Problem with XMLTABLE and LEFT OUTER JOIN

Hi all.
I have one problem with XMLTABLE and LEFT OUTER JOIN, in 11g it returns correct result but in 10g it doesn't, it is trated as INNER JOIN.
SELECT * FROM v$version;
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
PL/SQL Release 11.2.0.1.0 - Production
"CORE     11.2.0.1.0     Production"
TNS for Linux: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production
--test for 11g
CREATE TABLE XML_TEST(
     ID NUMBER(2,0),
     XML XMLTYPE
INSERT INTO XML_TEST
VALUES
     1,
     XMLTYPE
          <msg>
               <data>
                    <fields>
                         <id>g1</id>
                         <dat>data1</dat>
                    </fields>
               </data>
          </msg>
INSERT INTO XML_TEST
VALUES
     2,
     XMLTYPE
          <msg>
               <data>
                    <fields>
                         <id>g2</id>
                         <dat>data2</dat>
                    </fields>
               </data>
          </msg>
INSERT INTO XML_TEST
VALUES
     3,
     XMLTYPE
          <msg>
               <data>
                    <fields>
                         <id>g3</id>
                         <dat>data3</dat>
                    </fields>
                    <fields>
                         <id>g4</id>
                         <dat>data4</dat>
                    </fields>
                    <fields>
                         <dat>data5</dat>
                    </fields>
               </data>
          </msg>
SELECT
     t.id,
     x.dat,
     y.seqno,
     y.id_real
FROM
     xml_test t,
     XMLTABLE
          '/msg/data/fields'
          passing t.xml
          columns
               dat VARCHAR2(10) path 'dat',
               id XMLTYPE path 'id'
     )x LEFT OUTER JOIN
     XMLTABLE
          'id'
          passing x.id
          columns
               seqno FOR ORDINALITY,
               id_real VARCHAR2(30) PATH '.'
     )y ON 1=1
ID     DAT     SEQNO     ID_REAL
1     data1     1     g1
2     data2     1     g2
3     data3     1     g3
3     data4     1     g4
3     data5          Here's everything fine, now the problem:
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
PL/SQL Release 10.2.0.1.0 - Production
"CORE     10.2.0.1.0     Production"
TNS for HPUX: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - Production
--exactly the same environment as 11g (tables and rows)
SELECT
     t.id,
     x.dat,
     y.seqno,
     y.id_real
FROM
     xml_test t,
     XMLTABLE
          '/msg/data/fields'
          passing t.xml
          columns
               dat VARCHAR2(10) path 'dat',
               id XMLTYPE path 'id'
     )x LEFT OUTER JOIN
     XMLTABLE
          'id'
          passing x.id
          columns
               seqno FOR ORDINALITY,
               id_real VARCHAR2(30) PATH '.'
     )y ON 1=1
ID     DAT     SEQNO     ID_REAL
1     data1     1     g1
2     data2     1     g2
3     data3     1     g3
3     data4     1     g4As you can see in 10g I don't have the last row, it seems that Oracle 10g doesn't recognize the LEFT OUTER JOIN.
Is this a bug?, Metalink says that sometimes we can have an ORA-0600 but in this case there is no error returned, just incorrect results.
Please help.
Regards.

Hi A_Non.
Thanks a lot, I tried with this:
SELECT
     t.id,
     x.dat,
     y.seqno,
     y.id_real
FROM
     xml_test t,
     XMLTABLE
          '/msg/data/fields'
          passing t.xml
          columns
               dat VARCHAR2(10) path 'dat',
               id XMLTYPE path 'id'
     )x,
     XMLTABLE
          'id'
          passing x.id
          columns
               seqno FOR ORDINALITY,
               id_real VARCHAR2(30) PATH '.'
     )(+) y ;And is giving me the complete output.
Thanks again.
Regards.

Similar Messages

  • Difference between merge-Not matched and left outer join

    Why should Merge-Not Matched be used instead of left outer join? I believe both will enable comparison of 2 tables. So what is the difference. Please advice.
    mayooran99

    MERGE is way to encapsulate all conditions within single statement
    The equivalent implementation using join would require three different statements 
    1 UPDATE using INNER JOIN
    1 INSERT using LEFT JOIN
    and 1 DELETE using LEFT JOIN in reverse order
    Both approaches work fine
    so all that you need to do is left join operation to find difference you can use either
    But MERGE has one additional advantage in case you need to get output from MERGE and use it for further manipulation like further insert to child table
    I've explained it here
    http://visakhm.blogspot.in/2014/09/t-sql-tips-multifaceted-merge-statement.html
    Please Mark This As Answer if it solved your issue
    Please Vote This As Helpful if it helps to solve your issue
    Visakh
    My Wiki User Page
    My MSDN Page
    My Personal Blog
    My Facebook Page

  • Performance problems with XMLTABLE and XMLQUERY involving relational data

    Hello-
    Is anyone out there using XMLTABLE or XMLQUERY with more than a toy set of data? I am running into serious performance problems tyring to do basic things such as:
    * Combine records in 10 relational tables into a single table of XMLTYPE records using XMLTABLE. This hangs indefinitely for any more than 800 records. Oracle has confirmed that this is a problem and is working on a fix.
    * Combine a single XMLTYPE record with several relational code tables into a single XMLTYPE record using XMLQUERY and ora:view() to insert code descriptions after each code. Performance is 10 seconds for 10 records (terrible) passing a batch of records , or 160 seconds for one record (unacceptable!). How can it take 10 times longer to process 1/10th the number of records? Ironically, the query plan says it will do a full table scan of records for the batch, but an index access for the one record passed to the XMLQUERY.
    I am rapidly losing faith in XML DB, and desparately need some hints on how to work around these performance problems, or at least some assurance that others have been able to get this thing to perform.

