Problem in editing xml document

Hi,
Can anybody help me out of this problem basically i want to develop sample prog that will take care of editng the existing xml document eg. i want to edit resource file for the application like if user want to change some property through the user interface and i want to reflect that input to the xml files.
Help me as soon as possible ............. its very urgent .......................
Regards
Sanket

Output document with a transformer.
TransformerFactory tFactory =TransformerFactory.newInstance();
            Transformer transformer = tFactory.newTransformer();
            DOMSource source = new DOMSource(document);
            StreamResult result = new StreamResult(new File("c:/output/output.xml"));
            transformer.transform(source, result);

Similar Messages

Help required to edit xml document

I am new to java and xml compatibility.I just had familiarised SAX parser.
I now want to familiarse the technology to edit xml document from a java program(more precisely write to an xml file).I came to know about many methods - JAXP DOM method,JAXB api method - and is totally confused.
Can any body give me guidance about these api's and suggest a method that
i should follow?
i repeat that my application will have to frequently edit xml files
Thank you

Hi,
it's very easy to edit and create XML. See examples in docs: http://livedocs.adobe.com/flex/3/langref/XML.html#includeExamplesSummary
There are many examples how to get attributes and other data.
You also can set attributes the same way.
If you have concrete questions, ask.

Using JAXB to edit XML documents

I am trying to understand how (and whether) JAXB can be used to make the following types of changes to an existing XML document. I know that I can EDIT an XML document using the set methods that are generated by JAXB (in conformance with the XML Schema), and then I create a Marshaller and marshall the root element object.
However, I have not figured out how to do any of the following:
(i) insert a new element
(ii) delete an existing element
(iii) reorder elements.
Here is an excerpt from an XML document:
<directory name="dir">
<file name="file1"/>
<file name="file2"/>
<file name="file3"/>
</directory>
The order in which the file elements appear is significant.
If I want to add a new file (file4), how would I do this? Where would it be added, at the end? What if I wanted to add it after file2?
If I want to delete file1, I don't know how to do that.
Finally, if I want to move file2 after file3, I don't know how to do that.
It seems as though I need access to the underlying com.sun.xml.bind.util.ListImpl (or similar collection object), which holds the actual file elements when JAXB unmarshals the xml file. However, this seems dangerous and I have gotten a concurrent access exception while trying to do something like this. (Another problem has to do with iterators, where I can't iterate through a list and then make a change to the list w/o messing up the iterator.)
If there are any technologies other than JAXB that might accomplish this, but that provide data binding, I would be happy to hear about it. (I could try SAX/DOM/JDOM/DOM4J or XSLT, I guess, but I like the data binding of JAXB.)

As is typical for me, I answered my own questions.
if you are outside of an iterator, you can simply use the:
add(object)
add(position,object)
remove(object)
methods of the List interface to add and remove elements from the list of elements.
Also, if you use a ListIterator, you can call the add() and remove() methods of ListIterator while iterating through the list.
In order to reorder elements in the list, use:
Collections.swap(list,pos1,pos2). Why this method is not built into the List interface itself is beyond me. This was only added in 1.4, btw.

Problem in inserting XML document

Give XML DTD :
<!ELEMENT a (b, c)>
<!ELEMENT b (#PCDATA)>
<!ELEMENT c (d, e)>
<!ELEMENT d (#PCDATA)>
<!ELEMENT e (#PCDATA)>
I made schema at Oracle8i as this:
create type c_t
as object (d varchar2(3),
e varchar2(3));
create table a (
b varchar2(3),
c c_t,
constraint b_pk primary key (b));
And the XML document to insert into DB is as this:
<?xml version="1.0"?>
<ROWSET>
<ROW>
"100"
<c><d>"aaa"</d><e>"abc"</e></c>
</ROW>
<ROW>
"200"
<c><d>"bbb"</d><e>"def"</e></c>
</ROW>
</ROWSET>
Using Oracle8i's XML-JAVA library interface,
I tried to insert the XML document into the DB table, but JAVA runtime exception occurred says "java.lang.NoSuchMethodError: oracle.jdbc.oci8.OCIDBAccess: method initObjectFields(Loracle/jdbc/dbaccess/DBColumn;[BI)V not found".
How can I solve this problem?
null

try calling dbms_xmlgen.setrowsettag(qryctx,'siteMap') ;
before retrieving the result with DBMS_XMLGEN.getxmltype (qryctx);

