Query to get the Cumulative salary from EMP
SQL query to find out cumulative salary.
EX:
EMPNO ENAME SAL CUMSAL
1 AAAA 1500 1500
2 BBBB 1000 2500
3 CCCC 1250 3750
Hi Madhan,
If you talking abt query to find the total sal of each employee i.e., SAL + CUMSAL then you can use the below query:
select a.empno,a.ename,a.sal + b.cumsal totalsal from
emp a, emp b
where a.empno = b.empno;
Regards,
Murali Mohan
Similar Messages
-
Query to get the po amount from the pr
Hi
how to get the POnumber and PO amount from the Pr number. there are hundred's of PO's raise against the PR's
and want to know the amount from their PO's to know the avaible fund left with the department.
Regards
ArifuddinHi Madhan,
If you talking abt query to find the total sal of each employee i.e., SAL + CUMSAL then you can use the below query:
select a.empno,a.ename,a.sal + b.cumsal totalsal from
emp a, emp b
where a.empno = b.empno;
Regards,
Murali Mohan -
How to get second maximum salary from employee table(sql query)
how to get second maximum salary from employee table(sql query)
dude there is no matter of structure .........that user already said its from employee table ...............its basic table in sql and there is no need to specify the table structure
.........i think u got my point I think you are the one who didn't understand Sarma's point.
Give a man a fish and you feed him once. Teach a man how to fish and you feed him a life long.
>
and the query is
select max(sal) from emp where sal<(select max(sal)
from emp);
this will give the 2nd max salary from the emp tableBtw: You solution is bad, because it needs to scan and sort the table emp twice. And a better solution has been given already.
Message was edited by:
Sven W. - reordered statements -
RQL Query to get the specific range of product items from product catalog.
Hi All,
I need to do the batch wise query to product catalog.
For that i have use Query builder but that is giving me repeated items, now i wanted to use RQL using rqlStatement.
Please help me in solving the issue.
Query which i have used using QueryBuilder.
RepositoryView productView = productRepo.getView("product");
QueryBuilder productBuilder = productView.getQueryBuilder();
Query productQuery = productBuilder.createUnconstrainedQuery();
RepositoryItems[] productItems = productView.executeQuery(productQuery,startIndex,endIndex);
Can anybody help me in writing RQL Query to get the specific range of product items from product catalog.Hi Shakuntala,
There is no executeQuery method defined in RqlStatement Interface, which will accept index for output result.
So As far as I know, what u are trying to achieve is not possible with RQL statements OOTB way.U can consider range of results based on some condition from Repository items.
Please let me know if u find any way to implement it.
Above Query builder should always return different ids if range is not overlapping with previous range.
Please verify that repeated items ids are same or different,
Quoting from API docs:
RepositoryItem[] executeQuery(Query pQuery,
int pStartingIndex,
int pEndingIndex)
throws RepositoryException
Executes the given query and returns an array of matching RepositoryItems, which are contained within a total potential result set. For example used if one wanted to retrieve elements 50-60 from a query which could return 100 elements.
Regards,
Nitin. -
Get the record count from a query
Hi,
does anyone know how to get the record count from a sql query?
e.g: I've got a ResultSet from the Statement.excuteQuery(), and I want to know how many records this ResultSet contains, how to get this?
I'd read thoughout the documents of Statement and ResultSet, but couldn't find a solution, do I have to use another seperate query such as "select count(*)" to do this?
thanks.
Yang LiuIf you are not using a scrollable result set then the following is the best way to do it.
there are several key words in SQL that can be used, the one you are interested in is count();
so if your query at the moment is
"select col1, col2, col3 from my_table where col2=? and col3=?"you can work out how many rows will be returned by executing this command first
"select count(col1) from my_table where col2=? and col3=?"this will return a result set with one row and one column, you can get the row count as follows:
ResultSet rs = ps.executeQuery();
int rowCount = rs.getInt(1);I hope this helps :) -
Query to get the data of all the columns in a table except any one column
Can anyone please tell how to write a query to get the data of all the columns in a table except one particular column..
For Example:
Let us consider the EMP table.,
From this table except the column comm all the remaining columns of the table should be listed
For this we can write a query like this..