    <Note>Long post, sorry.</Note>
    First, thanks for the responses above. I'm impressed with the quality of thought put into them. (Do the forum rules allow me to offer rewards? :) One suggestion in particular made a big performance improvement, and I’m encouraged to hear of good performance in pure XML situations. Unfortunately, I think there is a real performance challenge in two use cases that are pertinent to the XML+relational subject of this post and probably increasingly common as XML DB usage increases:
    •     Converting legacy tabular data into XML records; and
    •     Performing code table lookups for coded values in XML records.
    There are three things I want to accomplish with this post:
    •     Clarify what we are trying to accomplish, which might expose completely different approaches than I have tried
    •     Let you know what I tried so far and the rationale for my approach to help expose flaws in my thinking and share what I have learned
    •     Highlight remaining performance issues in hopes that we can solve them
    What we are trying to accomplish:
    •     Receive a monthly feed of 10,000 XML records (batched together in text files), each containing information about an employee, including elements that repeat for every year of service. We may need to process an annual feed of 1,000,000 XML records in the future.
    •     Receive a one-time feed of 500,000 employee records stored in about 10 relational tables, with a maximum join depth of 2 or 3. This is inherently a relational-to-XML process. One record/second is minimally acceptable, but 10 records/sec would be better.
    •     Consolidate a few records (from different providers) for each employee into a single record. Given the data volume, we need to achieve a minimum rate of 10 records per second. This may be an XML-only process, or XML+relational if code lookups are done during consolidation.
    •     Allow the records to be viewed and edited, with codes resolved into user-friendly descriptions. Since a user is sitting there, code lookups done when a record is viewed (vs. during consolidation) should not take more than 3 seconds total. We have about 20 code tables averaging a few hundred rows each, though one has 450,000 rows.
    As requested earlier, I have included code at the end of this post for example tables and queries that accurately (but simply) replicate our real system.
    Why we did and why:
    •     Stored the source XML records as CLOBS: We did this to preserve the records exactly as they were certified and sent from providers. In addition, we always access the entire XML record as a whole (e.g., when viewing a record or consolidating employee records), so this storage model seemed like a good fit. We can copy them into another format if necessary.
    •     Stored the consolidated XML employee records as “binary XML”. We did this because we almost always access a single, entire record as a whole (for view/edit), but might want to create some summary statistics at some point. Binary XML seemed the best fit.
    •     Used ora:view() for both tabular source records and lookup tables. We are not aware of any alternatives at this time. If it made sense, most code tables could be pre-converted into XML documents, but this seemed risky from a performance standpoint because the lookups use both code and date range constraints (the meaning of codes changes over time).
    •     Stored records as XMLTYPE columns in a table with other key columns on the table, plus an XMLTYPE metadata column. We thought this would facilitate pulling a single record (or a few records for a given employee) quickly. We knew this might be unnecessary given XML indexes and virtual columns, but were not experienced with those and wanted the comfort of traditional keys. We did not used XMLTYPE tables or the XML Repository for documents.
    •     Used XMLTABLE to consolidate XML records by looping over each distinct employee ID in the source batch. We also tried XMLQUERY and it seems to perform about the same. We can achieve 10 to 20 records/second if we do not do any code lookups during consolidation, just meeting our performance requirement, but still much slower than expected.
    •     Used PL/SQL with XMLFOREST to convert tabular source records to XML by looping over distinct employee IDs. We tried this outside PL/SQL both with XMLFOREST and XMLTABLE+ora:view(), but it hangs in both cases for more than 800 records (a known/open issue). We were able to get it to work by using an explicit cursor to loop over distinct employee IDs (rather than processing all records at once within the query). The performance is one record/second, which is minimally acceptable and interferes with other database activity.
    •     Used XMLQUERY plus ora:view() plus XPATH constraints to perform code lookups. When passing a single employee record, the response time ranges from 1 sec to 160 sec depending on the length of the record (i.e., number of years of service). We achieved a 5-fold speedup using an XMLINDEX (thank you Marco!!). The result may be minimally acceptable, but I’m baffled why the index would be needed when processing a single XML record. Other things we tried: joining code tables in the FOR...WHERE clauses, joining code tables using LET with XPATH constraints and LET with WHERE clause constraints, and looking up codes individually via JDBC from the application code at presentation time. All those approaches were slower. Note: the difference I mentioned above in equality/inequality constraint performance was due to data record variations not query plan variations.
    What issues remain?
    We have a minimally acceptable solution from a performance standpoint with one very awkward PL/SQL workaround. The performance of a mixed XML+relational data query is still marginal IMHO, until we properly utilize available optimizations, fix known problems, and perhaps get some new query optimizations. On the last point, I think the query plan for tabular lookups of codes in XML records is falling short right now. I’m reminded of data warehousing in the days before hash joins and star join optimization. I would be happy to be wrong, and just as happy for viable workarounds if I am right!
    Here are the details on our code lookup challenge. Additional suggestions would be greatly appreciated. I’ll try to post more detail on the legacy table conversion challenge later.
    -- The main record table:
    create table RECORDS (
    SSN varchar2(20),
    XMLREC sys.xmltype
    xmltype column XMLREC store as binary xml;
    create index records_ssn on records(ssn);
    -- A dozen code tables represented by one like this:
    create table CODES (
    CODE varchar2(4),
    DESCRIPTION varchar2(500)
    create index codes_code on codes(code);
    -- Some XML records with coded values (the real records are much more complex of course):
    -- I think this took about a minute or two
    DECLARE
    ssn varchar2(20);
    xmlrec xmltype;
    i integer;
    BEGIN
    xmlrec := xmltype('<?xml version="1.0"?>
    <Root>
    <Id>123456789</Id>
    <Element>
    <Subelement1><Code>11</Code></Subelement1>
    <Subelement2><Code>21</Code></Subelement2>
    <Subelement3><Code>31</Code></Subelement3>
    </Element>
    <Element>
    <Subelement1><Code>11</Code></Subelement1>
    <Subelement2><Code>21</Code></Subelement2>
    <Subelement3><Code>31</Code></Subelement3>
    </Element>
    <Element>
    <Subelement1><Code>11</Code></Subelement1>
    <Subelement2><Code>21</Code></Subelement2>
    <Subelement3><Code>31</Code></Subelement3>
    </Element>
    </Root>
    for i IN 1..100000 loop
    insert into records(ssn, xmlrec) values (i, xmlrec);
    end loop;
    commit;
    END;
    -- Some code data like this (ignoring date ranges on codes):
    DECLARE
    description varchar2(100);
    i integer;
    BEGIN
    description := 'This is the code description ';
    for i IN 1..3000 loop
    insert into codes(code, description) values (to_char(i), description);
    end loop;
    commit;
    end;
    -- Retrieve one record while performing code lookups. Takes about 5-6 seconds...pretty slow.
    -- Each additional lookup (times 3 repeating elements in the data) adds about 1 second.
    -- A typical real record has 5 Elements and 20 Subelements, meaning more than 20 seconds to display the record
    -- Note we are accessing a single XML record based on SSN
    -- Note also we are reusing the one test code table multiple times for convenience of this test
    select xmlquery('
    for $r in Root
    return
    <Root>
    <Id>123456789</Id>
    {for $e in $r/Element
        return
        <Element>
          <Subelement1>
            {$e/Subelement1/Code}
    <Description>
    {ora:view("disaac","codes")/ROW[CODE=$e/Subelement1/Code]/DESCRIPTION/text() }
    </Description>
    </Subelement1>
    <Subelement2>
    {$e/Subelement2/Code}
    <Description>
    {ora:view("disaac","codes")/ROW[CODE=$e/Subelement2/Code]/DESCRIPTION/text()}
    </Description>
    </Subelement2>
    <Subelement3>
    {$e/Subelement3/Code}
    <Description>
    {ora:view("disaac","codes")/ROW[CODE=$e/Subelement3/Code]/DESCRIPTION/text() }
    </Description>
    </Subelement3>
    </Element>
    </Root>
    ' passing xmlrec returning content)
    from records
    where ssn = '10000';
    The plan shows the nested loop access that slows things down.
    By contrast, a functionally-similar SQL query on relational data will use a hash join and perform 10x to 100x faster, even for a single record. There seems to be no way for the optimizer to see the regularity in the XML structure and perform a corresponding optimization in joining the code tables. Not sure if registering a schema would help. Using structured storage probably would. But should that be necessary given we’re working with a single record?
    Operation Object
    |SELECT STATEMENT ()
    | SORT (AGGREGATE)
    | NESTED LOOPS (SEMI)
    | TABLE ACCESS (FULL) CODES
    | XPATH EVALUATION ()
    | SORT (AGGREGATE)
    | NESTED LOOPS (SEMI)
    | TABLE ACCESS (FULL) CODES
    | XPATH EVALUATION ()
    | SORT (AGGREGATE)
    | NESTED LOOPS (SEMI)
    | TABLE ACCESS (FULL) CODES
    | XPATH EVALUATION ()
    | SORT (AGGREGATE)
    | XPATH EVALUATION ()
    | SORT (AGGREGATE)
    | XPATH EVALUATION ()
    | TABLE ACCESS (BY INDEX ROWID) RECORDS
    | INDEX (RANGE SCAN) RECORDS_SSN
    With an xmlindex, the same query above runs in about 1 second, so is about 5x faster (0.2 sec/lookup), which is almost good enough. Is this the answer? Or is there a better way? I’m not sure why the optimizer wants to scan the code tables and index into the (one) XML record, rather than the other way around, but maybe that makes sense if the optimizer wants to use the same general plan as when the WHERE clause constraint is relaxed to multiple records.
    -- Add an xmlindex. Takes about 2.5 minutes
    create index records_record_xml ON records(xmlrec)
    indextype IS xdb.xmlindex;
    Operation Object
    |SELECT STATEMENT ()
    | SORT (GROUP BY)
    | FILTER ()
    | NESTED LOOPS ()
    | FAST DUAL ()
    | TABLE ACCESS (BY INDEX ROWID) SYS113473_RECORDS_R_PATH_TABLE
    | INDEX (RANGE SCAN) SYS113473_RECORDS_R_PATHID_IX
    | SORT (AGGREGATE)
    | FILTER ()
    | TABLE ACCESS (FULL) CODES
    | FILTER ()
    | NESTED LOOPS ()
    | FAST DUAL ()
    | TABLE ACCESS (BY INDEX ROWID) SYS113473_RECORDS_R_PATH_TABLE
    | INDEX (RANGE SCAN) SYS113473_RECORDS_R_PATHID_IX
    | SORT (GROUP BY)
    | FILTER ()
    | NESTED LOOPS ()
    | FAST DUAL ()
    | TABLE ACCESS (BY INDEX ROWID) SYS113473_RECORDS_R_PATH_TABLE
    | INDEX (RANGE SCAN) SYS113473_RECORDS_R_PATHID_IX
    | SORT (AGGREGATE)
    | FILTER ()
    | TABLE ACCESS (FULL) CODES
    | FILTER ()
    | NESTED LOOPS ()
    | FAST DUAL ()
    | TABLE ACCESS (BY INDEX ROWID) SYS113473_RECORDS_R_PATH_TABLE
    | INDEX (RANGE SCAN) SYS113473_RECORDS_R_PATHID_IX
    | SORT (GROUP BY)
    | FILTER ()
    | NESTED LOOPS ()
    | FAST DUAL ()
    | TABLE ACCESS (BY INDEX ROWID) SYS113473_RECORDS_R_PATH_TABLE
    | INDEX (RANGE SCAN) SYS113473_RECORDS_R_PATHID_IX
    | SORT (AGGREGATE)
    | FILTER ()
    | TABLE ACCESS (FULL) CODES
    | FILTER ()
    | NESTED LOOPS ()
    | FAST DUAL ()
    | TABLE ACCESS (BY INDEX ROWID) SYS113473_RECORDS_R_PATH_TABLE
    | INDEX (RANGE SCAN) SYS113473_RECORDS_R_PATHID_IX
    | SORT (AGGREGATE)
    | FILTER ()
    | NESTED LOOPS ()
    | FAST DUAL ()
    | TABLE ACCESS (BY INDEX ROWID) SYS113473_RECORDS_R_PATH_TABLE
    | INDEX (RANGE SCAN) SYS113473_RECORDS_R_PATHID_IX
    | SORT (AGGREGATE)
    | TABLE ACCESS (BY INDEX ROWID) SYS113473_RECORDS_R_PATH_TABLE
    | INDEX (RANGE SCAN) SYS113473_RECORDS_R_PATHID_IX
    | TABLE ACCESS (BY INDEX ROWID) RECORDS
    | INDEX (RANGE SCAN) RECORDS_SSN
    Am I on the right path, or am I totally using the wrong approach? I thought about using XSLT but was unsure how to reference the code tables.
    I’ve done the best I can constraining the main record to a single row passed to the XMLQUERY. Given Mark’s post (thanks!) should I be joining and constraining the code tables in the SQL WHERE clause too? That’s going to make the query much more complicated, but right now we’re more concerned about performance than complexity.