Small problem reading an XML document

Hi,
I have code that can read an XML document like this:
<?xml version="1.0" encoding="UTF-8"?>
<something>
<order orderid="1">
<customerid>12341</customerid>
</order>
</something>
but when I take out the first tag <something> and last tag </something> , it doesn't work at all and I have no clue why. Here is my code:
public class SaveOrders extends Object {
 try {
 //Get the root element and all order elements
 Element ordersRoot = ordersDoc.getDocumentElement();
 NodeList orders = ordersRoot.getElementsByTagName("order");
 for (int i = 0; i < orders.getLength(); i++) {
 //For each order, get the order element
 Element thisOrder = (Element)orders.item(i);
 } catch (ClassNotFoundException e) {
 System.out.println("Error creating class: "+e.getMessage());thanks for your help!

Every XML document must have a Document Root (in your case <something>). So, if you have multiple <order>'s within your XML document, there is no Doc Root! Eeek!
Get it? If you only have one <order> per XML file, then you should be alright (and might have another problem) because that <order> becomes the root, but the instant you have more than one, you need something to put all of them (your Doc Root).
Hope that helps!

Editing XML documents from iFS WebUI

When I click on an XML document within the iFS WebUI, it opens the file and shows it to me within Internet Explorer.
I want the document to be opened on my workstation with Arbortext Epic Editor, but IE keeps trying to display it.
Has anyone had a problem like this? I don't want Internet Explorer to open the document, but what the XML file is associated with within Windows...
I have tried changing the MIME type for XML documents within JWS from default to application/octet-stream in an attempt to force IE to pass it to the operating system... but it didn't work.. unless I change the wrong mime.properties file...
Anyone have a solution?

Did you change your settings in IE for that mimetype ?
<BLOCKQUOTE>quote:<HR>Originally posted by David Thomas ([email protected]):
When I click on an XML document within the iFS WebUI, it opens the file and shows it to me within Internet Explorer.
I want the document to be opened on my workstation with Arbortext Epic Editor, but IE keeps trying to display it.
Has anyone had a problem like this? I don't want Internet Explorer to open the document, but what the XML file is associated with within Windows...
I have tried changing the MIME type for XML documents within JWS from default to application/octet-stream in an attempt to force IE to pass it to the operating system... but it didn't work.. unless I change the wrong mime.properties file...
Anyone have a solution?<HR></BLOCKQUOTE>
null

Problem to validate XML document if the type of root element is abstract

I have the following XML document:
<?xml version="1.0" encoding="UTF-8"?>
<ct013/>
It corresponds to the following XSD Schema:
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema">
 <xs:element name="ct013" type="foo"/>
 <xs:complexType abstract="true" name="foo"/>
 <xs:complexType name="fixedType">
 <xs:complexContent>
 <xs:restriction base="foo"/>
 </xs:complexContent>
 </xs:complexType>
</xs:schema>
Please take attention to the fact that the type of root element of that BDD is abstract.
XML Schema provides a mechanism to force substitution for a particular element or type. When an element or type is declared to be "abstract", it cannot be used in an instance document. When an element is declared to be abstract, a member of that element's substitution group must appear in the instance document. When an element's corresponding type definition is declared as abstract, all instances of that element must use xsi:type to indicate a derived type that is not abstract.
Declaring an element as abstract requires the use of a substitution group. Declaring a type as abstract simply requires the use of a type derived from it (and identified by the xsi:type attribute) in the instance document.
For more information of using abstract types please see chapter 4.7 Abstract Elements and Types of XML Schema Part 0: Primer Second (http://www.w3.org/TR/xmlschema-0/#abstract).
In this case there is Oracle bug when I try to validate this XML document using Oracle XDK:
String validate(String xml, String schema)
throws XSDException, XMLParseException, SAXException, IOException
System.setPropert("oracle.xml.parser.debugmode", "true");
XSDValidator xsdValidator = new XSDValidator();
XMLError xmlError = new XMLError();
xmlError.setErrorHandler(new DocErrorHandler());
XMLDocument xmlDocument = parseXMLDocument(xml);
XMLDocument schemaXMLDocument = parseXMLDocument(schema);
XMLSchema xmlSchema = (XMLSchema) new XSDBuilder().build(schemaXMLDocument, null);
xsdValidator.setError(xmlError);
xsdValidator.setSchema(xmlSchema);
xsdValidator.validate(xmlDocument);
return getValidationError(xsdValidator);
I get the following error:
Can't find resource for bundle oracle.xml.mesg.XMLResourceBundle, key XSD-2046.
I tried to validate this XML document using two other libraries - XSD Schema Validator (http://apps.gotdotnet.com/xmltools/xsdvalidator/Default.aspx) and xsdvalid-29 (http://www.w3.org/XML/Schema#XSDValid). Both libraries pointed me on the error that the type of root element is abstract and it cannot be used for doing validation.
I think that Oracle should return me explaining message but not to throw exception.
Am I right? Is there really Oracle bug or I miss something?
Any help, hits, advices would be gratfully apriciated.

