Query in query, how can i do this?
hi,
As we can use nested query in sql but unfortunately it cant be done in forms6i, e.g.
INSERT INTO ARSP(QTY, amt )
( select bpmad.qty, ( select sum(CUTD.BGHANA) from CUTD)
from bpmadIn sql this query work but in forms6i it doesnt work, i am using this query in key-commit trigger.
Any help provided will be appreciated thanks
Regards
M. Laeeque A.
in forms6i it doesnt workWhat does it doesnt work mean? Do you get an error? Is the insert not performed? Anyway, is this the original insert-statement or did you reduce it to show here?
Similar Messages
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How can I perform this kind of range join query using DPL?
How can I perform this kind of range join query using DPL?
SELECT * from t where 1<=t.a<=2 and 3<=t.b<=5
In this pdf : http://www.oracle.com/technology/products/berkeley-db/pdf/performing%20queries%20in%20oracle%20berkeley%20db%20java%20edition.pdf,
It shows how to perform "Two equality-conditions query on a single primary database" just like SELECT * FROM tab WHERE col1 = A AND col2 = B using entity join class, but it does not give a solution about the range join query.I'm sorry, I think I've misled you. I suggested that you perform two queries and then take the intersection of the results. You could do this, but the solution to your query is much simpler. I'll correct my previous message.
Your query is very simple to implement. You should perform the first part of query to get a cursor on the index for 'a' for the "1<=t.a<=2" part. Then simply iterate over that cursor, and process the entities where the "3<=t.b<=5" expression is true. You don't need a second index (on 'b') or another cursor.
This is called "filtering" because you're iterating through entities that you obtain from one index, and selecting some entities for processing and discarding others. The white paper you mentioned has an example of filtering in combination with the use of an index.
An alternative is to reverse the procedure above: use the index for 'b' to get a cursor for the "3<=t.b<=5" part of the query, then iterate and filter the results based on the "1<=t.a<=2" expression.
If you're concerned about efficiency, you can choose the index (i.e., choose which of these two alternatives to implement) based on which part of the query you believe will return the smallest number of results. The less entities read, the faster the query.
Contrary to what I said earlier, taking the intersection of two queries that are ANDed doesn't make sense -- filtering is the better solution. However, taking the union of two queries does make sense, when the queries are ORed. Sorry for the confusion.
--mark -
Hi guys i am beginner , just wanted to know some info , how can i improve this query ..
select *
from tableA A, viewB B,
where A.key = B.key
and a.criteria1 = '111'
and a.criteria2 = some_funtion(a.key)
one more thing should function should be on left side of equal sign.
will a join make it better or something else is needed more than that .952936 wrote:
Hi guys i am beginner , just wanted to know some info , how can i improve this query ..
select *
from tableA A, viewB B,
where A.key = B.key
and a.criteria1 = '111'
and a.criteria2 = some_funtion(a.key)
one more thing should function should be on left side of equal sign.
will a join make it better or something else is needed more than that .If you are a beginner try to learn the ANSI Syntax. This will help you a lot to write better queries.
Your select would look like this in ANSI.
select *
from tableA A
JOIN viewB B ON A.key = B.key
WHERE a.criteria1 = '111'
and a.criteria2 = some_function(a.key);The good thing here is that this separates the typical joining part of the select from the typical filter criteria.
The other syntax very often let you forget one join. Just because there are so many tables and so many filters, that you just don't notice correctly anymore what was join and what not.
If you notice that the number of column is not what you expect, you can easiely modify the query and compare the results.
example A
Remove View B from the query (temporarily comment it out).
select *
from tableA A
--JOIN viewB B ON A.key = B.key
WHERE a.criteria1 = '111'
and a.criteria2 = some_funtion(a.key)
example B
You notice, that values from A are missing. Maybe because there is no matching key in ViewB? Then change the join to an outer join.
select *
from tableA A
LEFT OUTER JOIN viewB B ON A.key = B.key
WHERE a.criteria1 = '111'
and a.criteria2 = some_funtion(a.key)(The outer keyword is optional, left join would be enough). -
How can i join this two query?
