Please help with optimizing aggregate query

Good Morning.
I hope this will be a simple question, so I won't give a lot of detail about the db unless you ask for clarification.
I have four tables I need to join. CLC can have many CLS, and a CLS can have many CUSTD, and a CUSTD can have many CUSTDR.
I need to add up all the rows in CUSTD for one CLC, and subtract the sum of all the rows in CUSTDR for that CLC.
I first tried this
SELECT SUM(custd.amount_owed) - SUM(cusdr.amount_refunded)but that doesn't work because the amount owed is returned for every amount refunded.
Then I tried using a subquery
   SELECT
      TO_CHAR(owed.amount - NVL(SUM(custdr.refund_amount),0), 'L999G999G999G999D00')
    INTO
      g$_value
    FROM
      claim_settlements          cls
      ,customer_debts            custd
      ,customer_debt_recoveries custdr
         SELECT
            cls1.clc_id                 id
            ,SUM(custd1.owed_amount),0 amount
          FROM
            claim_settlements    cls1
            ,customer_debts      custd1
          WHERE
                custd1.st_table_short_name = 'CLS'
            AND custd1.key_value = cls1.id
            AND custd1.status != 'WO'
          GROUP BY
            cls1.clc_id
      )owed
    WHERE
          custd.st_table_short_name = 'CLS'
      AND custd.key_value = cls.id
      AND custd.id = custdr.custd_id(+)
      AND cls.clc_id = p$_key_value
      AND owed.id = cls.clc_id
    GROUP BY
      owed.amount;   I would like to know if this is possible using an analytic sum. This query works, but I read that analytics are better than sub queries, and I am still not sure on all the uses of analytic functions.
Thanks
Message was edited by:
dmill
Updated my question.
Message was edited by:
dmill

Thanks, Nic
That is the kind of query I was imaging, so I hope we can get it to work.
Here is information about the tables and the data:
DESC customer_debts
Name                           Null     Type
ID                             NOT NULL NUMBER(28)
CUSTA_ID                       NOT NULL NUMBER(28)
GLTT_ID                        NOT NULL NUMBER(28)
ST_TABLE_SHORT_NAME            NOT NULL VARCHAR2(10)
KEY_VALUE                      NOT NULL NUMBER(28)
OWED_AMOUNT                    NOT NULL NUMBER(11,2)
OWED_BY_CUSTOMER               NOT NULL VARCHAR2(1)
STATUS                         NOT NULL VARCHAR2(2)
NOTES                                   VARCHAR2(4000)
DATE_CREATED                   NOT NULL DATE
CREATED_BY                     NOT NULL VARCHAR2(30)
DATE_MODIFIED                           DATE
MODIFIED_BY                             VARCHAR2(30)
13 rows selected
DESC customer_debt_recoveries
Name                           Null     Type
ID                             NOT NULL NUMBER(28)
CUSTD_ID                       NOT NULL NUMBER(28)
ST_TABLE_FOR_PAID_BY           NOT NULL VARCHAR2(10)
KEY_VALUE_FOR_PAID_BY          NOT NULL NUMBER(28)
REFUND_AMOUNT                  NOT NULL NUMBER(11,2)
REFUND_CHECK_NUMBER                     NUMBER(9)
DATA_SOURCE                    NOT NULL VARCHAR2(1)
NOTES                                   VARCHAR2(4000)
DATE_CREATED                   NOT NULL DATE
CREATED_BY                     NOT NULL VARCHAR2(30)
DATE_MODIFIED                           DATE
MODIFIED_BY                             VARCHAR2(30)
12 rows selected
customer_debts custd
ID                     CSL_ID                 OWED_AMOUNT
1                      4143802                20
2                      4143802                10
3                      4143802                10
5                      4143796                10
6                      4143806                10
7                      999999999              20
8                      999999999              10
9                      999999999              10
11                     4143802                100
9 rows selected
customer_debt_recoveries custdr
ID                     CUSTD_ID               REFUND_AMOUNT
1                      5                      10
2                      1                      27
3                      1                      5
3 rows selected
claim_charges clc and claim_settlements cls
CLC_ID                 CLS_ID
537842                 4143802
537842                 999999999
538057                 4143796
538209                 4143806
4 rows selectedThe clc is the object that we want the information for. For example, clc 537842 should return the amount of 148, which is the sum of all the debts minus the sum of all the recoveries.
clc 4143796 would return 0
and 4143806 would return 10
When I run your query for clc 537842, which looks like this with joins
select distinct
       clc.id clc_id
       ,sum(custd.owed_amount) over (partition by clc.id, cls.id, custd.id)
       sum(custdr.refund_amount) over (partition by clc.id, cls.id, custd.id, custdr.id) amount_owed
from
claim_charges             clc
,claim_settlements        cls
,customer_debts           custd
,customer_debt_recoveries custdr
where
      cls.clc_id = clc.id
AND custd.key_value = cls.id
AND custd.st_table_short_name = 'CLS'
AND custd.id = custdr.custd_id (+)
AND custd.status != 'WO'
AND clc.id = 537842I get this result
CLC_ID                 AMOUNT_OWED
537842
537842                 35
537842                 13
3 rows selectedThanks again, and let me know if this is not enough info.