Select empno, ename, job, mgr, sal, hiredate, deptno from emp;
Just to avoid only one column, I mentioned all the remaining ( 7 ) columns of the table in the query..
As the EMP table consists only 8 columns, it doesn't seem much difficult to mention all the columns in the query,
but if a table have 100 columns in the table, then do we have to mention all the columns in the query..?
Is there any other way of writing the query to get the required result..?
Thanks..Your best best it to just list all the columns. Any other method will just cause more headaches and complicated code.
If you really need to list all the columns for a table because you don't want to type them, just use something like...
SQL> ed
Wrote file afiedt.buf
1 select trim(',' from sys_connect_by_path(column_name,',')) as columns
2 from (select column_name, row_number() over (order by column_id) as column_id
3 from user_tab_cols
4 where column_name not in ('COMM')
5 and table_name = 'EMP'
6 )
7 where connect_by_isleaf = 1
8 connect by column_id = prior column_id + 1
9* start with column_id = 1
SQL> /
COLUMNS
EMPNO,ENAME,JOB,MGR,HIREDATE,SAL,DEPTNO
SQL> -
How can i get the maximum salary first in the order of ascending
Hi,
How can i get the maximum salary first in the order of ascending.
I need the sql query.
my output should like:
Emp_Name Salary
A 5000
SS 100
AA 300
DD 700
WW 2000
Thanks,
MuthyaM.Here is an example :
SQL> with mytable as
2 ( select 'aa' as col1, 300 col2 from dual union all
3 select 'ss' as col1, 100 col2 from dual union all
4 select 'a' as col1, 5000 col2 from dual union all
5 select 'dd' as col1, 700 col2 from dual union all
6 select 'ww' as col1, 2000 col2 from dual )
7 select col1, col2
8 from mytable
9 order by decode(row_number() over (order by col2 desc),1,0,1),col2;
CO COL2
a 5000
ss 100
aa 300
dd 700
ww 2000
SQL>Nicolas. -
Can I get a query to get the output data like 4th column instead of 3rd col
Can I get a query to get the output data like 4th column instead of 3rd column ?
SQL> select emp.deptno, empno, rownum from emp, dept where emp.deptno=dept.deptno;
DEPTNO EMPNO ROWNUM
10 7782 *1* *1*
10 7839 *2* *2*
10 7934 *3* *3*
20 7369 *4* *1*
20 7876 *5* *2*
20 7902 *6* *3*
20 7788 *7* *4*
20 7566 *8* *5*
30 7499 *9* *1*
30 7698 *10* *2*
30 7654 *11* *3*
30 7900 *12* *4*
30 7844 *13* *5*
30 7521 *14* *6*
14 rows selected.SQL> select emp.deptno, emp.empno,
2 row_number() over(order by emp.deptno, emp.empno) rn,
3 row_number() over(partition by emp.deptno order by emp.empno) dept_rn
4 from emp, dept
5 where emp.deptno=dept.deptno
6 order by emp.deptno, emp.empno;
DEPTNO EMPNO RN DEPT_RN
10 7782 1 1
10 7839 2 2
10 7934 3 3
20 7369 4 1
20 7566 5 2
20 7788 6 3
20 7876 7 4
20 7902 8 5
30 7499 9 1
30 7521 10 2
30 7654 11 3
30 7698 12 4
30 7844 13 5
30 7900 14 6
14 rows selected.Regards,
Dima -
How to get 2 maximum salary from salary field?
how to get 2 maximum salary from salary field data?
like 1000
5000
8600
2000
3000
u want 8600 in ist place and 5000 in second place ?
cud u plz suggest me any query?Hi,
If already data is in internal table then
DATA : v_cnt TYPE i.
SORT ITAB BY salary DESCENDING.
LOOP AT ITAB.
v_cnt = v_cnt + 1.
IF v_cnt > 2.
EXIT.
ENDIF.
MOVE : itab-salary to ITAB1.
ENDLOOP.
if you want extract data from database table then slect the data inot internal table and do like above.
Pls. reward if useful... -
How can I get the checked item from a list that is generated automatically?
