Problem in getting correct datain DSO although routine is working!
I have two DSOs -DSO03 and DSO04 and in-between a transformation where a 0Order_Val field is getting calculated using the routine code as below:-
IF ( COMM_STRUCTURE-PROCESSKEY = '001' or
COMM_STRUCTURE-PROCESSKEY = '011' or
COMM_STRUCTURE-PROCESSKEY = '021' or
COMM_STRUCTURE-PROCESSKEY = '004' or
COMM_STRUCTURE-PROCESSKEY = '014' or
COMM_STRUCTURE-PROCESSKEY = '024' )
AND COMM_STRUCTURE-BWAPPLNM EQ 'MM'
AND COMM_STRUCTURE-ORDER_VAL <> 0.
perFORM QUANTITY_CONVERT
USING COMM_STRUCTURE-ORDER_VAL
COMM_STRUCTURE-po_UNIT
COMM_STRUCTURE-base_uom
COMM_STRUCTURE-numerator
COMM_STRUCTURE-denomintr
CHANGING RESULT.
Problem:-
For few doc numbers, the Quantity convert is fetching correct data, after applying the convert subroutine.
But in some, (although it is not supposed to return 0 after applying the sub-routine of Quantity_Convert),
it is showing wrong result as "0" in DSO04,
(although there is value in DSO03 for the field 0Order_Val).
Example:-
Doc num Field name DSO 3 Value DSO4Value Remarks
4500000089 0Order_ Val 3686.21 3686.21 Correct
4500000084 0Order_Val 500000 0 Wrong
While trying to debug the ABAP routine through breakpoints, I have found that the result fetched is correct (i.e. 500000 for doc_num: 4500000084) but when displaying data in DSO04 it is showing "0".
I have checked the input parameters and all are same.
Only exception is difference in currency between the two records.
One is USD (Doc num :4500000089) and the other is ESD (Doc num :4500000084).
Although currency is not any input parameter.
Also have tried Overwrite/summation setting in the Transformation but with no result.
If anyone can indicate any solution to this peculiar problem then it will be very helpful.
Regards,
Ritu.
email: [email protected]
Hi,
it is a bug in the Acrobat Reader. I had the same problem. Just add an input field called "myIndex" into the row and store there the current index when creating the line. With this solution you can programatically work with your own created index without the bug of the Acrobat Reader.
Take care,
Thomas
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So I tried the SUM_DISTINCT function next - SUM_DISTINCT(AMOUNT). Got me a lot closer, but now my total was too low. Figured out that was because if I had separate checks with the same check amount, that check amount only gets added in one time. Say Check 18 is for $100.00 and Check 39 is for $100.00, I only get $100.00 into the total instead of $200.00. Which when you think about it, is exactly what the SUM_DISTINCT function means. Since the chances of check amounts being duplicated are low, that is why I get close to the right number, but when dealing with tens of thousands of checks, check amount duplication does happen.
So on my totals for the SUM_DISTINCT column, I finally figured out that a CELL SUM got me closer to the right number. I only had a problem now when, on the same bank name and job number, would still have duplicate check amounts at that key (group by) status level. Percentage wise, my error is low - off maybe $200,000 out of $180,000,000. So close to the right number, yet so far.
The same thing happens in raw SQL. If you think about the raw join result, you can see what is happening -
check 1, check 1 amount, invoice 1
check 1, check 1 amount, invoice 2
check 2, check 2 amount, invoice 3
check 3, check 3 amount, invoice 4
So if you do SUM(CHECK AMOUNT), well yeah, it will add in the check 1 amount twice.
If you do SUM_DISTINCT(CHECK AMOUNT), then check 1 amount only gets counted once. Great. Ahh, but what if check 3 amount = check 1 amount? Oops, the check 3 amount is excluded.
Does anyone know of a way to get around this problem? I have been playing around with the functions, but the SQL reference does not give many examples to help understand all the various optional parameters. I know, in vague concept, what I want. Something like -
SUM(AMOUNT) DISTINCT ON CHECK_ID, or
SUM_DISTINCT(AMOUNT) DISTINCT ON CHECK_ID.
