Problem with stretching pattern on footer

On the master page i have put a triangle on the bottom as my footer and placed on top a pattern. When I look in master page I see that the pattern stretches across the entire page as I require however when I upload the page it appears only partially. Take a look at my site to see what I mean - www.ozzywizzpop.com
How can I rectify this?
Thanks,
Chris Kimber

Thanks for the response. I changed the name of the file and it is working properly.
Just curious to know which component of the server does this work of looking for URL pattern and forwarding the request to the appropriate Servlet. If you can explain i will be really elightened

Similar Messages

Problem with last column in footer - 11G

Hello,
I have a problem with displaying sum in footer for af:table .
The footer connected to attributeValues which defined in the pageDef.
I have 3 columns in the footer, the two first are shown fine, but last one is empty , althouh they are defined the same way.
Replacing the order of columns did not resolve the problem, because still the last column is not shown.
Any help will be appriciated.
pageDef:
<attributeValues id="BalancesDetailsViewSumCountUsed"
IterBinding="InitBvBalancesDetailsViewIterator">
<AttrNames>
<Item Value="SumCountUsed"/>
</AttrNames>
</attributeValues>
<attributeValues id="BalancesDetailsViewSumDifference" IterBinding="InitBvBalancesDetailsViewIterator">
<AttrNames>
<Item Value="SumDifference"/>
</AttrNames>
</attributeValues>
Jspx:
column c2 is fine , but c3 is empty
<af:column sortProperty="CountUsed" sortable="false" id="*c2*"
headerText="#{res['balances.countUsed']}" width="80px">
<af:outputText value="#{row.CountUsed}">
<f:convertNumber groupingUsed="false"
pattern="#{bindings.BalancesAMBalancesDetailsView.formats.CountUsed}"/>
</af:outputText>
<f:facet name="footer">
<af:outputText value="#{bindings.BalancesDetailsViewSumCountUsed.inputValue}">
<f:convertNumber groupingUsed="false"
pattern="#{bindings.BalancesDetailsViewSumCountUsed.format}"/>
</af:outputText>
</f:facet>
</af:column>
<af:column sortProperty="Difference" sortable="false" id="*c3*"
headerText="#{res['balances.difference']}" width="80px">
<af:outputText value="#{row.Difference}">
<f:convertNumber groupingUsed="false"
pattern="#{bindings.BalancesAMBalancesDetailsView.formats.Difference}"/>
</af:outputText>
*<f:facet name="footer">*
*<af:outputText value="#{bindings. BalancesDetailsViewSumDifference.inputValue}">*
*<f:convertNumber groupingUsed="false"*
*pattern="#{bindings. BalancesDetailsViewSumDifference.format}"/> </af:outputText>*
*</f:facet>*
</af:column>
Thanks!

Thanks you all!
I found the problem. The iterator which sum the coulmn was at the last after the second sum, so it return null.
So I replaced the hasNext() function with getAllRowsInRange() and now it is OK.

Problem with a pattern

I have a problem with a pattern.
I want to put a patter to validate an e-mail but i don´t find the way to do it

Hi Veloki,
You can drag and drop custom "email Adress" object from Custom Object Library. It includes the script for email validation in the validate event of email area.
// Validate the email address.
var r = new RegExp("^[a-z0-9_\\-\\.]+\\@[a-z0-9_\\-\\.]+\\.[a-z]{2,3}$"); // Create a new Regular Expression Object.
// Set the regular expression to look for an email address in general form.
var result = r.test(this.rawValue); // Test the rawValue of the current object to see
// if it fits the general form of an email address.
if (result == true) // If it fits the general form,
true; // all is well.
else // Otherwise,
false; // fail the validation.
Asiye