I have two table table employee and CSEReduxResponses
In table employee i have
CREATE TABLE [dbo].[employee](
[emp_id] [int] IDENTITY(1,1) NOT NULL,
[emp_namefirst] [varchar](255) NOT NULL,
[emp_namemiddle] [varchar](50) NULL,
[emp_namelast] [varchar](255) NOT NULL
on responds i have
CREATE TABLE [dbo].[CSEReduxResponses](
[response_id] [int] IDENTITY(1,1) NOT NULL,
[employee] [int] NOT NULL,
[employeedept] [int] NOT NULL,
[star] [tinyint] NOT NULL,
[status] [int] NOT NULL,
[approvedby] [int] NULL,
[approveddate] [datetime] NULL,
[execoffice_status] [int] NULL,
Im trying to get the employee with the MAX execpffice_status( this is either a 1 or 0).
i have this query that i made for it
select top(1) with ties employee, SUM(execoffice_status) as 'total'
from CSEReduxResponses
group by employee
order by 'total' desc
my query for employee table is
select emp_namefirst as first , emp_namelast as [last]
from phonelist.dbo.employee where emp_namefirst is not null
How can i get this 2 query together so i can output the employee (first and last )name
with the max exeoffice_status?
i use :
Microsoft SQL Server Management Studio 10.0.2531.0
ps: sorry if i put this is the wrong forum, this is my first time here and first post.Are you looking for the below?
CREATE TABLE [dbo].[employee](
[emp_id] [int] IDENTITY(1,1) NOT NULL,
[emp_namefirst] [varchar](255) NOT NULL,
[emp_namemiddle] [varchar](50) NULL,
[emp_namelast] [varchar](255) NOT NULL
Insert into Employee Values('abc','bcd','cdf')
Insert into Employee Values('xyz','yxw','xwv')
CREATE TABLE [dbo].[CSEReduxResponses](
[response_id] [int] IDENTITY(1,1) NOT NULL,
[employee] [int] NOT NULL,
[employeedept] [int] NOT NULL,
[star] [tinyint] NOT NULL,
[status] [int] NOT NULL,
[approvedby] [int] NULL,
[approveddate] [datetime] NULL,
[execoffice_status] [int] NULL,
Insert into [CSEReduxResponses]( employee,employeedept,star,status,approvedby,approveddate,execoffice_status)
Values(1,100,1,1,1,GETDATE(),0),
(1,100,1,1,1,GETDATE(),1),
(2,100,1,1,1,GETDATE(),0)
;With cte as( Select *,SUM([execoffice_status]) over(partition by Employee) sumstatus From [CSEReduxResponses] )
Select Distinct A.*,B.sumstatus
From Employee A
Inner Join cte B On A.emp_id = B.employee
--OR
;With cte as( Select employee ,SUM([execoffice_status]) sumstatus From [CSEReduxResponses] group by Employee)
Select Distinct A.*,(Select sumstatus From cte B where A.emp_id = B.employee)
From Employee A
Drop table Employee,[CSEReduxResponses] -
How can I make this complex query?
I donât know how can I do this complex query...
I have the tables Customers, Vehicles and Models. A customer can have 0-N Vehicles and a vehicle have 1 Model.
Customers: ID_Customer (PK), Name, LastName...
Vehicles: ID_Vehicle (PK), ID_Customer, ID_Model, date_sale
Models: ID_Modelo (PK), Model_Name
Then I need to know the buy average time (date_sale) between 2 models (ID_Model)
For example I have these Vehicles:
ID_Vehicle (PK)...ID_Customer...ID_Model....date_sale
1................................123....................1.............21/05/2000
2................................459....................3............ 16/08/2000
3................................123....................2............ 28/06/2001
4................................516....................1............ 09/09/2001
5................................459....................4............ 18/10/2002
6................................516....................2............ 20/12/2002
If I want to know the buy average time (date_sale) between ID_Model 1 and ID_Model 2 it is. (403 + 467) / 2 = 435 days !!!
* Customer 123 (model 1 to 2): 25/06/2001 â 21/05/2000 ==> 403 days
* Customer 516 (model 1 to 2): 01/12/2002 â 01/05/2000 ==> 467 days.
I need to do the query for all the combination models. For example If I have the Models 1, 2 and 3 I need to obtain:
Source_Model.....Target_Model....Buy_Average_Time
1......................................1....................... xxx days
1......................................2....................... xxx days
1......................................3....................... xxx days
2......................................1....................... xxx days
2......................................2....................... xxx days
2......................................3....................... xxx days
3......................................1....................... xxx days
3......................................2....................... xxx days
3......................................3....................... xxx days
If it is necessary I could create a table with the fields Source_Model, Target_Model and Buy_Average_Time for accelerate the query time response.
But how can I do this query??????????
Thanks very much!!!Hi,
Thanks for your reply but It is not correct for me because the Customer could have several vehicles in her life.
