Query to get IBAN numbers

Hi,
Has anybody created a query to get the IBAN number.
If i join LFBK and TIBAN table and enter just vendor number it gives me list of all IBAN numbers which were changed. I would just like to get the current IBAN numebr in a vendor which is existing right now.
Can anyone let me know how to get this
JR

Try the following plan. The plan is to create a new field to populate with the maximum of the dates and make it compare with the valid from dates. Strike the difference between these two fields. Pull only those records where the valid from date is equal to maximum date.
Go to the infoset. Click on Extras. Create an additional field say MAXDATE LIKE TIBAN-VALID_FROM.
Go to the coding section and give the following coding
<b>DATA: ZMAXDATE LIKE TIBAN-VALID_FROM.
CLEAR:ZMAXDATE, MAXDATE.
SELECT MAX( VALID_FROM ) FROM TIBAN INTO ZMAXDATE WHERE
BANKS = LFBK-BANKS AND
BANKL = LFBK-BANKL AND
BANKN = LFBK-BANKN.
MAXDATE = ZMAXDATE.</b>
Generate, save, assign the additional field to a field group.
Also include VALID_FROM field of TIBAN table into the field group.
Go to query, and create a local field called Difference, by enabling short names on. Give the ZMAXDATE field as MAX and TIBAN-VALID_FROM as VALFROM. Give the formula for the new field as difference between VALFROM - MAX.
Include the new field in the selection parameters. When running the report restrict the DIFFERENCE field = 0.

Similar Messages

How to get total numbers and total price in query reports

Hi,
how to get total numbers and total price in query reports.for example:
particular item is issued 3 times a week...I need total quantity of item issued
my query...
SELECT T0.[DocNum], T1.[ItemCode], T1.[Quantity], T1.[Price] FROM OIGE T0 INNER JOIN IGE1 T1 ON T0.DocEntry = T1.DocEntry WHERE T1.[ItemCode] Like '%%[%1]%%' and T1.[U_WOType]='[%0]'

Hi,
Try this:
SELECT T1.[ItemCode], SUM (T1.[Quantity]) as [Total Quantity], SUM (T1.[Quantity] * T1.[Price]) as [Total Price] FROM OIGE T0 INNER JOIN IGE1 T1 ON T0.DocEntry = T1.DocEntry WHERE T1.[ItemCode] Like '%%[%1]%%' and T1.[U_WOType]='[%0]'
Group By T1.[ItemCode]
Beni.

Sql query to get numbers from 0 to 99

How can we write an sql query to get values from 0 to 99 ... this shouldn't be coming from any table

Bawer wrote:
Result: (quickly replied by oracle)
SQL-Error: ORA-30009 (Not enough memory for connect by - 1GB reserved for oracle on VirtualBox)Oracle version? Takes about 8 seconds on my:
SQL> select * from v$version
2 /
BANNER
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Prod
PL/SQL Release 10.2.0.4.0 - Production
CORE 10.2.0.4.0 Production
TNS for 32-bit Windows: Version 10.2.0.4.0 - Production
NLSRTL Version 10.2.0.4.0 - Production
Elapsed: 00:00:00.14
SQL> select count(*) from (
2 SELECT LEVEL - 1
3 FROM DUAL
4 CONNECT BY LEVEL <= 10000000
5 )
6 /
COUNT(*)
10000000
Elapsed: 00:00:07.76
SQL> SY.

Query help : Query to get values SYSDATE-1 18:00 hrs to SYSDATE 08:00 hrs

Hi Team
I want the SQl query to get the data for the following comparison : -
Order Created is a Date Column , and i want to find out all the values from (SYSDATE-1) 18:00 hours to SYSDATE 08:00 hours
i.e.
(SYSDATE-1) 18:00:00 < Order.Created < SYSDATE 08:00:00.
Regards