I am still pretty new a CF and could really use some help. I am trying to get each item that is checked from a page that generates the list automatically from a query and get the associated textbox text with it. For example:
<!--- Start Get Data Hierarchy List--->
<cfquery datasource="MyDatasource" name="qry_GetData">
SELECT C.taxonomy_id, C.lvl, C.taxonomy_name, C.taxonomy_tree, C.taxonomy_guid, C.taxonomy_standard_name
FROM dbo.taxonomy AS P
JOIN dbo.taxonomy AS C
ON P.taxonomy_id = 21
AND C.hid.IsDescendantOf(P.hid) = 1
AND C.lvl = 3
</cfquery>
<!--- Start Get Data Hierarchy List--->
<cfloop query="qry_GetData">
<input type="checkbox" name="cbox_PE_SelTax#taxonomy_id#" value="#taxonomy_name#"><font size="4" color="3399FF"> #taxonomy_name#</font>
<br />
- Details of experience with #taxonomy_name#:<input name="tbox_PE_SelTax#taxonomy_id#" id="tbox_PE_SelTax#taxonomy_id#" size="50%">
<br />
<br />
</cfloop>Dave,
Thank you for your help so far. I must not be asking the right question. Here is the whole breakdown. I am writing this page to collect the users information, Name, Title, Company, and technologies they are familiar with. I then want that information emailed to me upon submission. The point I am running into a problem (even with your last post) is how to write the action part of it that will email the checked items to me. I cannot figure out if I need to use CFLOOP (if so, how) or what the best method is. I am a very visual lerner and can understand how code works easily, but I have not found any examples for my situation. Again, I really appriciate all of your help thus far.
Thank you! -
Is there a way to get the correct order from the dependent types of a sche
Hi ,
I have a CT facing the following problem:
When trying to built a SQL script to create all the object types within a schema using the DBMS_METADATA packages.
Did insert in a table the names of the types that will be exported following a concrete order, next loop into the table and call the DBMS_METADATA package for each row.
These type are depedent between them, there are some type attributes calling other types and here the issue
First : try to generate the order by created column of dba_objects and when the generated SQL script is launched a lot of type appearing as incomplete state due to the order isn't correct.
Second : try to insert the table ordering by object_id colums of dba_tables view, it appears incomplete types too.
Currently want to insert the table using a recursive query with connect by against the dba_type_attrs starting with the rows when ATTR_TYPE_NAME is not null (the types that are called by other types), but this way has a issue dificult to resolve: the roots of hierarchy are the rows when ATTR_TYPE_NAME is not null and we've dependencies between roots nodes
The question is is there a way to get the correct order from the dependent types of a schema?
Platform: IBM SP AIX
DB version: 9.2.0.7
Any help will be appreciated .
Thanks in advance.The xxx_dependencies view should give you the dependencies betwee nthe various types. I would look at something along the lines of:
SELECT object_name, referenced_name
FROM (SELECT o.object_name, d.referenced_name
FROM user_objects o, user_dependencies d
WHERE o.object_name = d.name(+) and
o.object_type = d.type(+) and
d.referenced_type(+) = 'TYPE' and
o.object_type = 'TYPE')
START WITH referenced_name IS NULL
CONNECT BY PRIOR object_name = referenced_nameThe outer join between user_objects and user_dependencies is required to generate the names of types which are not dependent on other types, or do not have other types dependent on them.