If I make the query with my examples data it is OK
ID_Vehicle (PK)...ID_Customer...ID_Model....date_sale
1................................123....................1.............21/05/2000
2................................459....................3............ 16/08/2000
3................................123....................2............ 28/06/2001
4................................516....................1............ 09/09/2001
5................................459....................4............ 18/10/2002
6................................516....................2............ 20/12/2002
select v1.id_model as source_model,
v2.id_model as target_model,
avg (v2.date_sale - v1.date_sale) || ' days' as buy_average_time
from vehicles v1,
vehicles v2
where v1.id_customer = v2.id_customer
and v2.date_sale > v1.date_sale
group by v1.id_model, v2.id_model;
I received:
SOURCE_MODEL TARGET_MODEL BUY_AVERAGE_TIME
..............1................................2.....................................435 days
..............3................................4.....................................793 days
But If I insert a new vehicle:
ID_Vehicle (PK)...ID_Customer...ID_Model....date_sale
7................................516....................3............ 16/08/2003
And I execute the query now I receive:
SOURCE_MODEL TARGET_MODEL BUY_AVERAGE_TIME
..............1................................2...........................435 days
..............1................................3...........................706 days
..............2................................3...........................239 days
..............3................................4...........................793 days
It is NO correct because I donât have the 1 (Source_model) to 3 (Target_model) combination in the Vehicles data!!! (I have 1 to 2 and 2 to 3 but NO 1 to 3!!!!).
Then the query is not OK for me!
Besides If I modify the Vehicle 7 data and put ID_Model = 2:
ID_Vehicle (PK)...ID_Customer...ID_Model....date_sale
7................................516....................2............ 16/08/2003
I received:
SOURCE_MODEL TARGET_MODEL BUY_AVERAGE_TIME
..............1................................2...........................525,33 days
..............2................................2...........................239 days
..............3................................4...........................793 days
It is NO correct because the BUY_AVERAGE_TIME for 1 to 2 combination is 435 days (the same of the original query) because I aggregate only the combination 2 to 2 with the ID_VEHICLE 7
Below I attach the examples scripts.
Could you help me with this query, please?
Thanks very much!
CREATE TABLE VEHICLES
ID_VEHICLE NUMBER(9),
ID_CUSTOMER NUMBER(9),
ID_MODEL NUMBER(9),
DATE_SALE DATE
TABLESPACE USERS
PCTUSED 0
PCTFREE 10
INITRANS 1
MAXTRANS 255
STORAGE (
INITIAL 64K
MINEXTENTS 1
MAXEXTENTS 2147483645
PCTINCREASE 0
BUFFER_POOL DEFAULT
LOGGING
NOCACHE
NOPARALLEL;
INSERT INTO VEHICLES ( ID_VEHICLE, ID_CUSTOMER, ID_MODEL, DATE_SALE ) VALUES (
1, 123, 1, TO_Date( '05/21/2000 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO VEHICLES ( ID_VEHICLE, ID_CUSTOMER, ID_MODEL, DATE_SALE ) VALUES (
2, 459, 3, TO_Date( '08/16/2000 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO VEHICLES ( ID_VEHICLE, ID_CUSTOMER, ID_MODEL, DATE_SALE ) VALUES (
3, 123, 2, TO_Date( '06/28/2001 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO VEHICLES ( ID_VEHICLE, ID_CUSTOMER, ID_MODEL, DATE_SALE ) VALUES (
4, 516, 1, TO_Date( '09/09/2001 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO VEHICLES ( ID_VEHICLE, ID_CUSTOMER, ID_MODEL, DATE_SALE ) VALUES (
5, 459, 4, TO_Date( '10/18/2002 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO VEHICLES ( ID_VEHICLE, ID_CUSTOMER, ID_MODEL, DATE_SALE ) VALUES (
6, 516, 2, TO_Date( '12/20/2002 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
INSERT INTO VEHICLES ( ID_VEHICLE, ID_CUSTOMER, ID_MODEL, DATE_SALE ) VALUES (
7, 516, 2, TO_Date( '08/16/2003 12:00:00 AM', 'MM/DD/YYYY HH:MI:SS AM'));
COMMIT;
CREATE TABLE MODELS
ID_MODELO NUMBER(9),
MODEL_NAME VARCHAR2(25 BYTE)
TABLESPACE USERS
PCTUSED 0
PCTFREE 10
INITRANS 1
MAXTRANS 255
STORAGE (
INITIAL 64K
MINEXTENTS 1
MAXEXTENTS 2147483645
PCTINCREASE 0
BUFFER_POOL DEFAULT
LOGGING
NOCACHE
NOPARALLEL;
INSERT INTO MODELS ( ID_MODELO, MODEL_NAME ) VALUES (
1, 'MODEL 1');
INSERT INTO MODELS ( ID_MODELO, MODEL_NAME ) VALUES (
2, 'MODEL 2');
INSERT INTO MODELS ( ID_MODELO, MODEL_NAME ) VALUES (
3, 'MODEL 3');
INSERT INTO MODELS ( ID_MODELO, MODEL_NAME ) VALUES (
4, 'MODEL 4');
COMMIT;
CREATE TABLE CUSTOMERS
ID_CUSTOMER NUMBER(9),
NAME VARCHAR2(25 BYTE),
LASTNAME VARCHAR2(25 BYTE)
TABLESPACE USERS
PCTUSED 0
PCTFREE 10
INITRANS 1
MAXTRANS 255
STORAGE (
INITIAL 64K
MINEXTENTS 1
MAXEXTENTS 2147483645
PCTINCREASE 0
BUFFER_POOL DEFAULT
LOGGING
NOCACHE
NOPARALLEL;
INSERT INTO CUSTOMERS ( ID_CUSTOMER, NAME, LASTNAME ) VALUES (
123, 'Customer 123', 'A');
INSERT INTO CUSTOMERS ( ID_CUSTOMER, NAME, LASTNAME ) VALUES (
459, 'Customer 459', 'B');
INSERT INTO CUSTOMERS ( ID_CUSTOMER, NAME, LASTNAME ) VALUES (
516, 'Customer 516', 'C');
INSERT INTO CUSTOMERS ( ID_CUSTOMER, NAME, LASTNAME ) VALUES (
318, 'Customer 318', 'D');
COMMIT; -
Can anyone tell me how can i optimize this query...