Problem with date pattern

Hi all,
I have a little maddening problem with oracle.jbo.domain.Date.
I have a viewObject with an attribute (fechaCompra) type Date and I need the time too so in controlHints I have defined:
format type: Simple Date
Format: yyyy-MM-dd 'at' hh:mm:ss
Right, on runTime now i see ok the data and in the inputDate appears the calendar and the hour .
But when I take the value of this attribute, to call a void that takes a oracle.jbo.domain.Date type, raises an error when parses the value of the atribute.
All this doesn't happen when in the view object the controlHints are defined like this:
format type: Simple Date
Format: yyyy-MM-dd
Any idea?
Thanks in advance,
Rowan

hello,
My guess would be that when you drop your formatted date into the methode the parse function is called from String to date, this work with no time attached.
But fails with the time attached. I would double check the specific class you pass to each method to be sure they are correct.
hat you mention parse gives an even bigger hint that you are using the parse function from oracle.jbo.domain.Date, which takes a string.
This function will fail with your custom patterns.
//get the value
String value = .....
//Not 100% sure if the at needs to be escaped or not
DateFormat sdf = new SimpleDateFormat("yyyy-MM-dd at hh:mm:ss");
//Prolly needs a try catch, writing this by hand
java.util.Date utilDate = sdf.parse(value);
java.sql.Date sqlDate = new java.sql.Date(utilDate.getTime());
oracle.jbo.domain.Date jboDate = new oracle.jbo.domain.Date(sqlDate);
//pass to your method-Anton

Design flaw in overloading? Problem with visitor pattern

I have been trying some implementations of the Visitor pattern in Java and have encountered a problem with overloaded methods in Java. It seems that the caller (client) of a overloaded method decides what implementation of that method is chosen. I find that strange from an OO / encapsulation point of view and it gets me into problems when using Visitor. This code shows my problem:
// a class with overloaded methods
public class OverLoadingTest {
     public void print(String s) {
          System.out.println("This looks like a String to me:");
          System.out.println("\"" + s + "\"");
     public void print(Object o) {
          System.out.println("This looks like an Object to me:");
          System.out.println("\"" + o + "\"");
//a client for that class
public class OverLoadingTestClient {
     public void test() {
          OverLoadingTest test = new OverLoadingTest();
          Object o1 = "String in an Object reference";
          String s1 = "String in a String reference";
          test.print(o1);
          test.print(s1);
     public static void main(String[] args) {
          new OverLoadingTestClient().test();
//And the output is:
This looks like an Object to me:
"String in an Object reference"
This looks like a String to me:
"String in a String reference"
//The output I would have expeced (wanted):
This looks like a String to me: //it is a String!
"String in an Object reference"
This looks like a String to me:
"String in a String reference"
Why is this? Is there a work around?

The specific method is decided on in compile time and by the client of that method, not the provider. I'd expect the client to just invoke the method and let the privider figure out what implementation to choose. Whatever the client thinks that he is providing as argument types.
I am implementing a slightly different version compared to http://ootips.org/visitor-pattern.html. I find implementing "v.visit(this);" for every subclass of the Visisted superclass strange. Why an abstract method "accept(Visitor v);" when all subclasses will iplement it in the same way ("v.visit(this);")?
Daan

Problems with Factory pattern

Sorry... I know this topic has been done to death but I still have some questions.
In my development, I keep encountering a recurring problem that I believe should be solved by the 'factory pattern'. (Note: I'm not a patterns nut so I am only guessing about the correct pattern).
Here is the problem:
I develop an abstract base class. I extend the base class with several subclasses. Exterior objects use the instances via a base class reference and I don't want to them to have to know which is the correct subclass or how to create the instance.
My solution is to make a create(param, param,...) method in the base class and using the param(s) construct the instance something like:static Foo create(int type)
Foo instance = null;
String className = "com.myco.foos.DefaultFoo";
if(CONST_A == type)
className = "com.myco.foos.FooA";
else if(CONST_B == type)
className = "com.myco.foos.FooB";
{on and on...}
{using reflection create a new instance from the className String}
return instance;
}The obvious problem with the create() method is that it becomes a maintenence point and I don't like the idea of a base class knowing about subclasses.
Anyone know better a solution? Comments?
Thanks in advance.

