Query to find today's records?

Hello,
I am working on a little CF project and I need to find all
records that have today's date (time would also be included on the
field, in case that is relevant) What query would you use to
retrieve all records entered "today"? Thank you!

No dateValue () has been part of Microsoft Access for a while
now. What version of Access are you using?
Are you using Access as a front end to MS SQL?
Anyway, there is something else going on.
Turn on all debugging options and post the EXACT, FULL, error
message here.

Similar Messages

Query to find the latest record with respect to the current status

Dear gurus
I have the following data in a table
Customernum
bkcode
reqtdate
Prevstat
currstat
The data will be like this
CustomerNum bkcode reqdate prevstat currstat
5900 1 03-Aug-12 0 1
5900 1 06-Aug-12 1 0
5900 5 22-Jun-12 0 1
If a customer has an issue to solved, a record is added with bkcode , register date and currstat will be 1
If the issue is resolved for the bookingcode,a new record is added, the currentstatus will become 0. and prev stat will show 1. Row no 1 and 2 reflects this case
If this table is queried for finding the unresolved issues. the output should be only the Last row of the above example. since issue with bookingcode 1 has been resolved
I have trying hard to get this thing confused what to use Lead or Max
Kindly guide me

Hi,
one way here:
WITH mytable(CustomerNum, bkcode, reqdate, prevstat, currstat)
AS
   SELECT 5900, 1, TO_DATE('03-Aug-12', 'DD-Mon-YY'), 0, 1 FROM DUAL UNION ALL
   SELECT 5900, 1, TO_DATE('06-Aug-12', 'DD-Mon-YY'), 1, 0 FROM DUAL UNION ALL
   SELECT 5900, 5, TO_DATE('22-Jun-12', 'DD-Mon-YY'), 0, 1 FROM DUAL
SELECT CustomerNum, bkcode, reqdate, prevstat, currstat
FROM (SELECT a.*
             , ROW_NUMBER() OVER (PARTITION BY CustomerNum, bkcode
                                       ORDER BY reqdate DESC) AS rn
          FROM mytable a
WHERE rn=1
   AND currstat=1;
CUSTOMERNUM     BKCODE REQDATE     PREVSTAT   CURRSTAT
       5900          5 22-JUN-12          0          1Regards.
Al
Edited by: Alberto Faenza on Dec 18, 2012 5:23 PM
Changed again!! Previous logic was wrong

SQL Query issue find difference in records

Hi All,
I am using oracle 10g. I need urgent help in finding difference in records based on date:
I have table sales as below:
salesman SALES_COUNT DATE
JOHN 20 04/01/2012
DENNY 15 04/01/2012
JOHN 30 04/02/2012
DENNY 30 04/02/2012
JOHN 45 04/03/2012
DENNY 50 04/03/2012
SALES_COUNT is increasing for sales man with date. Its like cumulative count. John has total sales from 04/01/2012 to 04/03/2012 is 50 and same case with Denny. This SALES_COUNT will keep on increasing with dates as sales keep adding in the table for each salesman.
But i want to have seprate counts for each salesman.
for e.g: SALES_COUNT JOHN on 04/02/2012 is 30-20 =10
SALES_COUNT JOHN on 04/03/2012 is 45-30 =15
SALES_COUNT DENNY on 04/02/2012 is 30-15 =15
SALES_COUNT JOHN on 04/03/2012 is 50-30 =20
Please help me with this scenario and let me know if need more information. I will greatly appreciate your help.
Thanks.

