PHP - MySQL - SET column

In my sql database I have a set column that works fine. The user can select multiple options. However, I am having trouble displaying those options using the record set in dreamweaver. I want the recordset to find any one of the possible options and display the record, but it's not displaying anything. Am I missing something here?

OK, my bad. So a SET is sort of a user defined datatype, where the developer sets the allowable values of the column? The thing that troubled me is that the example the reference guide gives shows it being used to store multiple values as in the last line here:
For example, a column specified as SET('one', 'two') NOT NULL can have any of these values:
'one'
'two'
'one,two'
So that's not really a problem inherent in a SET column, just a way that it can be misused like any other string column.
David_Powers wrote:
bregent wrote:
I'll just put in my $0.02 that +99% of the time using a SET to store more than one piece of data in a database field is a bad idea. It violates rules of normalization and makes data analysis very difficult.
Not really. A SET column in MySQL doesn't violate the rules of normalization. It's actually a shorthand way of creating a lookup table - or a linking table, since it creates a many-to-many relationship. Internally, MySQL simply stores a numerical reference to each value. In other words, behind the scenes it's storing a bunch of foreign keys.
The way you search for a particular option stored in a SET column is to use the MySQL function, FIND_IN_SET().
SELECT * FROM mytable
WHERE FIND_IN_SET('whatever', column_name)

Similar Messages

PHP MySQL 2 column list

I am building at site in dreamweaver using PHP/MySQL.
I have a page that will list a bunch of categories. I would
like to have them in a two column list instead of one. It will look
better as far as the design goes. How can I do this. I would like
each column to be an equal amount as possible

On 13 Mar 2007 in macromedia.dreamweaver.appdev,
newhorizonhosting.com
wrote:
> I have a page that will list a bunch of categories. I
would like to
> have them in a two column list instead of one. It will
look better
> as far as the design goes. How can I do this. I would
like each
> column to be an equal amount as possible
Have a look at Tom Muck's Horizontal Looper extension:
http://www.tom-muck.com/extensions/help/HorizontalLooper/
Joe Makowiec
http://makowiec.net/
Email:
http://makowiec.net/email.php

Problems with recordset in PHP/MySQL setting

We use Dreamweaver CS5 for creating dynamic pages (PHP pages with MySQL database). We test the site locally on a Windows 7 operating system with EasyPHP as WAMP server.
We often have a problem in managing the record set.
The following problem occurs quite often:
We take a PHP page. We create a recordset. We use a dynamic table or a repeated region to show the results of the recordset. So far so good.
Then we want to change something to the recordset for example the filter. When editing the recordset, the advanced mode is shown, it is impossible to swith to the simple mode.
By deleting the recordset the problem is not solved. By deleting and afterwards rebuilding the recordset, syntax errors occur. It seems that the php code for building the recordset didn't dissapear.
The only solutions till now seems to completely restart with a new PHP page.
Anyone has a solution for this or anyone did experience the same problem ?
Thank you very much in advance.
Ilse

You cannot switch to Simple mode in the Recordset dialog box if you have made any changes to the SQL in Advanced mode.
Opening the Recordset dialog box to edit the settings does occasionally result in the code being inserted again instead of being changed. This appears to be an intermittent bug, which I have experienced myself, and know that others have complained about it, too. As far as I know, there is no solution other than to watch carefully the code that Dreamweaver generates.
If you don't understand the code, you would be well advised to learn what it means and does. Relying on Dreamweaver to do everything for you severely limits what you can do with PHP/MySQL. Adobe regards the server behaviors as quick prototyping tools, rather than for developing production websites.