Define Element1 as follows:
<xs:element name="Element1">
<xs:complexType>
<xs:complexContent>
<xs:restriction base="xs:string"/>
</xs:complexContent>
</xs:complexType>
</xs:element>
Does the XML document get validated if the element is specified as
<Element1></Element1>

Problem in displaying XML document from database

Hi I am getting only record in printing xml file which takes from data base.
Here is my programme.
Document doc;
��public void processTable(Connection con, String tableName)
��{
��try
��{
��this.iColumnCount=0;
��HashMap hm = new HashMap();
��//XML related Interfaces
��DocumentBuilderFactory dbf;
��DocumentBuilder db;
��Element rootElement = null;
Element colData = null;
��Element relElement = null;
��
��//Database relevent Interface
��ResultSet rslt = null;
��DatabaseMetaData dmd = null;
��ResultSetMetaData rsmd= null;
��//Initilize the Factory Classes
��dbf = DocumentBuilderFactory.newInstance();
��db = dbf.newDocumentBuilder();
��doc = db.newDocument();
��//Assign the root elements to document
��rootElement = doc.createElement("entity");
colData = getColMetaData(tableName);
��rootElement.appendChild(colData);
��doc.appendChild(rootElement);
��TransformerFactory tFactory = TransformerFactory.newInstance();
��Transformer transformer = tFactory.newTransformer();
��transformer.transform(new DOMSource(doc),
��new StreamResult(new FileOutputStream(tableName+".xml")));
��} catch (Exception sqle)
��{
��e.printStackTrace();
��}
��}
��/**
��* Method getColMetaData.
��* @param tableName
��* @return Element
��*/
��private Element getColMetaData(String tableName)
��{
��try{
��ResultSet rslt = null;
��ResultSetMetaData rsmd = null;
��DataTypeMap dtp = new DataTypeMap();
��HashMap hm = new HashMap();
��hm = dtp.DataTypes();
��Connection con = db.createConnection();
��Statement stmt = con.createStatement();
��String sQuery = "select * from " +tableName;
��rslt = stmt.executeQuery(sQuery);
��rsmd = rslt.getMetaData();
��Element rooElement = null;
��//Element currentElement =null;
��iColumnCount = rsmd.getColumnCount();
��Element currentElement = null;//doc.createElement("field");
// rootElement = doc.createElement("column");
��for (int i = 1; i <= iColumnCount; i++)
��{
currentElement = doc.createElement("field");
��currentElement.setAttribute("DBFieldName",rsmd.getColumnName(i));
��currentElement.setAttribute("FieldName",rsmd.getColumnLabel(i));
��
��}
��return currentElement;
��catch(Exception ee){
��logger.info(ee.getMessage());
��}
��return null;
��}
Here 'return currentElement;' return the collection of elements.But when I print
document it is giving only last element.I am not getting how only one record is printing even it has more records
please help me in this regards.
here the out put:
<?xml version="1.0" encoding="UTF-8"?>
<entity>
��<field DBFieldName="X_TYPE" FieldName="X_TYPE"/>
</entity>
-krish
[email protected]

