Procedure to return many rows

Question

I have managed to get a single row procedure to function as i wish however am having trouble when i would like to incorporate a select statement that will return more than one row.
CREATE OR REPLACE PROCEDURE p_count_houses
(v_ten_type IN tbl_accommodation.ten_type%type,
v_accommodation_id OUT tbl_accommodation.accommodation_id%type)
IS
v_temp_accommodation tbl_accommodation.accommodation_id%type;
BEGIN
     SELECT count(accommodation_id)
     INTO v_temp_accommodation
     FROM tbl_accommodation
     WHERE ten_type = v_ten_type
     AND furnished = 1;
v_accommodation_id := v_temp_accommodation;
END p_count_houses;
works as i wish
however if i was to remove the count(...) and simply select accommodation_id i would then get an error to do with the fetch. So how would i go about doing what i need to do
Thanks

Answer 1

Not sure whether you want to return the multiple values through the argument or in the return clause. Probably one of the following may help:
1. Return through the collection, assume that you are expecting multiple rows from the query:
Create or Replace Type v_Acc is Table of tbl_accommodation.accommodation_id%type;
CREATE OR REPLACE PROCEDURE p_count_houses
(v_ten_type IN tbl_accommodation.ten_type%type,
v_accommodation_id OUT v_Acc)
IS
BEGIN
SELECT accommodation_id
Bulk Collect INTO v_accommodation
FROM tbl_accommodation
WHERE ten_type = v_ten_type
AND furnished = 1;
END p_count_houses;
The result will be copied into the collection, and the collection will be returned through the argument. Please see the changes in the code.
2. Return using the PIPELINED and PIPE ROW in the function.
Create or Replace Type v_Acc is Table of tbl_accommodation.accommodation_id%type;
CREATE OR REPLACE FUNCTION p_count_houses
(v_ten_type IN tbl_accommodation.ten_type%type)
Return v_Acc PIPELINED as
Cursor C1 is
SELECT accommodation_id
FROM tbl_accommodation
WHERE ten_type = v_ten_type
AND furnished = 1;
Begin
For Rec1 in C1
Loop
Pipe Row (Rec1.accommodation_id);
End Loop;
End p_count_houses;
To see the result in SQL prompt, issue the following command:
Select * from Table( p_count_houses( value_for_v_ten_type ));
The result will be something like this:
COLUMN_VALUE
1
2
3
4
5
...