Does this give you what you want?
with t as (
     select 'JOHN' salesman, 20 sales_count, to_date('04/01/2012', 'mm/dd/yyyy') sale_date from dual
     union all
     select 'DENNY' salesman, 15 sales_count, to_date('04/01/2012', 'mm/dd/yyyy') sale_date from dual
     union all
     select 'JOHN' salesman, 30 sales_count, to_date('04/02/2012', 'mm/dd/yyyy') sale_date from dual
     union all
     select 'DENNY' salesman, 30 sales_count, to_date('04/02/2012', 'mm/dd/yyyy') sale_date from dual
     union all
     select 'JOHN' salesman, 45 sales_count, to_date('04/03/2012', 'mm/dd/yyyy') sale_date from dual
     union all
     select 'DENNY' salesman, 50 sales_count, to_date('04/03/2012', 'mm/dd/yyyy') sale_date from dual
select salesman,
       sales_count sales_todate,
       sale_date,
       sales_count - lag(sales_count, 1, 0) over (partition by salesman order by sale_date) daily_sales
from t
SALESMAN,SALES_TODATE,SALE_DATE,DAILY_SALES
DENNY,15,4/1/2012,15
DENNY,30,4/2/2012,15
DENNY,50,4/3/2012,20
JOHN,20,4/1/2012,20
JOHN,30,4/2/2012,10
JOHN,45,4/3/2012,15

Query to find out empty records

Hi experts,
I want to find out those tables in my databases which does not have any records or data. I have many tables in my databases which are totally empty. Please help me to build a query . Which database view i should access to find out the tables with empty records? Please help.

Hello,
Just pass the user list you want to count and not admin users or other default users.
SELECT owner, table_name, num_rows
      FROM dba_tables
      WHERE owner IN ('MYUSER','OTHERUSER');or this
DECLARE
   CURSOR mycur
   IS
      SELECT owner, table_name, num_rows
      FROM dba_tables
      WHERE owner NOT IN ('SYS', 'SYSTEM', 'SYSMAN', 'OUTLN')
            AND iot_name IS NULL;
   v_sql     VARCHAR2 (100);
   v_count   NUMBER := 0;
BEGIN
   FOR cur IN mycur
   LOOP
      v_sql     := NULL;
      v_count   := 0;
      v_sql     :=
         'select count (*) from ' || cur.owner || '.' || cur.table_name;
      EXECUTE IMMEDIATE v_sql INTO v_count;
      IF (v_count = 0)
      THEN
         DBMS_OUTPUT.put_line(   'Table name = '
                              || cur.table_name
                              || ' rows '
                              || v_count);
      END IF;
   END LOOP;
END;Regards

Query to find 10 latest records

hi all,
i have 100 records with following attributes.
username
mobile no
date
i want to select 10 latest rocords for a perticular mobile no(based on date attribute).
regards,
uttam

Hi Mohan,
I would use the same analytic function to get the records. However, I will have to modify the expression to get the records starting from the latest date as posted by Uttam. I just added the option DESC to start from the latest record and run down to the earliest.
select * from(
select username, mobile_no, date,
rank() over(partition by mobile_no order by date DESC) rn
from tabl1)
WHERE rn<=10;

Query to find records with more than 2 decimal places

I have written the below query to find records with more than 2 decimal places, but it is returning records with decimal places 1 & 2.
The datatype of the AMT column is NUMBER (without any precision).
SELECT amt FROM amount_table
WHERE substr(amt, instr(amt, '.')) LIKE '.%'
       AND length(substr(amt, instr(amt, '.') + 1)) > 2Output:-
AMT
*41591.1*
*275684.82*
*64491.59*
*3320.01*
*6273.68*
*27814.18*
*30326.79*
131.8413635
162.5352898
208.5203816
8863.314632
22551.27856
74.716992
890.0158441
2622.299682
831.6683841
*1743.14*
2328.195877
3132.453438
5159.827334
3.236234727
37.784
Thanks

Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
create table amount_table
LINE_NUMBER        NUMBER not null,
FEE_AMT            NUMBER not null
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (60208, 41591.1);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (60213, 275684.82);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (60238, 64491.59);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (63026, 3320.01);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (59906, 6273.68);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (83111, 27814.18);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (83114, 30326.79);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112395, 131.8413634682);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112399, 162.5352898104);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112402, 208.5203815738);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112403, 8863.3146321954);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112406, 22551.2785551322);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112407, 74.716992);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112410, 890.015844079);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112411, 2622.2996817048);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112414, 831.6683840698);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112415, 1743.14);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112418, 2328.1958771886);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112419, 3132.4534379886);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112422, 5159.8273341686);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112423, 3.2362347266);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112426, 37.784);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112427, 198.7423503696);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112430, 0.7220848332);
insert into amount_table (LINE_NUMBER, FEE_AMT)
values (2112433, 12.4149375254);

