Query Help - Add a column that doesn't exist in table

Hello,
i have an application that runs a query in code off of a main query, and that query in code requires a column that does not exist in the main query that I created. how do I go about adding a column to a query that does not actually exist in the table or database that I am querying?
For Example:
SELECT PROJ_ID, PROJECT_NAME
FROM PROJECT
I need a column called "DELETE_SESSION_ID" and this database/table does not contain that column anywhere. Is it best to create a view that creates the column somehow? I would prefer not having to create the column inside of the table. Any ideas are greatly appreciated.
Thanks,
Jeff

user10249614 wrote:
Hello,
i have an application that runs a query in code off of a main query, and that query in code requires a column that does not exist in the main query that I created. how do I go about adding a column to a query that does not actually exist in the table or database that I am querying?
For Example:
SELECT PROJ_ID, PROJECT_NAME
FROM PROJECT
I need a column called "DELETE_SESSION_ID" and this database/table does not contain that column anywhere. Is it best to create a view that creates the column somehow? I would prefer not having to create the column inside of the table. Any ideas are greatly appreciated.
Thanks,
JeffYou need a way to obtain the value you need - a function to generate it, perhaps. A view using such a function or aquiring the value by other means should work well.
Pipelined functions work well to generate values that aren't in the database at run time - if your version of Oracle supports them

Similar Messages

Enhancing existing Abap code: using values that doesn't exist in table

Hi, 
I would like to enhance this code . My requirement is as follows. 
I have two tables customer and product 
<pre>KNVP customer master data table
Customer PF Person
700008 YF 45555
700008 YQ 46666
700008 ZF 46666
700008 YM 49999
700008 ZQ 44444
700008 ZM 43333
T179 product hierarchy table*
product hier PF
1000014000 ZM
1000015000 ZF
1000033000 ZQ
The current extractor is showing YM for all YPF values
Customer Zperson ZPF YPF YPerson
700008 46666 ZF YM 49999
700008 43333 ZQ YM 49999
700008 44444 ZM YM 49999</pre>
 
Case 1:IF customer doesn't have Partner function value YQ in master data then partner function YF person and partner function should be use.
 
case 2: IF customer doesn't have Partner function value YF in master data then partner function YQ person and partner function should be use.
 
case3:IF customer doesn't have Partner function value YQ and YF in master data then partner function YM person and partner function should be use.
 
The tricky part is that YQ doesn't exist in T179 table
 
<pre>
LOOP AT T_DATA.
 ZIDX = SY-TABIX.
 CLEAR T179.
 Select partner function, assigned to current
 product hierarchy level 2
 SELECT * FROM T179
 WHERE STUFE = '2'
 AND PRODH = T_DATA-PRODH.
 ENDSELECT.
 Replace value with new partner function.
 by replacing first letter to 'Y'
 CONCATENATE 'Y' T179-ZZPARVW+1(1) INTO NEWPF.
 Try to find new sales employee with this new partner function
 CLEAR KNVP.
 SELECT * FROM KNVP UP TO 1 ROWS
 WHERE KUNNR = T_DATA-KUNNR
 AND VKORG = T_DATA-VKORG
 AND PARVW = NEWPF.
 ENDSELECT.
 IF SY-SUBRC EQ 0.
 New partner found with this partner function
 T_DATA-ZPARVW = NEWPF.
 T_DATA-ZPERNR = KNVP-PERNR.
ELSE.
 NEWPF = 'YM'.
 Try to find new sales employee with partner function 'YM'
 CLEAR KNVP.
 SELECT * FROM KNVP UP TO 1 ROWS
 WHERE KUNNR = T_DATA-KUNNR
 AND VKORG = T_DATA-VKORG
 AND PARVW = NEWPF.
 ENDSELECT.
 T_DATA-ZPARVW = NEWPF.
 T_DATA-ZPERNR = KNVP-PERNR.
 ENDIF.
 MODIFY T_DATA INDEX ZIDX TRANSPORTING ZPARVW ZPERNR.
</pre>
 Edited by: Matt on Aug 24, 2010 9:31 AM - fixed formatting