HTH
John -
How to modify the query to get the output in a single row
Hi All,
Below is the query i have written it works fine
select DISTINCT right(left(CTACCT,13),4) AS LocationNum,
tODS_GLBalance.FiscalYearId AS FiscalYearId,
tODS_GLBalance.FiscalMonthOfYearId AS FiscalMonthOfYearId,
--tods_GLMetadata.Metric,
Case when
tods_GLMetadata.Metric = 'Gross Margin'
Then SUM(Balance)
Else 0
END AS GrossMargin,
Case when
tods_GLMetadata.Metric = 'Occupancy'
Then SUM(Balance)
Else 0
END AS Occupancy,
Case when
tods_GLMetadata.Metric = 'Payroll Dollars'
Then SUM(Balance)
Else 0
END AS Payroll,
Case when
tods_GLMetadata.Metric = 'CF Sales'
Then SUM(Balance)
Else 0
END AS OperatingSales,
Case when
tods_GLMetadata.Metric = 'Operations'
Then SUM(Balance)
Else 0
END AS OperatingExpenses
-- 0 as payroll
from ods.[JJill].[tODS_GLBalance]
inner join ods.Staging.tODS_INF_GLPCT ON tODS_GLBalance.PageNum = tODS_INF_GLPCT.CTPAGE
inner join ods.JJill.tods_GLMetadata ON tods_GLMetadata.AcctDescription = tODS_INF_GLPCT.CTDESC
where
(tODS_GLBalance.FiscalYearId = 2012) and
(tODS_GLBalance.FiscalMonthOfYearId = 2) and
(right(left(CTACCT,13),4)= 3020)
group by
right(left(CTACCT,13),4),
tODS_GLBalance.FiscalYearId,
tODS_GLBalance.FiscalMonthOfYearId,
tods_GLMetadata.Metric
This is the sample output,
LocationNum FiscalYearId FiscalMonthOfYearId GrossMargin Occupancy Payroll OperatingSales OperatingExpenses
3020 2012 2 -112477.00 0.00 0.00 0.00 0.00
3020 2012 2 0.00 0.00 0.00 -158288.94 0.00
3020 2012 2 0.00 0.00 0.00 0.00 5625.44
3020 2012 2 0.00 0.00 24185.79 0.00 0.00
3020 2012 2 0.00 31075.53 0.00 0.00 0.00
But, i am expecting the output to be something like this
LocationNum FiscalYearId FiscalMonthOfYearId GrossMargin Occupancy Payroll OperatingSales OperatingExpenses
3020 2012 2 -112477.00 31075.53 24185.79 -158288.94 5625.44
Can someone please help me with changing my query to get the desired output?
Please let me know if you have any questions.
ThanksTry this:
SELECT DISTINCT
RIGHT(LEFT(CTACCT,13),4) AS LocationNum, tODS_GLBalance.FiscalYearId AS FiscalYearId, tODS_GLBalance.FiscalMonthOfYearId AS FiscalMonthOfYearId,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Gross Margin' THEN Balance ELSE 0 END ) AS GrossMargin,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Occupancy' THEN Balance ELSE 0 END ) AS Occupancy,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Payroll Dollars' THEN Balance ELSE 0 END ) AS Payroll,
SUM(CASE WHEN tods_GLMetadata.Metric = 'CF Sales' THEN Balance ELSE 0 END ) AS OperatingSales,
SUM(CASE WHEN tods_GLMetadata.Metric = 'Operations' THEN Balance ELSE 0 END ) AS OperatingExpenses
FROM ods.[JJill].[tODS_GLBalance]
INNER JOIN ods.Staging.tODS_INF_GLPCT
ON tODS_GLBalance.PageNum = tODS_INF_GLPCT.CTPAGE
INNER JOIN ods.JJill.tods_GLMetadata
ON tods_GLMetadata.AcctDescription = tODS_INF_GLPCT.CTDESC
WHERE tODS_GLBalance.FiscalYearId = 2012
AND tODS_GLBalance.FiscalMonthOfYearId = 2
AND RIGHT(LEFT(CTACCT,13),4) = 3020
GROUP BY right(left(CTACCT,13),4), tODS_GLBalance.FiscalYearId, tODS_GLBalance.FiscalMonthOfYearId, tods_GLMetadata.Metric -
How to get the Node Value from XmlValue result?
Hi ,
I am not able to get the Node Value from the result. In my XQuery im selecting till a Node, if i change my query as
collection('PhoneBook')/phone_book/contact_person/address/string()", qc);
im getting the node value, but here the problem is its not a Node so i cannot get the Node name.
So how can i get the Node Name and Node value together?
any help please ????