Query to find out 2 columns duplicate records

hi
how can i find out duplicate records from a table with 2columns duplicated
eg: emp_id, book_id duplicated together
emp_id book_id
001 A
001 A
001 B
in this case query should return ( emp_id: 001 , book_id: A ) because these are duplicated together

SQL> with t as
2 (
3 select 1 a,'A' b from dual
4 union all
5 select 1,'A' from dual
6 union all
7 select 1,'B' from dual
8 )
9 select distinct a,b
10    from (
11 select t.*,count(1) over (partition by a,b order by a) cnt
12    from t)
13   where cnt > 1
14 /
         A B
         1 A
SQL> with t as
2 (
3 select 1 a,'A' b from dual
4 union all
5 select 1,'A' from dual
6 union all
7 select 1,'B' from dual
8 )
9   select a,b
10     from t
11    group by a,b
12   having count(*) > 1
13 /
         A B
         1 A

Query to find out the time used by an user for an application

Hello All,
I want to know the query to find out the whole time used by the user for an application. Please view the below data
Employee:
SNO EMP_ID EMP_NAME EMP_DATE LOGIN_TIME LOGOUT_TIME
1 10 Visu 21-Nov-2010 06:30:00 07:30:00
2 10 Visu 21-Nov-2010 06:40:00 07:20:00
3 10 Visu 21-Nov-2010 06:50:00 07:50:00
4 10 Visu 21-Nov-2010 07:30:00 08:30:00
5 10 Visu 21-Nov-2010 09:30:00 10:30:00
By checking the above data we can say that the total time Visu used the application is
8.30 - 6.30 (From 1,2,3,4 records) = 2hrs
10.30 - 9.30 (Based on 5th rec) = 1hr
So the total time Visu used the application would be 3 hrs = 180 mins.
Could you please help me in getting the result from that data using a query?

odie_63 wrote:
I think it may be solved with analytics too.
with t1 as (
            select 1 sno,10 emp_id,'Visu' emp_name,'21-Nov-2010' emp_date,'06:30:00' login_time,'07:30:00' logout_time from dual union all
            select 2,10,'Visu','21-Nov-2010','06:40:00','07:20:00' from dual union all
            select 3,10,'Visu','21-Nov-2010','06:50:00','07:50:00' from dual union all
            select 4,10,'Visu','21-Nov-2010','07:30:00','08:30:00' from dual union all
            select 5,10,'Visu','21-Nov-2010','09:30:00','10:30:00' from dual
     t2 as (
            select emp_id,
                    emp_name,
                    emp_date,
                    to_date(emp_date || login_time,'DD-MON-YYYYHH24:MI:SS') login_time,
                    to_date(emp_date || logout_time,'DD-MON-YYYYHH24:MI:SS') logout_time
              from t1
     t3 as (
            select t2.*,
                    case
                      when login_time < max(logout_time) over(
                                                              partition by emp_id,emp_date
                                                              order by login_time
                                                              rows between unbounded preceding
                                                                       and 1 preceding
                        then 0
                      else 1
                    end start_of_group
              from t2
     t4 as (
            select t3.*,
                    sum(start_of_group) over(partition by emp_id,emp_date order by login_time) grp
              from t3
     t5 as (
            select emp_id,
                    emp_date,
                    min(login_time) login_time,
                    max(logout_time) logout_time
              from t4
              group by emp_id,
                       emp_date,
                       grp
select emp_id,
        numtodsinterval(sum(logout_time - login_time),'day') time_spent
from t5
group by emp_id
order by emp_id
    EMP_ID TIME_SPENT
        10 +000000000 03:00:00.000000000
SQL> SY.

