Polar to rectangular conversion

I want to enter this foumula =B2*cos(C2) Where B2=4, C2=-30
the result I get from this formula is .617...
The answer I'm looking for is 3.46, I know the difference has to do with radians and degrees, but I can't seem to get the answer I want using the DEGREES function.
3.46 is the answer I get with my TI calculator set to degrees, and .617... is the answer I would get with it set to radians. I'm trying to set this up in a spreadsheet, to help speed things up. Any ideas?

Allen,
Thanks for the feedback. Easy to remember if you know the definition of a Radian. It's the angle formed by the portion of a circle (pie slice) where the length of the section of perimeter is equal to the radius of the circle. Of course you know from geometry that the total perimeter (circumference) is 2PiR and that is your 360 degrees.
Regards,
Jerry

Similar Messages

HP35s complex numbers

My background is with the HP41C,CV,CX (41). I am now attempting to emulate routines I developed for the 41 for solutions on an HP35s (35) in RPN mode. My issue is with polar to rectangular conversion on the 35. The 41 had P-R and R-P keys. The 35 does not and wants to handle the conversion as “complex numbers”.The 41 key sequence is:RENTϴ (value)P-R X appears in x (stack) registerY appears in y (stack) registerThe stack contains two discrete values, x, y The 35 sequence is:Display .0Rϴ (key)ϴ (value)ENTx and y appear as x i y in the x registerCan I segregate x and y to complete the next 41 step? The next step in the 41 routine is Σ+.That operation generates cumulative Cartesian coordinates for each subsequent entry of R, ϴ in the Σx and Σy statistic registers Can that be emulated in the 35s?

My background is with the HP41C,CV,CX (41). I am now attempting to emulate routines I developed for the 41 for solutions on an HP35s (35) in RPN mode. My issue is with polar to rectangular conversion on the 35. The 41 had P-R and R-P keys. The 35 does not and wants to handle the conversion as “complex numbers”.The 41 key sequence is:RENTϴ (value)P-R X appears in x (stack) registerY appears in y (stack) registerThe stack contains two discrete values, x, y The 35 sequence is:Display .0Rϴ (key)ϴ (value)ENTx and y appear as x i y in the x registerCan I segregate x and y to complete the next 41 step? The next step in the 41 routine is Σ+.That operation generates cumulative Cartesian coordinates for each subsequent entry of R, ϴ in the Σx and Σy statistic registers Can that be emulated in the 35s?

Rectangular to Polar Conversion

My old HP calculator finally died after 25 years of service and I have bought an HP35s as a replacement. The seemingly straightforward operation of converting rectangular to polar is not working:
8.66 [i] 5 [Enter] simply returns 8.66i5.00 in the display
The opposite function (polar to rectangular works fine:
10 [theta] 30 [Enter] correctly returns 8.66i5.00
What's up with the R/P???? What am I missing???? Can anyone please offer the soulution. I need to get back to work. Thank you.

Hi,
There sadly is no R<->P keytop function on the HP-35s.
However, it can be achieved in different ways:
In your example you are using the complex number format, you need to change display modes to rQa ( R theta A, orange shift, Display (left arrow) item 10 ). Of course now all complex numbers are in polar format and you need to change the display setting back to rectangular format for rectangular co-ordinates.
Another solution is to use a program to convert between rectangular and polar form, e.g.:
http://www.hpmuseum.org/cgi-sys/cgiwrap/hpmuseum/articles.cgi?read=983
or
http://www.geocalc.com.au/uploaded/HP35S%20Rectangular%20Polar%20Conversions.pdf
Best regards.
(edited to correct some grammar)
Note: I do not work for HP, I just like playing with calculators :-)

3D Polar Plot

I want to plot a 3D Polar Plot with Angle Axis as Angle, Radius Axis as Frequency and a third axis representing intensity at that point. For the snap shot of the image i have attached a .jpg file. Give me a perfect solution as soon as possible.
Thank You in advance
Attachments:
3D polar.JPG ‏22 KB

Hi 3D Polar,
well, you could use an intensity plot with embedded background graphics for the grid. Then you only have to plot the intensities after converting polar to rectangular coordinates.
Asking for a "perfect solution" is like wanting all for nothing...
Best regards,
GerdW
CLAD, using 2009SP1 + LV2011SP1 + LV2014SP1 on WinXP+Win7+cRIO
Kudos are welcome