Problem in displaying the XML Data from database
Hi I have requirement of generating the XML from database.I could able to acheive partially.
I am giving the problem below.
public void processTable()
Element rootElement = doc.createElement("entity");
Element colData= getColMetaData(tableName);
rootElement.appendChild(colData);
doc.appendChild(rootElement);
//print the document
/*getColData method as follows*/
private Element getColMetaData(String tableName)
try{
ResultSet rslt = null;
ResultSetMetaData rsmd = null
Connection con = db.createConnection();
Statement stmt = con.createStatement();
String sQuery = "select * from " +tableName;
rslt = stmt.executeQuery(sQuery);
rsmd = rslt.getMetaData();
iColumnCount = rsmd.getColumnCount();
Element currentElement = doc.createElement("field");
for (int i = 1; i <= iColumnCount; i++)
currentElement.setAttribute("FieldName",rsmd.getColumnName(i));
currentElement.setAttribute("Position", parseString(i));
rootElement.appendChild(currentElement);
return currentElement;
catch(Exception ee){
logger.info(ee.getMessage());
return null;
/* End of Method*/
Here when I printing the document it is giving out put like :
<entity >
<field FieldName="X_ID" Position="1"/>
</entity>
The is displaying only one field information even though table contains more then one column.If we maintain all the aboue code in single method it is working fine.I want to decouple the like above.Bcz I may have more then one set of elements like this.
Please help in this regards,
-Krish
[email protected]

Editing xml documents

My application uses xml for data persistency. My question is:
1. is there a way to partially edit part of the xml file? because if I make some small changes to my data, i wish to save just that part.
2. Or I can just save the whole thing and overwrite the orignal file entirely, is this a common practice?
thanks!

A javax.xml.transform.Transformer transform method stores a Documentnode or a DocumentFragment node.
Transformer transformer;
Document document;
Node node;
DocumentFragment documentFragment=document.createDocumentFragment();
documentFragment.appendChild(node);
transformer.transform(new DOMSource(document), new StreamResult(new File("c:/output/output.xml")));
transformer.transform(new DOMSource(documentFragment), new StreamResult(new File("c:/output/outputNode.xml")));

SAF-T Problem when editing XML file

hello,
SAP released the RTXDART_PT report, to satisfy a new Portuguese legal requirement that becomes mandatory for all companies (following OECD norm).
The SAF-T is a file containing reliable accounting data exportable from an original accounting system (we use DART module in SAP) for a specific time period and easily readable.
I have just implemented the solution DART but I have a problem to produce the XML file.
I have the flat file using FTW1A transaction but when I launch RTXDART_PT transaction, I have not the XML file created.
Does anybody know how to proceed ?
Thank you very much.

Bom dia
Nós temos um problema com o Codepage layout, mesmo depois de termos aplicado a nota:
Note 1128306 - SAFT-PT: RTXDART_PT : Dart PT additional corrections
Criado o Badi e aplicado as correcções adicionais.
O que se passa é que na edição do XML sempre que temos caracteres "&" por exemplo em fornecedores "R & R, lda" o que nos é visualizado através de um editor de XML é o seguinte: "R & R, lda" isto acontece com diversos caracteres que o programa não converte, alguém tem alguma ideia de uma possivel solução?
Obrigado
JM

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I have a problem using an include statement in xsd. I try to include another
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<xsd:include schemaLocation="../../XXX.xsd"/>
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ayache

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Problem validating XMl document

Hi everyone,
I'm facing a problem validating a XML document with Apache toolkit under windows XP and eclipse 3.0
I generate a pair of public/private keys using the RSA algorithm. The keys are of arbitrary length, but satisfying RSA conditions, ie we can encrypt and decrypt.
I can sign my XML document, but no way to validate it. Validation is only ok when I generate random keys using the KeyPairGenerator.
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Thansk a lot for your precious help.

solved!
urghh...forgot to load th eschema..duh. (must be friday)
here's the fixed code:
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    // the xml document does not specified the System ID or location of
    // schema..and use no namespace
    public void parse(HandlerType type, String xmldoc) throws SAXException, IOException {
        File           schema      = schemaMap.get(type);
        DefaultHandler handler     = handlerMap.get(yype);
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        InputSource source = new InputSource(new StringReader(xmldoc));
        reader.setContentHandler(handler);
        reader.setFeature("http://xml.org/sax/features/validation", true);
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        reader.setFeature("http://apache.org/xml/features/validation/schema-full-checking", true);
        reader.setProperty("http://apache.org/xml/properties/schema/external-noNamespaceSchemaLocation",
        "file:///" + schema.getAbsolutePath());
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How do I parse a XML document?