Hi, Rohit,
942281 wrote:
If i want the data in the below way i.e.
from (SYSDATE-1) 18:00 hours to SYSDATE 17:59 hours ---> (SYSDATE-1) 18:00:00 < Order.Created < SYSDATE 07:59:00.If you want to include rows from exactly 18:00:00 yesterday (but no earlier), and exclude rows from exatly 08:00:00 today (or later), then use:
WHERE   ord_dtl.submit_dt >= TRUNC (SYSDATE) - (6 / 24)
AND     ord_dtl.submit_dt < TRUNC (SYSDATE) + (8 / 24)
So can i use the below format : -
ord_dtl.submit_dt BETWEEN trunc(sysdate)-(6/24) and trunc(sysdate)+(7.59/24) . Please suggest . .59 hours is .59 * 60 * 60 = 2124 seconds (or .59 * 60 = 35.4 minutes), so the last time included in the range above is 07:35:24, not 07:59:59.
If you really, really want to use BETWEEN (which includes both end points), then you could do it with date arithmentic:
WHERE   ord_dtl.submit_dt BETWEEN TRUNC (SYSDATE) - (6 / 24)
                  AND         TRUNC (SYSDATE) + (8 / 24)
                                           - (1 / (24 * 60 * 60))but it would be simpler and less error prone to use INTERVALs, as Karthick suggested earlier:
WHERE   ord_dtl.submit_dt BETWEEN TRUNC (SYSDATE) - INTERVAL '6' HOUR
                  AND         TRUNC (SYSDATE) + INTERVAL '8' HOUR
                                           - INTERVAL '1' SECONDEdited by: Frank Kulash on Apr 17, 2013 9:36 AM
Edited by: Frank Kulash on Apr 17, 2013 11:56 AM
Changed "- (8 /24)" to "+ (8 /24)" in first code fragment (after Blushadown, below)

Need to create report query to get latest open and last closed period for given application

Hi All,
I need to create a report query to get below result displayed in report output.
1)   -   Application name
2)   -    Ledger name
-o/ -Operating Unit
3)   - Last Closed Period
4)   - Current Open Period
5)   - Date Closed – Last Closed Period
6)   - Date Open – Current Open Period
I tr I tried to create the query below is the same. Please let me know if it looks fine.
SELECT *
FROM (SELECT fav.application_name ,
               hou.name Operating_Unit_Name,
               gl.name Ledger_name,
               gl.latest_opened_period_name,
               gps.period_name Period_Name,
               DECODE(gps.closing_status, 'O', 'Open', 'C', 'Closed') status,
               gps.last_update_date Last_status_modified_date
          FROM gl_period_statuses gps,
               gl_sets_of_books   gsob,
               fnd_application_vl fav,
               hr_operating_units hou,
               gl_ledgers         gl
         WHERE gps.period_name = gps.period_name
           AND gps.closing_status ='C'
           AND fav.application_short_name =
               NVL('&p_application_short_name', fav.application_short_name)
           AND gps.application_id = fav.application_id
           AND gsob.set_of_books_id = gps.set_of_books_id
           AND hou.set_of_books_id = gps.set_of_books_id
           AND gl.ledger_id = gsob.set_of_books_id
           AND hou.organization_id=NVL('&p_operating_unit',hou.organization_id)
           AND gl.ledger_id=NVL('&p_ledger_id',gl.ledger_id)
         ORDER BY gps.last_update_date desc )WHERE ROWNUM = 1
UNION ALL
SELECT *
FROM (SELECT fav.application_name Application_Name,
               hou.name Operating_Unit_Name,
               gl.name Ledger_name,
               gl.latest_opened_period_name,
               gps.period_name Period_Name,
               DECODE(gps.closing_status, 'O', 'Open', 'C', 'Closed') status,
               gps.last_update_date Last_status_modified_date
          FROM gl_period_statuses gps,
               gl_sets_of_books   gsob,
               fnd_application_vl fav,
               hr_operating_units hou,
               gl_ledgers         gl
         WHERE gps.period_name = gps.period_name
           AND gps.closing_status = 'O'
           AND fav.application_short_name =
               NVL('&p_application_short_name', fav.application_short_name)
           AND gps.application_id = fav.application_id
           AND gsob.set_of_books_id = gps.set_of_books_id
           AND hou.set_of_books_id = gps.set_of_books_id
           AND gl.ledger_id = gsob.set_of_books_id
           AND hou.organization_id=NVL('&p_operating_unit',hou.organization_id)
           AND gl.ledger_id=NVL('&p_ledger_id',gl.ledger_id)
         ORDER BY gps.last_update_date desc)
         WHERE ROWNUM = 1