Can anyone tell me how can i optimize this query ??? :
Select Distinct eopersona.numident From rscompeten , rscompet , rscv , eopersona , rscurso , rseduca , rsexplab , rsinteres
Where ( ( (LOWER (rscompeten.nombre LIKE '%caracas%') AND ( rscompeten.id = rscompet.idcompeten ) AND ( rscv.id = rscompet.idcv ) AND ( eopersona.id = rscv.idpersona ) )
OR ( (LOWER (rscurso.nombre) LIKE '%caracas%') AND ( rscv.id = rscurso.idcv ) AND ( eopersona.id = rscv.idpersona ) )
OR ( (LOWER (rscurso.lugar) LIKE '%caracas%') AND ( rscv.id = rscurso.idcv ) AND ( eopersona.id = rscv.idpersona ) )
OR ( (LOWER (rseduca.univinst) LIKE '%caracas%)' AND ( rscv.id = rseduca.idcv ) AND ( eopersona.id = rscv.idpersona ) )
OR ( (LOWER (rsexplab.nombempre) LIKE '%caracas%' AND ( rscv.id = rsexplab.idcv ) AND ( eopersona.id = rscv.idpersona ) )
OR ( (LOWER (rsinteres.descrip) LIKE '%caracas%' AND ( rscv.id = rsinteres.idcv ) AND ( eopersona.id = rscv.idpersona ) )
OR ( (LOWER (rscv.cargoasp) LIKE '%caracas%' AND ( eopersona.id = rscv.idpersona ) )
OR ( LOWER (eopersona.ciudad) LIKE '%caracas%' AND ( eopersona.id = rscv.idpersona )
PLEASE IF YOU FIND SOMETHING WRONG.. PLEASE HELP ME.. this query takes me aproximatelly 10 minutes and the database is really small ( with only 200 records on each table )You are querying eight tables, however in any of your OR predicates you're only restricting 3 or 4 of those tables. That means that the remaining 4 or 5 tables are generating cartesian products. (n.b. the cartesian product of 5 tables with 200 rows each results in g 200^5 = 320,000,000,000 rows) Then you casually hide this behind "distinct".
A simple restatement of your requirements looks like this:
Select eopersona.numident
From rscompeten,
rscompet,
rscv,
eopersona
Where LOWER (rscompeten.nombre) LIKE '%caracas%'
AND rscompeten.id = rscompet.idcompeten
AND rscv.id = rscompet.idcv
AND eopersona.id = rscv.idpersona
UNION
Select eopersona.numident
From rscurso ,
rscv,
eopersona
Where LOWER (rscurso.nombre) LIKE '%caracas%'
AND rscv.id = rscurso.idcv
AND eopersona.id = rscv.idpersona
UNION
Select eopersona.numident
From rscurso ,
rscv,
eopersona
Where LOWER (rscurso.lugar) LIKE '%caracas%'
AND rscv.id = rscurso.idcv
AND eopersona.id = rscv.idpersona
UNION
...From there you can eliminate redundancies as desired, but I imagine that the above will perform admirably with the data volumes you describe. -
Dear Sir/Madam
I am trying to update Ios7 for iPhone 4 but there is an unknown error occurred like (-23). My Laptop OS is Windows 08.ios 7 update which can updated and remaining 30minutes are left out. Than after error which can be show as i have mentioned above.