Yes, that is the Factory pattern you describe. The client programs are going to call your createFoo() method and get back an instance of a subclass of Foo. Typically this pattern is used where there is some external entity that determines what subclass will be returned -- for example a system property -- and the client programs call createFoo() with no arguments. In this case reflection is used to create the instance, and your base class does not need to know anything about any subclasses.
However, if your client programs can influence the choice of subclass, then they will have to pass some kind of parameter into createFoo(). At this point, createFoo() requires some decision logic that says "create this, or that, depending on the input parameter". And if that parameter is simply a code that enables the client programs to say "Give me a ChocolateFoo instance", then returning "new ChocolateFoo()" is the most straightforward design. But in this case, why can't the client program do that?
If you don't like the base class having to know about subclasses (and you shouldn't be happy if it does), then you could have a helper class -- FooFactory -- that contains only the static method createFoo(). This class would know about Foo, and about any of its subclasses that it can produce instances of. It's still a maintenance point, no avoiding that, but at least it is off by itself somewhere.

Problem with phonenumber pattern

Hello,
I've got a problem with my display and validation pattern for my phone numbers.
In Holland we have two sorts of phone numbers:
Always 10 numbers, but some regions have a 3 digit area code,
other regions a 4 digit area code.
Example:
012-3456789
0123-456789
This is also the way I want my users to enter the data.
I want to display them as followed:
012-3456789 --> 012 - 345 67 89
0123-456789 --> 0123 - 456 789
My display pattern right now is: text{999 - 999 99 99}|text{9999 - 999 999}
My edit pattern is: text{999-9999999}|text{9999-999999}
My validation pattern is: text{999-9999999}|text{9999-999999}
(With a pop-up message to fill in 10 numbers, area code seperated from the rest by a dash, as in the example)
The problem is that the validation works fine, but it always transforms the phonenumber to the first option (999 - 999 99 99).
How can I fix this?
Greetings and thanks in advance,
Sterre

Hi Veloki,
You can drag and drop custom "email Adress" object from Custom Object Library. It includes the script for email validation in the validate event of email area.
// Validate the email address.
var r = new RegExp("^[a-z0-9_\\-\\.]+\\@[a-z0-9_\\-\\.]+\\.[a-z]{2,3}$"); // Create a new Regular Expression Object.
// Set the regular expression to look for an email address in general form.
var result = r.test(this.rawValue); // Test the rawValue of the current object to see
// if it fits the general form of an email address.
if (result == true) // If it fits the general form,
true; // all is well.
else // Otherwise,
false; // fail the validation.
Asiye

Problems with calculation in table footer

I’m working on a 'dynamic form’ with an expandable table (i.e. the user presses a button to add a new row), there are cells in each row for beginning month & ending month, plus an autocalc total field containing the formula: “ending – beginning +1” (which accurately calculates total months e.g. Jan-Dec = 12 months). There is also a ‘total months’ field in the footer which sums the row ‘total’ cells. The problem I have is that the user could add a blank row throwing off the total cell in the footer. Any suggestions to accomplish my goal of presenting accurate total in footer while ‘idiot proofing’ the form?

A link to the your live test page would be much more productive here.
It's much easier for us to diagnose problems when we can see your page & images in our browsers.
Nancy O.
Alt-Web Design & Publishing
Web | Graphics | Print | Media Specialists
http://alt-web.com/
http://twitter.com/altweb

Having problem with extra space below footer (sticky footer already checked)

Hi there, im having this problem after updated my adobe muse cc. For some reason there is extra space below the footer.
It looks fine when i try to view them offline, but when I upload them, the extra space appears. Here's the url for both of the website with extra space below
1. http://unionvisual.web.id/home-page.html
2. PT-Smas

Hi there
Thx for your reply, is here i upload my screenshot
and here

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To make sure that this is not software related, set it back to factory settings, without using a backup afterwards, described in this article:
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Repair and replacement costs depend on your iPhone model and your AppleCare product coverage. Apple will run a diagnostic test to determine whether your iPhone has experienced additional damage. If it has, or if it needs other repairs, you may need to pay an out-of-warranty service fee. Accidental damage isn't covered under the Apple One Year Limited Warranty.
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Problem with "stretching" when using report generation vi's to print fron panel.

