Problem printing the methods due to lack of understanding

Question

Okay, i'm pretty sure i have all my code correct except for the System.out.println's at the top to print the methods below. What am i doing wrong? Its suppose to be a program that prompts for amount of random numbers, the first part sorts/finds the median, and the second part finds the mode.
import javax.swing.*;
import java.io.*;
import java.util.*;
public class Assignment2part1
public static void main (String arg[])
     String numRandomNum= JOptionPane.showInputDialog("How many random numbers would you like?");
   int setRandomNum = Integer.parseInt(numRandomNum);
     Random num = new Random();
     for (int i = 0; i < setRandomNum ; i++)
            int number =num.nextInt(10) + 1;
            System.out.println(number);
          System.out.println(median(number[] ));   // #############################Problem here
          System.out.println(mode(????));     // #################################Problem here
public static void median (int[] a)
          int temp=0;
          for (int i=0; i<a.length; i++)
               for (int j=0; j<a.length; j++)
               if (a[i] > a[j])
                    temp = a;
                    a[i] = a[j];
                    a[j] = temp;
          if (a.length%2==1)
               return a[a.length/2];
               else
                    return ( a[a.length/2] + (a[a.length/2]-1)/2 );
public static int mode (int[] a)
     int mostFreqNum=-1, mostFreqCount=1, noModeFlag=0, cNum=0, cCount=0;
     for (int i=0; i<a.length; i++)
          cCount=1;
          cNum=a[i];
          for (int j=0; j<a.length; J++)
               if (i!=j && a[j] != mostFreqNum && a[j] == cNum)
                    cCount++;
          if (cCount>mostFreqCount)
               mostFreqCount=cCount;
               mostFreqNum=cNum;
               noModeFlag=0;
          else if (cCount==mostFreqCount)
               noModeFlag=1;
          if (noModeFlag=1)
               return -1;
          else
               return mostFreqNum;

Answer 1

No, i completely understand, so it needs to be in the main section, SO would it be something like.......
import javax.swing.*;
import java.io.*;
import java.util.*;
public class Assignment2part1
public static void main (String arg[])
     String numRandomNum= JOptionPane.showInputDialog("How many random numbers would you like?");
   int setRandomNum = Integer.parseInt(numRandomNum);
     Random num = new Random();
     for (int i = 0; i < setRandomNum ; i++)
            int number =num.nextInt(10) + 1;
            System.out.println(number);
          int [] a= {number};          //#################Edited
          System.out.println(median(number[] ));
          System.out.println(mode(
public static int median (int[] a)
          int temp=0;
          for (int i=0; i<a.length; i++)
               for (int j=0; j<a.length; j++)
               if (a[i] > a[j])
                    temp = a;
                    a[i] = a[j];
                    a[j] = temp;
          if (a.length%2==1)
               return a[a.length/2];
               else
                    return ( a[a.length/2] + (a[a.length/2]-1)/2 );
public static int mode (int[] a)
     int mostFreqNum=-1, mostFreqCount=1, noModeFlag=0, cNum=0, cCount=0;
     for (int i=0; i<a.length; i++)
          cCount=1;
          cNum=a[i];
          for (int j=0; j<a.length; J++)
               if (i!=j && a[j] != mostFreqNum && a[j] == cNum)
                    cCount++;
          if (cCount>mostFreqCount)
               mostFreqCount=cCount;
               mostFreqNum=cNum;
               noModeFlag=0;
          else if (cCount==mostFreqCount)
               noModeFlag=1;
          if (noModeFlag=1)
               return -1;
          else
               return mostFreqNum;
I'm still not quite sure on the syntax of the print ln, what needs to go into the ().   I appreciate the step by step help