How can i resolved this error? So please help me.
Thanks & Regards,
Vatsal DesaiError 20, 21, 23, 26, 28, 29, 34, 36, 37, 40
These errors typically occur when security software interferes with the restore and update process. Use the steps to troubleshoot security software issues to resolve this issue. In rare cases, these errors may be a hardware issue. If the errors persist on another computer, the device may need service.
Also, check your hosts file to verify that it's not blocking iTunes from communicating with the update server. See the steps under the heading "Blocked by configuration (Mac OS X / Windows) > Rebuild network information > Mac OS X > The hosts file may also be blocking the iTunes Store." If you have software used to perform unauthorized modifications to the iOS device, uninstall this software prior to editing the hosts file to prevent that software from automatically modifying the hosts file again on restart.
all of this from
iTunes: Specific update-and-restore error messages and advanced troubleshooting -
How can i run this query in BI Answers
Hi,
pls tell me how can i run this sql statement in BI Answers....???
select abc_date,abc_asset_desc,sum(nvl(abc_market_val_lcy,0)+nvl(abc_accr_lcy,0)) "total balance" from abc
group by abc_date,abc_asset_desc;any help would be appriciated.... :-)
RegardsStrange question this one.
normally with Answers you pick the columns you want to report on and the BI server will construct the SQL for you.
In this example you would need a star with the abc dimension logical table and a logical fact for abc (these can be in the same table), which has a calculated field for 'Total Balance'.
You then pick the columns you require and Answer and the BI will automatically add the group by.
Adrian
Majendi -
My 2009 iMac freezes and won't run more than one application at a time - how can I fix this?
Help! My iMac has been getting worse regarding freezing, especially when trying to open iPhoto. It will load slowly, and then I get the pinwheel of death for ever, until I shutdown and try over again. It usually takes several tries, and usually overnight. How can I resolve this issue?
First, back up all data immediately, as your boot drive might be failing.
Step 1
This diagnostic procedure will query the log for messages that may indicate a system issue. It changes nothing, and therefore will not, in itself, solve your problem.
If you have more than one user account, these instructions must be carried out as an administrator.
Triple-click anywhere in the line below on this page to select it:
syslog -k Sender kernel -k Message CReq 'GPU |hfs: Ru|I/O e|find tok|n Cause: -|NVDA\(|timed? ?o' | tail | open -ef
Copy the selected text to the Clipboard by pressing the key combination command-C.
Launch the Terminal application in any of the following ways:
☞ Enter the first few letters of its name into a Spotlight search. Select it in the results (it should be at the top.)
☞ In the Finder, select Go ▹ Utilities from the menu bar, or press the key combination shift-command-U. The application is in the folder that opens.
☞ Open LaunchPad. Click Utilities, then Terminal in the icon grid.
Paste into the Terminal window (command-V). I've tested these instructions only with the Safari web browser. If you use another browser, you may have to press the return key.
The command may take a noticeable amount of time to run. Wait for a new line ending in a dollar sign (“$”) to appear.
A TextEdit window will open with the output of the command. Normally the command will produce no output, and the window will be empty. If the TextEdit window (not the Terminal window) has anything in it, stop here and post it — the text, please, not a screenshot. The title of the TextEdit window doesn't matter, and you don't need to post that.
Step 2
There are a few other possible causes of generalized slow performance that you can rule out easily.
Disconnect all non-essential wired peripherals and remove aftermarket expansion cards, if any.
Reset the System Management Controller.
Run Software Update. If there's a firmware update, install it.
If you're booting from an aftermarket SSD, see whether there's a firmware update for it.
If you have a portable computer, check the cycle count of the battery. It may be due for replacement.
If you have many image or video files on the Desktop with preview icons, move them to another folder.
If applicable, uncheck all boxes in the iCloud preference pane. See whether there's any change.
Check your keychains in Keychain Access for excessively duplicated items.
Boot into Recovery mode, launch Disk Utility, and run Repair Disk.
If you have a MacBook Pro with dual graphics, disable automatic graphics switching in the Energy Saverpreference pane for better performance at the cost of shorter battery life.
Step 3
When you notice the problem, launch the Activity Monitor application in any of the following ways:
☞ Enter the first few letters of its name into a Spotlight search. Select it in the results (it should be at the top.)
☞ In the Finder, select Go ▹ Utilities from the menu bar, or press the key combination shift-command-U. The application is in the folder that opens.
☞ Open LaunchPad. Click Utilities, then Activity Monitor in the icon grid.
Select the CPU tab of the Activity Monitor window.
Select All Processes from the View menu or the menu in the toolbar, if not already selected.