I am using LabVIEW 6.0.1 and when I use the "Append Front Panel Image to Report" vi to print my fron panel, the result is an elongated (stretched)version of my front panel that runs off the page and doesn't show some of the content. Does anyone know why this happens?

Hello,
I have never heard of this problem before. My first suggestion for you is to install the LabVIEW 6.0.2 update, as there were some fixes included in this update regarding printing from LabVIEW. Also, have you tried printing the report to a different printer, to see if the problem is inherent to the subVI or inherent to your printer?
If you are continuing to have any problems, please let me know, and if possible, attach an example VI to your reply that demonstrates the behavior so I can reproduce it.
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Problem with fill pattern in oracle reports 11g

Hi all,
regardless of the fill pattern we use, on paper lines with a fill pattern appear completely black
no longer using a fill pattern is not an option as we have > 200 reports (migrated from 6i) that use them
running such a report from the builder choosing paper layout does show the report output correctly on our development PCs
development PC OS : XP
WLS 10.3.3 (32 bit)
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server : Win 2008 64 bit
WLS 10.3.3 (64 bit)
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Martin

anyone ?

ASAP PLZ- Having problems with basic pattern input/output

Hey! I am new to this forum, and I am also new to java =).
I am writing a program that prompts a user to select 1 pattern out of 5. then the user needs to choose the number of lines he/she wants to display for instace:
(MENU)
PATTERN 5
1
12
123
1234
USER Selection : Pattern 5
Choose Number of Lines: 3
OUTPUT
Pattern 5
1
12
123
I have a basic code for a pyramid that deals with leading spaces etc.. but I don't have a clue how to use that method with my program
MY PROGRAM:
//Purpose:     Displaying Patterns
//Input:          User's selection
//Output:     Messages
//Author;     Fares
//Program:     4
//Date:          9/15/2009
import java.util.Scanner;
public class MyPatterns4{
public static void main(String[] args) {
// Declarations
Scanner scan = new Scanner(System.in);
     String outputString;
     int option = 1;
     int lines;
     // Paterns
     String patternOne;
     patternOne = "\n\t Pattern I \n\t 1 \n\t 12 \n\t 123 \n\t 1234 \n\t 12345 \n\t 123456";
     String patternTwo;
     patternTwo= "\n\t Pattern II \n\t 123456 \n\t 12345 \n\t 1234 \n\t 123 \n\t 12 \n\t 1";
     String patternThree;
     patternThree = "\n\t Pattern III \n\t 1 \n\t 21 \n\t 321 \n\t 4321 \n\t 54321 \n\t 654321";
     String patternFour;
     patternFour = "\n\t Pattern IV \n\t 123456 \n\t 12345 \n\t 1234 \n\t 123 \n\t 12 \n\t 1";
     String patternFive;
     patternFive = "\n\t Pattern V \n\t 1 \n\t 12 \n\t 123 \n\t 123456 \n\t 123 \n\t 12";
     // Prompt the user to select a pattern
     outputString = "------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t" +
"3 Display Pattern III\n\t4 Display Pattern IV\n\t" +
          "5 Display Pattern V\n\t" + "6 Display All Patterns\n\n\n\t" + "0 Quit\n\n\n";
     System.out.println(outputString);
     System.out.print("\tEnter your selection: ");
     option = scan.nextInt();
     // Keep reading data until the user enters 0
     while (option !=0){
               while (option == 6) {
               outputString = "\nChoose another selections!\n";
                                   System.out.println(patternOne);
                                   System.out.println(patternTwo);
                                   System.out.println(patternThree);
                                   System.out.println(patternFour);
                                   System.out.println(patternFive);
                                   System.out.println(outputString);
          outputString = "--------------------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t" +
"3 Display Pattern III\n\t4 Display Pattern IV\n\t" +
          "5 Display Pattern V\n\t" + "6 Display All Patterns\n\n\n\t" + "0 Quit\n\n\n";
          System.out.println(outputString);
          System.out.print("\tEnter your selection: ");
          option = scan.nextInt();
while (option != 0 && option !=6) {
               System.out.print("\tEnter number of lines: ");
               lines = scan.nextInt();
               if (lines < 1 || lines > 6) {
System.out.println("\tYou must enter a number from 1 to 6");
          System.out.print("\tEnter number of lines: ");
               lines = scan.nextInt();
          while (lines < 1 || lines > 6) {
System.out.println("\tYou must enter a number from 1 to 6. The program will now end.");
System.exit(0);}
               switch (option) {
                    case 1: // write the code to display Pattern I here
                                   outputString = "\n Choose another selection! \n";
                                   System.out.println(patternOne);
                                   System.out.println(outputString);
                                   break;
                    case 2:      // write the code to display Pattern II here
                                   outputString = "\nChoose another selection!\n";
                                   System.out.println(patternTwo);
                                   System.out.println(outputString);
                                   break;
                    case 3:     // write the code to display Pattern III here
                                   outputString = "\nChoose another selection!\n";
                                   System.out.println(patternThree);
                                   System.out.println(outputString);
                                   break;
                    case 4:      // write the code to display Pattern IV here
                                   outputString = "\nChoose another selection!\n";
                                   System.out.println(patternFour);
                                   System.out.println(outputString);
                                   break;
                    case 5:      // write the code to display Pattern V here
                                   outputString = "\nChoose another selection!\n";
                                   System.out.println(patternFive);
                                   System.out.println(outputString);
                                   break;
                    case 6: // the code to display all paterns
                                   outputString = "\nChoose another selections!\n";
                                   System.out.println(patternOne);
                                   System.out.println(patternTwo);
                                   System.out.println(patternThree);
                                   System.out.println(patternFour);
                                   System.out.println(patternFive);
                                   System.out.println(outputString);
                                   break;
                    default: outputString = "\nInvalid Selection\n";
                                   System.out.println(outputString);
                                   break;
               }// end of switch
          outputString = "------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t" +
"3 Display Pattern III\n\t4 Display Pattern IV\n\t" +
          "5 Display Pattern V\n\t" + "6 Display All Patterns\n\n\n\t" + "0 Quit\n\n\n";
          System.out.println(outputString);
          System.out.print("\tEnter your selection: ");
          option = scan.nextInt();
} }// end of while loop
}// end of main method
}// end of class