How to find the longest record in a table?

Hello,
Is there a function to find the longest record in a table? Or is there a data dictionary that would tell you which record contains the longest data?
I have a table with five columns and one million records. I want to find the record (5 columns combined) with the longest data. Thank you.

Dear watson2000!
The function "VSIZE" tells you the number of bytes in the internal representation of a column which means the size of a value within a column. An example of vsize can be found here:
[http://www.adp-gmbh.ch/ora/sql/vsize.html]
So I think you should try it with this query to get the size of the longest record:
SELECT MAX(VSIZE(column1)) +
       MAX(VSIZE(column2)) +
       MAX(VSIZE(column3)) +
       MAX(VSIZE(column4)) +
       MAX(VSIZE(column5)) AS "Maximum Row"
FROM your_table;To identify the longest record try like this:
SELECT rowid
FROM   your_table
GROUP BY rowid
HAVING (MAX(VSIZE(column1)) +
         MAX(VSIZE(column2)) +
         MAX(VSIZE(column3)) +
         MAX(VSIZE(column4)) +
         MAX(VSIZE(column5))) = (SELECT MAX(VSIZE(column1)) +
                                      MAX(VSIZE(column2)) +
                                      MAX(VSIZE(column3)) +
                                      MAX(VSIZE(column4)) +
                                      MAX(VSIZE(column5))
                               FROM your_table;)I hope that these two queries could be of help to you.
yours sincerely
Florian W.
Edited by: Florian W. on 23.04.2009 20:53

Query to find the Salary table details HRMS 11i

I am looking query to find the persons salary details in Oralce EBS 11i.
I tried the below query bu it didn'ty work.
SELECT papf.employee_number
,papf.full_name
,pj.NAME job
,haou.NAME ORGANIZATION
,ppp.proposed_salary_n salary
FROM per_all_people_f papf
,per_all_assignments_f paaf
,per_jobs pj
,hr_all_organization_units haou
,per_position_definitions ppd
,per_all_positions pap
,per_pay_proposals ppp
WHERE 1 = 1
AND SYSDATE BETWEEN papf.effective_start_date AND papf.effective_end_date
AND papf.current_employee_flag = 'Y'
AND papf.employee_number IS NOT NULL
AND paaf.person_id = papf.person_id
AND SYSDATE BETWEEN paaf.effective_start_date AND paaf.effective_end_date
AND paaf.job_id = pj.job_id
AND paaf.organization_id = haou.organization_id
AND paaf.position_id = pap.position_id
AND pap.position_definition_id = ppd.position_definition_id
AND ppp.pay_proposal_id = (SELECT MAX (pay_proposal_id)
FROM per_pay_proposals
WHERE assignment_id = paaf.assignment_id)
In our case all the below tables have 0 records..
select count(*) from PER_PAY_PROPOSALS ;
COUNT(*)
         0
select count(*) from pay_element_entry_values_f;
COUNT(*)
         0
select count(*) from PAY_ELEMENT_ENTRY_VALUES_F;
COUNT(*)
         0
select count(*) from PAY_ELEMENT_ENTRIES_F;
COUNT(*)
         0

Hi,
Your results clearly states that there is no salary data which is been captured as well as there are no element entries which are assigned to any assignment.
Please do the below which will insert records in salary as well as element entries table:
1. Add a salary proposal to any active employee (People Enter and Maination --> Search for any employee --> Assignment --> Salary) - This will insert a record in PER_PAY_PROPOSALS table
2. Add an element entry to any active assignment (People Enter and Maination --> Search for any employee --> Assignment --> Entries) - This will insert a record in PAY_ELEMENT_ENTRIES_F and PAY_ELEMENT_ENTRY_VALUES_F table
Hope this clarifies.
Thanks,
Sanjay