Change polar data to cartesian coordinates

The txt file is the data get form 2D laser rangefinder, which every 1°capture a obstacle distance information and 180 data in total. Obviously,this is under polar coordinate system.
first,I would like to change the log file's data under polar coordinate to cartesian coordinates by multiply sin(theta) and cos(theta).second,the result data form 2D array,and then conbine another array which is 1D zero array to form a 3D array.Please tell me how to realize it.
Thanks
Attachments:
01.txt ‏2 KB

You don't need any trigonometry, just go via complex numbers. Attached is one simple possibility. (note that LabVIEW 8.0 has a single tool to go from "r,theta" to "x,y" in the complex palette). See attached, LabVIEW 7.0.
You might need to tweak it for the desired definition of the angles (ccw vs. cw)
Alternatively, there is also a 1D polar to rectangular tool in the "math.. array operations" palette that you could use, just create a ramp for theta and initialize a zero array for Z.
Message Edited by altenbach on 06-30-2006 12:07 AM
LabVIEW Champion . Do more with less code and in less time .
Attachments:
rangefinder.vi ‏43 KB

Trapcode Form/Particular like plugins for photoshop?

Hello all,
I would like to know if any of you knows about any plugins for photoshop, that work the same as trapcode form or trapcode particular...
I found the Ulead Particles plugin and haven't tried it yet, but it seems from what i saw that its not that important, what it does looks to me like it can be done with brushes...
I am looking for a plugin that can shatter text or images, turn images or text into particles, and everthing trapcode form and particular can do...
I know everything can be done using the available standard tools, but i am looking for something faster..
Thank you for your help

Hello, John!
I think that those guys have a filter : http://www.frischluft.com/
I would search google for rays of light photoshop tutorials...
but most of them will be rectangular to polar> wind, wind, motion blur>polar to rectangular... I guess that you already tried it.

Trying to Create Cone from Image

I am attempting to take a circular image (a logo of something) and edit it so that it can be printed and turned into a small cone. I have spent HOURS researching this and cannot seem to find the the problem. I've followed the steps below (found on a tutorial at another website) and the gap (where the circle gets slid under itself to create the cone shape) is so small. I have messed around with it since this morning and am at my wit's end. Thank you, in advance, for any assistance!
Let's consider my avatar as the original image. I make sure it is cropped into a circle.
Then in photoshop, I do Filter->Distort->Polar coordinates->Polar to rectangular:
Then, I resize the contents (but not the container [e.g. select all, edit->transform->scale]) of the image horizontally. The percentage I reduce is the percentage of degrees I will remove:
Finally, I go back to polar coordinates, and retrim as a circle: (OP: I don't know what they mean by "retrim as a circle," though, so I stop after selecting "rectangular to polar")
Wrapping the image around the removed wedge is an exercise left to the reader.

Thank you for your reply, Nancy! I actually want to print this and then "assemble" it into a cone.
Here is the original tutorial. The original person was able to accomplish exactly what I want...I just can't figure out where I'm going wrong!
http://design.tutsplus.com/tutorials/illustrate-a-traffic-cone-icon-in-photoshop--psd-121

How to go for the Log Polar Conversion of the image.

How to go for the Log Polar Conversion of the image.

Hi,
I'm not sure if you mean using the polar plot vi, but if so there is an example shipped with LabVIEW. Go to Example Finder and search for 'polar', and you should find Polar Plot Demo.vi. Also, here are some useful links:
Link 1
Link 2
Hope this helps!
Jeremy L.
National Instruments
Jeremy L.
National Instruments

I'm using the 1D Rectangular to Polar VI and would like to know the output magnitude units.

What is the magnitude output unit expressed in? VRMS, DB, etc...?The other output from the 1D Rectangular to Polar VI, phase, is expressed in radians.

The 1D Rectangular to Polar VI only accepts inputs without units, it seems.
This is just a geometric transformation and the magnitude output should thus get the same "units" as the x and y inputs originally had (before stripping the units off).
LabVIEW Champion . Do more with less code and in less time .