//Purpose: Displaying Patterns
//Input: User's selection
//Output: Messages
//Author; Fares
//Program: 4
//Date: 9/15/2009
import java.util.Scanner;
public class MyPatterns4{
public static void main(String[] args) {
// Declarations
Scanner scan = new Scanner(System.in);
String outputString;
int option = 1;
int lines;
// Paterns
String patternOne;
patternOne = "\n\t Pattern I \n\t 1 \n\t 12 \n\t 123 \n\t 1234 \n\t 12345 \n\t 123456";
String patternTwo;
patternTwo= "\n\t Pattern II \n\t 123456 \n\t 12345 \n\t 1234 \n\t 123 \n\t 12 \n\t 1";
String patternThree;
patternThree = "\n\t Pattern III \n\t 1 \n\t 21 \n\t 321 \n\t 4321 \n\t 54321 \n\t 654321";
String patternFour;
patternFour = "\n\t Pattern IV \n\t 123456 \n\t 12345 \n\t 1234 \n\t 123 \n\t 12 \n\t 1";
String patternFive;
patternFive = "\n\t Pattern V \n\t 1 \n\t 12 \n\t 123 \n\t 123456 \n\t 123 \n\t 12";
// Prompt the user to select a pattern
outputString = "------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t"
"3 Display Pattern III\n\t4 Display Pattern IV\n\t"
"5 Display Pattern V\n\t" "6 Display All Patterns\n\n\n\t" "0 Quit\n\n\n";
System.out.println(outputString);
System.out.print("\tEnter your selection: ");
option = scan.nextInt();
// Keep reading data until the user enters 0
while (option !=0){
while (option == 6) {
outputString = "\nChoose another selections!\n";
System.out.println(patternOne);
System.out.println(patternTwo);
System.out.println(patternThree);
System.out.println(patternFour);
System.out.println(patternFive);
System.out.println(outputString);
outputString = "--------------------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t"
"3 Display Pattern III\n\t4 Display Pattern IV\n\t"
"5 Display Pattern V\n\t" "6 Display All Patterns\n\n\n\t" "0 Quit\n\n\n";
System.out.println(outputString);
System.out.print("\tEnter your selection: ");
option = scan.nextInt();
while (option != 0 && option !=6) {
System.out.print("\tEnter number of lines: ");
lines = scan.nextInt();
if (lines < 1 || lines > 6) {
System.out.println("\tYou must enter a number from 1 to 6");
System.out.print("\tEnter number of lines: ");
lines = scan.nextInt();
while (lines < 1 || lines > 6) {
System.out.println("\tYou must enter a number from 1 to 6. The program will now end.");
System.exit(0);}
switch (option) {
case 1: // write the code to display Pattern I here
outputString = "\n Choose another selection! \n";
System.out.println(patternOne);
System.out.println(outputString);
break;
case 2: // write the code to display Pattern II here
outputString = "\nChoose another selection!\n";
System.out.println(patternTwo);
System.out.println(outputString);
break;
case 3: // write the code to display Pattern III here
outputString = "\nChoose another selection!\n";
System.out.println(patternThree);
System.out.println(outputString);
break;
case 4: // write the code to display Pattern IV here
outputString = "\nChoose another selection!\n";
System.out.println(patternFour);
System.out.println(outputString);
break;
case 5: // write the code to display Pattern V here
outputString = "\nChoose another selection!\n";
System.out.println(patternFive);
System.out.println(outputString);
break;
case 6: // the code to display all paterns
outputString = "\nChoose another selections!\n";
System.out.println(patternOne);
System.out.println(patternTwo);
System.out.println(patternThree);
System.out.println(patternFour);
System.out.println(patternFive);
System.out.println(outputString);
break;
default: outputString = "\nInvalid Selection\n";
System.out.println(outputString);
break;
}// end of switch
outputString = "------------------------------------\n\t1 Display Pattern I\n\t2 Display Pattern II\n\t"
"3 Display Pattern III\n\t4 Display Pattern IV\n\t"
"5 Display Pattern V\n\t" "6 Display All Patterns\n\n\n\t" "0 Quit\n\n\n";
System.out.println(outputString);
System.out.print("\tEnter your selection: ");
option = scan.nextInt();
} }// end of while loop
}// end of main method
}// end of class