Hi,
thanks for your input, I have written it like this and it is working well for YQ and YF partner functions but YM is not showing when both are missing.
LOOP AT T_DATA.
 ZIDX = SY-TABIX.
 CLEAR T179.
* Select partner function, assigned to current
* product hierarchy level 2
 SELECT * FROM T179
 WHERE STUFE = '2'
 AND PRODH = T_DATA-PRODH.
 ENDSELECT.
* Replace value with new partner function.
* by replacing first letter to 'Y'
 CONCATENATE 'Y' T179-ZZPARVW+1(1) INTO NEWPF.
IF SY-SUBRC EQ 0.
IF NEWPF EQ 'YF'.
 READ TABLE T_KNVP WITH KEY PARVW = 'YF'.
 IF SY-SUBRC EQ 0. "YF exists in master data
 CLEAR KNVP.
 SELECT * FROM KNVP UP TO 1 ROWS
 WHERE KUNNR = T_DATA-KUNNR
 AND VKORG = T_DATA-VKORG
 AND PARVW = 'YF'.
 ENDSELECT.
 T_DATA-ZPARVW = 'YF'.
 T_DATA-ZPERNR = KNVP-PERNR.
 ELSE.
 READ TABLE T_KNVP WITH KEY PARVW = 'YQ'.
 IF SY-SUBRC EQ 0. "YQ exists in master data
 CLEAR KNVP.
 SELECT * FROM KNVP UP TO 1 ROWS
 WHERE KUNNR = T_DATA-KUNNR
 AND VKORG = T_DATA-VKORG
 AND PARVW = 'YQ'.
 ENDSELECT.
 T_DATA-ZPARVW = 'YQ'.
 T_DATA-ZPERNR = KNVP-PERNR.
ENDIF.
ENDIF.
ENDIF.
IF NEWPF EQ 'YQ'.
 READ TABLE T_KNVP WITH KEY PARVW = 'YQ'.
 IF SY-SUBRC EQ 0. "YQ exists in master data
 CLEAR KNVP.
 SELECT * FROM KNVP UP TO 1 ROWS
 WHERE KUNNR = T_DATA-KUNNR
 AND VKORG = T_DATA-VKORG
 AND PARVW = 'YQ'.
 ENDSELECT.
 T_DATA-ZPARVW = 'YQ'.
 T_DATA-ZPERNR = KNVP-PERNR.
 ELSE.
 READ TABLE T_KNVP WITH KEY PARVW = 'YF'.
 IF SY-SUBRC EQ 0. "YF exists in master data
 CLEAR KNVP.
 SELECT * FROM KNVP UP TO 1 ROWS
 WHERE KUNNR = T_DATA-KUNNR
 AND VKORG = T_DATA-VKORG
 AND PARVW = 'YF'.
 ENDSELECT.
 T_DATA-ZPARVW = 'YF'.
 T_DATA-ZPERNR = KNVP-PERNR.
ENDIF.
ENDIF.
ENDIF.
 ELSE.
 NEWPF = 'YM'.
* Try to find new sales employee with partner function 'YM'
 CLEAR KNVP.
 SELECT * FROM KNVP UP TO 1 ROWS
 WHERE KUNNR = T_DATA-KUNNR
 AND VKORG = T_DATA-VKORG
 AND PARVW = NEWPF.
 ENDSELECT.
 T_DATA-ZPARVW = NEWPF.
 T_DATA-ZPERNR = KNVP-PERNR.
 ENDIF.
 MODIFY T_DATA INDEX ZIDX TRANSPORTING ZPARVW ZPERNR.
 ENDLOOP.
thanks
Edited by: Bhat Vaidya on Aug 30, 2010 1:31 PM

Query to add a column in between existing cols of a table?

HI All,
I have two questions.
1. Query to add a column in between existing cols of a table? (not at the end. This is view of an order of output fields in a report)
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I need a query(probably) to swap the col1 and col2 values . NOT AS A RESULT SET, BUT IT NEEDS TO GET CHANGED IN THE TABLE.
Please help !

