Please help with regular expression
Hello,
With the help of my previous posting answers, Re: Procedure to Extract multiple substring from a string , I updated the query. But, I am not getting desired answer in all case. Could you please help me out? My query is based on the previous posting. Any other simple way to achieve this?
I will really appreciate it.
select
ltrim ( regexp_substr(txt, '\[(\w+)', 1, level), '[') as id, /* id is number */
ltrim ( regexp_substr(ltrim ( regexp_substr(txt, ':[^]]+', 1, level), ':'), '\w+-*\d*', 1, 1), ':') as qid, /* Qid could be char/number/space any combination except ':' */
ltrim ( regexp_substr(ltrim ( regexp_substr(txt, ':[^]]+', 1, level), ':'), '\w+', 1, 2), ':') as num,
to_date( ltrim ( regexp_substr(ltrim ( regexp_substr(txt, ':[^]]+', 1, level), ':'), '[^:]+', 1, 3), ':'),'MM/DD/YY') as effdate
from (
select '[10946:M100:N:][10947:Q1222:N:][38198:PPP-2:N:][13935:PPP-6:N:][38244:QQQ-4:Y:01/01/10]' as txt
from dual
connect by level <= length(regexp_replace(txt, '[^[]'));I should get :
ID QID NUM EFFDATE
10946 M100 N
10947 Q1222 N
38198 PPP-2 N
13935 PPP-6 N
38244 QQQ-4 Y 01-JAN-10But, getting
ID QID NUM EFFDATE
10946 M100 N
10947 Q1222 N
38198 PPP-2 2
13935 PPP-6 6
38244 QQQ-4 4 01-JAN-10Thanks,
Hi,
So the num column is wrong, is that it?
Describe what the num column should be. For example "num is the 3rd part of the :-delimited list enclosed in the square brackets".
If that's what you want, then change the definition of num from
... ltrim ( regexp_substr(ltrim ( regexp_substr(txt, ':[^]]+', 1, level), ':'), '\w+', 1, 2), ':') as num,to
... REGEXP_SUBSTR ( REGEXP_SUBSTR ( txt
, '[^]]+'
, 1
, LEVEL
, '[^:]+'
, 1
, 3
) AS num,
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Could some also tell me how do I apply *<sname>*prometheuzz my source code as suggested by you is
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while(RegexMatcher.find())
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RegexMatcher = Regex.matcher(chkEnty);
while(RegexMatcher.find())
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Matcher m1 = Pattern.compile("([A-Z]\\.\\s?)+").matcher(chkEnty);
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FnameVector2.addElement(Fname2);
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for(int v=0;v<FnameVector2.size();v++)
System.out.println(FnameVector2.elementAt(v));//It's printing fine here
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System.out.println(SnameVector1.elementAt(v));//It's printing fine here
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<?xml version="1.0" encoding="UTF-8"?>
<ref-list>
<name>A. B. Cccccc and X. Y. Zzzzzz</name>
<name>K. Name</name>
The output after executing the above source code is
<?xml version="1.0" encoding="UTF-8"?>
<ref-list>
<name><fname>A. </fname>B. <sname>Cccccc</sname>and <fname>X. <fname>Y. </fname></fname><sname>Zzzzzz</sname></name>
<name><fname><fname><fname><fname><fname><fname>K. </fname></fname></fname></fname></fname></fname><sname>Name</sname></name>
But I need my output as
<?xml version="1.0" encoding="UTF-8"?>
<ref-list>
<name><fname>A. B. </fname><sname>Cccccc</sname>and <fname>X. Y. </fname><sname>Zzzzzz</sname></name>
<name><fname>K. </fname><sname>Name</sname></name>
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i want to modify this regex so that
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String pattern = "^\\d\\d/\\d\\d/\\d\\d\\d\\d$";
System.out.println("00/23/1985".matches(pattern));
as expected returns 'true'. -
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http://help.adobe.com/en_US/Acrobat/9.0/Professional/WS58a04a822e3e50102bd615109794195ff-7 c4b.w.html
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