Query quote help-Please ignore this thread
Dear all,
Please ignore this thread.
Thanks for understanding
Kai
Edited by: KaiS on Nov 12, 2009 9:33 AM
try
and A.subno =''' || subno || ''' ;' from usr_inf where rownum <300;
those are two single quotes ('), not double quotes.
Similar Messages
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Please ignore this thread. i have chosen wrong forum..
hi all
i have two tables called 'details' and 'containers'.
Two tables are related with company and reference.
i have two repeating frames, one for 'details' and other one for 'containers' those frames contains the filelds from the respective tables.
my requirement is i want to print one field from 'details' say(detail_no) to the the repeating frame of the 'containers' so for that i suppose to write the query to join these two tables(now seperate queries for two tables) or i can use the like to join them.
which is the best option and why?
Thanks..
Edited by: user13329002 on Sep 19, 2010 1:10 AMPlease do not start another thread.
Change the subject here to "Please Ignore" and post your question as part of the existing thread.
Thank you. -
Bfile image problem---please ignore this thread
Hi all,
I am using Oracle 10.2.0.2.0 on x86_64 GNU/Linux .
I am using a table with column bfile datatype. Bfile column links to oracle directory "frameroot" which contains image frames. when i check data of link (bfile) in oracle sql developer it shows the below :
Name : 2009_pre
Data Length : 55044
File Exists : true
Directory aliase : FRAMEROOT
but when i click image option its is giving the below error :
"Image could not be decoded from the binary stream".
As i think sql developer should show the image of the bfile datatype.
I am using oracle sql developer version 1.2.1
Please suggest.
Thanks
Vipin
Edited by: VipinK on Jun 8, 2010 10:07 PMDuplicate post. Please change the subject to "Please Ignore"
Please never do this.
thank you.
PS: There is a SQL*Developer forum and that is the only place to post questions about SQL*Developer. -
Hello Creative Cloud Illustrator Community:
Help Please!
This is with regard to creating a compound path:
I have set some white type on a circle and then created outlines. I then placed the outlined type on a black stroked ring which I then selected "outlined stroke." I then put both "outlined" graphical elements on a separate solid bkg. (all 3 are on the same layer). Lastly, I then selected the top two elements and went to "make" a "compound path" (because I want the type to be the "holes" so I can see through to the background). However, the only effect I get is the white outlined type turning black (the same color as the black ring). What am i doing wrong? I can achieve the desired result with simple boxes but it won't work with a circular type path, a stroked ring and a solid bkg.
Any help on this would be greatly appreciated!
Thank You!Thanks for the response Jacob.
Unfortunately, I tried your suggestion with no success. BTW, minus front is now Subtract. Apparently, by clicking option>subtract, it works in the same way as minus front. I tried this to no avail.
Let me reiterate please.
I have 3 graphic elements-all on the same layer:
1. Background: Gold circle with a fill and no stroke.
2. Middle: Black ring (Stroked) inside gold background circle.
3. Top: White copy set on a circular type path and placed directly on top of middle black ring.
Both the middle black ring and top type path HAVE BEEN CONVERTED TO OUTLINES.
LASTLY, I select the Middle and Top, go to Compound Paths and choose "Make" and my white copy turns to black. Wrong!
WHAT I WANT TO HAPPEN: I want the white copy to become HOLES, so the GOLD background shows through.
Any solutions would be very much appreciated! -
Sorry. This is where my question should be....
"In the ICLOUD section of iCal" - I don't have this on my Mac iCal. How would I get it? I currently have an empty iCal on iCloud. I urgently need to back up my iCal, Could anyone help please? This is SO frustrating.Have you enabled iCloud syncing for calendars on your mac, which requires OS X Lion (10.7.2)? See http://www.apple.com/icloud/setup/mac.html.
-
Ignore this thread - not sure how to delete it
I solved my problem and I'm not sure how to delete this thread.
I'm just a lowly user of Aperture but when I want to compare an original image to the edited one on my screen, I simply hit the keyboard letter "M" on my keyboard. This reveals the original photo before editing and hitting M again gives you edited version. I do this in the VIEWER mode to toggle between the two.