(PHP/MySql) Create Recordset but no column

Thanks for reading this, I am new to PHP/MySql
I have created a website www.ritchiecraft.co.uk which uses
PHP/MySql with Dreamweaver 8. I have created recordsets on most
items pages and filtered data as neccessary. After the site was up
and running I was required to insert a new topic and when I went to
create a new page and insert the recordset no data was placed in
the columns area and the filter/sort options were greyed out. I
checked the existing pages and found that this was happening to all
pages with recordsets. The connection, table data was there.
The site still works fine but I cannot introduce new pages or
edit existing because of the recordset problem. I was advised
previously to delete the Dreamweaver cache file but this did not
help.
The site is hosted commercially and the database was created
with phpMyAdmin and dont seem to have any connection problems.
Thanks for your time and any suggestions are welcome.

sweetman wrote:
> How can I set a query so that it sounds like this:
>
> SELECT $_GET['id'] FROM mytable ORDER BY myorder ASC?
You can't do it through the Recordset dialog box. The simple
way to do
it is to create this query in the Recordset dialog box:
SELECT * FROM myTable
ORDER BY myOrder ASC
Then go into Code view and locate the following line:
$query_recordsetName = "SELECT * FROM myTable ORDER BY
myOrder ASC";
Change it to this:
if (isset($_GET['id'])) {
$col = get_magic_quotes_gpc() ? stripslashes($_GET['id']) :
$_GET['id'];
$col = mysql_real_escape_string($_GET['id']);
else {
$col = '*';
$query_recordsetName = "SELECT $col FROM myTable ORDER BY
myOrder ASC";
David Powers, Adobe Community Expert
Author, "The Essential Guide to Dreamweaver CS3" (friends of
ED)
Author, "PHP Solutions" (friends of ED)
http://foundationphp.com/

How to set up a PHP/mySQL "server" in arch?

Hi,
I know its a wide question, and i may have to go to different howtos and such, but as this distro is different from the others there might be some differences in that.
If i want to run a PHP based site in mozilla and the site is hosted in my machine, do i need to do something real strange to make it work ?
if you can post any link to some info, it wont hurt. and yes i will google anyway!

sud_crow wrote:If i want to run a PHP based site in mozilla and the site is hosted in my machine, do i need to do something real strange to make it work?
I am running Apche/PHP/MySQL on my machine and simple to setup. Few things requires to know. It can be done in different way. This is how I do including how to test the server(s). Host name is: "localhost". If anything is missing, please let me know.
INSTALL:
pacman -S apache
pacman -S php
pacman -S mysql
APACHE:
1. Add the following line in /etc/httpd/conf/httpd.conf :
LoadModule php4_module /usr/lib/apache/libphp4.so
AddModule mod_php4.c
AddType application/x-httpd-php .php
2. Add line in /etc/host :
127.0.0.1 localhost.localdomain localhost
3. Edit /etc/rc.conf :
# Networking
HOSTNAME="localhost"
4. Run in terminal (root):
# /etc/rc.d/httpd start
5. Edit /etc/httpd/conf/httpd.conf (close "AddModule mod_php4.c"):
LoadModule php4_module /usr/lib/apache/libphp4.so
# AddModule mod_php4.c
AddType application/x-httpd-php .php
6. Add line in /etc/rc.local (to start at boot):
/etc/rc.d/httpd start
Test Apache:
http://localhost/
PHP:
1. Edit /usr/etc/php.ini (open the mysql extension):
extension=mysql.so
Test PHP with a simple script:
<html>
This is a test. Say hello to Arch:

<body>
<?php
$myvar = "Hello Arch Linux";
echo $myvar;
?>
</body>
</html>
Save the file as "test.php" and copy to /home/httpd/html/
Test PHP:
http://localhost/test.php
MySQL:
1. Run in terminal:
# /etc/rc.d/mysqld start
2. Add line in /etc/rc.local (to start at boot):
/etc/rc.d/mysqld start
Test MySQL
Run in terminal (don't enter any password):
# mysql -p
Note: Change the /var/lib/mysql directory to user "mysql" if not getting MySQL to run.
For more information (if new in PHP/MySQL):
http://hotwired.lycos.com/webmonkey/99/21/index2a.html