Polar grids in XY grpah (just like default rectangular grids)

I want to plot a realtime data of voltage vs time in polar format. I want the polar grids to be dynamic (for eg., rectangular grids in XY graph, which change as I zoom the XY Graph).
I have tried "polar plot with points function" and XY graph. I have been successful in plotting the graph. But zoom functionality is very high priorty as it could be hours of data on same polar plot.
Problem with "Polar Plot function":-
It gives output as picture unlike XY Graph. I haven't been able to zoom this picture output as we do with XY Graph.
Problem with "XY Graph Function":-
I plot the static grid. I plot the real time graph too, but independently. When I try to plot realtime on static grid that I made, it erases the grid and only plot remains. If I try to bundle this realtime plot with other static plots (grids) and plot it just plots it as a static against the grid.
I am attaching my files please take a look. I am using LabVIEW 2013.
I have read many forum discussions on this forum bu they don't solve my problem. I am stuck in this problem since some days now, so any help would be appreciated. Its my first post at this forum, so any feedback on my post too will be appreciated.

Okay, document here how you solved your problem, so later someone with a similar problem can find it.
Cameron
To err is human, but to really foul it up requires a computer.
The optimist believes we are in the best of all possible worlds - the pessimist fears this is true.
Profanity is the one language all programmers know best.
An expert is someone who has made all the possible mistakes.
To learn something about LabVIEW at no extra cost, work the online LabVIEW tutorial(s):
LabVIEW Unit 1 - Getting Started
Learn to Use LabVIEW with MyDAQ

Difference between Circular, Rectangular and Free form Antenna??

Hi All,
What is the difference between a Circular, Rectangular and a Free form field Antenna other than the physical appearance?
Thanks,
Shridhar..

Hi Shridhar,
RFID Antennas
RFID antennas are always connected to an interrogator. This allows for the transmission of signals to and from the tag.
Antenna Design
Depending on the design, antennas can be either mono-static or bi-static:
Mono-static antennas are based on a principle by which a single antenna transmits a signal coming from the interrogator to the area as well as receives a signal coming from tags and these functions are switched in fractions of seconds. This requires use of a circulator in a reader that multiplexes the receive and transmit signals through a single port. There is some loss and phase distortion due to the use of a circulator.
Bi-static antennas include two antennas, where one antenna is dedicated to transmitting, and the other antenna is dedicated to receiving. Both dedicated antennas can be but do not have to be in the same casing. In bi-static antenna, a circulator is not required, which improves the performance and sensitivity of the antenna.
Antenna Polarity
Antenna polarity is very important because it affects the quality of communication between the interrogator and tag.
The interrogator's antenna and the tag's antenna should have the same polarization. If polarization is not realized, a severe loss in signal, along with a drastic decrease in a read range, which results in unsuccessful communication with a tag, can be experienced.
<b>Polarization can be either circular or linear.</b>
Linear polarization is relative to the surface of the earth.
<b>Linear polarization can also be either horizontal or vertical:</b>
Horizontally polarized signals propagate parallel to the earth.
Vertically polarized signals propagate perpendicular to the earth.
Antennas with circular polarization can receive signals from both the vertical and horizontal planes by injecting the signal at two points on the antenna radiated slightly out of phase creating a rotating effect on the field. However, there is a slight loss of signal strength, due to the constructive and deconstructive effect of the field being slightly out of phase.
Refer this link to get the other details regarding the Antenna Design
http://www.ibmpressbooks.com/articles/article.asp?p=413662&seqNum=2&rl=1
Also the Refer this link to get the detailed Antenna Anatomy
http://americanrfidsolutions.com/members/download/3.pdf
I hope This answers your question.
Regards ,
Pawan

Polar equation of a line between two points

I am trying to make a method to output the points (in polar coordinates (r, theta)) along a line between two given polar coordinates.
This will mimick the path of an object traveling across a radar screen.
Is this possible?