CHECK_ID is the internal Oracle id number for each check, from the ap_checks_all table. Check number is not unique enough, since different bank accounts may be using the same check number in the same time period. So I want a way to be able to add my check amount to the total one time when there are multiple invoices on the check, and then get each invidual check amount (one time) added up to get my check total amount.
Like I said, no problems with Discoverer or raw SQL if doing just one table. But once I join checks to invoice payments, poof, I run into trouble.
I did not think I was trying to do anything unusual. So quite surprising that having so much trouble trying to find a way around this problem.
Hope this detail explanation makes some sense. Thanks for any help/insight anyone can give me.
John DickeyMichael,
Nope, that does not work. It truly just gives me an average. My desired (table) report row format is this -
Bank name , Job Number, Check Count , Invoice Count , Check Amount Total
So this is a SUMMARY report. Not a detail report. If I do detail, I do not have any problems - I get my correct check amount total. If I do just the ap_checks_all table, I get the correct amount (but then cannot get my invoice count). I get the correct check count (count distinct on check id). I get the correct invoice count. When I added a calculation column using the Average function as you suggested, I see on each row what is likely the average check amount. Which is exactly what you would expect to see.
Now I did get a brainstorm and tried this. I calculated both the average and average distinct on check amount, then multiplied each by my check count. Darn. Still does not work. The Average Distinct * Check Count = SUM_DISTINCT(CHECK AMOUNT), which I already have. Average Distinct apparently only includes a duplicate check amount one time in calculating the average (which when you think about it, makes sense, darn it). The AVERAGE function still has the problem, it looks like, of including the check amount each time on checks with multiple invoices (and thus multiple rows in the join result) in determining the average. Which when you think about the raw join result from joining checks to invoice payments tables, makes sense. The result of AVERAGE * CHECK COUNT is better than the SUM(AMOUNT) column, but not as good as the SUM_DISTINCT(AMOUNT) column.
Any other ideas? Interesting that something that seems like a pretty basic thing to do, if it does have a solution, is not a very obvious/simple solution.
John Dickey -
BI Query with Hierarchy in VC does not get correct values
Hello Gurus,
I am building a model in VC for Performance Score card using Query as data service.
I have the following problem.
When I execute query in BEx with Hierachy_node variable , it is getting correct values, but the same is getting incorrect values in VC.
The Hierarcynode variable I am using is a TOP node, then the values including child nodes are also should be displayed, which is working fine with BEx query but not in VC.
When I execute the query with hierarchy node value as child node I am getting correct values both in VC and in BEx.
The correct values are not shown only when I use top nodes.
Please help me in this regard.
Thanks in advance
GaneshHi
We are facing the same issue. Is this issue resolved? Pls let us know the solution
Regards
Aruna -
Problem in getting Norms for each BOM
Hi Experts,
I am doing a report for stock with subcontractors and I am facing a problem in getting the accurate
Norms (STPO~MENGE) against the BOM (STPO~STLNR) for each EBELN.
My requirement is :
1. Finished Goods - ( MSEG~MATNR) or (EKPO~MATNR) but mseg-matnr is more prefered as my output is based on the mkpf-budat , WHERE BWART IN ('101','102') then
MSEG~EBELN.
IF EKPO-PSTYP ne ' 3 ' delete Finished goods.
Then I take raw materials for finished goods and BOM for each rawmaterials.
2. Raw materials - select (RESBMATNR, RESBSTLNR, RESBSTLKN, RESBSTPOZ) where resb-baugr = mseg-matnr and ebeln = mseg-ebeln.
Now I am facing problem in getting NORMS against each BOM.
3. Norms - * select STPOMENGE where STLNR = RESBSTLNR , IDNRK = RESB~MATNR,
STPOZ = RESB~STPOZ.
But I am not getting the correct Norms for each EBELN, please advice if my logic is wrong or if my
tables are wrong.
Thanks
Karthik.