PHP MySQL data display problem

I am having trouble getting data to display on my web page.In Dreamweaver CS3, I created a new page.
Selected PHP as the type.
Saved it.
Connected a database and created a recordset (all using Dreamweavers menus. I did not write any code).
NOTE: The database is on a remote server.
The TEST button displayed the records from the recordset with no problem.
On the new page, I then typed some text.
Then dragged some fields from the Bindings tab to the page.
I saved it and then went to preview it in my browser.
The page comes up completely blank. Not even the text shows.
I then saved the page as an HTML page.
When I preview this in my browser, the text shows, but the fields and data do not.
I then tried creating a dynamic table (again, using the Dreamweaver menus.).
A similar thing happens, ie. If I save it as an HTML, the text shows and the column labels and border shows, but no data.
Nothing shows if I save it as a PHP file.
I can view the data online using files created by PHPMagic, so I know the data is there and retrievable.
It is just in pages created in Dreamweaver that don’t work.
What am I doing wrong?

My web server supports PHP. I can disply PHP pages created by other software packages, just not the Dreamweaver ones.
Frank
Date: Thu, 4 Jun 2009 19:04:03 -0600
From: [email protected]
To: [email protected]
Subject: PHP MySQL data display problem
To view php pages - or pages with PHP code in them - in a browser, the page must be served up by a Web server that supports PHP. You can set up a testing server on your local machine for this purpose. Look for WAMP (Windows), MAMP (Mac), or XXAMP for some easily installed packages.
Mark A. Boyd
Keep-On-Learnin'
This message was processed and edited by Jive.
It shall not be considered an accurate representation of my words.
It might not even have been intended as a reply to your message.
>

Football/soccer results grid advice php/mysql

I need to create the above from my database, and I am not sure how to go about it.
Basically this calculates all the goals scored against another team. If team 1 (column) is the same as team 1 (row) an "x" is put in place as team 1 cannot play itself
I have added my database structure
Image of example
http://filedb.experts-exchange.com/incoming/2010/08_w34/t337870/Untitled-1.jpg
CREATE TABLE IF NOT EXISTS `matches` (
`match_id` int(8) NOT NULL auto_increment,
`date` date default NULL,
`time` varchar(5) default NULL,
`report` longtext,
`referee_id` int(8) NOT NULL,
`season_id` int(8) NOT NULL,
PRIMARY KEY (`match_id`),
KEY `referee_id` (`referee_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;
-- Dumping data for table `matches`
INSERT INTO `matches` (`match_id`, `date`, `time`, `report`, `referee_id`, `season_id`) VALUES
(1, '2010-08-02', '15:00', 'N/A', 1, 2010),
(2, '2010-08-10', '15:00', 'n/a', 1, 2010);
CREATE TABLE IF NOT EXISTS `matchscores` (
`matchscores_id` int(8) NOT NULL auto_increment,
`match_id` int(8) NOT NULL,
`team` int(8) NOT NULL,
`score` int(8) default NULL,
PRIMARY KEY (`matchscores_id`),
KEY `match_id` (`match_id`,`team`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=3 ;
-- Dumping data for table `matchscores`
INSERT INTO `matchscores` (`matchscores_id`, `match_id`, `team`, `score`) VALUES
(1, 1, 1, 2),
(2, 1, 2, 1);
CREATE TABLE IF NOT EXISTS `team` (
`team_id` int(8) NOT NULL auto_increment,
`team_name` varchar(255) NOT NULL,
`team_address` text,
`team_phone` varchar(25) default NULL,
`team_email` varchar(255) default NULL,
`team_web` varchar(255) default NULL,
`colours_home` varchar(50) default NULL,
`colours_away` varchar(50) default NULL,
`manager` varchar(255) default NULL,
`assistant` varchar(255) default NULL,
`club_rep` varchar(255) default NULL,
`division` varchar(255) default NULL,
`team_pic` varchar(255) default NULL,
`team_logo` varchar(255) default NULL,
`profile` mediumtext,
`honours` mediumtext,
`password` varchar(10) NOT NULL,
PRIMARY KEY (`team_id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;