XML :
<?xml version="1.0" encoding="UTF-8"?>
<phone_book>
<contact_person>
<name>
<first_name>Michael</first_name>
<second_name>Harrison</second_name>
</name>
<address city="yyyyy" pincode="600017" state="xxxxx">
176 Ganesan street, Janakinagar, alwarthirunagar
</address>
</contact_person>
<phone_number type="mobile">9881952233</phone_number>
<phone_number type="home">044-24861311</phone_number>
<phone_number type="office">080-12651174</phone_number>
</phone_book>
Code:
XmlQueryContext qc = manager.createQueryContext();
XmlResults rs = manager.query
("collection('PhoneBook')/phone_book/contact_person/address", qc);
while(rs.hasNext()){
XmlValue val = rs.next();
System.out.println(val.getNodeName() + " = [ " + val.getNodeValue() + " ] ");
Output
address = [ ]You are right, this seemed un-intuitive to me too, but I finally understood how it's done.
The "value" of a node is actually the total amount of text that is not contained in any of the node's child nodes (if any). So a node with child nodes can still have text value.
To get the 'value' of an element node, you must therefore concatenate the values of all children of type "XmlValue::TEXT_NODE", of that node. Try it.
In your example, the <address> node has no child elements, my guess is that BDB XML stores the address string "176 Ganesan street, Janakinagar, alwarthirunagar" inside a child node of <address> node (of type XmlValue::TEXT_NODE) because you wrote the string on a separate line. -
What is the best way to get the notes content from iphone 4 to 4s without doing a restore? i want the new phone to be totally new but not sure how to get notes content across. If I do a restore as I have when previously from one iphone to another it has shown (in settings, usage) the cumulative usage from previous phones so all the hours of calls on all previous iphones will be displayed even though its brand new. Anyone know how I can get my notes (from standard iphone notes app) to my new iphone 4s without restoring from previous iphone 4. Thanks for any help offered.
First, if you haven't updated to iTunes 10.5, please update now as you will need it for the iPhone 4S and iOS 5.
Once you're done installing iTunes 10.5, open it. Connect your iPhone to iTunes using the USB cable. Once your iPhone pops up right click on it. For example: an iPhone will appear and it will say "Ryan's iPhone."
Right click on it and select "Backup" from the dropdown menu. It will start backing up. This should backup your notes.
Please tell me if you have any problems with backing up.
Once you backup and get your iPhone 4S, you must follow these steps. If you don't follow these steps, you will not be able to get your notes on your new iPhone 4S.
Open up iTunes again then right click on your device (iPhone 4S). Once you do you will see a dropdown menu. It will say "Restore from Backup..." Select this and it'll ask for a backup, select it from the dropdown menu. For example "Ryan's iPhone - October 12, 2011." Pick that and it will restore to your backup. Do this when you get your iPhone 4S so you will not lose anything. Even though you're restoring, you're getting back, since you're getting the previous settings, notes, contacts, mail and other settings from your old iPhone. You'll still have Siri though! So, restore when you first get it. Also frequently backup your device, as it will be worth it. You can restore from a backup if something goes wrong or save your data for a future update.
Once you do that, you should have your notes on your new iPhone 4S and iOS 5.
Please tell me if you need any help.
I hoped I answered your questions and solved your problem! -
Query to get the hierarchical results
Hi,
Please help me in writing a Query to get the hierarchical results. I want a result like follows...
course-----groupname---TotalMembers---NotStarted---INProgress---Completed
Course1---country1--------12---------------6----------3-------------3
Course1-----state11-------12---------------6----------3-------------3
Course1------District111--10---------------5----------0-------------0
Course1--------City1111----0---------------0----------0-------------0
Course1--------City1112----1---------------0----------0-------------1
Course1--------City1113----6---------------3----------2-------------1
Course1---country2--------12---------------6----------3-------------3
Course1----state21--------12---------------6----------3-------------3
Course1------District211--10---------------5----------0-------------0
Course1--------City2111----0---------------0----------0-------------0
Course1--------City2112----1---------------0----------0-------------1
Course1--------City2113----6---------------3----------2-------------1
Course2---country1--------12---------------6----------2-------------3
Course2----state11--------12---------------6----------2-------------3
Course2------District111--10---------------5----------0-------------0
Course2--------City1111----0---------------0----------0-------------0
Course2--------City1112----1---------------0----------0-------------1
Course2--------City1113----6---------------3----------1-------------2
Course2---country2--------12---------------6----------3-------------3
Course2-----state21-------12---------------6----------3-------------3
Course2------District211--10---------------5----------0-------------0
Course2--------City2111----0---------------0----------0-------------0
Course2--------City2112----1---------------0----------0-------------1
Course2--------City2113----6---------------3----------2-------------1
These are the Tables available to me.