  • Left Outer Join Help...

    Hi Everyone,
    I am still in the process of learning SQL, and I am having trouble specifically with the the left outer join.  I normally join tables using equijoin's, but I am not getting the right data set returns, and thought the using a left or right outer join would resolve the problem...
    Here is my SQL that is working properly with 1 left outer join.  I am building the query slowly so in the next SQL you will see where I am seeing the error.  I don't expect you to understand the data and columns I am trying to join, I believe the problems I am experiencing are related to syntax, and I am hoping you can find where my syntax errors are.
    select
      s.name as "Screen Name",
      sv.view_name as "View Name",
      s_view.name
    from
      s_screen s,
      s_screen_view sv
      left outer join s_view
      ON (sv.view_name = s_view.name)
    where
      sv.screen_id = '1-866A-1X3LU' and
      s.row_id = sv.screen_id and
      s.repository_id = '1-866A-1' and
      s_view.repository_id = '1-866A-1';
    Here is the SQL where I am experiencing the following error...
    Error:
    ORA-00904: "SV"."VIEW_NAME": invalid identifier
    00904. 00000 -  "%s: invalid identifier"
    *Cause:   
    *Action:
    Error at Line: 14 Column: 7
    Problematic SQL:
    select
      s.name as "Screen Name",
      sv.view_name as "View Name",
      s_view.name,
      s_applet.name as Applet
      --a.name as "Applet Name"
    from
      s_screen s,
      s_screen_view sv,
      s_view_wtmpl_it wti
      left outer join s_view
      ON (sv.view_name = s_view.name)
      left outer join s_applet
      ON (wti.name = s_applet.name)
    where
      sv.screen_id = '1-866A-1X3LU' and
      s.row_id = sv.screen_id and
      s.repository_id = '1-866A-1' and
      s_view.repository_id = '1-866A-1';
    Thanks in advance for your help.
    Chris

    Hi,
    cjpicc11 wrote:
    What is an Oracle style join vs. ANSI join?
    Would this be Oracle Style or ANSI Join?
      left outer join s_view
      ON (sv.view_name = s_view.name)
      left outer join s_applet
    Would this be Oracle Style or ANSI Join?
    s.row_id = sv.screen_id
    "Oracle style" or "old style" joins have commas between tables in the FROM clause, and the join conditions are all in the WHERE clause.  They do not use the keywords JOIN or ON.
    ANSI style joins have the keyword JOIN between tables (sometimes accompanied by other keywords, such as LEFT, OUTER or CROSS), and the join conditions are given in the FROM clause, usually after the keyword ON.
    The first example you gave is an ANSI style join.  It has the JOIN keyword, not a comma, between tables.
    The second example you gave:
    s.row_id = sv.screen_id
    could be part of either.  It could occur in an ANSI join (in the FROM clause, after the keyword ON), or it could occur in an old-style join (in the WHERE clause).

  • Using Command to fix null / left outer join issue

    Hi
    I was told awhile ago that it's possible to fix crystal's issue with left outer join and null records being eliminated.
    I think i remember most of how this goes, but i can't seem to duplicate it.
    1) You can't have any select expert -- record
    2) You create the report normally and then make a new report using the SQL Query
         - Can't remember if its the whole report or upto the tables that have hisotry (null results)
    3) You move parts from WHERE to FROM
    Hopefully someone can help correct the steps i'm doing wrong or add what i'm missing from this.
    Below is the Query from my comlpeted report, but when i run it with the last LEFT OUTER JOIN added it removes all the products with no sales during that year.
    Any help would be greatly appreciated even if it's to say this can't be done.
    SELECT
    "prod_warehouse"."pw_whs_id",
    "prod_warehouse"."pw_prodline_id",
    "prod_warehouse"."pw_prod_id",
    "prod_warehouse"."pw_bin_location1",
    "prod_warehouse"."pw_min_onhand_qty",
    "prod_warehouse"."pw_max_onhand_qty",
    "prod_warehouse"."pw_onhand_qty",
    "product_lookup"."prlkp_lang1_1_desc",
    "prod_customer"."prcu_cust_part_num",
    "contract_details"."cond_level1_amt",
    "sales_history"."sah_year"
    FROM   (((("sisl_data05"."dbo"."products" "products"
    LEFT OUTER  JOIN "sisl_data05"."dbo"."prod_warehouse" "prod_warehouse"
    ON ("products"."pr_prod_id"="prod_warehouse"."pw_prod_id")
    AND ("products"."pr_prodline_id"="prod_warehouse"."pw_prodline_id"))
    LEFT OUTER JOIN "sisl_data05"."dbo"."product_lookup" "product_lookup"
    ON ("products"."pr_prod_id"="product_lookup"."prlkp_prod_id")
    AND ("products"."pr_prodline_id"="product_lookup"."prlkp_prodline_id"))
    LEFT OUTER JOIN "sisl_data05"."dbo"."prod_customer" "prod_customer"
    ON ("products"."pr_prod_id"="prod_customer"."prcu_prod_id")
    AND ("products"."pr_prodline_id"="prod_customer"."prcu_prodline_id"))
    LEFT OUTER JOIN "sisl_data05"."dbo"."contract_details" "contract_details"
    ON "prod_warehouse"."pw_prod_id"="contract_details"."cond_prod_id")
    LEFT OUTER JOIN "sisl_data05"."dbo"."sales_history" "sales_history"
    ON (("prod_warehouse"."pw_whs_id"="sales_history"."sah_sortkey1")
    AND ("prod_warehouse"."pw_prod_id"="sales_history"."sah_sortkey2"))
    AND ("prod_warehouse"."pw_prodline_id"="sales_history"."sah_sortkey3")
    WHERE
    "prod_warehouse"."pw_whs_id"='20123'
    AND ("prod_warehouse"."pw_onhand_qty"<>0
    OR "prod_warehouse"."pw_bin_location1"<>'  '
    OR "prod_warehouse"."pw_max_onhand_qty">0)
    AND "sales_history"."sah_year"=2014
    ORDER BY "prod_warehouse"."pw_bin_location1", "prod_warehouse"."pw_prod_id"