You might also try selecting an image while in SPLIT VIEW mode, holding down the command key and selecting a second image...this puts both (or several if you want) images in the viewer in order to compare.
Hope this helps a little! -
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This is what i want...
a small form (table) that states this..
Description:
Browse:
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thanks
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Please help me in the below :
select 'SELECT A.SUBNO,A.CONTRNO,a.NAME "Subscriber Name" , b.name "Contract Name" ,
B.STREET,B.BUILD_NO,B.BSTREET_NO,B.APARTMENT,b.id_no "ID Number",c.codetext
FROM usr_infA, med_deptB, adm_natC
WHERE A.CONTRNO=B.CONTRNO AND
B.NATIONALLITY=C.CODE and A.subno =' || subno || ' ;' from usr_inf where rownum <300;this query produces the below output
SELECT A.SUBNO,A.CONTRNO,a.NAME "Subscriber Name" , b.name "Contract Name" ,
B.STREET,B.BUILD_NO,B.BSTREET_NO,B.APARTMENT,b.id_no "ID Number",c.codetext
FROM usr_infA, med_deptB, adm_natC
WHERE A.CONTRNO=B.CONTRNO AND
B.NATIONALLITY=C.CODE and A.subno =22000004 ;rather I want this to be
SELECT A.SUBNO,A.CONTRNO,a.NAME "Subscriber Name" , b.name "Contract Name" ,
B.STREET,B.BUILD_NO,B.BSTREET_NO,B.APARTMENT,b.id_no "ID Number",c.codetext
FROM usr_infA, med_deptB, adm_natC
WHERE A.CONTRNO=B.CONTRNO AND
B.NATIONALLITY=C.CODE and A.subno ='22000004' ;I want the number 2200004 to be in quotes '22000004'
TIA
Kaiselect 'SELECT A.SUBNO,A.CONTRNO,a.NAME "Subscriber Name" , b.name "Contract Name" ,
B.STREET,B.BUILD_NO,B.BSTREET_NO,B.APARTMENT,b.id_no "ID Number",c.codetext
FROM usr_inf A, med_dept B, adm_nat C
WHERE A.CONTRNO=B.CONTRNO AND
B.NATIONALLITY=C.CODE and A.subno =''' || subno || ''' ;' from usr_inf where rownum <300;Note. I also added spaces between your table names and aliases in your FROM clause. -
Divay: Hello! Welcome to Adobe Customer Service.
Jeff Daniels: Hi, please help me!
Divay: I understand that you need help with Adobe Flash Player, but I am really sorry we don't support this Software over the chat, Please visit forums.adobe.com
Jeff Daniels: no! it doesnt help
Jeff Daniels: neither does your website
Jeff Daniels: why does it try to install and half way through loses connection, tries to reconnect, but never does!
Jeff Daniels: this is so frustrating
Jeff Daniels: the self help = no help
Jeff Daniels: ive read the formums, no help
Divay: You can post your own thread there. We don't have expertise over this product.
Jeff Daniels: someone in your company must, please provide me a contact
Divay: Please visit forums.adobe.com , This is the only point of contact.
Jeff Daniels: no
Jeff Daniels: I have tried everything on your site and to no avail...please connect me with someone that can offer support
Jeff Daniels: its not that hard a simple download that doesnt work!
Divay: We don't have support available for it, All freeware Products are just supported on Forums.adobe.com
Jeff Daniels: i dont care if its freeware...its your company's product
Jeff Daniels: im not the only one experiencing this issue
Jeff Daniels: nowhere on the site does it mention what to do if download looses connection
Jeff Daniels: how do you have a product that isnt supported
Jeff Daniels: terrible customer service
Divay: I am sorry but this is the only Support option.Jeff Daniels wrote:
Jeff Daniels: ive read the formums, no help
And all the links to the offline installers didn't help? -
Help please! This will be a user error im sure!