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quote:
Originally posted by:
rere
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|   0 | SELECT STATEMENT                      |                              |     1 |    50 |       |    22 |
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|* 7 |          INDEX RANGE SCAN             | IDX_ENERGY_PDCT_CAT          | 1978 |       |       | 2478 |
|   8 |        SORT GROUP BY                  |                              |     1 |    40 |       | 1160 |
|* 9 |         TABLE ACCESS BY INDEX ROWID   | EES_HOSP_CHG_PROV            |     4 |    72 |       |     1 |
| 10 |          NESTED LOOPS                 |                              |     1 |    40 |       | 1157 |
| 11 |           NESTED LOOPS                |                              |     1 |    22 |       | 1156 |
|* 12 |            TABLE ACCESS BY INDEX ROWID| MVW_EES_ICD_STATS            |     1 |    16 |       | 1155 |
|* 13 |             INDEX RANGE SCAN          | MVWICDSTATS_DISCQTR_IDX      |    13M|       |       | 26068 |
|* 14 |            TABLE ACCESS BY INDEX ROWID| EES_CONS_PROV                |     1 |     6 |       |     1 |
|* 15 |             INDEX UNIQUE SCAN         | EES_CONS_PROV_PK             |     1 |       |       |       |
|* 16 |           INDEX RANGE SCAN            | PROV_ID_IDX_2                |    65 |       |       |     1 |
|   3 |   MERGE JOIN CARTESIAN                |                              |     1 |    50 |       |    22 |
|   4 |    VIEW                               |                              |     1 |    13 |       |     3 |
|   5 |     SORT GROUP BY                     |                              |     1 |    13 |       |       |
|   6 |      VIEW                             |                              | 3053 | 39689 |       |     3 |
|   7 |       TABLE ACCESS FULL               | SYS_TEMP_0FD9D68B3_C112F95D | 3053 |   110K|       |     3 |
|   8 |    VIEW                               |                              |     1 |    37 |       |    19 |
|   9 |     SORT GROUP BY                     |                              |     1 |    37 |       |    19 |
| 10 |      VIEW                             |                              | 3053 |   110K|       |     3 |
| 11 |       TABLE ACCESS FULL               | SYS_TEMP_0FD9D68B3_C112F95D | 3053 |   110K|       |     3 |
Predicate Information (identified by operation id):
   4 - access("EES_ENERGY_MASTER"."PROV_ID"="EES_CONS_PROV"."PROV_ID")
   5 - filter("EES_CONS_PROV"."CONS_06_09_YN"='N' OR "EES_CONS_PROV"."CONS_06_09_YN"='Y')
   6 - filter("EES_ENERGY_MASTER"."DISC_MON">=2006101 AND SUBSTR("EES_ENERGY_MASTER"."ICD_CODE",1,2)='68-gyn'
              AND "EES_ENERGY_MASTER"."MANUFACTURER"='EES')
   7 - access("EES_ENERGY_MASTER"."PDCT_CAT"='Energy')
   9 - filter("EES_HOSP_CHG_PROV"."PDCT_CAT"='Energy' AND "EES_HOSP_CHG_PROV"."MANUFACTURER"='EES')
12 - filter("MVW_EES_ICD_STATS"."ICD_GROUP"='68-gyn')
13 - access("MVW_EES_ICD_STATS"."DISC_QTR">=20061 AND "MVW_EES_ICD_STATS"."DISC_QTR" IS NOT NULL)
14 - filter("EES_CONS_PROV"."CONS_06_09_YN"='N' OR "EES_CONS_PROV"."CONS_06_09_YN"='Y')
15 - access("MVW_EES_ICD_STATS"."PROV_ID"="EES_CONS_PROV"."PROV_ID")
16 - access("MVW_EES_ICD_STATS"."PROV_ID"="EES_HOSP_CHG_PROV"."PROV_ID")
Please help with some solution.

OK: the third parameter of the SUBSTR function indicates the (maximum) length of the returnd string.
Therefore SUBSTR("EES_ENERGY_MASTER"."ICD_CODE",1,2) could possibly be '68' , but never '68-gyn'.
'68-gyn' is just 4 characters too long.
Urs

Need some help with the Select query.

