Problem in configuring Apache Tomcat Server

Question

Hi, I am facing problem in configuring Apache Tomcat server. I have downloaded its version 4.1.18 from the Internet. After unzipping and installing it, I have enabled the Root Context, enabled the Invoker Servlet, haven't changed the port to 80 from default 8080, have turned on the Servlet Reloading, have set the Java_Home variable in autoexec.bat, and have changed the DOS memory setting to 4096.
Also, the concerned lines in my autoexec.bat file look like this:
path c:\windows;c:\windows\command;c:\jdk1.2;c:\jsdk2.0;
c:\JavaWebServer2.0;c:\jakarta-tomcat-4.1.18
set java_home=c:\jdk1.2
set tomcat_home-c:\jakarta-tomcat-4.1.18
set classpath=.;c:\ServDevel;.;c:\jakarta-tomcat-4.1.18\common\lib\servlet.jar;.;c:\jsdk2.0\lib\servlet.jar;.;
Still, after having done all this, when I start the server using startup.bat (which happens without any problems) and type in http://localhost:8080/ on the browser to test the server, nothing happens. It doesn't show me the Tomcat Welcome screen. I get an error page saying "This page is not available". Why? Where am I going wrong?
Sushant

Answer 1

1) Try http://127.0.0.1:8080
2) set tomcat_home-c:\jakarta-tomcat-4.1.18
Is the minus-sign after tomcat_home also in the autoexec.bat?
Replace it with an equals-sign
3) When you run startup.bat, is a new command window opened and are the following three lines displayed at the end? It should stay open, otherwise something is wrong (unless running as a service).
INFO: Initializing Coyote HTTP/1.1 on port 8080
Starting service Tomcat-Standalone
Apache Tomcat/4.1.18