Tbilly,
I have just the thing you are looking for. Check this out
here:
http://www.smithmediafusion.com/poll/poll.html
MySQL and php with a Flash front.
drop me an email if you are interested and would like more
info.
danswhc AT yahoo dot Com
Dan Mode
--> Adobe Community Expert
*Flash Helps*
http://www.smithmediafusion.com/blog/?cat=11
*THE online Radio*
http://www.tornadostream.com
<--check this
*Must Read*
http://www.smithmediafusion.com/blog
"tbilly" <[email protected]> wrote in
message
news:erfeo6$9a$[email protected]..
> Can anyone recommend a book or tutorial for a survey or
poll script I
> could
> implement using php/MySQL? Preferably one with options
such as: changing
> question types (radio vs. checkboxes), sessions, and
graphical displays of
> results. Would like to use dreamweaver to set up content
management pages
> to
> edit/add answers and questions in a database. Thanks in
advance.
>

Can't connect PHP/MySQL 404 error

Wow, the learning curve is killing me. Yet another challenge. I'm using Dreamweaver CC and this tutorial http://www.adobe.com/devnet/dreamweaver/articles/setup_php.html
I'm at this step:
Open comments.php. You must have a PHP page open in the Document window to create a MySQL connection.
In the Databases panel (choose Window > Databases), click the Plus button on the panel and select MySQL Connection.The MySQL Connection dialog box appears.
Type connTest as the connection name.
For the MySQL Server, type localhost.If you are using the MAMP default ports on a Mac, use localhost:8889.
For the User Name, type phptestuser.
Type the password you chose for the phptestuser account in the Password field.
For the Database, type php_test.Note: You don't need to precede the underscore with a backslash here. It was inserted by phpMyAdmin in the previous section (see Figure 20) only because phpMyAdmin uses a query that permits wildcard characters.
Click Test.Dreamweaver attempts to connect to the database. If the connection fails, do the following:
Double-check the server name, user name, and password.
Check the settings for the folder Dreamweaver uses to process dynamic pages (see Specifying a Testing Server for Dreamweaver).
Verify that the web and MySQL servers are both running.
Temporarily disable any firewall or security program. If the connection works, you need to configure the security program to permit communication between Dreamweaver and MySQL.
Click OK. The new connection appears in the Databases panel.
Expand the connTest connection, and then expand the Tables branch. You'll see the comments table in the database, which you can expand to reveal the details of the table columns (see Figure 23).
As far as I can tell I have followed this tutorial to the letter.
As far as I can tell, XAMPP/php mySQL are all running fine, the files are in the correct place and everything should be working. However when I hit test I get a 404 error. (Same error when I hit the select button.)
The suggested problems on the 404 message are:
1. There is no testing server running on the server machine.
Pretty sure the testing server is running. Is there any way to test this, other than to note that xampp is definitely running right now and that I can log into phpMYadmin no problem?
2. The testing server specified for this site does not map to the http://localhost/php_test/_MMServerScripts/MMHTTPDB.php URL Verify that the URL Prefix maps to the root of the site.
Ummm...I'm pretty sure I put things where I was told to put them in the tutorial, but I'm lost at this point where I should verify what. A clue here? The files are where they are supposed to be, but maybe I entered something wrong? Except...I'm not sure what that could be or where to find it. Whatever IT is.
Everything in local files is looking good.
Thanks for your help!
PS: Extra points to anyone who figures out how to make copy/pasteable error messages! These buggers are the bane of my life!

Bgupta, you rock!
I hope you have copied the "mysql.php" and "MMHTTPDB.php" files from "C:\Users\username\AppData\Roaming\Adobe\Dreamweaver CC\locale\Configuration\Connections\Scripts\PHP_MySQL\_mmDBScripts" to "C:\xampp\htdocs\phptest\_mmServerScripts"
This was EXACTLY the problem. I checked the tutorial and I couldn't even find where the tutorial said to do this. (If I missed it, let me know where in the tutorial it was, please.)
Fixed!