It is within the table I believe (I'm not a DBA or a developer) since I created a BLOB column and then used the file browse feature to allow users to attach a resume to the table in order to be able to perform a search of the attached documents.
I'm just having a hard time pointing the link in the search results report to the document in the blob column.
The information on that page is great if you're trying to create a link to the document on the initial report.
But I created a query using Oracle Text to run a report that does a boolean search of the attached word documents in the table.
When it displays the search results, it doesn't create a link to the document and I can't figure out how to do it.
Here's a link the the instructions I used to create the initial search report with Oracle Text, mind you I only created the index and query, I didn't add in all the link data since they're using documents on websites and I'm using documents in a table.
http://www.oracle.com/technology/products/database/application_express/pdf/apex_text_application_v1.6.pdf
If you can help me with this I'd really appreciate it.
Thanks again.
Greg
Edited by: gjones77 on Dec 2, 2008 8:14 AM

How do I get the Numbers application iOS 7.0.4 unstuck updating on iPad 2?

How do I get the Numbers application unstuck in updating on iPad 2? After the last update of iOS 7 it started acting up. Then weeks ago (in November) I opened the application right after iOS 7.0.4 update and while accessing a file it got stuck, some files are white and I can access them. Other files are gray and I can not open them. The application goes white when it first opens up instead of just opening then there is a delay, then it eventually opens. It is stuck updating.
I have tried various things. 1) Rebooting, 2) hard reboot (holding down the off button and home key until the apple icon appears), 3) tried putting it in Airplane mode-reboot-then connect to computer and iTunes-then rebooted. 4) tried opening a file in another application- I get an error message that says : can't open spreadsheet- this spreadsheet is updating, wait for it to finish then try opening. 5) sending spreadsheet- I get an error message that says : this spreadsheet is updating, wait for it to finish then try sending. None of these have worked.
I am at my wits end I use these files for my business and I am self-employed, some files I can't access at all, this is very serious for me. If you know how to fix this please help me. I transferred all of my NECESSARY and IMPORTANT client files to Numbers from Excel, I've been using Numbers successfully for about 1 year.

Better to post your topic in the developer community > Developer Forums: Apple Support Communities

Is there a way to get phone numbers back on my iphone / or excel sheet?

Is there a way to get phone numbers back on my iphone / or excel sheet?
What I've done:
I've upgraded my iphone from 2.0 to 2.1. To be able to do this I've upgraded to the latest iTunes and switched my USB port several times until it was finaly installed. Then, despite iTunes taking 3 hours time for making backups, I found my phone to be completely empty when it was finished. So, I tried to restored the phone. This gave an error 1602 and bricked my phone. Tried it all over again two times more with same results.
The bottom line is that I have an empty phone and I really would like to have my phone numbers back. There's some 1.02 GB of backup information in the apple directory, so I guess they must be something there. But how do I know which file I need and how to decode it?

Your contacts should still be on whatever program you sync your iphone to (i.e. Outlook, address book).
The iphone is not a stand alone device. It is designed to be synced with a computer. If you have not been syncing with a compatible program, then you are out of luck. Your contacts are not included in the back-up because it is meant to be synced with your computer.
"Although iTunes backs up most of your iPhone and iPod touch settings, downloaded applications, and other information (Contacts, calendars, notes, images in the Camera Roll), your audio, video, and photo content are not included in the backup."
http://support.apple.com/kb/HT1414

Query to get the data of all the columns in a table except any one column

Can anyone please tell how to write a query to get the data of all the columns in a table except one particular column..
For Example:
Let us consider the EMP table.,
From this table except the column comm all the remaining columns of the table should be listed
For this we can write a query like this..
Select empno, ename, job, mgr, sal, hiredate, deptno from emp;
Just to avoid only one column, I mentioned all the remaining ( 7 ) columns of the table in the query..
As the EMP table consists only 8 columns, it doesn't seem much difficult to mention all the columns in the query,
but if a table have 100 columns in the table, then do we have to mention all the columns in the query..?
Is there any other way of writing the query to get the required result..?
Thanks..

