Process.start("winword", filename) can not open file with space in the path and name

Question

Hi,
I am trying to write a class which can open file with selected application. for simplicity, now I just hard code the varaibles.
the problem: if the path or file name has space in it, even it exist, winword still can not open it.
could someone kindly show me what I did wrong and how to do it properly.
Thanks in advance.
Belinda
public static class FileOpen
public static void info()
string path = @"c:\a temp folder\aaa 1.txt";
if (File.Exists(path))
    // the file I am using in the sample does exist
     MsgBox.info("yes");
else
     MsgBox.info("no");
// working
//Process.Start("winword", "c:\\aaa.txt");
// not working
//Process.Start("winword", "c:\aaa.txt");
// not working
Process.Start("winword", "c:\\a temp folder\\aaa 1.txt");
// not working
Process.Start("winword", path);

Answer 1

string AppPath;
AppPath = ReadRegistry(Registry.CurrentUser, "Software\\FabricStudio", "TARGETDIR", value).ToString() + @"help";
string FileName = "'"+ AppPath + "\\ImageSamples.doc" + "'";
try
System.Diagnostics.Process.Start("Winword.exe", FileName);
can any body please help for this.
where i am making mistake?