Query to find customers who have not purchased anything

I have a query to find customers who have purchased what we call consumables (using item property) over a given period:
SELECT T0.CardCode, T0.CardName, T0.DocDate, T0.DocTotal, T1.ItemCode, T1.Dscription,T1.quantity, T2.ItmsGrpNam
FROM OINV T0 INNER JOIN INV1 T1 ON T0.DocEntry = T1.DocEntry, OITG T2
WHERE T0.DocDate BETWEEN '[%0]' AND '[%1]' AND T1.ItemCode like '2ssy%' AND T2.ItmsGrpNam = 'consumable'
I have another to show customers who have a particular type of equipment:
SELECT T0.manufSN,T0.itemName, T3.Name, T2.Address, T2.Street, T2.Block, T2.City, T2.County, T2.ZipCode
FROM OINS T0 INNER JOIN OCRD T1 ON T0.customer = T1.CardCode INNER JOIN CRD1 T2 ON T1.CardCode = T2.CardCode Inner Join OCPR T3 ON T0.ContactCod = T3.CntctCode
WHERE T0.manufSN like 'P%' AND T2.AdresType= 'S'
What I would like is to find those customers who have this equipment (query 2) but who have NOT purchased and consumables in say the last year.
I have tried using Excel by finding duplicates and taking those in query 1 from those in query 2 but it's very messy.
Has anyone done anything like this or got any good ideas?
Thanks

Hi Ralph,
Well, I enjoy teaching, so let's start at the beginning. SQL is a fairly full-featured language, and it supports recursion and nesting. That's why the books online often describe elements of the SQL statements as "expression" - it may be more than a field or a simple function occurring there. Nesting is the little puppy we used here.
Now, in your first post, you said: "What I would like is to find those customers who have this equipment (query 2) but who have NOT purchased and consumables (query 1) in say the last year."
So, our common point between the two queries is the customer, the CardCode. That's what this part does: F0.CardCode = T0.Customer. In my internal convention, I used F for Filter. So we only want the results in the filter where the CardCode matches the CardCode/Customer from the main query tables. It's the sole contact point between the two queries.
You also said you wanted only the items where they had purchased no consumables, which basically translates into: a count of the records equals 0. Now, since all we're interested in from the second query, the consumables query is how many records we returned, we get rid of all the columns except for one that we apply a COUNT to. After that, it's a simple criteria: the result of the second query has to equal 0. This is how the criteria looks after you take out all the details and put only the important brackets in: (SELECT COUNT...FROM...WHERE...) = 0.
This might be confusing at first, because most of the time we return recordsets from queries, but a standard feature of SQL is to return a value of any data type if the query returns a single row and a single column. This wouldn't work at all if we had more than one column in our nested query (or would require lots of tweaking), and although it returns a number of results in the complete process of the whole SQL statement, it only returns one result for each row.
Regards,
Mark Dielmann
Edited by: Mark Dielmann on Nov 13, 2009 12:30 PM - Forum doesn't support advanced formatting on answered questions.
Edited by: Mark Dielmann on Nov 13, 2009 12:32 PM - Salutations and more formatting.
Edited by: Gordon Du on Nov 13, 2009 10:35 AM - There are maximum characters limitation for correct format

Query to find 18 yrs Children

Hi All,
Can anybody tell me, how to write a Query to find the persons date of birth less than or equal to 18 yrs till today ?
Thanks in advance.

Something else like this ?
SQL> select * from mytable;
USERNAME                       CREATED
SYS                            13/11/05
SYSTEM                         12/11/05
OUTLN                          11/11/05
DBSNMP                         10/11/05
PS                             09/11/05
H89UCBAC                       08/11/05
PEOPLE                         07/11/05
TOTO                           09/11/06
8 rows selected.
--Take the users created in the last year.
SQL> select *
2 from   mytable
3 where created>=add_months(sysdate,1*-12)
4 /
USERNAME                       CREATED
TOTO                           09/11/06
SQL> Nicolas.