Your best best it to just list all the columns. Any other method will just cause more headaches and complicated code.
If you really need to list all the columns for a table because you don't want to type them, just use something like...
SQL> ed
Wrote file afiedt.buf
1 select trim(',' from sys_connect_by_path(column_name,',')) as columns
2 from (select column_name, row_number() over (order by column_id) as column_id
3        from user_tab_cols
4        where column_name not in ('COMM')
5        and   table_name = 'EMP'
6       )
7 where connect_by_isleaf = 1
8 connect by column_id = prior column_id + 1
9* start with column_id = 1
SQL> /
COLUMNS
EMPNO,ENAME,JOB,MGR,HIREDATE,SAL,DEPTNO
SQL>

How to modify the query to get the output in a single row

Hi All,
Below is the query i have written it works fine
select DISTINCT right(left(CTACCT,13),4) AS LocationNum,
tODS_GLBalance.FiscalYearId AS FiscalYearId,
tODS_GLBalance.FiscalMonthOfYearId AS FiscalMonthOfYearId,
--tods_GLMetadata.Metric,
Case when
tods_GLMetadata.Metric = 'Gross Margin'
Then SUM(Balance)
Else 0
END AS GrossMargin,
Case when
tods_GLMetadata.Metric = 'Occupancy'
Then SUM(Balance)
Else 0
END AS Occupancy,
Case when
tods_GLMetadata.Metric = 'Payroll Dollars'
Then SUM(Balance)
Else 0
END AS Payroll,
Case when
tods_GLMetadata.Metric = 'CF Sales'
Then SUM(Balance)
Else 0
END AS OperatingSales,
Case when
tods_GLMetadata.Metric = 'Operations'
Then SUM(Balance)
Else 0
END AS OperatingExpenses
-- 0 as payroll
from ods.[JJill].[tODS_GLBalance]
inner join ods.Staging.tODS_INF_GLPCT ON tODS_GLBalance.PageNum = tODS_INF_GLPCT.CTPAGE
inner join ods.JJill.tods_GLMetadata ON tods_GLMetadata.AcctDescription = tODS_INF_GLPCT.CTDESC
where
(tODS_GLBalance.FiscalYearId = 2012) and
(tODS_GLBalance.FiscalMonthOfYearId = 2) and
(right(left(CTACCT,13),4)= 3020)
group by
right(left(CTACCT,13),4),
tODS_GLBalance.FiscalYearId,
tODS_GLBalance.FiscalMonthOfYearId,
tods_GLMetadata.Metric
This is the sample output,
LocationNum FiscalYearId FiscalMonthOfYearId GrossMargin Occupancy Payroll OperatingSales OperatingExpenses
3020 2012 2 -112477.00 0.00 0.00 0.00 0.00
3020 2012 2 0.00 0.00 0.00 -158288.94 0.00
3020 2012 2 0.00 0.00 0.00 0.00 5625.44
3020 2012 2 0.00 0.00 24185.79 0.00 0.00
3020 2012 2 0.00 31075.53 0.00 0.00 0.00
But, i am expecting the output to be something like this
LocationNum FiscalYearId FiscalMonthOfYearId GrossMargin Occupancy Payroll OperatingSales OperatingExpenses
3020 2012 2 -112477.00 31075.53 24185.79 -158288.94 5625.44
Can someone please help me with changing my query to get the desired output?
Please let me know if you have any questions.
Thanks

Try this:
SELECT DISTINCT
RIGHT(LEFT(CTACCT,13),4) AS LocationNum, tODS_GLBalance.FiscalYearId AS FiscalYearId, tODS_GLBalance.FiscalMonthOfYearId AS FiscalMonthOfYearId,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Gross Margin' THEN Balance ELSE 0 END ) AS GrossMargin,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Occupancy' THEN Balance ELSE 0 END ) AS Occupancy,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Payroll Dollars' THEN Balance ELSE 0 END ) AS Payroll,
SUM(CASE WHEN tods_GLMetadata.Metric = 'CF Sales' THEN Balance ELSE 0 END ) AS OperatingSales,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Operations' THEN Balance ELSE 0 END ) AS OperatingExpenses
FROM ods.[JJill].[tODS_GLBalance]
INNER JOIN ods.Staging.tODS_INF_GLPCT
ON tODS_GLBalance.PageNum = tODS_INF_GLPCT.CTPAGE
INNER JOIN ods.JJill.tods_GLMetadata
ON tods_GLMetadata.AcctDescription = tODS_INF_GLPCT.CTDESC
WHERE tODS_GLBalance.FiscalYearId = 2012
AND tODS_GLBalance.FiscalMonthOfYearId = 2
AND RIGHT(LEFT(CTACCT,13),4) = 3020
GROUP BY right(left(CTACCT,13),4), tODS_GLBalance.FiscalYearId, tODS_GLBalance.FiscalMonthOfYearId, tods_GLMetadata.Metric

Query to get all active customers in oracle apps

Hi All,
I want to grab all active customers account number, customer name, email address, tel number. Could any one give me the query to get it.
Thanks,
Red.