    Try this:
    SELECT
    prod_warehouse.pw_whs_id,
    prod_warehouse.pw_prodline_id,
    prod_warehouse.pw_prod_id,
    prod_warehouse.pw_bin_location1,
    prod_warehouse.pw_min_onhand_qty,
    prod_warehouse.pw_max_onhand_qty,
    prod_warehouse.pw_onhand_qty,
    product_lookup.prlkp_lang1_1_desc,
    prod_customer.prcu_cust_part_num,
    contract_details.cond_level1_amt,
    sales_history.sah_year
    FROM sisl_data05.dbo.products products
      LEFT OUTER  JOIN sisl_data05.dbo.prod_warehouse prod_warehouse
        ON products.pr_prod_id=prod_warehouse.pw_prod_id
        AND products.pr_prodline_id=prod_warehouse.pw_prodline_id
      LEFT OUTER JOIN sisl_data05.dbo.product_lookup product_lookup
        ON products.pr_prod_id=product_lookup.prlkp_prod_id)
        AND products.pr_prodline_id=product_lookup.prlkp_prodline_id
      LEFT OUTER JOIN sisl_data05.dbo.prod_customer prod_customer
        ON products.pr_prod_id=prod_customer.prcu_prod_id
        AND products.pr_prodline_id=prod_customer.prcu_prodline_id
      LEFT OUTER JOIN sisl_data05.dbo.contract_details contract_details
        ON prod_warehouse.pw_prod_id=contract_details.cond_prod_id
      LEFT OUTER JOIN sisl_data05.dbo.sales_history sales_history
        ON prod_warehouse.pw_whs_id=sales_history.sah_sortkey1
        AND prod_warehouse.pw_prod_id=sales_history.sah_sortkey2
        AND prod_warehouse.pw_prodline_id=sales_history.sah_sortkey3
        AND sales_history.sah_year = 2014
    WHERE prod_warehouse.pw_whs_id='20123'
      AND (prod_warehouse.pw_onhand_qty<>0
        OR prod_warehouse.pw_bin_location1<>'  '
        OR prod_warehouse.pw_max_onhand_qty>0)
    Take a look at what I've done with the last line of the last join.  The issue is that when you left join to a table and you use that table in the Where clause, you've basically turned your you left outer join into an inner join because the record has to be there in order to get the value in the filter.  By moving the filter into the join, you'll still get the rest of the data when there is no corresponding record.
    NOTE:  Crystal adds all sorts of "extra" stuff like quotes and parentheses that you don't need and which I have removed to make the query easier to read.
    -Dell

  • Left Outer Join with more than two tables in both CR 8.5 and XIR2

    I am trying to create a report and I have tried two versions of Crystal but I ultimately need the report in CR8.5 for compatibility with the client's system.  I think I am starting to figure out what might be wrong and it might be my understanding of SQL, but I can't see why someone hasn't needed this in the past. Ultimately I want to see all projects and any journal entry that might be posted for that project.
    Database is MySQL 5.0.38 and using MySQL ODBC driver 3.51.19.
    Project header table information will be populated. Each line item on a journal entry can be tagged with the project ID. But for me to pull the journal entry date I need also to link to a third table for the journal entry header info.
    I want to see all projects, whether a journal entry has been posted or not.
    So the links are like this
    ProjectHeader --->Left Outer Join ---> JELines ---> Inner Join ---> JEHeader
    I think in this scenerio Crystal is treating the LOJ as an IJ.
    I created two brand new reports today, one in CR8.5 and one in CR XIR2. Once I edited the automatic CR8.5 SQL statement (which I have been doing for years, usually without problem), they both ran properly. I linked customers to their invoices. Customers without invoices showed properly. But then I linked the invoices to the payments of the invoices and immediately lost customers without orders in both reports.
    So apparently only two tables are allowed in Outer Joins. Does this make sense?  I checked out the w3schools tutorial on SQL and it doesn't mention this limitation and I can't find anywhere else that it specifically indicates this but all samples of code I have seen only show two tables.  I just thought for presentation as a sample that was easiest to understand and we could expand as necessary.
    If this is correct, how does one go about accounting for this kind of thing?  One solution that goes through my mind is creating a view at the database level for the link between journal entry lines and journal entry headers.  Would this be a good solution under normal circumstances?
    A second option that I had to implement because of timelines, is to use a subreport linked to the main report through the project ID to pull the information for the journal entries and just pass the totals I need to the main report through a shared variable.
    These aren't normal circumstances because I don't have access to the database so I can't create the view.  I have come across this concept several times and I have been able to use subreports to solve it but I am trying to find a better solution for the future as sometimes subreports can be slow.  So are there any alternatives I have not considered here?
    TIA rasinc

    So after some more work and another post.  I was able to get this to work.
    Items disappear when linking to another table
    My issues were two fold.  I was selecting on the tables on the right-side of the original Inner Join.  However, I was checking for Nulls.  This apparently is correct but you must check for the Nulls first eg. (IsNull (JEHeader.Field1) OR JEHeader.Field1 <= 100).  I had my original statement reversed checking for <= 100 before checking for Nulls.
    I also did not set all links to be Left Outer Join.  I had the Inner Join.  I actually have about 6 tables in this report so all the links need to be set Outer Join.  So this now seems to be corrected.
    Thanks

  • Left outer join problem -- need feedback

    using crystal 2008
    haveing prolbems with a left outerjoin to get a blank field(null) to show up.
    basically i have some po line have have long descriptions or text fields that i want to include with the report. Below is my sql statement. I have written a formula with a join between 2 fields to get the report to work- this does but- it leave the polines off that do not have a long description.  I have tried left outer joins but seem to be having problems.  The long description field where the data is actually at is under my po.line table, although serveral area have long description fields -
    *one note i had to add a duplicate table to the field to get some items in my header to work properly - not sure if this is effecting the report or not.
    OK- when I set up the link to a LO join enforce from = to
    and dont add the ldtext.field to the report the left outjoin works(but no long description)and all my line items show up.
    1. when I keep the same join and add either just the ld.text field to  the report it comes back with a error saying invalid table
    2. when i use my formula that joins the ld.text and po.line and place it in the report with the same left outerjoin i get the same failure.
    3.  when i dont reference the ldtext(field) at all in the report it works fine w/ the lo join
    4. when i Dont use a left outer join and use my formula(see below)
    if not isnull(({LONGDESCRIPTION.LDTEXT }))
    then {POLINE.DESCRIPTION}+{LONGDESCRIPTION.LDTEXT}
    else {POLINE.DESCRIPTION}
    and link from poline.ld
    to ld.ldtext - my formula works and populates the po.line and the ld.text together - except that any po.line with no description will not show up. Like its not there.
    Not sure what to do?
    here is my current sql statement with the longdescription field in the select statement
    here is the error statement i am getting:
    Failed to retrieve data from the database:
    Details:42000[intersolv][odb sql base driver][sql base] 00906 itn invalid table name[database vendor code:906]
    sql statement:
    SELECT "PO"."PONUM", "PO"."STATUS", "PO"."VENDOR",
    "COMPANIES"."NAME", "COMPANIES"."ADDRESS1",
    "COMPANIES"."ADDRESS2", "COMPANIES"."ADDRESS3",
    "COMPANIES"."ADDRESS4", "COMPANIES"."PHONE",
    "COMPANIES"."FAX", "COMPANIES_1"."NAME",
    "COMPANIES_1"."ADDRESS1", "COMPANIES_1"."ADDRESS2",
    "COMPANIES_1"."ADDRESS3", "COMPANIES_1"."ADDRESS4",
    "COMPANIES_1"."CONTACT", "COMPANIES_1"."PHONE",
    "COMPANIES_1"."FAX", "PO"."PURCHASEAGENT",
    "PO"."ORDERDATE",
    "PO"."REQUIREDDATE", "PO"."PAYMENTTERMS",
    "PO"."SHIPVIA", "PO"."FREIGHTTERMS", "PO"."FOB",
    "POLINE"."DESCRIPTION", "POLINE"."ITEMNUM",
    "POLINE"."ORDERQTY", "POLINE"."UNITCOST",
    "POLINE"."LOADEDCOST", "POLINE"."POLINENUM",
    "PO"."SHIPTOATTN", "LONGDESCRIPTION"."LDTEXT"
    FROM   ("MAXIMO"."PO" "PO" LEFT OUTER JOIN
    "MAXIMO"."LONGDESCRIPTION" "LONGDESCRIPTION" ON "PO"."LDKEY"="LONGDESCRIPTION"."LDKEY"),
    "MAXIMO"."POLINE" "POLINE",
    "MAXIMO"."COMPANIES" "COMPANIES_1",
    "MAXIMO"."COMPANIES" "COMPANIES"
    WHERE  ("PO"."PONUM"="POLINE"."PONUM") AND ("PO"."VENDOR"="COMPANIES_1"."COMPANY") AND ("PO"."SHIPTO"="COMPANIES"."COMPANY") AND "PO"."PONUM"='3386-053'

    If you took the time to read this thanks.... turns out... and I just want to pull my hair out over this.  My connection had a  old odbc driver so somehow it would not allow a left outer join....go figure - weeks of agony over that..... thanks ....have to say love this forum.

