Problem with a pattern

I have a problem with a pattern.
I want to put a patter to validate an e-mail but i don´t find the way to do it

Hi Veloki,
You can drag and drop custom "email Adress" object from Custom Object Library. It includes the script for email validation in the validate event of email area.
// Validate the email address.
var r = new RegExp("^[a-z0-9_\\-\\.]+\\@[a-z0-9_\\-\\.]+\\.[a-z]{2,3}$"); // Create a new Regular Expression Object.
// Set the regular expression to look for an email address in general form.
var result = r.test(this.rawValue); // Test the rawValue of the current object to see
// if it fits the general form of an email address.
if (result == true) // If it fits the general form,
true; // all is well.
else // Otherwise,
false; // fail the validation.
Asiye

Similar Messages

Problem with date pattern

Hi all,
I have a little maddening problem with oracle.jbo.domain.Date.
I have a viewObject with an attribute (fechaCompra) type Date and I need the time too so in controlHints I have defined:
format type: Simple Date
Format: yyyy-MM-dd 'at' hh:mm:ss
Right, on runTime now i see ok the data and in the inputDate appears the calendar and the hour .
But when I take the value of this attribute, to call a void that takes a oracle.jbo.domain.Date type, raises an error when parses the value of the atribute.
All this doesn't happen when in the view object the controlHints are defined like this:
format type: Simple Date
Format: yyyy-MM-dd
Any idea?
Thanks in advance,
Rowan

hello,
My guess would be that when you drop your formatted date into the methode the parse function is called from String to date, this work with no time attached.
But fails with the time attached. I would double check the specific class you pass to each method to be sure they are correct.
hat you mention parse gives an even bigger hint that you are using the parse function from oracle.jbo.domain.Date, which takes a string.
This function will fail with your custom patterns.
//get the value
String value = .....
//Not 100% sure if the at needs to be escaped or not
DateFormat sdf = new SimpleDateFormat("yyyy-MM-dd at hh:mm:ss");
//Prolly needs a try catch, writing this by hand
java.util.Date utilDate = sdf.parse(value);
java.sql.Date sqlDate = new java.sql.Date(utilDate.getTime());
oracle.jbo.domain.Date jboDate = new oracle.jbo.domain.Date(sqlDate);
//pass to your method-Anton

Design flaw in overloading? Problem with visitor pattern

I have been trying some implementations of the Visitor pattern in Java and have encountered a problem with overloaded methods in Java. It seems that the caller (client) of a overloaded method decides what implementation of that method is chosen. I find that strange from an OO / encapsulation point of view and it gets me into problems when using Visitor. This code shows my problem:
// a class with overloaded methods
public class OverLoadingTest {
     public void print(String s) {
          System.out.println("This looks like a String to me:");
          System.out.println("\"" + s + "\"");
     public void print(Object o) {
          System.out.println("This looks like an Object to me:");
          System.out.println("\"" + o + "\"");
//a client for that class
public class OverLoadingTestClient {
     public void test() {
          OverLoadingTest test = new OverLoadingTest();
          Object o1 = "String in an Object reference";
          String s1 = "String in a String reference";
          test.print(o1);
          test.print(s1);
     public static void main(String[] args) {
          new OverLoadingTestClient().test();
//And the output is:
This looks like an Object to me:
"String in an Object reference"
This looks like a String to me:
"String in a String reference"
//The output I would have expeced (wanted):
This looks like a String to me: //it is a String!
"String in an Object reference"
This looks like a String to me:
"String in a String reference"
Why is this? Is there a work around?

