removed; "Basic Latin", for example, becomes "BasicLatin". The category names are those defined in table 4-5 of the Standard (p. 88), both normative and informative."
Other than that, I don't know, sorry.

Pattern Matching/Encoding

I have the following code working to identify characters in a string that are not in the ASCII character set. Now I want to do the same thing and compare the string to the Cp1252 character set but regex doesn't seem to have that functionality.
I tried Pattern pattern = Pattern.compile("\\P{Cp1252}");
Can anyone point me in the right direction?
     Pattern pattern = Pattern.compile("\\P{ASCII}");
     while ((test=r.readLine())!=null) {
            Matcher matcher = pattern.matcher(test);
            boolean found = false;
            while (matcher.find()) {
                w.write(i + delim + matcher.group() + delim + (matcher.start() + 1) + delim + (matcher.end() + 1) + delim + test);
                w.write('\r');
                w.write('\n');
                found = true;
            }

As a rule, regexes don't match characters according to whether they're covered by a given encoding. (The "ASCII" in \p{ASCII} isn't so much a reference to the ASCII charset as it is an acknowledgement that other charsets exist, in the same sense that nobody ever used the phrase "analog wristwatch" until digital watches came out.) However, Java's Pattern class does have a pre-defined character class, \p{L1}, that seems to correspond to Latin1, or ISO-8859-1. Cp1252 is a superset of Latin1 which adds several characters in the 128-159 range that Latin1 doesn't use.
Matching those characters in a Java program is tricky because (1) if you type them in directly and then save the source file as Latin1 (the default encoding on some systems), they'll all turn to garbage; and (2) you can't use their Cp1252 encodings, as in [0xF0-0x9F], because Java char's are encoded as UTF-16. The only safe way to match them (or not match them, in your case) is to type in their Unicode escapes:
"[^\\p{L1}\u0152\u0153\u0160\u0161\u0178\u017D\u017E\u0192" +
"\u02C6\u02DC\u2013\u2014\u2018-\u201A\u201C-\u201E" +
"\u2020-\u2022\u2026\u2030\u2039\u203A\u20AC\u2122]"

Pattern matching String

Similar Messages

Maybe you are looking for