Problems with type ... is table of - values

Question

Hello,
please look at the following procedure:
CREATE OR REPLACE PROCEDURE fct_s_snpdb_ersetzung_einzeln (
p_tnr IN VARCHAR2,
p_ersetzung IN VARCHAR2
IS
-- DECLARE VARIABLES
p_ersetzung_rep VARCHAR2(4000);
v_test_table NUMBER;
TYPE nersetzungtab IS TABLE OF VARCHAR2(4000)
--s_snpdb_tnr_ersetzung.ersetzung%TYPE
INDEX BY BINARY_INTEGER;
v_ersatzliste nersetzungtab;
v_anzersatzliste NUMBER;
v_test VARCHAR2(4000);
v_instr NUMBER;
i NUMBER := 1;
BEGIN
SELECT 1
INTO v_test_table
FROM all_tables
WHERE table_name LIKE 'S_SNPDB_TEMP_ERSETZUNG';
IF (v_test_table <> 1) THEN
EXECUTE IMMEDIATE 'create table s_snpdb_temp_ersetzung (tnr_ersetzung varchar2(19))';
END IF;
EXECUTE IMMEDIATE 'truncate table s_snpdb_temp_ersetzung';
IF (p_tnr IS NOT NULL) THEN
p_ersetzung_rep := '''' || p_tnr || ''',' || p_ersetzung;
p_ersetzung_rep := REPLACE(p_ersetzung, '''', '');
ELSE
p_ersetzung_rep := REPLACE(p_ersetzung, '''', '');
END IF;
v_instr := INSTR (p_ersetzung_rep, ',');
WHILE (v_instr > 0) LOOP
v_test := TRIM(SUBSTR(p_ersetzung_rep, 1, v_instr - 1));
v_ersatzliste(i) := v_test;
p_ersetzung_rep := SUBSTR(p_ersetzung_rep, v_instr + 1);
v_instr := INSTR(p_ersetzung_rep, ',');
i := i + 1;
END LOOP;
--now the problem comes
FOR f IN 1 .. i LOOP
EXECUTE IMMEDIATE 'INSERT INTO s_snpdb_temp_ersetzung VALUES(:tnr)'
USING v_ersatzliste(i);
END LOOP;
END fct_s_snpdb_ersetzung_einzeln;
The inputvalue for p_ERSETZUNG = 'A42020002 39 ','A42020004 55 ','A54017901 02 ','A54017901 03 ','A42020002 60 ','A42020004 15 '
I want to separate each value in separate row of a table.
It runs fine until the "insert into" statement.
Here I get the error "no data found". This means, that the variable v_ersatzliste(i) contains no value. I used the debugger, the separation of the value runs fine, but why the variable v_ersatzliste(i) has no values. I didn't find the problem.
Its not the first time, I use "type ... is table of", but till now I never had problems with this.
What could be the reason for no founded data in my variable.
Thanks in advance
D. Mildner

Answer 1

ohhh yes, you're right.
I think I should go home now :-).
Thanks very much.