Edited by: Karthik R on Mar 13, 2009 10:32 AM
Edited by: Karthik R on Mar 13, 2009 10:32 AM
Edited by: Karthik R on Mar 13, 2009 10:33 AMHi Karthik,
You try this one, which I already tried and working fine for me when i developed a custom's enquiry report,
here is a peice of code,
SELECT ABUDAT AXBLNR BMBLNR BZEILE
BBWART BEBELN BMENGE BDMBTR B~KUNNR
INTO CORRESPONDING FIELDS OF TABLE IT_FINAL
FROM MKPF AS A INNER JOIN MSEG AS B ON AMBLNR = BMBLNR AND
AMJAHR = BMJAHR
WHERE A~BUDAT IN S_BUDAT AND
B~MATNR = WA_IMAT-MATNR AND
B~WERKS IN S_WERKS .
IF NOT IT_FINAL IS INITIAL.
SELECT MATNR WERKS STLAN STLNR STLAL
FROM MAST INTO TABLE IT_MAST
WHERE MATNR = WA_IMAT-MATNR AND
WERKS IN S_WERKS AND
STLAN = '1'.
ENDIF.
IF NOT IT_MAST IS INITIAL.
SELECT STLTY STLNR STLAL DATUV BMEIN BMENG
FROM STKO INTO TABLE IT_STKO
FOR ALL ENTRIES IN IT_MAST
WHERE STLNR = IT_MAST-STLNR AND
STLAL = IT_MAST-STLAL AND ( STLTY = 'D' OR STLTY = 'E' OR STLTY = 'K' OR
STLTY = 'M' OR STLTY = 'S' OR STLTY = 'T' OR STLTY = 'P' ).
ENDIF.
IF NOT IT_STKO IS INITIAL.
SELECT STLNR DATUV IDNRK POSNR MEINS MENGE
FROM STPO INTO TABLE IT_STPO
FOR ALL ENTRIES IN IT_STKO
WHERE STLNR = IT_STKO-STLNR AND STLTY = IT_STKO-STLTY.
ENDIF.
IF NOT IT_STPO IS INITIAL.
SELECT MATNR MAKTX
FROM MAKT INTO TABLE IT_MAKT
FOR ALL ENTRIES IN IT_STPO
WHERE MATNR = IT_STPO-IDNRK AND
SPRAS = 'EN'.
ENDIF.
LOOP AT IT_STKO INTO WA_STKO.
" Own Custom Logic, If Item Quantity is 500 KG, how to calculate per KG, Simple divide by the same Qty.
IF WA_STKO-BMEIN = 'KG'.
LOOP AT IT_STPO INTO WA_STPO.
WA_STPO-RATIO = WA_STPO-MENGE / WA_STKO-BMENG.
MODIFY IT_STPO FROM WA_STPO.
CLEAR : WA_STPO.
ENDLOOP.
ENDIF.
CLEAR : WA_STKO.
ENDLOOP.
LOOP AT IT_STPO INTO WA_STPO.
LOOP AT IT_MAKT INTO WA_MAKT.
MOVE-CORRESPONDING WA_MAKT TO WA_STPO.
DELETE TABLE IT_MAKT FROM WA_MAKT.
CLEAR : WA_MAKT.
EXIT.
ENDLOOP.
MODIFY IT_STPO FROM WA_STPO.
CLEAR : WA_STPO.
ENDLOOP.
LOOP AT IT_FINAL1 INTO WA_FINAL1 WHERE BWART = '101' OR BWART = '102'.
MOVE WA_FINAL1-BUDAT TO WA_FINAL2-BUDAT.
MOVE WA_FINAL1-EBELN TO WA_FINAL2-EBELN.
MOVE WA_FINAL1-MENGE TO WA_FINAL2-MENGE.
MOVE WA_FINAL1-DMBTR TO WA_FINAL2-DMBTR.
APPEND WA_FINAL2 TO IT_FINAL2.
CLEAR : WA_FINAL1.
ENDLOOP.
Thanks & Regards,
Dileep .C -
Have you tried returning a photo book that has a binding problem? I just ordered 2 large hardcover photobooks and one arrived with the inside binding messed up. Do you know how this can get corrected? They were over $80 and it seems they should not be flawed. I would appreciate any tips. lindajenkins
Contact Apple Support - link at the bottom of every page of these forums
LN
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