The specific method is decided on in compile time and by the client of that method, not the provider. I'd expect the client to just invoke the method and let the privider figure out what implementation to choose. Whatever the client thinks that he is providing as argument types.
I am implementing a slightly different version compared to http://ootips.org/visitor-pattern.html. I find implementing "v.visit(this);" for every subclass of the Visisted superclass strange. Why an abstract method "accept(Visitor v);" when all subclasses will iplement it in the same way ("v.visit(this);")?
Daan

Problems with Factory pattern

Sorry... I know this topic has been done to death but I still have some questions.
In my development, I keep encountering a recurring problem that I believe should be solved by the 'factory pattern'. (Note: I'm not a patterns nut so I am only guessing about the correct pattern).
Here is the problem:
I develop an abstract base class. I extend the base class with several subclasses. Exterior objects use the instances via a base class reference and I don't want to them to have to know which is the correct subclass or how to create the instance.
My solution is to make a create(param, param,...) method in the base class and using the param(s) construct the instance something like:static Foo create(int type)
Foo instance = null;
String className = "com.myco.foos.DefaultFoo";
if(CONST_A == type)
className = "com.myco.foos.FooA";
else if(CONST_B == type)
className = "com.myco.foos.FooB";
{on and on...}
{using reflection create a new instance from the className String}
return instance;
}The obvious problem with the create() method is that it becomes a maintenence point and I don't like the idea of a base class knowing about subclasses.
Anyone know better a solution? Comments?
Thanks in advance.

Yes, that is the Factory pattern you describe. The client programs are going to call your createFoo() method and get back an instance of a subclass of Foo. Typically this pattern is used where there is some external entity that determines what subclass will be returned -- for example a system property -- and the client programs call createFoo() with no arguments. In this case reflection is used to create the instance, and your base class does not need to know anything about any subclasses.
However, if your client programs can influence the choice of subclass, then they will have to pass some kind of parameter into createFoo(). At this point, createFoo() requires some decision logic that says "create this, or that, depending on the input parameter". And if that parameter is simply a code that enables the client programs to say "Give me a ChocolateFoo instance", then returning "new ChocolateFoo()" is the most straightforward design. But in this case, why can't the client program do that?
If you don't like the base class having to know about subclasses (and you shouldn't be happy if it does), then you could have a helper class -- FooFactory -- that contains only the static method createFoo(). This class would know about Foo, and about any of its subclasses that it can produce instances of. It's still a maintenance point, no avoiding that, but at least it is off by itself somewhere.

Problem with phonenumber pattern

Hello,
I've got a problem with my display and validation pattern for my phone numbers.
In Holland we have two sorts of phone numbers:
Always 10 numbers, but some regions have a 3 digit area code,
other regions a 4 digit area code.
Example:
012-3456789
0123-456789
This is also the way I want my users to enter the data.
I want to display them as followed:
012-3456789 --> 012 - 345 67 89
0123-456789 --> 0123 - 456 789
My display pattern right now is: text{999 - 999 99 99}|text{9999 - 999 999}
My edit pattern is: text{999-9999999}|text{9999-999999}
My validation pattern is: text{999-9999999}|text{9999-999999}
(With a pop-up message to fill in 10 numbers, area code seperated from the rest by a dash, as in the example)
The problem is that the validation works fine, but it always transforms the phonenumber to the first option (999 - 999 99 99).
How can I fix this?
Greetings and thanks in advance,
Sterre

Hi Veloki,
You can drag and drop custom "email Adress" object from Custom Object Library. It includes the script for email validation in the validate event of email area.
// Validate the email address.
var r = new RegExp("^[a-z0-9_\\-\\.]+\\@[a-z0-9_\\-\\.]+\\.[a-z]{2,3}$"); // Create a new Regular Expression Object.
// Set the regular expression to look for an email address in general form.
var result = r.test(this.rawValue); // Test the rawValue of the current object to see
// if it fits the general form of an email address.
if (result == true) // If it fits the general form,
true; // all is well.
else // Otherwise,
false; // fail the validation.
Asiye

Intermittent problems with strange patterns on screen

My new (refurbed) 17in Intel Imac starts up periodically with a strange pattern running at 45 degrees across the entire screen (little multicolor boxes or rectangles) then the screen goes to all blue and freezes with no further activity. I have run the hardware test, reset pram and disk utility with no solutions. It will still boot up perfectly about every 3rd attempt. I'm running 10.4.10. Any help would be greatly appreciated.