  • Left outer join 3 tables with where-statement

    Hi folks,
    I hope you can understand (and maybe solve) my problem.
    Generally I try to left outer join three tables. The third table is used for a WHERE-statement.
    The three table structures are the following:
    table 1 (user)   
    user1 | key
    table 2 (detail)  
    key | ID
    table 3 (header)
    ID | user2                 
    ...and I want to achieve the following structure (as example filled with data):
    user | key | ID
    |-----|----
    xy    | a    | 001
    xy    | b    | #
    z     | b     | #
    The clue ist the usage of the third table. I need the table to set user1 and user2 equal (WHERE) but there are two problems:
    1) Obviously I can't left outer join two tables with each other. In this case I already used the 'key' of table 1 to join it with the 'key' of table 2. So I can't left outer join the 'ID' of table 2 with the 'ID' of table 3. Error message that I can only left outer join a table once. Any proposals?
    2) I have to include a WHERE to equal user1 with user2. But I am not allowed to use the user2 from table 3 because of the left outer join.
    I tried this coding:
    SELECT auser1 akey b~id INTO TABLE itab FROM ( table1 AS a
      LEFT OUTER JOIN table2 AS b ON akey = bkey )
      LEFT OUTER JOIN table3 AS c ON bID = cID )
      WHERE auser1 = cuser2.
    I would really appreciate your help.
    Regards
    MrclSpdl

    IF you want to join a DB table with an internal table, you need to use the 'FOR ALL ENTRIES' statement.
    select dbfields
    into table itab2
    from dbtab
    for all entries in itab
    where dbfield1 = itab-field1.
    This will get you a second internal table with all the corresponding data for the first selection.  You can then join them with a loop through the first table and a read table on the second table (for 1 - 1 relation) or a nested loop statement on both tables (for 1 - N relation).  Make itab a hashed table when using read table with key, use a sorted table if you need to loop without key access.
    Regards,
    Freek

  • How to use left outer joins ,right outer joins and order by clause for belo

    Hi,
    How to use left outer joins ,right outer joins and order by clause for below XML query.
    The query which is red colour returns null then its not displaying any values for columns in that tables. Tried decode, nvl function hasn't worked.
    SELECT XMLAGG ( XMLELEMENT( "P", XMLFOREST( P.process_id AS Ppid,
              (SELECT XMLAGG( XMLELEMENT( "PI", XMLFOREST( PI.question_id AS PIqid,
                                       PI.process_id AS PIpid,
    PI.innertext AS
                                       PItext, PI.itemtype AS PItype,
                                       PI.linkfrom AS PIfrom,
                                       PI.linkto AS PIto,
    PI.associated AS PIas,
                                       PI.content_id AS PIc,
                                       PI.exitpoint1_id AS PIe1,
                                       PI.exitpoint2_id AS PIe2,
                                       PI.exitpoint3_id AS PIe3,
                                       PI.followoncall AS PIfoc,
    PI.userinput AS PIui,
                                       PI.resolveidentifier AS PIri,
    PI.libquestion_idfk AS PIlqid,
                                       PI.isLocked AS PIstls,
                                       PI.PreviousAnswer AS PIPAns,
                                       PI.VisibleToAgent AS PIVAgent,
                                       PI.RetryAttempt AS PIRetry,
                                       PI.Tags AS PITag,
                                  SELECT XMLAGG( XMLELEMENT( "PO", XMLFOREST( PO.option_id AS POoid,
                                       PO.question_id AS POqid,
                                                           PO.process_id AS popid,
                                                           PO.opt_innertext AS POtext,
                                                           PO.opt_linkfrom AS POfrom,
                                                           PO.opt_linkto AS POto,
                                                           PO.libquestion_idfk AS POlqid,
                                                           PO.liboption_idfk AS POloid ) ) )
                                  FROM vw_liveProcessOption_Sim_v6 PO
                                       WHERE PI.question_id = PO.question_id (+)
                                  AND PI.process_id = PO.process_id (+)
                                  ) "A" ) ) ) AS "PO"
         FROM vw_liveProcessItem_Sim_v6 PI
              WHERE P.process_id = PI.process_id
              ) "A" ) ) ) AS "PI"
    FROM liveProcess_ec P
    WHERE (P.process_id = 450)
    Any help really appreciated.
    Thanks