Show if field is not empty - PHP/MySQL

Is there a way I can only show bits of a page if a recordset
has entries in a certain field, automatically hiding the area if
the field is empty. (PHP/MySQL)
To put it in real terms, I have loads of products listed in a
repeating table. If a product has a photo gallery related to it
there is a 1 entered in 'photos' field, it has a video attached
here is a 1 entered in 'videos field and likewise for reviews it
will have a 1 entered in the reviews field.
What I'd like to have is a photo, video and review icon/link
in the 'master table' which only appears in the repeated products
that have a 1 listed in that field and have them not appear at all
when there is a 0 in the field.
Can anyone help me figure it out

ADDT is certainly a great help, as it - among many other
features - will allow you define whatever page element as
"show/hide" based on a query result -- for this it´s using a
so-called "condition builder" which lets you do that without
coding.
However you can achieve the same result without needing to
resort to ADDT -- by using a basic "if" condition that´s
checking the respective table column for having the value "1"
stored, and if so, display the page segment
The following 3 examples should work when replacing the
sample "queryname" with the query name your page is actually using:
<?php if ($row_queryname['photos'] == '1') {?>
display photo icon here
<?php }?>
<?php if ($row_queryname['videos'] == '1') {?>
display video icon here
<?php }?>
<?php if ($row_queryname['reviews'] == '1') {?>
display videos icon here
<?php }?>

PHP/Mysql issue

I use Dreamweaver CS3 to create my sites on a Windows/Apache
Server with PHP5 and Mysql 5. The site works perfectly on my
testing server at home. On the Web server I'm getting the following
error which causes the page to not load:
PHP Warning: mysql_query(): supplied argument is not a valid
MySQL-Link resource in
/hermes/bosweb/web248/b2488/ipw.horsehelp/public_html/residents/residents.php
on line 63
PHP Warning: mysql_select_db(): supplied argument is not a
valid MySQL-Link resource in
/hermes/bosweb/web248/b2488/ipw.horsehelp/public_html/residents/residents.php
on line 61
The lines in question are:
Line 61 - mysql_select_db($database_conn_phh, $conn_phh);
$query_getSuccess = "SELECT * FROM horses WHERE status =
'Success Story' ORDER BY horse_barn ASC";
$getSuccess = mysql_query($query_getSuccess, $conn_phh) or
die(mysql_error());
$row_getSuccess = mysql_fetch_assoc($getSuccess);
$totalRows_getSuccess = mysql_num_rows($getSuccess);
All of the code is supplied by Dreamweaver. I did not tweak
the code. I'm not a web developer and what I have found out there
is still reading greek to me. My connection file is working and
connecting the database that I have tested.
Since the above code is throughout the site in one form or
another it's causing me major headaches. Any help would be
appreciated.

This is the first time I've used Adobe products so if the
following is in the wrong forum (It's the closest one I found so
far) or the format is incorrect please forgive me.
I'm new to Dreamweaver CS3 and as I was reading the "first
steps" it mentions to set up a Dreamweaver site right away. I got
as far as completing "Site Definition" page under the basic side of
the setup screen.
The next screen is "Do you want to work with server
Technology?"
There are 2 options - Yes or No. If you select yes a
drop-down menu appears with several options (but you can only
select one)...
Asp Javascript
Asp VbScript
Asp.net#
Asp.net Vb
Cold Fusion
JSP
Php MySql.
I know nothing about these format and brand new to web design
so I thought it best to contact GoDaddy (my hosting account) to
find out what their servers would support. I spoke to a tech rep
but she wasn't sure.
She did mention that I have a windows hosting account and Php
MySql would not work unless I changed to their Linux platform at no
additional charge.
The site I have in mind will design with CSS, Liquid layout,
have some flash, widgets, an inquiry form that clients complete and
results e-mailed to me, auto-responder, Paypal link and whatever
else I can discover from Dreamweaver.
My question being:
I haven't even begun designing my site because I do not know
what weather I should select the Yes option and select one of the
formats mentioned above (if so which one) - or select the No
option. If I do select the No option at the very beginning, will I
have problems with my site uploading and working correctly?
Thank you
Travis