To make sure that this is not software related, set it back to factory settings, without using a backup afterwards, described in this article:
Use iTunes to restore your iOS device to factory settings - Apple Support
If the screen has still this pattern, the issue is hardware related and the phone needs to be serviced. In that case it might be enough to let Apple replace the screen.
Screen repair service pricing
Repair and replacement costs depend on your iPhone model and your AppleCare product coverage. Apple will run a diagnostic test to determine whether your iPhone has experienced additional damage. If it has, or if it needs other repairs, you may need to pay an out-of-warranty service fee. Accidental damage isn't covered under the Apple One Year Limited Warranty.
Model
Screen repair cost
iPhone 6
$109
iPhone 6 Plus, iPhone 5s, iPhone 5c, iPhone 5
$129
Plus a $6.95 shipping fee, if required. Fees are in USD and exclude local tax. Pricing is for service through Apple. The final service fee we charge will be determined during testing. Pricing and terms vary for service through an Apple Authorized Service Provider.
copied from Service Answer Center - iPhone

Problem with fill pattern in oracle reports 11g

Hi all,
regardless of the fill pattern we use, on paper lines with a fill pattern appear completely black
no longer using a fill pattern is not an option as we have > 200 reports (migrated from 6i) that use them
running such a report from the builder choosing paper layout does show the report output correctly on our development PCs
development PC OS : XP
WLS 10.3.3 (32 bit)
Reports builder 11.1.1.3.0
server : Win 2008 64 bit
WLS 10.3.3 (64 bit)
report output is PDF
the way we work when a user prints a report, the pdf is created on the reports server and then send to the client using webutil and then the report is printed using Adobe Reader 9.3.2
any ideas ?
thx in advance
Kr
Martin

anyone ?