    user512743 wrote:
    Hi,
    Here below is the scripts of tables, insert statements and Required output.
    CREATE TABLE VW_LIVEPROCESSOPTION_SIM_v6
    (     "OPTION_ID" NUMBER,
         "QUESTION_ID" NUMBER(10,0),
         "PROCESS_ID" NUMBER(10,0),
         "OPT_INNERTEXT" VARCHAR2(200 CHAR),
         "OPT_LINKFROM" VARCHAR2(20 CHAR),
         "OPT_LINKTO" VARCHAR2(20 CHAR),
         "LIBQUESTION_IDFK" NUMBER,
         "LIBOPTION_IDFK" NUMBER
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,2,450,'Yes',null,'5',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,3,450,'Yes',null,'5',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,5,450,'Yes',null,'6',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,6,450,'Yes',null,'7',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,8,450,'Block All',null,'9',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,9,450,'Yes',null,'10',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,11,450,'Yes',null,'12',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,12,450,'Yes',null,'13',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (1,14,450,'Yes',null,'16',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,2,450,'No',null,'3',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,3,450,'No',null,'4',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,5,450,'No',null,'8',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,6,450,'No',null,'8',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,8,450,'Standard',null,'11',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,9,450,'No',null,'11',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,11,450,'No',null,'14',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,12,450,'No',null,'14',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (2,14,450,'No',null,'15',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (3,8,450,'Disabled',null,'12',null,null);
    Insert into VW_LIVEPROCESSOPTION_SIM_v6(OPTION_ID,QUESTION_ID,PROCESS_ID,OPT_INNERTEXT,OPT_LINKFROM,OPT_LINKTO,LIBQUESTION_IDFK,LIBOPTION_IDFK) values (4,8,450,'User Defined',null,'12',null,null);
    REATE TABLE "VW_LIVEPROCESSITEM_SIM_v6"
    (     "QUESTION_ID" NUMBER(10,0),
         "PROCESS_ID" NUMBER(10,0),
         "INNERTEXT" VARCHAR2(200 CHAR),
         "ITEMTYPE" VARCHAR2(50 CHAR),
         "LINKFROM" VARCHAR2(500 CHAR),
         "LINKTO" VARCHAR2(500 CHAR),
         "ASSOCIATED" VARCHAR2(200 CHAR),
         "CONTENT_ID" NUMBER,
         "EXITPOINT1_ID" NUMBER(10,0),
         "EXITPOINT2_ID" NUMBER(10,0),
         "EXITPOINT3_ID" NUMBER(10,0),
         "RESOLVEIDENTIFIER" VARCHAR2(40 CHAR),
         "LIBQUESTION_IDFK" NUMBER(10,0),
         "FOLLOWONCALL" NUMBER(1,0),
         "USERINPUT" VARCHAR2(200 CHAR),
         "ISLOCKED" NUMBER(1,0),
         "PREVIOUSANSWER" NUMBER(1,0),
         "VISIBLETOAGENT" NUMBER(1,0),
         "RETRYATTEMPT" NUMBER(10,0),
         "TAGS" VARCHAR2(50 BYTE)
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (1,450,'CBB1015 - Router Firewall Settinngs Process','Title',null,'2',null,null,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (2,450,'Is the customers PC Firewall turned off?','Question','1','2.2,2.1',null,null,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (3,450,'Advise the customer to turn off the PC Firewall in order to continue. Has this been done?','Question','2.2','3.2,3.1',null,278,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (4,450,'Advise the customer the PC Firewall must be switched off before this process????','ExitPoint','3.2',null,null,null,14,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (5,450,'Is the customer able to access the internet now?','Question','3.1,2.1','5.2,5.1',null,null,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (6,450,'Is the customer having a problem with a specific website?','Question','5.1','6.2,6.1',null,null,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (7,450,'1536: CBB1008 - Browser Setup and Daignostics','SubProcess','6.1',null,'1536-1-0',null,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (8,450,'What is the security level on the CPE Management page?','Question','6.2,5.2','8.4,8.3,8.2,8.1',null,279,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (9,450,'Change the security level to Standard. Does this resolve the customers issue?','Question','8.1','9.2,9.1',null,280,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (10,450,'Issue Resolved','ExitPoint','9.1',null,null,null,1,6,122,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (11,450,'Change the security level to Disabled. Is the customer able to browse the internet?','Question','9.2,8.2','11.2,11.1',null,281,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (12,450,'Change the security level to Standard. Is the customer able to browse the internet now?','Question','11.1,8.3,8.4','12.2,12.1',null,283,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (13,450,'Issue Resolved','ExitPoint','12.1',null,null,null,1,6,123,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (14,450,'Ask the customer to perform a master reset. Does this resolve their issue?','Question','12.2,11.2','14.2,14.1',null,282,null,null,null,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (15,450,'Faulty CPE','ExitPoint','14.2',null,null,null,1,6,124,null,null,null,null,null,null,null,null,null);
    Insert into VW_LIVEPROCESSITEM_SIM_v6 (QUESTION_ID,PROCESS_ID,INNERTEXT,ITEMTYPE,LINKFROM,LINKTO,ASSOCIATED,CONTENT_ID,EXITPOINT1_ID,EXITPOINT2_ID,EXITPOINT3_ID,RESOLVEIDENTIFIER,LIBQUESTION_IDFK,FOLLOWONCALL,USERINPUT,ISLOCKED,PREVIOUSANSWER,VISIBLETOAGENT,RETRYATTEMPT,TAGS) values (16,450,'Issue Resolved','ExitPoint','14.1',null,null,null,1,6,123,null,null,null,null,null,null,null,null,null);
    CREATE TABLE "LIVEPROCESS_EC_V"
    (     "PROCESS_ID" NUMBER(10,0),
         "USER_ID" NUMBER(10,0),
         "CREATED" TIMESTAMP (6)
    Insert into LIVEPROCESS_EC (PROCESS_ID,USER_ID,CREATED) values (450,7460,to_timestamp('21-APR-08 09.34.41.000000000 AM','DD-MON-RR HH.MI.SS.FF AM'));
    Required O/P in XML format
    <P>
    <Ppid>450</Ppid>
    <PI>
    <PIqid>1</PIqid>
    <PIpid>450</PIpid>
    <PItext>CBB1015 - Router Firewall Settinngs Process</PItext>
    <PItype>Title</PItype>
    <PIto>2</PIto>
    <PO />
    </PI>
    <PI>
    <PIqid>2</PIqid>
    <PIpid>450</PIpid>
    <PItext>Is the customers PC Firewall turned off?</PItext>
    <PItype>Question</PItype>
    <PIfrom>1</PIfrom>
    <PIto>2.2,2.1</PIto>
    <PO>
    <POoid>1</POoid>
    <POqid>2</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>5</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>2</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>3</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>3</PIqid>
    <PIpid>450</PIpid>
    <PItext>Advise the customer to turn off the PC Firewall in order to continue. Has this been done?</PItext>
    <PItype>Question</PItype>
    <PIfrom>2.2</PIfrom>
    <PIto>3.2,3.1</PIto>
    <PIc>278</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>3</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>5</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>3</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>4</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>4</PIqid>
    <PIpid>450</PIpid>
    <PItext>Advise the customer the PC Firewall must be switched off before this process????</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>3.2</PIfrom>
    <PIe1>14</PIe1>
    <PO />
    </PI>
    <PI>
    <PIqid>5</PIqid>
    <PIpid>450</PIpid>
    <PItext>Is the customer able to access the internet now?</PItext>
    <PItype>Question</PItype>
    <PIfrom>3.1,2.1</PIfrom>
    <PIto>5.2,5.1</PIto>
    <PO>
    <POoid>1</POoid>
    <POqid>5</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>6</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>5</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>8</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>6</PIqid>
    <PIpid>450</PIpid>
    <PItext>Is the customer having a problem with a specific website?</PItext>
    <PItype>Question</PItype>
    <PIfrom>5.1</PIfrom>
    <PIto>6.2,6.1</PIto>
    <PO>
    <POoid>1</POoid>
    <POqid>6</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>7</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>6</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>8</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>7</PIqid>
    <PIpid>450</PIpid>
    <PItext>1536: CBB1008 - Browser Setup and Daignostics</PItext>
    <PItype>SubProcess</PItype>
    <PIfrom>6.1</PIfrom>
    <PIas>1536-1-0</PIas>
    <PO />
    </PI>
    <PI>
    <PIqid>8</PIqid>
    <PIpid>450</PIpid>
    <PItext>What is the security level on the CPE Management page?</PItext>
    <PItype>Question</PItype>
    <PIfrom>6.2,5.2</PIfrom>
    <PIto>8.4,8.3,8.2,8.1</PIto>
    <PIc>279</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>8</POqid>
    <popid>450</popid>
    <POtext>Block All</POtext>
    <POto>9</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>8</POqid>
    <popid>450</popid>
    <POtext>Standard</POtext>
    <POto>11</POto>
    </PO>
    <PO>
    <POoid>3</POoid>
    <POqid>8</POqid>
    <popid>450</popid>
    <POtext>Disabled</POtext>
    <POto>12</POto>
    </PO>
    <PO>
    <POoid>4</POoid>
    <POqid>8</POqid>
    <popid>450</popid>
    <POtext>User Defined</POtext>
    <POto>12</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>9</PIqid>
    <PIpid>450</PIpid>
    <PItext>Change the security level to Standard. Does this resolve the customers issue?</PItext>
    <PItype>Question</PItype>
    <PIfrom>8.1</PIfrom>
    <PIto>9.2,9.1</PIto>
    <PIc>280</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>9</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>10</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>9</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>11</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>10</PIqid>
    <PIpid>450</PIpid>
    <PItext>Issue Resolved</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>9.1</PIfrom>
    <PIe1>1</PIe1>
    <PIe2>6</PIe2>
    <PIe3>122</PIe3>
    <PO />
    </PI>
    <PI>
    <PIqid>11</PIqid>
    <PIpid>450</PIpid>
    <PItext>Change the security level to Disabled. Is the customer able to browse the internet?</PItext>
    <PItype>Question</PItype>
    <PIfrom>9.2,8.2</PIfrom>
    <PIto>11.2,11.1</PIto>
    <PIc>281</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>11</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>12</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>11</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>14</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>12</PIqid>
    <PIpid>450</PIpid>
    <PItext>Change the security level to Standard. Is the customer able to browse the internet now?</PItext>
    <PItype>Question</PItype>
    <PIfrom>11.1,8.3,8.4</PIfrom>
    <PIto>12.2,12.1</PIto>
    <PIc>283</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>12</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>13</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>12</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>14</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>13</PIqid>
    <PIpid>450</PIpid>
    <PItext>Issue Resolved</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>12.1</PIfrom>
    <PIe1>1</PIe1>
    <PIe2>6</PIe2>
    <PIe3>123</PIe3>
    <PO />
    </PI>
    <PI>
    <PIqid>14</PIqid>
    <PIpid>450</PIpid>
    <PItext>Ask the customer to perform a master reset. Does this resolve their issue?</PItext>
    <PItype>Question</PItype>
    <PIfrom>12.2,11.2</PIfrom>
    <PIto>14.2,14.1</PIto>
    <PIc>282</PIc>
    <PO>
    <POoid>1</POoid>
    <POqid>14</POqid>
    <popid>450</popid>
    <POtext>Yes</POtext>
    <POto>16</POto>
    </PO>
    <PO>
    <POoid>2</POoid>
    <POqid>14</POqid>
    <popid>450</popid>
    <POtext>No</POtext>
    <POto>15</POto>
    </PO>
    </PI>
    <PI>
    <PIqid>15</PIqid>
    <PIpid>450</PIpid>
    <PItext>Faulty CPE</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>14.2</PIfrom>
    <PIe1>1</PIe1>
    <PIe2>6</PIe2>
    <PIe3>124</PIe3>
    <PO />
    </PI>
    <PI>
    <PIqid>16</PIqid>
    <PIpid>450</PIpid>
    <PItext>Issue Resolved</PItext>
    <PItype>ExitPoint</PItype>
    <PIfrom>14.1</PIfrom>
    <PIe1>1</PIe1>
    <PIe2>6</PIe2>
    <PIe3>123</PIe3>
    <PO />
    </PI>
    </P>
    Thanks in advance
    Edited by: user512743 on Nov 18, 2008 4:46 AM

  • Left Outer Joining multiple tables to one source table FAILS with VLD-1511

    Hi all,
    Is it me, or is OWB unable to handle left outer joining 1 source table to multiple other tables?
    I want to load a fact table so I have 1 source table with measures. This table must be outer joined to some dimensions that have their FK in the fact table.
    The SQL statement would look like this (and is perfectly valid):
    select ...
    from input, dim1, dim2
    where input.c1 = dim1.c1(+)
    and input.c2 = dim2.c2(+);
    I put the where clause in the joiner operator and validate, but that gives me message VLD-1511: A table may be outer joined to at most one other table.
    Even splitting this up into one outer join per joiner still gives this message.
    A search and look around on the forum and on metalink shows there are related issues (like bug 3334035). Seemingly creating a view is the work-around to use.....? (ie downgrading owb to a simple gui tool) }-;
    Have other people experienced this problem of not being able to outer join one input table to multiple other tables?
    Thanks,
    Ed

