Possible loss of precision - sorting 3 arrays respectively

Question

I have the following 2 arrays which need to be sorted according to a high-to-low sorted float array called avg. So float avg[5] is sorted high-to-low, and then String names[] is sorted respectively, for instance, before the sort, names[3]="Marty" and avg[3]=75, and after the sort 75 was in avg[0] because it was the highest, now Marty needs to be in names[0]. The same is with the int scores[5][8] array, the 5 rows need to be sorted corresponding to the new sorted avg array. Anyways here are the arrays and the sorting code i have. I get the error "possible loss of precision." Also the code tag on the forums isnt working for some reason.
Arrays:
float avg[]=new float[5];
int temp[] = {34, 24, 78, 65, 45, 100, 90, 97, 56, 89, 78, 98, 74, 90, 98, 24, 45, 76, 89, 54, 12, 20, 22, 55, 66};
String names[] = {"Mary","John","William","Debbie","Ralph"};
int scores[][]= new int[5][8];
for(a=0;a<=4;a++)
for(b=0;b<=4;b++,c++)
scores[a] = temp[c];
Sort:
public float sort(int[][] scores,String[] names, float avg[])
int g,r,c,d,e;
String q;
for (r=0;r<=3;r++)
for (g=r+1;g<=4;g++)
if (avg[r]<avg[g])
c=avg[r];
avg[r]=avg[g];
avg[g]=c;
q=names[r];
names[r]=names[g];
names[g]=q;
for(d=0;d<8;d++)
e=scores[r][d];
scores[r][d]=scores[g][d];
scores[g][d]=e;

Answer 1

The first time I got that error I misread it and got very excited: "possible lots of precision."
Any way, you should point out the line where this occurs:
c=avg[r];Here, c is an int and avg[r] a float. When you assign a float to an int, you loose
the factional data, and as well, float have hold larger values than int. Why not make c a float?