Basically I have just downloaded my photos taken on the iphone4 this week (daughters birthday), however some pics are up the wrong way and need editing etc..but each time my wife edits them on the laptop an error message comes up saying 'This photo cannot be saved because of a problem with the photos file properties' Please help! I told my wife we didnt need to take our camera as we had the phone and now she cant sort edit or share the pics! Thanks in advance!
Basically I have just downloaded my photos taken on the iphone4 this week (daughters birthday), however some pics are up the wrong way and need editing etc..but each time my wife edits them on the laptop an error message comes up saying 'This photo cannot be saved because of a problem with the photos file properties' Please help! I told my wife we didnt need to take our camera as we had the phone and now she cant sort edit or share the pics! Thanks in advance!
-
Help please? This is driving me MAD!!!
I have a gui and in it is a JLabel. The text for the JLabel is gained from a method class to another class.
The information is constantly changing and the JLabel needs to keep up to date. At the moment, i have a JButton that calls the method and then that updates the GUI.
I dont want to have to press the button. How can i do it so that it updates automatically, say every 5 seconds. Is there something i can but in actionPerformed???
Everything i have tried has reulted in the GUI not showing anything at all!
PLEASE PLEASE PLEASE PLEASE HELP!!!!please its for a very small bit of my dissertation.
I would read it, but im in hell trying to write the
technical report that has to go with my system.I thought your dissertation was a defense of knowledge you claim to gain during an investigation. And you need this information for that defense. If it is just given to you, how can you claim to have learned it?
� {� -
If MD02 don´t plan the components, please check this thread.
There is a new error in Md02 with IS-ADEC solution.
The BOM is not exploded and the components are not planned.
THis is a serious error with many consequences in planning and execution enviroment.
The note 1562786 will sove this issue.Please be informed about this note.
This is the validity of the note:
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Thanks
Maria Nunez Senior PP consultant of SAPHi Maria Nunez,
Firstly i would thanks for finding out new error in MD02. Some extent i got the issue but still need some more clarification on this.
Mainly I am not familiar with IS-ADEC could you please help me out to get more information obut it.
Thanks & Regards,
Madhu.G -
Guys I need help please read this and try to understand it
I want to know that what does a new driver has to do with modem that it makes noises like "click click" during the gameplay...
Right now i am using the old version that came with the box.It is 43.45 that has been released almost an year ago.Believe me guys it works almost perfect no noise and nothing.
If i come into 2004 then the latest version is 56.72 .I've heard that nVidia has uploaded this driver on april 1st (Happy fool day from nVidia). Thus guys i wish to come into this new year and i want to update my driver,and when i install this driver it will give me trouble from the modem. Couple of more things i have checked and they're the driver that came with the box is by DETONATOR and these days the drivers says FORCEWARE and the second thing is that the old software that comes in CD from nVidia doesnt contain "DIGITAL VIBRANCE" but all new drivers has it. Could this problem is from here? I am totally puzzled first i thought that there is something wrong with the graphic card but when i checked it was modem.When i changed the modem same problem.I changed the slot, same thing. Thought there is a virus or spyware but there was not.Hardware is ok because old version is working fine.
PLEASE GUYS I NEED ALL OF YOUR SUGGESTIONS DONT IGNORE MY PROBLEM
GRAPHIC CARD is MSI nVIDIA FX-5200
MB is MSI 865P-NEO
Modem is CONEXANT
One more thing i want to mention
if i turn on pc and start playing games(any 3D games) will run perfect on any driver whether it is new or oldest. But if i connect to internet with modem and later disconnect it and then start playing games or any 3D presentation the modem starts crying (CLICK CLICK) and this is the same sound that comes when we start connecting(dialing, probably when it gives signal) the internet.
In this situation i have to completely turn off my pc and also unplugging it (DISCHARGING ELECTRICITY). and then, when i turn on the pc and start any game without connecting to internet everything runs fine (On the new drivers)....
Now as i have mentioned before i changed the slots removed and even reinstalled.Nothing happens just a click click sound.
but for the old driver everything runs fine even if i am online and watching 3D presentations or playing games....