Color problem with telephone number in footer.

In the footer of my web page I entered a phone number and set the color. On the desktop the color is perfect but when you view it in a mobile device it changes the color to white. I am using Dreamweaver CS6 any help would be appreciated. Thx Rick

You can disable this feature for Apple devices by using
<meta name="format-detection" content="telephone=no">
You could also apply a span with a class around the phone number and then target that in the CSS - Apple devices make it a link so it would be something like the below:
<span class="iOS">01 234 567 8910</span>
.iOS a { /* styles here */ }
Or you could make it a link yourself by using the tel attribute:
<a href="tel:+112345678910">01 234 567 8910</a>
a[href^="tel:"] { /* styles here */ }

Funny problem with schema pattern regular expression

I have following element in my schema:
<xsd:element name="lD">
     <xsd:simpleType>
          <xsd:restriction base="xsd:string">
               <xsd:pattern value="\d{5,8}" />
          </xsd:restriction>
     </xsd:simpleType>
</xsd:element>then in the XML, I have:
<ID>
123456789
</ID>funny thing is the schema validates the value successfully. seems the upper bound of 8 the in the regular expression does not have any effect. however, 1234 would fail.
i looked up the schema prime on W3C, it specifies that {n,m} means at least n and at most m.
any idea anyone?
I have using Xerces 1.4.4.
Thanks

I tried the example you mentioned and it seemed to
work for me. It validated both the upper bound and
the lower bound. Looking at the Manifest file in
xerces jar, it looks like I have version 2.5.0yes, I know. Xerces 2 works, but Xerces 1 has the above problem. If you get Xerces 1.4.4 from xml.apache.org, you will see the problem.
I can not use Xerces 2 in our production environment yet.

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