Java does not plot in polar coordiantes, you'll have to convert to rectangular to get a plot. If you're just doing a sweep on a screen, then it's fairly simple to do:
r is the radius of your screen,
(0,0) is your Origin translated as (Xmax/2, Ymax/2)
when you draw the line you just start at your Origin and get your end values as
X1=X0+r*cos(Theta) and
Y1=Y0+r*sin(Theta),
I've not seen, nor do I think there is any other support to do what you want--you have to convert to (x,y) coordinate system.
This will leave a ragged edge so make a border around your screen.
import java.awt.Color;
import java.awt.Dimension;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.image.BufferedImage;
import java.awt.Point;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.Timer;
public class JRadar{
public JRadar(){
    JPanel p = new MyJPanel();
    JFrame f = new JFrame("ForumJunk: JRadar");
    f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    f.add(p);
    f.pack();
    f.setVisible(true);
public static void main(String[] args){
    new JRadar();
class MyJPanel extends JPanel implements ActionListener{
    Timer t = new Timer(10, this);
    Dimension d = new Dimension(512, 512);
    BufferedImage bi = new BufferedImage(d.width, d.height, BufferedImage.TYPE_INT_RGB);
    Graphics2D g = bi.createGraphics();
    double theta = 0;
    int r = d.width/2 - 16;
    Point origin = new Point(d.width/2, d.height/2);
    public MyJPanel(){
      g.setColor(Color.RED);
      this.setPreferredSize(d);
      t.start();
    public void actionPerformed(ActionEvent e){
      g.clearRect(0, 0, d.width, d.height);
      g.drawOval(16, 16, 480, 480);
      g.drawLine(origin.x, origin.y, (int)(origin.x+r*Math.cos(theta)), (int)(origin.y+r*Math.sin(theta)));
      theta += 0.01;
      if(theta>=Math.PI*2) theta = 0.0;
      repaint();
    public void paintComponent(Graphics g){
      super.paintComponent(g);
      g.drawImage(bi, 0, 0, this);
}Edited by: morgalr on Mar 3, 2010 4:59 PM: code example added

Log Polar transformation

I am using the IMAQ Vision. Let me know how to go for the Log Polar conversion of the image and do the FFT on the Image

EmmanuelGigy,
Thanks for using our discussion forum. You are correct about there not being a supported log-polar function in IMAQ. In fact, if it was supported it would most likely be included with our Vision Development module instead. If you are having trouble displaying your image, you may want to try some of the examples that install with IMAQ for Visual C. you can find these in Program Files>>National Instruments>>NI-IMAQ>>Sample>>Display. Hopefully these examples should help you out.
Regards
Dan
National Instruments

Problem with Color conversion ADM_Color to AI_Color

Hello friends,
I think this is going to be the first post in this "Illustrator SDK Forum".
I am having problem with 'Setting Art Work Colors'.
I am trying to get the color value from the user through a ADM dialogue window, using the function
sADMBasic->ChooseColor();
The function is returning color in
ADMRGBColor structure, whose members (
red, green, blue) are of the type
'short'.
Now, I want to print a rectangular box art filled with that 'user selected color'.
But the color I have with me is in the
ADMRGBColor(each member of type 'short') and to draw that on a illustrator file, I need the type
'AIThreeColrStyle'(each member is of the type AIReal).
I had no idea how to convert
ADMRGBColor to
AIThreeColorStyle, but after lots of 'trial and errors', I arrived at this 'crude' solution.
ADMRGBColor value was in the range
0-65535 and
AIThreeColorStyle was in the range
0-1
aiPathStyle.fill.color.c.rgb.red = ((float)admColor.red)/65535;
This conversion was working fine on Windows, but on Mac its giving weird results. Can some one tell me the proper solution for this conversion problem?
Thanking you,
Vijoy~
And thank you Adobe for givig us this "Illustrator SDK Forum".
Forums Operations "Why there is no SDK forum for Illustrator?" 12/13/04 4:21pm

The code above seems to work for me. I get the proper values in the rgb fields of the AIPathStyle struct. Are you sure you are filling in the remaining values in the struct (like fillPaint, overprint, etc.) with appropriate values?
Hope that helps,
-Frank

Re-sample in a rectangular coordinate system from polar

Suppose we take the red point on the polar grid. When i convert it to Re & Im parts i get a number in rectangular grid, but this point is not actually present in the rectangular grid shown on right. This polar point was found by interpolating some points. How can i find a point in rectangulr grid then?
thanks
Nghtcwrlr
********************Kudos are alwayzz Welcome !! ******************
Attachments:
Resampling.JPG ‏50 KB

It is not clear to me what you mean by "How can i find a point in rectangulr grid then?". What is "find" in this context?
If you have a 2D array and want to get an interpolated value at fractional indices, you could use bilinear (or higher) interpolation (see e.g. this old post for some ideas).
If you have an empty 2D array and want to populate it with values at fractional indices, you could fill the four nearest cells proportional to their distance to the fractional coordinates, similar to antialiasing.
Message Edited by altenbach on 03-10-2009 06:54 AM
LabVIEW Champion . Do more with less code and in less time .

Polar to rectangular conversion

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