> 1. Query to add a column in between existing cols of
a table? (not at the end. This is view of an order of
output fields in a report)
Not really sensible ito DBMS - it does not care how you want to view the data. The sequence and formats of columns are what you/the application need to specify in the SQL's projection clause.
Also keep in mind to achieve this, the DBMS will need to rewrite the entire table to fit this new column in-between existing columns. This is not the best of ideas.
The projection of rows is dealt with SQL statements - not with the physical storage implementation.
> 2. How do I swap the contents of two columns in a
table. Suppose in a table tab there are 2 cols ,
col1,col2 populated with some data.
I need a query(probably) to swap the col1 and col2
values . NOT AS A RESULT SET, BUT IT NEEDS TO GET
CHANGED IN THE TABLE.
This seems to work:
SQL> create table foo_tab( c1 varchar2(10), c2 varchar2(10) );
Table created.
SQL> insert into foo_tab select TO_CHAR(rownum), TO_CHAR(object_id) from user_objects where rownum < 11;
10 rows created.
SQL> commit;
Commit complete.
SQL> select * from foo_tab;
C1 C2
1 55816
2 55817
3 55818
4 55721
5 105357
6 105358
7 105359
8 105360
9 105361
10 60222
10 rows selected.
SQL> update foo_tab set c1=c2, c2=c1;
10 rows updated.
SQL> select * from foo_tab;
C1 C2
55816 1
55817 2
55818 3
55721 4
105357 5
105358 6
105359 7
105360 8
105361 9
60222 10
10 rows selected.
SQL>

When I set up my iPhone, I accidentally put in an apple ID that doesn't exist. Therefor, I don't know the password and can't delete my account from iCloud. Can anybody help?

When I set up my iPhone, I accidentally put in an apple ID that doesn't exist. Therefor, I don't know the password and can't delete my account from iCloud. I was trying to sync my contacts to my iPad and now it's not possible without iCloud on my phone. Can anybody help?

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message edited by: cs

Is it possible to add new columns with format "Text" once a table is linked to a form

Is it possible to add new columns with format "Text" once a table is linked to a form in Numbers for iPhone or is it impossible and thus a serious bug?(Rating stars and numeric vales seem to work.)
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How to deauthorize a computer , that doesn't exist anymore?

I unisnstalled windows , and for some reason when i inserted my ipod to the freshly installed windows+itunes , and logged on my account , iTunes said , that its a new computer and asked me to authorize it , and so i did.
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Hi All,
I am new to SSIS , I have to Add Audit Columns to the Dimension and Fact tables (Created & modified date Time) of the package.
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Please Mark This As Answer if it solved your issue
Please Mark This As Helpful if it helps to solve your issue
Visakh
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Problem creating new sites. The formula refers to a column that does not exist

Good morning,
I have a problem creating new sites in my development environment. We have a template which works properly when we create new sites with it. However, when we add one new content type in the site created and save it as a new template, we can't create new sites
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Hi Enrique,
According to your description, after added a content type into the new site and save the site as a template, there is an issue when creating another new with the newly
site template.
Based on the error message “The formula refers to a column that does not exist…”, seems that it would be an issue of a Calculated column in the content type you added,
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Feel free to reply if there any progress.
Best regards,
Patrick
Patrick Liang
TechNet Community Support

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Sign out and back into your apple id from Settings>iTunes and App stores>(Your apple ID)>Sign Out and then sign in again with the new address. Close app store from running in the background (or restart the phone if your unsure how to do this). If when trying to update any apps they are still asking for the old apple ID, delete and re-install those apps.

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Romania
0800 894847
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scabthepoetMar 15, 2015 2:00 PM Re: My iPhone 5 camera roll is empty, but under usage says 3.1GB - how can I delete?
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I went from barely having any room left on my phone to almost brand new again.
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Click here and fill out the form for assistance.
(34501)

Query Help - Add a column that doesn't exist in table

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