Phone number Regular expression Help

Question

Hi,
I am trying to validate phone number using regular expression.
The format shoud be either of the two given below. It should not
accept phone number of any other format other than the once given below.
I tried out the following regular expression
pn.matches("[\p{+}][0-9]+ ")
but it accepts alphabets too(which is wrong).
How do i check if the phone number is of the following format(OR condition).
0401234567
[phone]
Any help would be kindly appriciated.
Thanks
Sanam

Answer 1

There will probably be much more constraints on you phone numbers, but here's a start:String[] numbers = {"0401234567",      // should be ok
                    "040123456",       // wrong, one number too little
                    "[phone]",   // should be ok
                    "[phone]",  // wrong, one number too much
                    "[phone]"};   // wrong, one number too little
String regex = "\\+[0-9]{12}"+         // a + sign, followed by 12 numbers
               "|"+                    // OR
               "0[0-9]{9}";            // a zero, followed by 9 numbers
for(String n : numbers) {
  System.out.println("Is "+n+" valid? "+n.matches(regex));
}