Hello
I have a problem parsing a XML-document like the one below: Can anyone help me with a code example or something to get the tag "<Name>" out so that I get the string "Example5" and "Example3" out.
Thnx for any help!
Jimmy
The XML file looks like this (but without the line in the beginning of each row):
<?xml version="1.0" encoding="UTF-8"?>

<!DOCTYPE ThisExample SYSTEM "C:/example.dtd">
<?xml-stylesheet type="text/xsl" href="first.xslt"?>
<ThisExample>
____<Product>
________<Product_number>no1</Product_number>
________<Number>number1</Number>
____</Product>
____<Product>
________<Product_number>no2</Product_number>
________<Number>number2</Number>
____</Product>
____<Group>
________<Type>EX1</Type>
________<ProductVersionAllowed>Y</ProductVersionAllowed>
________<Preprocess>precmd.csh</Preprocess>
________<Postprocess>echo Finished</Postprocess>
________<Document>
____________<Name>Example1</Name>
____________<Product_number>no1</Product_number>
____________<Ticked_by_default>Y</Ticked_by_default>
________</Document>
________<Document>
____________<Name>Example2</Name>
____________<Product_number>no1</Product_number>
____________<Ticked_by_default>Y</Ticked_by_default>
________</Document>
________<Document>
____________<Name>Example3</Name>
____________<Product_number>no1</Product_number>
____________<Ticked_by_default>Y</Ticked_by_default>
________</Document>
____</Group>
____<Group>
________<Type>EX2</Type>
________<ProductVersionAllowed>N</ProductVersionAllowed>
________<Preprocess>precmd.csh</Preprocess>
________<Postprocess>echo Finished</Postprocess>
________<Document>
____________<Name>Example4</Name>
____________<Product_number>no2</Product_number>
____________<Ticked_by_default>Y</Ticked_by_default>
________</Document>
________<Document>
____________<Name>Example5</Name>
____________<Product_number>no2</Product_number>
____________<Ticked_by_default>Y</Ticked_by_default>
________</Document>
____</Group>
</ThisExample>

Thnx :O)
Now it worx!
Just one more thing. Can I get the number of elements there is in a tag? I.e. how many "Document"'s there are in 1 "Group"? I need this because I have too loop through a "Group" and print the name of every "Document".
At the moment I'm doing it like below, but that is not a nice solution, and it realy does not work that well:
Jimmy
int i = 1;
do
node = org.apache.xpath.XPathAPI.selectSingleNode(doc, "/PosttoolControl/Group[position()=" + i + "]/Type");
if (node.getFirstChild().getNodeValue() != null)
type = node.getFirstChild().getNodeValue();
PostToolDocGroupeComboBox.addItem(type);
i++;
} while (node.getFirstChild().getNodeValue() != null);

Error while building xml document

Hi Everyone,
I have a problem while building xml document.
I have developed my java files using IBM Eclipse 3.0 and i had no problem while executing the files.
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To the values element add xmlns:xsi and xsi:noNamespaceSchemaLocation.
<values xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
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No default attributes while Parsing XML document

Hellow.
I have such a problem:
I have XML document that uses XSD-schema.
In XSD-schema there is element that have two atributes:
<xsd:complexType name = "El1">
<xsd:attribute name = "atr1" xsd:default = "0" type = "xsd:boolean"/>
<xsd:attribute name = "atr2" default = "0" type = "xsd:boolean"/>
</xsd:complexType>And in XML document I write:
<El1 atr1 = "1"/>According to the XSD-schema parser must add to El1 second attribute "atr2" with its default value because it has default value. But when I do such a code:
factory = DocumentBuilderFactory.newInstance();
builder = factory.newDocumentBuilder();
doc = builder.parse(new File("file1.xml"));
Element pEl;
pEl = doc.getDocumentElement()
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What I have to do???

Hello All
I am new to this parsing world. I have a doubt. I have an XML like
<xml>
<platform name = "windows">
<computer>
<hostname> hostname1 </hostname>
<IPAddress>127.0.3.03 </IPAddress>
</computer>
<computer>
<hostname> hostname2 </hostname>
<IPAddress>127.0.3.04 </IPAddress>
</computer>
</platform>
<platform name = "unix">
<computer>
<hostname> hostname6 </hostname>
<IPAddress>127.0.3.08 </IPAddress>
</computer>
<computer>
<hostname> hostname7 </hostname>
<IPAddress>127.0.3.09 </IPAddress>
</computer>
</platform>
</xml>
If i want to get details about individual computer under each platform as a string how do i do that?
Which parser would be ideal to be used DOM or SAX.

Problem in editing xml document

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