    I have had some feedback from Oracle. It turns out this has to do with 2 issues. Below I have pasted the text that Support gave me:
    <---------- START QUOTE ---------->
    RESEARCH
    =========
    Bug 3437036 KEY LOOKUP DOES NOT DETECT ORA-1417 IN VALIDATE/GENERATE STEP
    Unpublished Bug 4211684 FORWARD PORT OF BUG 3437036
    shows:
    Some more development has been completed when this bug is fixed in Paris.
    The following are the details:
    1. If the join condition contains a full outer join such as
    tab1.c (+) = tab2.c (+) and tab2.c (+) = tab3.c
    then the new validations implemented for this bug do not apply since
    in OWB, full outer join triggers generation of joins in ANSI syntax.
    ANSI syntax does not have the original problem the base bug of this
    bug reported.
    2. If the join condition does not contain any full outer join condition,
    then the join is generated in Oracle join syntax, which is subject two
    several restrictions. The fix to this bug check two of the restrictions.
    3. The first restriction in Oracle syntax is that the outer join operator
    "(+)" can only directly be attached to a column name. If you attach it
    to an expression, such as the following:
    (tab1.c + 1) (+) = tab2.c
    Then there will be an ORA-936 error at the time of mapping deployment.
    For this case, I have added a validation message VLD-1512 to error out
    this situation.
    4. The second restriction in Oracle syntax is that a table can only be
    outer joined to exactly one other table.
    For example, this is an invalid join in Oracle syntax:
    tab1.c (+) = tab2.c and tab1.d (+) = tab3.d
    because tab1 is left outer joined to tab2 and tab3.
    But note that the following is still valid in Oracle syntax:
    tab1.c (+) = tab2.c and tab1.d = tab3.d (+)
    because tab1 is left outer joined to tab2 and right outer joined to tab3.
    So this latter case does not violate the restriction that "same oj" to
    more than 1 table is not allowed.
    If same oj to more than 1 table is specified in a join condition,
    VLD-1511 will be issued, and the map is made invalid.
    <---------- END QUOTE ---------->
    OWB does a partial validation, ie not all access paths are (can be) checked. A full check is only done by the database itself. So some scenarios (like checking whether multiple tables are outer joined the correct way) are not checked, and in this case are flagged with an error (even though it is actually a correct scenario).
    Seemingly this was not flagged with an error in earlier versions of OWB, so beware, OWB behaviour may change when upgrading...
    Alternative solutions are (1) using key lookups, (2) using a view with all outer joins in there, (3) using intermediate result tables between the joins.
    Hope this info helps some people prevent spending too much time on a false error message,
    Ed

  • Trouble With Left Outer Join

    I'm kind of new to using left outer joins, so I don't know if I'm doing it quite right. Right now there's only one table that may or may not have a corresponding record, so I'm only using left outer join on it. I get the error ORA-00904: "A"."SGBSTDN_PIDM": invalid identifier right now when I try to run my query. This gives me the impression that I need to use left outer join on all the tables in my FROM clause. Any suggestions on what I need to do?
    /*Get those students not awarded ACG1 yet with an entry in shrlgpa*/
    SELECT spriden_id id, spriden_last_name||', '||spriden_first_name name, sgbstdn_styp_code student_type,
    sorhsch_graduation_date hsch_grad_date,shrlgpa_hours_earned hours_earned,rorenrl_finaid_adj_hr hours_enrolled,
    0 AS disbursement_to_date, 0 AS offer_amt, 0 AS current_disbursement,
    rnvand0_unmet_need unmet_need, 'N' AS awarded
    FROM RCRESAR,RCRAPP1,SORHSCH,RORHSDT,SGBSTDN A,SORLCUR, shrlgpa, rorstat, ROBINST, spriden
    ,rnvand0
    LEFT OUTER JOIN rorenrl ON (A.sgbstdn_pidm = rorenrl_pidm)
    WHERE (RCRESAR_PELL_ELGBL = 'Y')
        AND  SORHSCH_GRADUATION_DATE>'01-JAN-2006'
        AND  RCRAPP1_CITZ_IND IN ('1','2')
        AND  RCRAPP1_CURR_REC_IND='Y'
        /*Possible change once rigorous curr. decided AND (RORHSDT_AP_IB_COURSES = 'Y' OR RORHSDT_REQ_COURSES='Y')*/
        AND RORHSDT_REQ_COURSES='Y'
        AND sgbstdn_stst_code = 'AS'
        AND  SGBSTDN_STYP_CODE IN ('F','H','T')
        AND (SORLCUR_DEGC_CODE LIKE 'B%' OR SORLCUR_DEGC_CODE LIKE 'A%'
        OR SORLCUR_DEGC_CODE = 'UND')
        AND sorlcur_seqno = (SELECT MAX(sorlcur_seqno)
                              FROM sorlcur
                              WHERE sorlcur_pidm = A.sgbstdn_pidm
                              AND sorlcur_term_code = &enrollment_term)
        AND  SORLCUR_CACT_CODE='ACTIVE' 
        AND rorenrl_term_code = &enrollment_term
        AND shrlgpa_hours_earned BETWEEN 0 AND 29
        AND shrlgpa_gpa_type_ind = 'O'
        AND rorstat_pckg_comp_date IS NOT NULL
        AND  A.SGBSTDN_TERM_CODE_EFF = (SELECT MAX(B.SGBSTDN_TERM_CODE_EFF)
                                                                            FROM SGBSTDN B
                                                                             WHERE B.SGBSTDN_PIDM = A.SGBSTDN_PIDM
                                                                             AND sgbstdn_term_code_eff <= &enrollment_term
        AND NOT EXISTS (SELECT 'X'
                                        FROM RPRAWRD
                                      WHERE RCRESAR_PIDM = RPRAWRD_PIDM
                                          AND RCRESAR_AIDY_CODE = RPRAWRD_AIDY_CODE
                                          AND RPRAWRD_FUND_CODE = 'ACG1')
         AND rorstat_pidm = rcresar_pidm
        AND spriden_pidm = rcresar_pidm
        AND  RCRAPP1_PIDM    = RCRESAR_PIDM 
        AND shrlgpa_pidm = rcresar_pidm
        AND  SORHSCH_PIDM   = RCRESAR_PIDM 
        AND  RORHSDT_PIDM   = RCRESAR_PIDM 
        AND  SGBSTDN_PIDM   = RCRESAR_PIDM    
        AND  SORLCUR_PIDM   = RCRESAR_PIDM 
        AND rnvand0_pidm = rorstat_pidm
        AND  RCRESAR_INFC_CODE = RCRAPP1_INFC_CODE 
        AND  RCRESAR_SEQ_NO      = RCRAPP1_SEQ_NO  
        AND  RCRAPP1_AIDY_CODE = RCRESAR_AIDY_CODE
        AND ROBINST_AIDY_CODE = RCRESAR_AIDY_CODE
        AND  RCRESAR_AIDY_CODE = '&AIDY_CODE'
        AND rorstat_aidy_code = rcresar_aidy_code
        AND rnvand0_aidy_code = rcresar_aidy_code
        AND spriden_change_ind IS NULL
        ORDER BY name

    Frank Kulash wrote:
    Hi
    blackhole82 wrote:
    Yeah I realized that I was probably mixing styles after it wouldn't work. What you suggested does execute, so I assume it's right even though I'm not getting any rows at the moment. Don't assume it's correct: verify it
    I suggest re-writing the query using all ANSI syntax.
    Start with just two tables. Make sure that join is working.
    When you have something that works perfectly with just those tables, then add one more table.
    So if I wanted to left outer join onto shrlgpa too I would just need to add that underneath the join for rorenrl before the , and SORLCUR?In your existing query, it looks like shrlgpa is only connected to rcresar, using an inner join. Do you want to change that?At any rate, the order of tables using the old doesn't matter. Using ANSI notation, however, a join condition can only reference tables that have already been named in the same group of ANSI-joined tables.
    So you would probably would have to re-arrange the FROM clause.
    Sorry, I don't understand exactly what you want to do, so I can't tell you exactly how to do it.
    Make you best guess, and try it.
    If it doesn't produce the results you want, and you can't figure out how to fix it, then post the query, some sample data, and the desired results. If you post just the revised query, and a description of the problem, I'll try to answer, but without the sample data and desired results I can't guarantee that I can.Well I'm getting rows and the data seems to go with the query I had before using the outer join except for the records that have no record on shrlgpa. It appears that by having the clauses
    AND shrlgpa_hours_earned BETWEEN 0 AND 29
    AND shrlgpa_gpa_type_ind = 'O'that those I'm trying to pull in with the left outer join are being eliminated. Is it possible to still limit the hours earned while pulling in those who do not have a record on shrlgpa? Before I was just using a UNION to accomplish this, but I thought that I might be able to fine tune the query to eliminate the need for another UNION.