(I have just given some examle data in tables, to get the idea)
"Groups" Table (This table gives the information of the group)
GROUPID-----NAME-------PARENTID
1---------Universe--------1
2---------country1--------1
3---------state11---------2
4---------District111-----3
5---------City1111--------4
6---------City1112--------4
7---------City1113--------4
8---------country2--------1
9---------state21---------8
10--------District211-----9
11--------City2111--------10
12--------City2112--------10
13--------City2113--------10
"Users" Table (This table provides the user information)
userID----FIRSTNAME---LASTNAME
user1-----------Jim-------Carry
user2-----------Tom-------lee
user3-----------sunny-----boo
user4-----------mary------mall
"User-Group" Tables (This table provides the relation between the groups
and the members)
GROUPID---userID
3-------------user1
3-------------user2
3-------------user4
4-------------user5
5-------------user6
5-------------user7
user_score (This table provides the user scores of different courses)
USERID----course-----STATUS
user1------course1-----complete
user1------course2-----NotStarted
user2------course1-----NotStarted
user2------course2-----complete
user3------course1-----complete
user3------course2-----InProgress
user4------course2-----complete
user4------course1-----NotStarted
I will explain the first four lines of the above result.
Course1---country1--------12---------------6----------4-------------2
Course1-----state11-------12---------------6----------4-------------2
Course1------District111--10---------------5----------3-------------2
Course1--------City1111----0---------------0----------0-------------0
Course1--------City1112----1---------------0----------0-------------1
Course1--------City1113----6---------------3----------2-------------1
# "city1111" group has 0 members
# "city1112" group has 1 member (1 member completed the course1)
# "city1113" group has 6 members(3 members notStarted,2 members
InProgress,1 member completed the course1)
# "District111" is the parent group of above three groups, and has 3
members.(2 members NotStarted,1 member InProgress the course1). But this
group has child groups, so the scores of this group has to rollup the
child groups scores also. Thats why it has 2+3+0+0=6 members Not
Started,1+2+0+0=3 members InProgress,0+0+1+1=2 members completed.
# "state11" group also same as the above group.
I am able to get the group hierarchy by using "Connect By" like follows
"select name,groupid,parentid from groups_info start with groupid=1 connect by parentid = prior groupid;"
But i want to get the result as i have mentioned in the begining of this discussion.
I am using oracle 8i (oracle8.1.7).
Thank you for any help
Srinivas MThis may not be exactly what you want,
but it should be fairly close:
SET LINESIZE 100
SET PAGESIZE 24
COLUMN groupname FORMAT A20
SELECT INITCAP (user_score.course) "course",
groupnames.name "groupname",
COUNT (*) "TotalMembers",
SUM (NVL (DECODE (UPPER (user_score.status), 'NOTSTARTED', 1), 0)) "NotStarted",
SUM (NVL (DECODE (UPPER (user_score.status), 'INPROGRESS', 1), 0)) "InProgress",
SUM (NVL (DECODE (UPPER (user_score.status), 'COMPLETE', 1), 0)) "Completed"
FROM user_score,
user_group,
(SELECT ROWNUM rn,
name,
groupid
FROM (SELECT LPAD (' ', 2 * LEVEL - 2) || name AS name,
groupid
FROM groups
START WITH groupid = 1
CONNECT BY PRIOR groupid = parentid)) groupnames
WHERE user_score.userid = user_group.userid
AND user_group.groupid IN
(SELECT groupid
FROM groups
START WITH groupid = groupnames.groupid
CONNECT BY PRIOR groupid = parentid)
GROUP BY user_score.course, groupnames.name, groupnames.rn
ORDER BY user_score.course, groupnames.rn
I entered the minimal test data that you
provided and a bit more and got this result
(It was formatted as you requested,
but I don't know if it will display properly
on this post, or wrap around):
course groupname TotalMembers NotStarted InProgress Completed
Course1 Universe 6 2 0 4