Query to find machines downloading from which DP

We have large environment with almost 100 Secondary sites.
All these secondaries are DP's as well.
Need to know any query to find, to which DP the machine is looking up to download the package? Heartbeat discovery happens on each DP i.e, secondary site. I need to know on which particular Secondary site the heartbeat for a machine is happening.
System Security analyst at CapG

Per Garth's answer, DP usage by clients isn't something explicitly tracked as it's truly a dynamic determination made every time the client needs content.
For your last statement, not sure what you are after: "I need to know on which particular Secondary site the heartbeat for a machine is happening." Heartbeat discovery records are created by the clients and have nothing specifically to do with secondary
sites. The clients do submit these to their management point though which is the MP of the secondary site in cases where the clients are using a secondary site.
Jason | http://blog.configmgrftw.com

Is it possible to find a base record for a given component using a SQL qry

Is it possible to find a base record for a given component through a SQL query ?
Ex:
1. VOUCHER for VCHR_EXPRESS
2. VENDOR for VNDR_ID
The below query gives multiple rows, I want it to restrict results to just one row
SELECT DISTINCT A.PNLGRPNAME AS COMPONENT, A.DESCR, A.ADDSRCHRECNAME, A.SEARCHRECNAME, D.RECNAME AS TableName
FROM PSPNLGRPDEFN A, PSPNLGROUP B, PSPNLDEFN C, PSPNLFIELD D, PSRECDEFN E
WHERE A.PNLGRPNAME = B.PNLGRPNAME
AND A.MARKET = B.MARKET
AND B.PNLNAME = C.PNLNAME
AND C.PNLNAME = D.PNLNAME
AND A.PNLGRPNAME = 'VNDR_ID' -- Component Name
AND E.RECNAME = D.RECNAME
AND E.RECTYPE =0
AND D.FIELDUSE =0
AND D.OCCURSLEVEL = 0
AND B.HIDDEN = 0
Thanks in Advance..

For the given examples, the problem is that there are pages in these components that contain subpages with record names specified. The SubPage field type appears to be at level 0, but if you view the SubPage definition, the records are at level 1. This is because the scroll area is contained within the subpage.
In theory, the situation is complicated by the fact that you can have subpages within subpages, which would force you to use a recursive query to fully expand the subpages. In practice, there probably aren't many, if any, pages where a scroll area is buried several subpages deep.
An alternative might be to compare the primary keys of the level 0 records to the primary keys of the add or search record keys. They should only match for the base record. Even this option is not trivial, though.
Regards,
Bob

Query to find Highest Salary

Hi,
What is the SQL query to find the 1st highest salary.
2nd Highest salary in the emp table.
likewise nth highest salary employee records.
Can anyone please give me the queries for the above scenarios.
Thanks

There are many nethods, some examples
Using group function:
SQL> l
1 SELECT ename,sal FROM emp e1
2 WHERE &val >= (SELECT COUNT(*) FROM emp e2
3*               WHERE e1.sal<=e2.sal)
SQL> /
Enter value for val: 1
old   2: WHERE &val >= (SELECT COUNT(*) FROM emp e2
new   2: WHERE 1 >= (SELECT COUNT(*) FROM emp e2
ENAME                                      SAL
KING                                      5000Using in-line view and rownum:
SQL> ed
Wrote file afiedt.buf
1 SELECT * FROM (SELECT ename,sal FROM emp ORDER BY SAL desc)
2* WHERE rownum<2
SQL> /
ENAME                                      SAL
KING                                      5000Using analytical function ROW_NUMBER
SQL> ed
Wrote file afiedt.buf
1 SELECT * FROM (SELECT ename,sal,ROW_NUMBER() OVER(ORDER BY sal desc) rn FROM emp )
2* WHERE rn=1
SQL> /
ENAME                                      SAL         RN
KING                                      5000          1Also you can use several other analytical functions as mentioned by Kartick. Search and read on the internet to find what is most suitable way and why!.
http://asktom.oracle.com/pls/apex/f?p=100:11:0::::P11_QUESTION_ID:2853107469873
http://asktom.oracle.com/pls/apex/f?p=100:11:0::::P11_QUESTION_ID:12759079666984

Query to find today's records?

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