Hi,
Please refer to this document, and see if it helps.
Note: 68046.1 - SQL Scripts To Extract Information Relating To A Particular Customer
https://metalink2.oracle.com/metalink/plsql/ml2_documents.showDocument?p_database_id=NOT&p_id=68046.1
Regards,
Hussein

Need help in SQL query to get only distinct records

Hi all.
I am new to oracle SQL and i want to write a query to get only distinct values from 2 tables.
for example i hade 2 tables table1(employee_id,employee_no,grade) and another table2 with same structure.
for example data in table1 is
Employeeid employeeno Grade
1 101 A
1 101 B
1 101 E
1 101 D
and data in table 2 is
Employeeid employeeno Grade
1 101 A
1 101 B
1 101 E
i want to display only the fourth row like the data that doesnt exist in table2 i,e (1 101 D)
I had too much records in both tables and i jst want to see the records that is in table 1 not in table 2 only.
employeeid and employeeno are the same in both tables
I hope u understand my query. I user left outer join and right outer join bt it displays all the results that and matching and unmatching. I want jst unmatched records.
Any help is highly Appreciated.
Thanx in Advance.
I am using oracle 10G on windows

Try MINUS:
http://download.oracle.com/docs/cd/B19306_01/server.102/b14200/queries004.htm#i2054381
SQL> -- generating sample data:
SQL> with t1 as (
2 select 1 employeeid, 101 employeeno, 'A' grade from dual union
3 select 1, 101, 'B' from dual union
4 select 1, 101, 'E' from dual union
5 select 1, 101, 'D' from dual
6 )
7 , t2 as (
8 select 1 employeeid, 101 employeeno, 'A' grade from dual union
9 select 1, 101, 'B' from dual union
10 select 1, 101, 'E' from dual
11 )
12 --
13 -- actual query:
14 --
15 select employeeid
16 ,      employeeno
17 ,      grade
18 from   t1
19 minus
20 select employeeid
21 ,      employeeno
22 ,      grade
23 from   t2;
EMPLOYEEID EMPLOYEENO G
         1        101 D
1 row selected.

Steps of abap query--- to get the reports

steps of abap query -
to get the reports

Hi Deva,
For step by step procedure to create an ABAP query you can refer to the following links
http://www.thespot4sap.com/Articles/SAP_ABAP_Queries_Introduction.asp
http://allaboutsap.blogspot.com/2007/09/sap-query-step-by-step.html

How can I get serial numbers or the free versions of Adobe, Air, Flash Player 14, and Reader XI Pro

How can I get serial numbers or the free versions of Adobe, Air, Flash Player 14, and Reader XI Pro that I had installed on my computer before Microsoft crashed my computer and I had to do a fresh install? I finished reinstalling Win 8.1Pro on my computer thanks to Microsoft Lvl 1 Techies corrupting my Command Structure so nothing would work. I had recently taken a picture of my installed programs (control panel, uninstall programs list) so that I would be able to reinstall everything I needed. I can't seem to find an email for the Reader which I remember paying for, the others I believe were free installs. Can anyone help me out.

Safari Version 5.0.5 < from your first post
5.0.5 is an outdated version of Safari.
There is an update available for Safari for version 5.1.1
That may help.
Click your Apple menu icon top left in your screen the click Software Update
Restart your Mac after the updates are installed.
Try full screen ...
If you have problems using Software Update from the menu you can use the standalone installer here > Safari 5.1.1

I am having trouble getting a numbers spreadsheet to hold different formats in the same column. A column with a date formatted heading will not convert to $ for the cells below.   Any suggestions would help.

I am having trouble getting a numbers spreadsheet to hold different formats in the same column. A column with a date formatted heading will not convert to $ for the cells below.   Any suggestions would help.