ASAP PLZ- Having problems with basic pattern input/output

Hey! I am new to this forum, and I am also new to java =).
I am writing a program that prompts a user to select 1 pattern out of 5. then the user needs to choose the number of lines he/she wants to display for instace:
(MENU)
PATTERN 5
1
12
123
1234
USER Selection : Pattern 5
Choose Number of Lines: 3
OUTPUT
Pattern 5
1
12
123
I have a basic code for a pyramid that deals with leading spaces etc.. but I don't have a clue how to use that method with my program
MY PROGRAM:
//Purpose:     Displaying Patterns
//Input:          User's selection
//Output:     Messages
//Author;     Fares
//Program:     4
//Date:          9/15/2009
import java.util.Scanner;
public class MyPatterns4{
public static void main(String[] args) {
// Declarations
Scanner scan = new Scanner(System.in);
     String outputString;
     int option = 1;
     int lines;
     // Paterns
     String patternOne;
     patternOne = "\n\t Pattern I \n\t 1 \n\t 12 \n\t 123 \n\t 1234 \n\t 12345 \n\t 123456";
     String patternTwo;
     patternTwo= "\n\t Pattern II \n\t 123456 \n\t 12345 \n\t 1234 \n\t 123 \n\t 12 \n\t 1";
     String patternThree;
     patternThree = "\n\t Pattern III \n\t 1 \n\t 21 \n\t 321 \n\t 4321 \n\t 54321 \n\t 654321";
     String patternFour;
     patternFour = "\n\t Pattern IV \n\t 123456 \n\t 12345 \n\t 1234 \n\t 123 \n\t 12 \n\t 1";
     String patternFive;
     patternFive = "\n\t Pattern V \n\t 1 \n\t 12 \n\t 123 \n\t 123456 \n\t 123 \n\t 12";
     // Prompt the user to select a pattern
     outputString = "------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t" +
"3 Display Pattern III\n\t4 Display Pattern IV\n\t" +
          "5 Display Pattern V\n\t" + "6 Display All Patterns\n\n\n\t" + "0 Quit\n\n\n";
     System.out.println(outputString);
     System.out.print("\tEnter your selection: ");
     option = scan.nextInt();
     // Keep reading data until the user enters 0
     while (option !=0){
               while (option == 6) {
               outputString = "\nChoose another selections!\n";
                                   System.out.println(patternOne);
                                   System.out.println(patternTwo);
                                   System.out.println(patternThree);
                                   System.out.println(patternFour);
                                   System.out.println(patternFive);
                                   System.out.println(outputString);
          outputString = "--------------------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t" +
"3 Display Pattern III\n\t4 Display Pattern IV\n\t" +
          "5 Display Pattern V\n\t" + "6 Display All Patterns\n\n\n\t" + "0 Quit\n\n\n";
          System.out.println(outputString);
          System.out.print("\tEnter your selection: ");
          option = scan.nextInt();
while (option != 0 && option !=6) {
               System.out.print("\tEnter number of lines: ");
               lines = scan.nextInt();
               if (lines < 1 || lines > 6) {
System.out.println("\tYou must enter a number from 1 to 6");
          System.out.print("\tEnter number of lines: ");
               lines = scan.nextInt();
          while (lines < 1 || lines > 6) {
System.out.println("\tYou must enter a number from 1 to 6. The program will now end.");
System.exit(0);}
               switch (option) {
                    case 1: // write the code to display Pattern I here
                                   outputString = "\n Choose another selection! \n";
                                   System.out.println(patternOne);
                                   System.out.println(outputString);
                                   break;
                    case 2:      // write the code to display Pattern II here
                                   outputString = "\nChoose another selection!\n";
                                   System.out.println(patternTwo);
                                   System.out.println(outputString);
                                   break;
                    case 3:     // write the code to display Pattern III here
                                   outputString = "\nChoose another selection!\n";
                                   System.out.println(patternThree);
                                   System.out.println(outputString);
                                   break;
                    case 4:      // write the code to display Pattern IV here
                                   outputString = "\nChoose another selection!\n";
                                   System.out.println(patternFour);
                                   System.out.println(outputString);
                                   break;
                    case 5:      // write the code to display Pattern V here
                                   outputString = "\nChoose another selection!\n";
                                   System.out.println(patternFive);
                                   System.out.println(outputString);
                                   break;
                    case 6: // the code to display all paterns
                                   outputString = "\nChoose another selections!\n";
                                   System.out.println(patternOne);
                                   System.out.println(patternTwo);
                                   System.out.println(patternThree);
                                   System.out.println(patternFour);
                                   System.out.println(patternFive);
                                   System.out.println(outputString);
                                   break;
                    default: outputString = "\nInvalid Selection\n";
                                   System.out.println(outputString);
                                   break;
               }// end of switch
          outputString = "------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t" +
"3 Display Pattern III\n\t4 Display Pattern IV\n\t" +
          "5 Display Pattern V\n\t" + "6 Display All Patterns\n\n\n\t" + "0 Quit\n\n\n";
          System.out.println(outputString);
          System.out.print("\tEnter your selection: ");
          option = scan.nextInt();
} }// end of while loop
}// end of main method
}// end of class