So anybody ????????????????????????assuming its a pci one as he suggests it may well be an irq thing
try playing swap the pci slot with it
' -
MS Query - Repost, Help please!
I have built a query in Access that I am accessing via .asp
pages (VB
Script). The query brings back related records (from another
table) , and
also has a count of these records against this relationship.
Heres the SQL that Access creates
SELECT sections.SectionID, sections.Section_Name,
Count(articles.ArticleID)
AS CountOfArticleID
FROM sections INNER JOIN articles ON sections.SectionID =
articles.SectionID
GROUP BY sections.SectionID, sections.Section_Name;
i.e.
Table 1
Sec 1
Sec 2
Sec 3
Table Two
Article 1, Sec1
Article 2, Sec1
Article 3, Sec 2
SO the query displays
Sec1, Article Count = 2
Sec2, Article Count =1
The problem I have is that how do I return Sec 3 within the
Query with a 0
(Zero) against it, it only seems to bring back the Sections
with related
record?
Any help or links to tutorial would be grateful
Thanks in advanceI believe if you replace:
INNER JOIN
with
LEFT OUTER JOIN
It will work.
Try it and let us know.
"The 'Ox'" <[email protected]> wrote in message
news:eqsr0b$10l$[email protected]..
>I have built a query in Access that I am accessing via
.asp pages (VB
> Script). The query brings back related records (from
another table) , and
> also has a count of these records against this
relationship.
>
> Heres the SQL that Access creates
>
> SELECT sections.SectionID, sections.Section_Name,
> Count(articles.ArticleID)
> AS CountOfArticleID
> FROM sections INNER JOIN articles ON sections.SectionID
=
> articles.SectionID
> GROUP BY sections.SectionID, sections.Section_Name;
>
>
> i.e.
>
> Table 1
> Sec 1
> Sec 2
> Sec 3
>
> Table Two
> Article 1, Sec1
> Article 2, Sec1
> Article 3, Sec 2
>
> SO the query displays
> Sec1, Article Count = 2
> Sec2, Article Count =1
>
> The problem I have is that how do I return Sec 3 within
the Query with a 0
> (Zero) against it, it only seems to bring back the
Sections with related
> record?
>
> Any help or links to tutorial would be grateful
>
> Thanks in advance
>
>
>
> -
Heirarchy query - Need help please!
DB ver: Oracle DB 10g Rel2
I have data as follows
LAST_NAME EMPLOYEE_ID MANAGER_ID
King 100 null
Cambrault 148 100
Bates 172 148
Bloom 169 148
Fox 170 148
Ozer 168 172
Smith 171 172
De Haan 102 169
Hunold 103 169
Austin 105 169
Ernst 104 170
When Cambrault(emp.id:148) logs in he should see the reporting structure as follows
- Cambrault
-- Bates
--- Ozer
--- Smith
-- Bloom
--- De Haan
--- Hunold
--- Austin
-- Fox
--- Ernst
Similerly when Bates(Emp.Id:172) logs in he should see as follows
- Bates
-- Ozer
-- Smith
How to write a query to get output of records as above?
I could write it as follows but getting all the records.
SELECT e1.ename||' works for Supervisor '||e2.ename
FROM emp e1, emp e2
WHERE e1.mgr = e2.empno;
Any help is highly appreciated. Thanks in advance.
movva
Edited by: cmovva on 27-Oct-2011 12:07 PMmaybe this example might help.