Hi Wayne,
Thank you for this response. I have tried this but when I start enterring $ amounts some, such as $6.00, go in OK others such as $4.00 appear as a date ie 4 Oct 12.
Kind regards
Paul

Query to get the hierarchical results

Hi,
Please help me in writing a Query to get the hierarchical results. I want a result like follows...
course-----groupname---TotalMembers---NotStarted---INProgress---Completed
Course1---country1--------12---------------6----------3-------------3
Course1-----state11-------12---------------6----------3-------------3
Course1------District111--10---------------5----------0-------------0
Course1--------City1111----0---------------0----------0-------------0
Course1--------City1112----1---------------0----------0-------------1
Course1--------City1113----6---------------3----------2-------------1
Course1---country2--------12---------------6----------3-------------3
Course1----state21--------12---------------6----------3-------------3
Course1------District211--10---------------5----------0-------------0
Course1--------City2111----0---------------0----------0-------------0
Course1--------City2112----1---------------0----------0-------------1
Course1--------City2113----6---------------3----------2-------------1
Course2---country1--------12---------------6----------2-------------3
Course2----state11--------12---------------6----------2-------------3
Course2------District111--10---------------5----------0-------------0
Course2--------City1111----0---------------0----------0-------------0
Course2--------City1112----1---------------0----------0-------------1
Course2--------City1113----6---------------3----------1-------------2
Course2---country2--------12---------------6----------3-------------3
Course2-----state21-------12---------------6----------3-------------3
Course2------District211--10---------------5----------0-------------0
Course2--------City2111----0---------------0----------0-------------0
Course2--------City2112----1---------------0----------0-------------1
Course2--------City2113----6---------------3----------2-------------1
These are the Tables available to me.
(I have just given some examle data in tables, to get the idea)
"Groups" Table (This table gives the information of the group)
GROUPID-----NAME-------PARENTID
1---------Universe--------1
2---------country1--------1
3---------state11---------2
4---------District111-----3
5---------City1111--------4
6---------City1112--------4
7---------City1113--------4
8---------country2--------1
9---------state21---------8
10--------District211-----9
11--------City2111--------10
12--------City2112--------10
13--------City2113--------10
"Users" Table (This table provides the user information)
userID----FIRSTNAME---LASTNAME
user1-----------Jim-------Carry
user2-----------Tom-------lee
user3-----------sunny-----boo
user4-----------mary------mall
"User-Group" Tables (This table provides the relation between the groups
and the members)
GROUPID---userID
3-------------user1
3-------------user2
3-------------user4
4-------------user5
5-------------user6
5-------------user7
user_score (This table provides the user scores of different courses)
USERID----course-----STATUS
user1------course1-----complete
user1------course2-----NotStarted
user2------course1-----NotStarted
user2------course2-----complete
user3------course1-----complete
user3------course2-----InProgress
user4------course2-----complete
user4------course1-----NotStarted
I will explain the first four lines of the above result.
Course1---country1--------12---------------6----------4-------------2
Course1-----state11-------12---------------6----------4-------------2
Course1------District111--10---------------5----------3-------------2
Course1--------City1111----0---------------0----------0-------------0
Course1--------City1112----1---------------0----------0-------------1
Course1--------City1113----6---------------3----------2-------------1
# "city1111" group has 0 members
# "city1112" group has 1 member (1 member completed the course1)
# "city1113" group has 6 members(3 members notStarted,2 members
InProgress,1 member completed the course1)
# "District111" is the parent group of above three groups, and has 3
members.(2 members NotStarted,1 member InProgress the course1). But this
group has child groups, so the scores of this group has to rollup the
child groups scores also. Thats why it has 2+3+0+0=6 members Not
Started,1+2+0+0=3 members InProgress,0+0+1+1=2 members completed.
# "state11" group also same as the above group.
I am able to get the group hierarchy by using "Connect By" like follows
"select name,groupid,parentid from groups_info start with groupid=1 connect by parentid = prior groupid;"
But i want to get the result as i have mentioned in the begining of this discussion.
I am using oracle 8i (oracle8.1.7).
Thank you for any help
Srinivas M