Course1 country1 5 2 0 3
Course1 state11 5 2 0 3
Course1 District111 2 0 0 2
Course1 City1112 1 0 0 1
Course1 City1113 1 0 0 1
Course1 country2 1 0 0 1
Course1 state21 1 0 0 1
Course1 District211 1 0 0 1
Course1 City2113 1 0 0 1
Course2 Universe 5 1 1 3
Course2 country1 4 1 1 2
Course2 state11 4 1 1 2
Course2 District111 1 0 1 0
Course2 City1113 1 0 1 0
Course2 country2 1 0 0 1
Course2 state21 1 0 0 1
Course2 District211 1 0 0 1
Course2 City2113 1 0 0 1
Here is the test data that I used, in case
anyone else wants to play with it:
create table groups
(groupid number,
name varchar2(15),
parentid number)
insert into groups
values (1,'Universe',null)
insert into groups
values (2,'country1',1)
insert into groups
values (3,'state11',2)
insert into groups
values (4,'District111',3)
insert into groups
values (5,'City1111',4)
insert into groups
values (6,'City1112',4)
insert into groups
values (7,'City1113',4)
insert into groups
values (8,'country2',1)
insert into groups
values (9,'state21',8)
insert into groups
values (10,'District211',9)
insert into groups
values (11,'City2111',10)
insert into groups
values (12,'City2112',10)
insert into groups
values (13,'City2113',10)
create table user_group
(groupid number,
userid varchar2(5))
insert into user_group
values (3,'user1')
insert into user_group
values (3,'user2')
insert into user_group
values (3,'user4')
insert into user_group
values (4,'user5')
insert into user_group
values (5,'user6')
insert into user_group
values (5,'user7')
insert into user_group
values (7,'user8')
insert into user_group
values (13,'user9')
insert into user_group
values (11,'use11')
insert into user_group
values (6,'use6')
create table user_score
(userid varchar2(5),
course varchar2(7),
status varchar2(10))
insert into user_score
values ('use6','course1','complete')
insert into user_score
values ('user9','course1','complete')
insert into user_score
values ('user9','course2','complete')
insert into user_score
values ('user8','course1','complete')
insert into user_score
values ('user8','course2','InProgress')
insert into user_score
values ('user1','course1','complete')
insert into user_score
values ('user1','course2','NotStarted')
insert into user_score
values ('user2','course1','NotStarted')
insert into user_score
values ('user2','course2','complete')
insert into user_score
values ('user3','course1','complete')
insert into user_score
values ('user3','course2','InProgress')
insert into user_score
values ('user4','course2','complete')
insert into user_score
values ('user4','course1','NotStarted')
Maybe you are looking for
-
This is the message in the dialog box that showed up: Firefox security alert Scanning of your system is currently on, please wait until the end. Your system affected by numerous virus attacks, Mozilla Firefox recommends you to install proper software
-
How to display a empty (non-existing) column and info in LAST row
Hello! I´m trying to create the code that diplays all authors (author.name), empty COLUMN, NR_OF_BOOK_PER_AUTHOR. I want the LAST ROW to display: (column1) the word 'Sum:', (column2) nr of authors, (column3) total sum of all books Headache: How do I
-
Support Package uprade in endless loop
Hello experts, we have a SP upgrade (from ECC level 10 to SP-level 16) running in a queue that is getting imported via SPAM (version 36). The import has been running for more than 24 hours, is this normal or did I hit an endless loop? I noticed it ha
-
MBP Retina 15" MID 2014 2.5Ghz OS X Yosemite 10.10 I have a external HDD and want to erase and restore my laptop so I can install windows via Bootcamp Assistant but I don't know how to boot from a clone to fix the issue and am not sure if when I eras
-
A question about Auto Save, Versions and Preview.
I haven't upgraded to Lion (yet?). I'm trying to understand what impact Lion will have on my workflow. Do I understand right that it is not possible to turn off Lion's Auto Save? And that the autosavings are stored in a hidden sqlLite data base? I us