Using LIMIT function in PHP/MySQL Dreamweaver RecordSet

I want to have a record set that skips the first record, and shows the next three. I've found several suggestions online to use the LIMIT function, but I keep getting "error in SQL syntax." What am I missing?
mysql_select_db($database_adventcms, $adventcms);
$query_rsSideNews = "SELECT * FROM tb_news LIMIT 1, 3 WHERE status = 'Live' ORDER BY `date` DESC";
$rsSideNews = mysql_query($query_rsSideNews, $adventcms) or die(mysql_error());
$row_rsSideNews = mysql_fetch_assoc($rsSideNews);
$totalRows_rsSideNews = mysql_num_rows($rsSideNews);

And there we go. That's the reason I need to go through PHP/MySQL training rather than relying on google searches!

Command in php / mysql

Hello,
I used to program a lot in ASP, and loved the command
function.
However, now that I'm programming in PHP I do not have this
at my disposal unfortunately.
How does everyone perform certain actions on forms right
now?, for example I'm performing an update on a record, but want to
update all records in the table first by setting a certain field to
0.
Any thoughts and ideas / samples are greatly
appreciated!

Jasmine2002 wrote:
> Correct, in ASP however I had the command so I can later
on easily call up the
> box and change / add / update my SQL.
>
> Do you just write the appropriate PHP for it?, I don't
really know how to
> properly write this in conjuction with Dreamweaver.
I suspect that command is probably a stored procedure.
Unfortunately,
stored procedures were added to MySQL only in version 5.0,
and
Dreamweaver doesn't support stored procedures in the PHP
MySQL server
model. (I've lobbied for support, but it hasn't happened
yet.)
Your update is rather unusual, but you should be able to get
Dreamweaver
to generate the code for you using the Update Record server
behavior.
David Powers, Adobe Community Expert
Author, "Foundation PHP for Dreamweaver 8" (friends of ED)
Author, "PHP Solutions" (friends of ED)
http://foundationphp.com/

Spry select list code to wire it to html data table SET column?

I am making a page based on Figure 15-14, Pg 878, in David Power's book, "Dw CS4 with CSS, Ajax and PHP. I have two separate html data tables hidden in the page, one for the specialties drop down select list and the other for the teachers master/detail regions. These are populated with php and working well. The spry select list and master/detail regions are working great except for one issue. The column in my html data table that is being filtered ("Specialty" in my code = 'Category' in the book's example code) is a SET column (with possible value of 1, 2, 3, 4, and/or 5). Clicking on the drop down menu brings up the records with a single value beautifully. The result for records with multiple values is a spry error "Invalid row number: 0". After four different versionings and methods of messing with this, I still haven't a clue. Please help me with how to rewire the Spry select list code so that it will read the records that have multiple items in that column. I have included the code below.
var data_set_teachers = new Spry.Data.HTMLDataSet(null, "teacher_data");
data_set_teachers.gallery = '1';
function chooseSet(dataSet, row, rowNumber)
if (row["Specialty"] == data_set_teachers.gallery) {
 return row;
return null;
data_set_teachers.filter(chooseSet);
function changeSet(set)
data_set_teachers.gallery = set;
data_set_teachers.filter(chooseSet);
data_set_teachers.setCurrentRowNumber(0);
var rows = data_set_teachers.getData();
for (var i = 0; i < rows.length; i++) {
 if (rows[i]["Specialty"] == set) {
 data_set_teachers.setCurrentRowNumber(i);
 break;
var data_set_specialties = new Spry.Data.HTMLDataSet(null, "specialty_data");