//Purpose: Displaying Patterns
//Input: User's selection
//Output: Messages
//Author; Fares
//Program: 4
//Date: 9/15/2009
import java.util.Scanner;
public class MyPatterns4{
public static void main(String[] args) {
// Declarations
Scanner scan = new Scanner(System.in);
String outputString;
int option = 1;
int lines;
// Paterns
String patternOne;
patternOne = "\n\t Pattern I \n\t 1 \n\t 12 \n\t 123 \n\t 1234 \n\t 12345 \n\t 123456";
String patternTwo;
patternTwo= "\n\t Pattern II \n\t 123456 \n\t 12345 \n\t 1234 \n\t 123 \n\t 12 \n\t 1";
String patternThree;
patternThree = "\n\t Pattern III \n\t 1 \n\t 21 \n\t 321 \n\t 4321 \n\t 54321 \n\t 654321";
String patternFour;
patternFour = "\n\t Pattern IV \n\t 123456 \n\t 12345 \n\t 1234 \n\t 123 \n\t 12 \n\t 1";
String patternFive;
patternFive = "\n\t Pattern V \n\t 1 \n\t 12 \n\t 123 \n\t 123456 \n\t 123 \n\t 12";
// Prompt the user to select a pattern
outputString = "------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t"
"3 Display Pattern III\n\t4 Display Pattern IV\n\t"
"5 Display Pattern V\n\t" "6 Display All Patterns\n\n\n\t" "0 Quit\n\n\n";
System.out.println(outputString);
System.out.print("\tEnter your selection: ");
option = scan.nextInt();
// Keep reading data until the user enters 0
while (option !=0){
while (option == 6) {
outputString = "\nChoose another selections!\n";
System.out.println(patternOne);
System.out.println(patternTwo);
System.out.println(patternThree);
System.out.println(patternFour);
System.out.println(patternFive);
System.out.println(outputString);
outputString = "--------------------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t"
"3 Display Pattern III\n\t4 Display Pattern IV\n\t"
"5 Display Pattern V\n\t" "6 Display All Patterns\n\n\n\t" "0 Quit\n\n\n";
System.out.println(outputString);
System.out.print("\tEnter your selection: ");
option = scan.nextInt();
while (option != 0 && option !=6) {
System.out.print("\tEnter number of lines: ");
lines = scan.nextInt();
if (lines < 1 || lines > 6) {
System.out.println("\tYou must enter a number from 1 to 6");
System.out.print("\tEnter number of lines: ");
lines = scan.nextInt();
while (lines < 1 || lines > 6) {
System.out.println("\tYou must enter a number from 1 to 6. The program will now end.");
System.exit(0);}
switch (option) {
case 1: // write the code to display Pattern I here
outputString = "\n Choose another selection! \n";
System.out.println(patternOne);
System.out.println(outputString);
break;
case 2: // write the code to display Pattern II here
outputString = "\nChoose another selection!\n";
System.out.println(patternTwo);
System.out.println(outputString);
break;
case 3: // write the code to display Pattern III here
outputString = "\nChoose another selection!\n";
System.out.println(patternThree);
System.out.println(outputString);
break;
case 4: // write the code to display Pattern IV here
outputString = "\nChoose another selection!\n";
System.out.println(patternFour);
System.out.println(outputString);
break;
case 5: // write the code to display Pattern V here
outputString = "\nChoose another selection!\n";
System.out.println(patternFive);
System.out.println(outputString);
break;
case 6: // the code to display all paterns
outputString = "\nChoose another selections!\n";
System.out.println(patternOne);
System.out.println(patternTwo);
System.out.println(patternThree);
System.out.println(patternFour);
System.out.println(patternFive);
System.out.println(outputString);
break;
default: outputString = "\nInvalid Selection\n";
System.out.println(outputString);
break;
}// end of switch
outputString = "------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t"
"3 Display Pattern III\n\t4 Display Pattern IV\n\t"
"5 Display Pattern V\n\t" "6 Display All Patterns\n\n\n\t" "0 Quit\n\n\n";
System.out.println(outputString);
System.out.print("\tEnter your selection: ");
option = scan.nextInt();
} }// end of while loop
}// end of main method
}// end of class

Funny problem with schema pattern regular expression

I have following element in my schema:
<xsd:element name="lD">
     <xsd:simpleType>
          <xsd:restriction base="xsd:string">
               <xsd:pattern value="\d{5,8}" />
          </xsd:restriction>
     </xsd:simpleType>
</xsd:element>then in the XML, I have:
<ID>
123456789
</ID>funny thing is the schema validates the value successfully. seems the upper bound of 8 the in the regular expression does not have any effect. however, 1234 would fail.
i looked up the schema prime on W3C, it specifies that {n,m} means at least n and at most m.
any idea anyone?
I have using Xerces 1.4.4.
Thanks

I tried the example you mentioned and it seemed to
work for me. It validated both the upper bound and
the lower bound. Looking at the Manifest file in
xerces jar, it looks like I have version 2.5.0yes, I know. Xerces 2 works, but Xerces 1 has the above problem. If you get Xerces 1.4.4 from xml.apache.org, you will see the problem.
I can not use Xerces 2 in our production environment yet.