Click the heading of the % CPU column in the process table to sort the entries by CPU usage. You may have to click it twice to get the highest value at the top. What is it, and what is the process? Also post the values for User, System, and Idle at the bottom of the window.
Select the Memory tab. What value is shown in the bottom part of the window for Swap used?
Next, select the Disk tab. Post the approximate values shown for Reads in/sec and Writes out/sec (not Reads in andWrites out.)
Step 4
If you have more than one user account, you must be logged in as an administrator to carry out this step.
Launch the Console application in the same way you launched Activity Monitor. Make sure the title of the Console window is All Messages. If it isn't, select All Messages from the SYSTEM LOG QUERIES menu on the left. If you don't see that menu, select
View ▹ Show Log List
from the menu bar.
Select the 50 or so most recent entries in the log. Copy them to the Clipboard by pressing the key combinationcommand-C. Paste into a reply to this message (command-V). You're looking for entries at the end of the log, not at the beginning.
When posting a log extract, be selective. Don't post more than is requested.
Please do not indiscriminately dump thousands of lines from the log into this discussion.
Important: Some personal information, such as your name, may appear in the log. Anonymize before posting. That should be easy to do if your extract is not too long. -
I put an audiobook into my Itunes and I have selected the setting as Audiobook instead of Music but the change doesn't stick. How can I make this work? I've updated all my software and still I can't get the setting to stay on Audiobook.
Thanks!From King_Penguin in response to an earlier query on this topic:
You should be able to copy it over by connecting your phone to your computer's iTunes and doing File > Devices > Transfer Purchases - it should copy over to the Books part of your library
Cheers,
GB -
How can I make this join in ADF and make CRUD operation in this
How to make this relation in ADF
I have table employees and this is my master table
Table Name: Employees
Columns:
Employee_id(PK)
Employee_name
Employee_Salary
I have a child table that is called related employee that contains employees related to this employee
Table_name: Related_Employee
Columns:
Related_Employee_Table_Id(PK)
Employee_id(FK)
Related_Employee_Id
When I open employee id = 100 for example and add related employee id = 10
this is added with no problem but the requirement is that when I open employee 10 I find employee id 100 as related employee
How can I make this scenario.The best way to understand this is to look at an example. If you are using an oracle database such as XE for you have a schema called hr. This shema has a number of tables two of which are departments and employees. a department has multiple employees correct. So in your example a employee may be related to x # of other employees perhaps. A very similar scenario as that in the hr Schema. If you don't have an Oracle XE database, download one from here -> http://www.oracle.com/technetwork/database/express-edition/downloads/index.html
Create Business Components off of the Departments and Employees schema and you'll see that due to the db design, you get what you're talking about for free (i.e. the join). Thus, you have the master-detail relationship you're looking for. For a quick tip, here is the relationship between departments and employees in the hr schema via a create script that you can exam with data inserts included:
SET SQLBLANKLINES ON
CREATE TABLE DEPARTMENTS
DEPARTMENT_ID NUMBER(4, 0) NOT NULL
, DEPARTMENT_NAME VARCHAR2(30 BYTE) NOT NULL
, MANAGER_ID NUMBER(6, 0)
, LOCATION_ID NUMBER(4, 0)
, CONSTRAINT DEPT_ID_PK PRIMARY KEY
DEPARTMENT_ID
USING INDEX
CREATE UNIQUE INDEX DEPT_ID_PK ON DEPARTMENTS (DEPARTMENT_ID ASC)
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 2
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
ENABLE
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 1
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
CREATE TABLE EMPLOYEES
EMPLOYEE_ID NUMBER(6, 0) NOT NULL
, FIRST_NAME VARCHAR2(20 BYTE)
, LAST_NAME VARCHAR2(25 BYTE) NOT NULL
, EMAIL VARCHAR2(25 BYTE) NOT NULL
, PHONE_NUMBER VARCHAR2(20 BYTE)
, HIRE_DATE DATE NOT NULL
, JOB_ID VARCHAR2(10 BYTE) NOT NULL
, SALARY NUMBER(8, 2)
, COMMISSION_PCT NUMBER(2, 2)
, MANAGER_ID NUMBER(6, 0)
, DEPARTMENT_ID NUMBER(4, 0)
, CONSTRAINT EMP_EMP_ID_PK PRIMARY KEY
EMPLOYEE_ID
USING INDEX
CREATE UNIQUE INDEX EMP_EMP_ID_PK ON EMPLOYEES (EMPLOYEE_ID ASC)