  • OJ syntax for multi-table left outer join with MS Oracle Driver

    I have a multi-table left outer join that works fine in SQL Server ODBC Driver, Oracle ODBC driver 8.01.07.00, but not with Microsoft ODBC Driver for Oracle 2.573.7326.0
    SELECT * from { oj A LEFT OUTER JOIN B ON A.col1 = B.col1 LEFT OUTER JOIN C ON A.col1 = C.col1 }
    I noticed someone had a similar problem (the proposed solution doesn't work):
    http://www.justpbinfo.com/listarchive/msg02874.html
    Does anyone know how to get this working with the Microsoft ODBC Driver for Oracle? Or does it just not work?

    The Microsoft ODBC Driver for Oracle 2.573.7326.0 does perform the same 'fix up' with {oj} in Oracle 8i. The problem is that it doesn't work when joining more than two tables:
    This works:
    SELECT * from { oj A LEFT OUTER JOIN B ON A.col1 = B.col1}
    This doesn't work:
    SELECT * from { oj A LEFT OUTER JOIN B ON A.col1 = B.col1 LEFT OUTER JOIN C ON B.col1 = C.col1 }
    (The second query will work with the Oracle Oracle ODBC driver, with a bit of tweaking. But I haven't found a way to get it to work with the Microsoft ODBC Driver for Oracle 2.573.7326.0. My suspicion is that it just doesn't work.)
    Gavin

  • Left outer join on Fact and dimension table.

    Hi all, I have a fact F with account number and few measures as columns.
    I also have a dimension D with account number, account name columns.
    Few account numbers from Fact doesnt exist in Dimension D , but they need to show up in the report though.
    How do I left join Fact and Dimension D in RPD?
    I have this report where I need to show Account Number, Account name, measures.
    If D doesnt have certain account numbers, I need to convert that account number from F as string and show it in the report in account name column.
    Can you pls help.

    Ok. I tried this:
    Driving table : Fact, Left outer join -- didnt work.
    Driving table: Dimension D left outer join -- didnt work either
    In either the case, I see physical query as D left outer Join on Fact F. and omitting the rows.
    And then I tried this -
    Driving table: Fact, RIght outer join.
    Now, this is giving me error:
    Sybase][ODBC Driver]Internal Error. [nQSError: 16001] ODBC error state: 00000 code: 30128 message: [Sybase][ODBC Driver]Data overflow. Increase specified column size or buffer size. [nQSError: 16011] ODBC error occurred while executing SQLExtendedFetch to retrieve the results of a SQL statement. (HY000)
    I checked all columns, everything matched with database table type and size.
    I am pulling Fact.account number, Dimension.account name, Fact.Measures. I am seeing this error each time I pull Fact.Account number.

  • Can we join 3 tables with left outer join

    hi friends.
          Can any one tell how to join 3 tables using <b>left outer join</b>...i tried by taking some fields of <b>ekko,ekpo,eket</b>, but this not working ... plz give a sample code with some fields.

    Hi Uday
    <b>Inner joins using 3 tables </b>
    <i><b>Try this :-</b></i>
    SELECT stpo~stlnr stpo~idnrk mast~matnr mara~mtart stpo~menge 
    INTO CORRESPONDING FIELDS OF TABLE zmat1 FROM mast 
    JOIN stpo ON stpo~stlnr = mast~stlnr 
    JOIN mara ON mara~matnr = mast~matnr 
    WHERE stpo~stlty = 'M' "AND stpo~idnrk IN s_matnr 
    AND mast~werks = 1000.
    <b><i>Here s_matnr is a select-options on the selection-screen. </i></b>
    <i><b>Or this. </b></i>
    <b>Code: </b>
         Select single Vbrk~Bukrs Vbrk~Kunrg    Vbrk~Vbeln 
                       Vbrk~Fkdat Vbrk~Bstnk_Vf Vbrk~Zterm 
                       Tvzbt~Vtext 
                       Vbak~Vbeln Vbak~Bstdk 
                       Likp~Vbeln Likp~lfdat    Likp~Lfuhr 
           into w_vbrk 
           from vbrk 
          inner join       Tvzbt on Tvzbt~Zterm        = Vbrk~Zterm      and 
                                    Tvzbt~Spras        = sy-langu 
          Inner join       Vbfa  as SalesLnk 
                                 on SalesLnk~vbeln     = pu_vbeln        and 
                                    SalesLnk~vbtyp_v   = c_order 
                inner join Vbak  on Vbak~Vbeln           = SalesLnk~Vbelv
          Inner join       Vbfa  as DeliveryLnk 
                                 on DeliveryLnk~vbeln   = pu_vbeln       and 
                                    DeliveryLnk~vbtyp_v = c_Delivery 
                inner join Likp  on Likp~Vbeln          = DeliveryLnk~Vbelv 
          where vbrk~vbeln = pu_Vbeln.
    <i><b>This code locates sales, delivery and payment terms info from a billing document number.</b></i> 
    <i><b>or</b></i>
    <b>
    Here, this one also works fine :</b>
    select zfpcd~cadivi zfpcd~proforma zfpcd~factura zfpcd~aniofactura 
    zfpcd~montousd zfpcd~montoap zfpcd~ebeln zfpcd~inco1 
    zfpcd~lifnr lfa1~name1 zcdvs~status zfpcd~conint 
    into it_lista 
    from zfpcd inner join zcdvs 
    on zfpcd~ebeln = zcdvs~ebeln 
    and zfpcd~proforma = zcdvs~proforma 
    and zfpcd~lifnr = zcdvs~lifnr 
    inner join lfa1 
    on zfpcd~lifnr = lfa1~lifnr 
    where zcdvs~status = '04'.
    Reward if helpfull
    Regards
    Pavan

  • LEFT OUTER JOIN with SubQuery

    I have two tables and I want to return all data from the first table with a piece of information from the second based on an effective date being at least a certain value. The tables I am working with contain billions of rows so I need a solution that will also scale.
    Sample tables:
    create table pp ( x number, y number);
    create table ec ( x number, y number, effdate date);
    insert into pp values (1,2);
    insert into pp values (2,3);
    insert into pp values (1,3);
    insert into ec values (1,2,sysdate);
    insert into ec values (2,3,sysdate);
    insert into ec values (1,3,sysdate+365);
    commit;
    select * from pp, ec where pp.x = ec.x(+) and pp.y=ec.y(+)
    and (effdate = ( select max(effdate) from ec ecc where ecc.y=ec.y and ecc.x = ec.x and effdate < sysdate) or effdate is null);
    The above query (and the one below) returns two rows. it does not return where the date does not meet the criteria.
    select * from pp LEFT OUTER JOIN ec ON pp.x = ec.x and pp.y=ec.y
    WHERE (effdate = ( select max(effdate) from ec ecc where ecc.y=ec.y and ecc.x = ec.x and effdate < sysdate) or effdate is null);
    This returns the three rows BUT IS VERY SLOW when run against the billion+ row table (because we cannot correlate the subquery results.)
    select * from pp LEFT OUTER JOIN (SELECT x, y, effdate
    FROM ec WHERE effDate = (SELECT MAX(EFFdate) from ec ecc where ecc.y=ec.y and ecc.x = ec.x and effdate < sysdate)) c ON c.x = pp.x and c.y = pp.y;

    It would help quite a bit to know
    1) your Oracle version
    2) your indexes and data volumes (do BOTH tables have billions of rows?)
    But here's something that may perform faster.
    ME_XE? WITH Maximizied AS
      2  (
      3     SELECT
      4        MAX(EffDate),
      5        x,
      6        y
      7     FROM ec
      8     WHERE EffDate < SYSDATE
      9     GROUP BY x, y
    10  )
    11  SELECT *
    12  FROM pp p, Maximizied m
    13  WHERE p.x = m.x (+)
    14  AND   p.y = m.y (+);
                     X                  Y MAX(EFFDAT                  X                  Y
                     2                  3 05-29-2008                  2                  3
                     1                  2 05-29-2008                  1                  2
                     1                  3
    3 rows selected.
    Elapsed: 00:00:00.03

Maybe you are looking for