Problems With url-pattern in a filter-mapping

Hi!
I need to make a filter when the clients call a jsf pages in /pages in my web application, but when i make the filter-mapping like this:
     <filter-mapping>
          <filter-name>sessionFilter</filter-name>
          <url-pattern>/pages/*.jsf</url-pattern>
     </filter-mapping>An exception appears:
SEVERE: Parse error in application web.xml
java.lang.IllegalArgumentException: Invalid <url-pattern> /pages/*.jsf in filter mapping
     at org.apache.commons.digester.Digester.createSAXException(Digester.java:2540)
     at org.apache.commons.digester.Digester.createSAXException(Digester.java:2566)
     at org.apache.commons.digester.Digester.endElement(Digester.java:1061)
     at org.apache.xerces.parsers.AbstractSAXParser.endElement(Unknown Source)
     at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanEndElement(Unknown Source)
     at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source)
     at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source)
     at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
     at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source)
     at org.apache.xerces.parsers.XMLParser.parse(Unknown Source)
     at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source)
     at org.apache.commons.digester.Digester.parse(Digester.java:1548)
     at org.apache.catalina.startup.ContextConfig.applicationConfig(ContextConfig.java:263)
     at org.apache.catalina.startup.ContextConfig.start(ContextConfig.java:624)
     at org.apache.catalina.startup.ContextConfig.lifecycleEvent(ContextConfig.java:216)
     at org.apache.catalina.util.LifecycleSupport.fireLifecycleEvent(LifecycleSupport.java:119)
     at org.apache.catalina.core.StandardContext.start(StandardContext.java:4290)
     at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1083)
     at org.apache.catalina.core.StandardHost.start(StandardHost.java:789)
     at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1083)
     at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:478)
     at org.apache.catalina.core.StandardService.start(StandardService.java:480)
     at org.apache.catalina.core.StandardServer.start(StandardServer.java:2313)
     at org.apache.catalina.startup.Catalina.start(Catalina.java:556)
     at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
     at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
     at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
     at java.lang.reflect.Method.invoke(Method.java:324)
     at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:287)
     at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:425)the <url-pattern>/pages/*</url-pattern> not work to me because process all pages, I nedd only *.jsf
Please Help me whit this.

"the <url-pattern>/pages/*</url-pattern> not work to me because process all pages, I nedd only *.jsf"
Yes but in the filter you can get the url from the request.getUrl() and then only process requests that contain .jsf. Simply just pass all other requests along.
Some information on url pattern matching:
http://edocs.bea.com/wls/docs61/webapp/components.html#113049

Problems with cron pattern in schedule editor

hi
I have a transaction that should be executed every 7 seconds. To do this I created a new entry in the schedule editor. Because of the tool to build the cron pattern showed every minute as the most often possible, I looked at the help of xMII.
There is said, that a pattern of */5 * * * * * would execute every 5 seconds. I changed to */7 * * * * * and saved. The result is, that it is executed every 7 minutes. That is also what I see in the scheduler. Even the pattern * * * * * * that should execute every second according to the help does not what is documented. It executes every minute.
So the question is, is it possible to execute a transaction every X seconds?
And the second question, is this a bug in the scheduler or ist the information provided in help wrong?
Thank you for help.
Kind regards,
Timo Bachert

OK, thank you. Then the help of xMII 12 says wrong (either in german as in english)
Timo

Problem with stretching pattern on footer

On the master page i have put a triangle on the bottom as my footer and placed on top a pattern. When I look in master page I see that the pattern stretches across the entire page as I require however when I upload the page it appears only partially. Take a look at my site to see what I mean - www.ozzywizzpop.com
How can I rectify this?
Thanks,
Chris Kimber

Thanks for the response. I changed the name of the file and it is working properly.
Just curious to know which component of the server does this work of looking for URL pattern and forwarding the request to the appropriate Servlet. If you can explain i will be really elightened

Problem with SimepleDateFormat for the military pattern....

i have the code, which has to display date in the military format i.e., "yyyyMMddhhmm".
java.util.Date date = new SimpleDateFormat("yyyyMMddhhmm").parse("200709201700");
System.out.println("Expected Date : " + date);
but output displays everytime i.e., Thu Sep 20 17:00:00 IST 2007
is there any problem with the pattern???