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 2
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
ENABLE
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 1
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
CREATE INDEX DEPT_LOCATION_IX ON DEPARTMENTS (LOCATION_ID ASC)
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 2
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
CREATE INDEX EMP_DEPARTMENT_IX ON EMPLOYEES (DEPARTMENT_ID ASC)
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 2
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
CREATE INDEX EMP_JOB_IX ON EMPLOYEES (JOB_ID ASC)
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 2
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
CREATE INDEX EMP_MANAGER_IX ON EMPLOYEES (MANAGER_ID ASC)
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 2
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
CREATE INDEX EMP_NAME_IX ON EMPLOYEES (LAST_NAME ASC, FIRST_NAME ASC)
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 2
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
ALTER TABLE EMPLOYEES
ADD CONSTRAINT EMP_EMAIL_UK UNIQUE
EMAIL
USING INDEX
CREATE UNIQUE INDEX EMP_EMAIL_UK ON EMPLOYEES (EMAIL ASC)
LOGGING
TABLESPACE "USERS"
PCTFREE 10
INITRANS 2
STORAGE
INITIAL 65536
MINEXTENTS 1
MAXEXTENTS UNLIMITED
BUFFER_POOL DEFAULT
ENABLE;
ALTER TABLE DEPARTMENTS
ADD CONSTRAINT DEPT_LOC_FK FOREIGN KEY
LOCATION_ID
REFERENCES LOCATIONS
LOCATION_ID
ENABLE;
ALTER TABLE DEPARTMENTS
ADD CONSTRAINT DEPT_MGR_FK FOREIGN KEY
MANAGER_ID
REFERENCES EMPLOYEES
EMPLOYEE_ID
ENABLE;
ALTER TABLE EMPLOYEES
ADD CONSTRAINT EMP_DEPT_FK FOREIGN KEY
DEPARTMENT_ID
REFERENCES DEPARTMENTS
DEPARTMENT_ID
ENABLE;
ALTER TABLE EMPLOYEES
ADD CONSTRAINT EMP_JOB_FK FOREIGN KEY
JOB_ID
REFERENCES JOBS
JOB_ID
ENABLE;
ALTER TABLE EMPLOYEES
ADD CONSTRAINT EMP_MANAGER_FK FOREIGN KEY
MANAGER_ID
REFERENCES EMPLOYEES
EMPLOYEE_ID
ENABLE;
ALTER TABLE DEPARTMENTS
ADD CONSTRAINT DEPT_NAME_NN CHECK
(DEPARTMENT_NAME IS NOT NULL)
ENABLE;
ALTER TABLE EMPLOYEES
ADD CONSTRAINT EMP_EMAIL_NN CHECK
(EMAIL IS NOT NULL)
ENABLE;
ALTER TABLE EMPLOYEES
ADD CONSTRAINT EMP_HIRE_DATE_NN CHECK
(HIRE_DATE IS NOT NULL)
ENABLE;
ALTER TABLE EMPLOYEES
ADD CONSTRAINT EMP_JOB_NN CHECK
(JOB_ID IS NOT NULL)
ENABLE;
ALTER TABLE EMPLOYEES
ADD CONSTRAINT EMP_LAST_NAME_NN CHECK
(LAST_NAME IS NOT NULL)
ENABLE;
ALTER TABLE EMPLOYEES
ADD CONSTRAINT EMP_SALARY_MIN CHECK
(SALARY > 0)
ENABLE;
COMMENT ON TABLE DEPARTMENTS IS 'Departments table that shows details of departments where employees
work. Contains 27 rows; references with locations, employees, and job_history tables.';
COMMENT ON TABLE EMPLOYEES IS 'employees table. Contains 107 rows. References with departments,
jobs, job_history tables. Contains a self reference.';
COMMENT ON COLUMN DEPARTMENTS.DEPARTMENT_ID IS 'Primary key column of departments table.';
COMMENT ON COLUMN DEPARTMENTS.DEPARTMENT_NAME IS 'A not null column that shows name of a department. Administration,
Marketing, Purchasing, Human Resources, Shipping, IT, Executive, Public
Relations, Sales, Finance, and Accounting. ';
COMMENT ON COLUMN DEPARTMENTS.MANAGER_ID IS 'Manager_id of a department. Foreign key to employee_id column of employees table. The manager_id column of the employee table references this column.';
COMMENT ON COLUMN DEPARTMENTS.LOCATION_ID IS 'Location id where a department is located. Foreign key to location_id column of locations table.';
COMMENT ON COLUMN EMPLOYEES.EMPLOYEE_ID IS 'Primary key of employees table.';
COMMENT ON COLUMN EMPLOYEES.FIRST_NAME IS 'First name of the employee. A not null column.';
COMMENT ON COLUMN EMPLOYEES.LAST_NAME IS 'Last name of the employee. A not null column.';
COMMENT ON COLUMN EMPLOYEES.EMAIL IS 'Email id of the employee';
COMMENT ON COLUMN EMPLOYEES.PHONE_NUMBER IS 'Phone number of the employee; includes country code and area code';
COMMENT ON COLUMN EMPLOYEES.HIRE_DATE IS 'Date when the employee started on this job. A not null column.';
COMMENT ON COLUMN EMPLOYEES.JOB_ID IS 'Current job of the employee; foreign key to job_id column of the
jobs table. A not null column.';
COMMENT ON COLUMN EMPLOYEES.SALARY IS 'Monthly salary of the employee. Must be greater
than zero (enforced by constraint emp_salary_min)';
COMMENT ON COLUMN EMPLOYEES.COMMISSION_PCT IS 'Commission percentage of the employee; Only employees in sales
department elgible for commission percentage';
COMMENT ON COLUMN EMPLOYEES.MANAGER_ID IS 'Manager id of the employee; has same domain as manager_id in
departments table. Foreign key to employee_id column of employees table.