Need some help with the Select query.
I had created a Z table with the following fields :
ZADS :
MANDT
VKORG
ABGRU.
I had written a select query as below :
select single vkorg abgru from ZADS into it_rej.
IT_REJ is a Work area:
DATA : BEGIN OF IT_REJ,
        VKORG TYPE VBAK-VKORG,
        ABGRU TYPE VBAP-ABGRU,
       END OF IT_REJ.
This is causing performance issue. They are asking me to include the where condition for this select query.
What should be my select query here?
Please suggest....
Any suggestion will be apprecaiated!
Regards,
Developer

Hello Everybody!
Thank you for all your response!
I had changes this work area into Internal table and changed the select query. PLease let me know if this causes any performance issues?
I had created a Z table with the following fields :
ZADS :
MANDT
VKORG
ABGRU.
I had written a select query as below :
I had removed the select single and insted of using the Structure it_rej, I had changed it into Internal table
select vkorg abgru from ZADS into it_rej.
Earlier :
IT_REJ is a Work area:
DATA : BEGIN OF IT_REJ,
VKORG TYPE VBAK-VKORG,
ABGRU TYPE VBAP-ABGRU,
END OF IT_REJ.
Now :
DATA : BEGIN OF IT_REJ occurs 0,
VKORG TYPE VBAK-VKORG,
ABGRU TYPE VBAP-ABGRU,
END OF IT_REJ.
I guess this will fix the issue correct?
PLease suggest!
Regards,
Developer.

Could you please help me make this query less complicated

could you please help me make this query less complicated
select t1.R_OBJECT_ID
from dm_relation_sp a, ddt_resolution_sp t1
where a.parent_id = '0900000283560456' -----------ID
and a.child_id = t1.R_OBJECT_ID
union all
select t3.R_OBJECT_ID
from ddt_resolution_sp t3
where t3.R_OBJECT_ID in (select t2.child_id
from dm_relation_sp t2
where t2.parent_id in (select a.child_id
from asud_fsk.dm_relation_sp a, asud_fsk.ddt_resolution_sp t1
where a.parent_id = '0900000283560456' -----------ID
and a.child_id = t1.R_OBJECT_ID))
union all
select t4.R_OBJECT_ID
from ddt_resolution_sp t4
where t4.R_OBJECT_ID in(
select t3.child_id from dm_relation_sp t3
where t3.parent_id in (
select t2.child_id
from asud_fsk.dm_relation_sp t2
where t2.parent_id in (select a.child_id
from asud_fsk.dm_relation_sp a, asud_fsk.ddt_resolution_sp t1
where a.parent_id = '0900000283560456' -----------ID
and a.child_id = t1.R_OBJECT_ID))
and t3.relation_name = 'RESOLUTION_RELATION')
union all
select t5.R_OBJECT_ID
from ddt_resolution_sp t5
where t5.R_OBJECT_ID in
(select t4.child_id
from dm_relation_sp t4
where t4.parent_id in(
select t3.child_id from dm_relation_sp t3
where t3.parent_id in (
select t2.child_id
from asud_fsk.dm_relation_sp t2
where t2.parent_id in (select a.child_id
from asud_fsk.dm_relation_sp a, asud_fsk.ddt_resolution_sp t1
where a.parent_id = '0900000283560456' -----------ID
and a.child_id = t1.R_OBJECT_ID))
and t3.relation_name = 'RESOLUTION_RELATION')
and t4.relation_name = 'RESOLUTION_RELATION')
Edited by: user13025450 on 29.04.2010 16:23

Hi,
Welcome to the forum! You'll find that there are many qualified people (such as Tubby) willing to help you. Will you do what you can to help them? In order to simplify the query you posted,someone will first have to understand what it does, what the tables that it uses are like, and what tools you have to work with (that is, what version of Oracle, and any other software you are using). To actually test their ideas, people will need versions of your tables.
Many people, if they spent enough time, might be able to figure out roughly what you are doing, make some tables themselves and test a solution. You can help with all of that. I assume you already know what the appliction is, and what this particular query is supposed to do: you don't have to figure out any of that, you just have to say it. You know what all your tables are, what the datatypes of all the columns are, and what kinds of data are in the tables: you don't have to guess at any of that.
Describe what you're doing. Think about it: how do we know that
SELECT NULL
FROM dual;doesn't do what you want?
Post CREATE TABLE and INSERT statements for a little sample data.
Post the results that this query is supposed to produce from those results. (Is it producing the right output now? Then it should be easy to post the correct results.)
Describe, as well as you can, how the present query is doing it.
Format your existing code, so it's easy to see what the different branches of the UNION are, and what the main clauses are in each one.
When posting formatted text (code or results) type these 6 characters
\(all small letters, inside curly brackets) before and after each formatted section, to keep this site from compressing the spaces.
Say what versions of Oracle (e.g. 10.2.0.3.0) and any other relevant software you are using.
I know it's a lot of work, but it really helps. You can do it as well (probably better) than anyone else, and if you're unwilling to do it, why should anyone else be willing?