By military format you mean 24 hour clock time, right? I believe "hh" in SimpleDateFormat is for 12 hour clock time and "HH" is for 2 digits of 24 hour clock time.
EDIT: Also, you're just parsing the string into a Date object. When you're printing, it'll simply use the toString() for Date, giving you an output as you see. If you want the output also to be formatted in the same way, you need to use the format() method of SimpleDateFormat with the same pattern on the Date.
People on the forum help others voluntarily, it's not their job.
Help them help you.
Learn how to ask questions first: http://faq.javaranch.com/java/HowToAskQuestionsOnJavaRanch
(Yes I know it's on JavaRanch but I think it applies everywhere)
Edited by: nogoodatcoding on Oct 3, 2007 6:03 PM

Irritating problem with Retina Display; dims/ flickers on and off and in weird pattern along bottom of screen

I bought a 13-inch Retina MBP in late September 2014, just a few months ago and i am starting to have problems with the screen.
First of all, the screen will sometimes fade and a weird pattern will appear at the bottom of the screen in which every second set of backlights is off and the other is on. Here is a picture that i found on the internet; from a much older mac though but still shows the problem.
The second problem, which is more irritating, is that every now and again the screen will sort of flicker where it will get darker then lighter and keep switching the brightness in a matter of seconds. This is so hard to look at!!
Hopefully there is an easy solution however i may have to take it to an Apple store and unfortunately get it replaced.
Thanks.

Howdy there chappo_10,
It sounds like you have a couple of unexpected video issues on your 13 inch MacBook Pro. I'd like to recommend these troubleshooting steps specifically to hep you determine if you need to take it to the Apple Store:
Apple computers: Troubleshooting issues with video on internal or external displays
Reset the system
You can reset the Mac's parameter RAM and SMC.
Reset the resolution
Start by resetting the Mac's parameter RAM. If the display does not come up, was previously set to an unsupported resolution, and still results in no video:
Start up in Safe Mode.
From the Apple () menu, choose System Preferences.
Choose Displays from the View menu to open the preferences pane.
Select any resolution and refresh rate that your display supports.
Restart your computer.
Thank you for using Apple Support Communities.
Take care,
Sterling

Illustrator 5 - patterns problem with printing

Hi please please help having majoy problems and need help asap in work!!!
I am working on a PC windows 7 illustrator 5.
when I create a pattern any type even a imple spot and fill a CAD t shirt, its fine, when I print it, it creates lines through out either vertica/horizonal when I send to someone else to print its fine when i print on another printer its fine. when using default pattern swatches from illutstrator it prints fine, it seems to be when I fill a flat CAD with a pattern and I have created it.
Is this something to do with printer? I need ergent help its driving me crazy have asked loads of IT people everyone is stuck even my collegues who have worked with software for years.
please please help!! I have tried everythint, loads of diffrent pattens and colours nothing is fixing, lines still show on pdf doc too.

Illustrator 5 is more than a decade old. If you really mean version 5, you may be hard pressed to find much help.
If by chance you mean CS5 (version 15) that's another matter.
Does the problem exisit in a new document or only in specific documents?
Have you tried trashing the Ai settings?
The fact that someone else can print it... as well as switching printers works, would lead to a issue with your print driver for the specific printer showing the issue. Or perhaps a combination of the print driver and the artwork construction. For example, the printer only handles Postscript level 2 and you need Postscript level 3 support to print the artwork properly.

Problem with a pattern

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