(useful for reflexive joins and CONNECT BY query)';
COMMENT ON COLUMN EMPLOYEES.DEPARTMENT_ID IS 'Department id where employee works; foreign key to department_id
column of the departments table'; -
When i double click itunes it doesn't open it just comes up with an error saying " The itunes library.itl file cannot be found or created. The default location for this file is in the 'itunes' folder in the 'music' folder. How can i fix this problem?
Anyone can help to advice how to solve this issue ?
-
i have 3 different itunes accounts and would like to combine them into just one for all my devices, a macbook pro, an iphone 4S, an older IPOD, and a ver sion one Ipad. how can i do this on all devices ?
i had one for a long time, then when i got the ipad i didn't realize they would all still work under one so i set up the second one on that
then when i got the new iphone i put in the info for the first and main one from my mac pro and it would not work at all, and i knew it was right, then it asked me to create a new one or i couldnt finish the setup
hence why i have 3 now
hard to believe you cannot combine into one
oh well, i will just make them all accessible for all 3
thanks -
I have an IMac which is my main computer and two IPads and an Ipod Nano.
Obviously we use these in sync as an when required via Itunes.
I have recommended a friend to have an IPAD2 and she wishes to load some of her existing cds into her Itunes Account.
If I wish to do this with my own, it is simple as we simply use the Imac which transfers content into Itunes.
However, my friend does not have a separate computer so I wish to load her CD's into Itunes and then sync to her Ipad without interfering with my own library and using her Apple ID.
How can I achieve this?" how can I sync my iphone to my mac book without losing all the music and pictures on it?"
You cannot. Copy everything you want form the old computer to the new one, then sync it.
it basically says you have to erase your iphone to sync to a new itunes!
Correct Iphone will sync, or manually manage, with one and only one computer/library at a time. Syncing, or manually managing, to another will indeed erase the current content. -
I already have an itunes account on my laptop but have been setup on a mac and have songs that have not been purchased from the itunes store, I cannot get the songs from my iPhone onto my itunes account on the mac. how can I do this?
You copy them from your old computer or your backup copy of your old computer.
The iphone is not a backup/storage device. -
Back then when I had the older update with iTunes i never had this problem with trying to put my mp3 files of music into my iTunes library. Now it doesn't want to be put into the library. Once I try to drag the music file to the iTunes library nothing happens, it just keeps showing a cancellation sign with my mouse. So how can I fix this?
Hi William.
The problem is probably that the index is corrupt and you need to completely re-create it rather than rebuilding individual mailboxes. I have no idea what the situation really is now after having tinkered with the contents of ~/Library/Mail/, though, so the following procedure may or may not work.
Verify/repair the startup disk (not just permissions), as described here:
The Repair functions of Disk Utility: what's it all about?
After having fixed all filesystem issues, if any, and making sure that there’s enough space available on the startup disk (a few GB, plus the space needed to make a backup copy of the Mail folder), try this:
1. Quit Mail if it’s running.
2. In the Finder, go to ~/Library/Mail/. Make a backup copy of this folder, just in case something goes wrong -- e.g. by dragging it to the Desktop while holding the Option (Alt) key down.
3. Locate Envelope Index and move it to the Trash. If you see an Envelope Index-journal file there, delete it as well.
4. Open Mail. It will tell you that your mail needs to be “imported”. Click Continue and Mail will proceed to re-create Envelope Index -- Mail says it’s “importing”, but it just re-creates the index if the mailboxes are already in Mail 2.x format.
Note: For those not familiarized with the ~/ notation, it refers to the user’s home folder, i.e. ~/Library is the Library folder within the user’s home folder.
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