HT5824 I switched over from an iPhone to a Samsung Galaxy S3 & I haven't been able to receive any text messages from iPhones. Please help with turning my iMessage completely off..

I switched over from an iPhone to a Samsung Galaxy S3 & I haven't been able to receive any text messages from iPhones. I have no problem sending the text messages but I'm not receivng any from iPhones at all. It has been about a week now that I'm having this problem. I've already tried fixing it myself and I also went into the sprint store, they tried everything as well. My last option was to contact Apple directly. Please help with turning my iMessage completely off so that I can receive my texts.

If you registered your iPhone with Apple using a support profile, try going to https://supportprofile.apple.com/MySupportProfile.do and unregistering it. Also, try changing the password associated with the Apple ID that you were using for iMessage.

How can I sync my iPhone on a different computer without erasing my applications? My iPhone was earlier synced with a PC which I don't use anymore. Please help with proper steps, if any.

How can I sync my iPhone on a different computer without erasing my applications? My iPhone was earlier synced with a PC which I don't use anymore.
On the new computer, I am getting a message that my all purchases would be deleted if I sync it with new iTunes library.
Please help with proper steps, if any.

Also see... these 2 Links...
Recovering your iTunes library from your iPod or iOS device
https://discussions.apple.com/docs/DOC-3991
Syncing to a New Computer...
https://discussions.apple.com/docs/DOC-3141

Please help with "You can't open the application NovamediaDiskSupressor because PowerPC applications are no longer supported." I have seen other responses on this but am not a techie and would not know how to start with that solution.

Please help with the message I am receving on startup ""You can't open the application NovamediaDiskSupressor because PowerPC applications are no longer supported."
I have read some of the replies in the Apple Support Communities, but as I am no techie, I would have no idea how I would implement that solution.
Please help with what I need to type, how, where, etc.
Many thanks
AppleSueIn HunterCreek

I am afraid there is no solution.
PowerPC refers to the processing chip used by Apple before they transferred to Intel chips. They are very different, and applications written only for PPC Macs cannot work on a Mac running Lion.
You could contact the developers to see if they have an updated version in the pipeline.

Hi, please help with the installation of Lightroom 4, I bought a new Mac (Apple) and I want to install a software that I have on the album cd. My new computer does not have the drives. Can I download software from Adobe? Is my license number just to be ab

Hi, please help with the installation of Lightroom 4, I bought a new Mac (Apple) and I want to install a software that I have on the album cd. My new computer does not have the drives. Can I download software from Adobe? Is my license number just to be able to download the srtony adobe.

Adobe - Lightroom : For Macintosh
Hal

[ETL]Could you please help with a problem accessing UML stereotype attributes ?

Hi all,
Could you please help with a problem accessing UML stereotype attributes and their values ?
Here is the description :
-I created a UML model with Papyrus tool and I applied MARTE profile to this UML model.
-Then, I applied <<PaStep>> stereotype to an AcceptEventAction ( which is one of the element that I created in this model ), and set the extOpDemand property of the stereotype to 2.7 with Papyrus.
-Now In the ETL file, I can find the stereotype property of extOpDemand as follows :
s.attribute.selectOne(a|a.name="extOpDemand") , where s is a variable of type Stereotype.
-However I can't access the value 2.7 of the extOpDemand attribute of the <<PaStep>> Stereotype. How do I do that ?
Please help
Thank you

Hi Dimitris,
Thank you , a minimal example is provided now.
Version of the Epsilon that I am using is : ( Epsilon Core 1.2.0.201408251031 org.eclipse.epsilon.core.feature.feature.group Eclipse.org)
Instructions for reproducing the problem :
1-Run the uml2etl.etl transformation with the supplied launch configuration.
2-Open lqn.model.
There are two folders inside MinimalExample folder, the one which is called MinimalExample has 4 files, model.uml , lqn.model, uml2lqn.etl and MinimalExampleTransformation.launch.
The other folder which is LQN has four files. (.project),LQN.emf,LQN.ecore and untitled.model which is an example model conforming to the LQN metamodel to see how the model looks like.
Thank you
Mana

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