Well I'll be damned!
What's done in the sample app is, of course, the intuitively obvious choice and is exactly what I started out trying to do the first time round.
But as I mentioned before, when I first tried it (yes: I'm pretty sure I set the "for" attribute on the inlineMessage components), I got the non-unique component id exception for the inlineMessage component(s) after adding the second (but not the first) row to the page.
Anyway, after dragging my inlineMessages to the exact same position as those in the AppModel example, now things work fine (except I think I'd like a line break before the message and to change the row/column styles so the values and messages line up properly...the look is rather ugly in the AppModel example when there are validation messages displayed).
Not sure, but I'm thinking maybe there was an issue with where the inline message markup was placed, my first time through, relative to the data table value bound component and the column header facet?
I was using the application view drag 'n drop feature the first time round and dragged the inlineMessage component to the spot just below the data table value bound component and hence just above the column header facet. In the AppModel example, OTOH, the inline messages are placed just after the column header facet.
Of course, I will now try to duplicate the original exception.
If I can (and it is an issue with placement), I will post back some sort of bug report or RFE. Otherwise, I'll post back declaring what a bone head I've been...;-)
Anyway, thanks for the quick response, v.
Campbell

I need help with DW, PHP & MySQL please.

Hello, I am new to website development and am trying to set up a form for collecting data on my website and have a question that I can’t find an answer to anywhere else. I was wandering if someone there would be kind enough to help? I am using Dreamweaver in CS4 and my host already has PHP & MySQL installed on the server that I can use. My question is: Do I need to download XAMP or WAMP on my computer before trying to connect my form to the server? Also, do I need to change the page I am putting the form on to .PHP extension or can I just embed the PHP form into an existing HTML page?
Most of the training tutorials I’ve read don’t start at the most basic beginning but rather expect people to already have a basic knowledge of the topics they are trying to learn. If anyone knows the best place to get answers to the most basic questions like this one or a beginners guide to working with DW, PHP & MySQL I will gladly go there rather than waste your time on questions you’ve probably already answered a bezillion times.
Thank you for the help.

Strictly speaking, you don't need XAMPP or WAMP on your local computer. But if you're serious about getting involved with PHP/MySQL, you should definitely set up a local testing environment with one or the other. It's safer and more efficient. Don't expose all your errors on a live server. You can find instructions on how to set up a testing environment here: http://www.adobe.com/devnet/dreamweaver/articles/setting_up_php.html.
To develop with PHP, you should always use a .php file name extension. Any other choice is very rare.
There's a tutorial on building your first dynamic website with DW here: http://www.adobe.com/devnet/dreamweaver/articles/first_dynamic_site_pt1.html.
For more in-depth help, you might want to consider grabbing hold of a copy of "The Essential Guide to Dreamweaver CS4 with CSS, Ajax, and PHP". (Yes, I wrote it, so it's a bit of shameless self-promotion, but you'll find it answers many of your questions - and probably a lot you hadn't even thought of.)

PHP MySQL Error Code 500

May be someone can help me out with this problem.
I have setup a new site using PHP MySQL and Dreamweaver 8.02.
Dreamweaver connects to the database but after creating a
recordset the recordset cannot be used.
instead Dreamweaver returns:
HTTP Error Code 500 internal Server Error
Any help will be much appriciated.
Jos

Hello,
I have also had the same error - namely that whilst I could connect via ftp, upload/download files, and view database tables, any attempt to view of modify recordsets resulted in error 500.
Having checked other potential causes (e.g. selection/non-selection use of passive FTP setting, enabling of php, etc.), on the back of posts here I contacted my host and asked if if could relate to mod security, as further investigation revealed that the issue only occurred on sites where mod security had not been disabled (I don't like to disable mod security for obvious reasons - and I'm told you can't do that site by site with apache2 anyway).
After a few false starts, the problem was resolved - with the following response from my host: "The false positives were being generated by "/_mmServerScripts/MMHTTPDB.php" and that is what we've worked around in the rules. As such, any domain on [servername] using that script in the same way shouldn't generate a false-positive moving forward."
So it seems the answer (assuming your on an apache server of course) may be to modify the rules to allow full access for MMHTTPDB.php.
I hope that is of help to some.

PHP - MySQL - SET column

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