This may not be exactly what you want,
but it should be fairly close:
SET      LINESIZE 100
SET      PAGESIZE 24
COLUMN   groupname FORMAT A20
SELECT   INITCAP (user_score.course) "course",
         groupnames.name "groupname",
         COUNT (*) "TotalMembers",
         SUM (NVL (DECODE (UPPER (user_score.status), 'NOTSTARTED', 1), 0)) "NotStarted",
         SUM (NVL (DECODE (UPPER (user_score.status), 'INPROGRESS', 1), 0)) "InProgress",
         SUM (NVL (DECODE (UPPER (user_score.status), 'COMPLETE', 1), 0)) "Completed"
FROM     user_score,
         user_group,
         (SELECT ROWNUM rn,
                 name,
                 groupid
          FROM   (SELECT     LPAD (' ', 2 * LEVEL - 2) || name AS name,
                             groupid
                  FROM       groups
                  START WITH groupid = 1
                  CONNECT BY PRIOR groupid = parentid)) groupnames
WHERE    user_score.userid = user_group.userid
AND      user_group.groupid IN
         (SELECT     groupid
          FROM       groups
          START WITH groupid = groupnames.groupid
          CONNECT BY PRIOR groupid = parentid)
GROUP BY user_score.course, groupnames.name, groupnames.rn
ORDER BY user_score.course, groupnames.rn
I entered the minimal test data that you
provided and a bit more and got this result
(It was formatted as you requested,
but I don't know if it will display properly
on this post, or wrap around):
course groupname            TotalMembers NotStarted InProgress Completed
Course1 Universe                        6          2          0          4
Course1   country1                      5          2          0          3
Course1     state11                     5          2          0          3
Course1       District111               2          0          0          2
Course1         City1112                1          0          0          1
Course1         City1113                1          0          0          1
Course1   country2                      1          0          0          1
Course1     state21                     1          0          0          1
Course1       District211               1          0          0          1
Course1         City2113                1          0          0          1
Course2 Universe                        5          1          1          3
Course2   country1                      4          1          1          2
Course2     state11                     4          1          1          2
Course2       District111               1          0          1          0
Course2         City1113                1          0          1          0
Course2   country2                      1          0          0          1
Course2     state21                     1          0          0          1
Course2       District211               1          0          0          1
Course2         City2113                1          0          0          1
Here is the test data that I used, in case
anyone else wants to play with it:
create table groups
(groupid number,
   name     varchar2(15),
   parentid number)
insert into groups
values (1,'Universe',null)
insert into groups
values (2,'country1',1)
insert into groups
values (3,'state11',2)
insert into groups
values (4,'District111',3)
insert into groups
values (5,'City1111',4)
insert into groups
values (6,'City1112',4)
insert into groups
values (7,'City1113',4)
insert into groups
values (8,'country2',1)
insert into groups
values (9,'state21',8)
insert into groups
values (10,'District211',9)
insert into groups
values (11,'City2111',10)
insert into groups
values (12,'City2112',10)
insert into groups
values (13,'City2113',10)
create table user_group
(groupid number,
   userid varchar2(5))
insert into user_group
values (3,'user1')
insert into user_group
values (3,'user2')
insert into user_group
values (3,'user4')
insert into user_group
values (4,'user5')
insert into user_group
values (5,'user6')
insert into user_group
values (5,'user7')
insert into user_group
values (7,'user8')
insert into user_group
values (13,'user9')
insert into user_group
values (11,'use11')
insert into user_group
values (6,'use6')
create table user_score
(userid varchar2(5),
   course varchar2(7),
   status varchar2(10))
insert into user_score
values ('use6','course1','complete')
insert into user_score
values ('user9','course1','complete')
insert into user_score
values ('user9','course2','complete')
insert into user_score
values ('user8','course1','complete')
insert into user_score
values ('user8','course2','InProgress')
insert into user_score
values ('user1','course1','complete')
insert into user_score
values ('user1','course2','NotStarted')
insert into user_score
values ('user2','course1','NotStarted')
insert into user_score
values ('user2','course2','complete')
insert into user_score
values ('user3','course1','complete')
insert into user_score
values ('user3','course2','InProgress')
insert into user_score
values ('user4','course2','complete')
insert into user_score
values ('user4','course1','NotStarted')

Query to get IBAN numbers

Similar Messages

Maybe you are looking for