SQL> select * from emp;
EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO
7902 FORD ANALYST 7782 03-Dec-81 3000.00 20
7839 KING PRESIDENT 17-Nov-81 5000.00 10
7698 BLAKE MANAGER 7839 01-May-81 2850.00 30
7782 CLARK MANAGER 7839 09-Jun-81 2450.00 10
7788 SCOTT ANALYST 7782 09-Dec-82 3000.00 20
7844 TURNER SALESMAN 7698 08-Sep-81 1500.00 0.00 30
7876 ADAMS CLERK 7782 12-Jan-83 1100.00 20
7900 JAMES CLERK 7698 03-Dec-81 950.00 30
7934 MILLER CLERK 7782 23-Jan-82 1300.00 10
7945 CINDY SALESMAN 7698 16-Jan-83 1800.00 30
7950 TINA SALESMAN 7698 18-Jan-83 1850.00 30
11 rows selected
SQL>
SQL> select substr(lpad(' ',2*(level-1)) || ename,1,40) employee_name, job, hiredate, sal
2 from emp
3 start with mgr is null
4 connect by prior empno = mgr;
EMPLOYEE_NAME JOB HIREDATE SAL
KING PRESIDENT 17-Nov-81 5000.00
BLAKE MANAGER 01-May-81 2850.00
TURNER SALESMAN 08-Sep-81 1500.00
JAMES CLERK 03-Dec-81 950.00
CINDY SALESMAN 16-Jan-83 1800.00
TINA SALESMAN 18-Jan-83 1850.00
CLARK MANAGER 09-Jun-81 2450.00
SCOTT ANALYST 09-Dec-82 3000.00
ADAMS CLERK 12-Jan-83 1100.00
FORD ANALYST 03-Dec-81 3000.00
MILLER CLERK 23-Jan-82 1300.00
11 rows selected
SQL> using your sample data something like this:
SQL> select *
2 from (select 'King' last_name, 100 employee_id, null manager_id from dual union all
3 select 'Cambrault' last_name, 148 employee_id, 100 manager_id from dual union all
4 select 'Bates' last_name, 172 employee_id, 148 manager_id from dual union all
5 select 'Bloom' last_name, 169 employee_id, 148 manager_id from dual union all
6 select 'Fox' last_name, 170 employee_id, 148 manager_id from dual union all
7 select 'Ozer' last_name, 168 employee_id, 172 manager_id from dual union all
8 select 'Smith' last_name, 171 employee_id, 172 manager_id from dual union all
9 select 'De,Haan' last_name, 102 employee_id, 169 manager_id from dual union all
10 select 'Hunold' last_name, 103 employee_id, 169 manager_id from dual union all
11 select 'Austin' last_name, 105 employee_id, 169 manager_id from dual union all
12 select 'Ernst' last_name, 104 employee_id, 170 manager_id from dual) e;
LAST_NAME EMPLOYEE_ID MANAGER_ID
King 100
Cambrault 148 100
Bates 172 148
Bloom 169 148
Fox 170 148
Ozer 168 172
Smith 171 172
De,Haan 102 169
Hunold 103 169
Austin 105 169
Ernst 104 170
11 rows selected
SQL>
SQL> select substr(lpad(' ',2*(level-1)) || e.last_name,1,40) last_name,
2 e.employee_id,
3 e.manager_id
4 from (select 'King' last_name, 100 employee_id, null manager_id from dual union all
5 select 'Cambrault' last_name, 148 employee_id, 100 manager_id from dual union all
6 select 'Bates' last_name, 172 employee_id, 148 manager_id from dual union all
7 select 'Bloom' last_name, 169 employee_id, 148 manager_id from dual union all
8 select 'Fox' last_name, 170 employee_id, 148 manager_id from dual union all
9 select 'Ozer' last_name, 168 employee_id, 172 manager_id from dual union all
10 select 'Smith' last_name, 171 employee_id, 172 manager_id from dual union all
11 select 'De,Haan' last_name, 102 employee_id, 169 manager_id from dual union all
12 select 'Hunold' last_name, 103 employee_id, 169 manager_id from dual union all
13 select 'Austin' last_name, 105 employee_id, 169 manager_id from dual union all
14 select 'Ernst' last_name, 104 employee_id, 170 manager_id from dual) e
15 start with e.manager_id is null
16 connect by prior e.employee_id = e.manager_id;
LAST_NAME EMPLOYEE_ID MANAGER_ID
King 100
Cambrault 148 100
Bloom 169 148
De,Haan 102 169
Hunold 103 169
Austin 105 169
Fox 170 148
Ernst 104 170
Bates 172 148
Ozer 168 172
Smith 171 172
11 rows selected
SQL>
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