Query to pick only first value/day

Question

I have a table with Account, Complaint and Date columns. Each Account can log multiple complaints each day.
Now i need a query to pick only the first complaint in a day from each account. If the same account logged in a complaint next day or any day after i want to show that as well.
Help me with your ideas. Thanks in advance for your help.

Answer 1

Maybe
with
first_complaints as
(select account,
        date
   from (select account,
                date,
                row_number() over (partition by account order by date) rn
           from a_table
  where rn = 1
select account,
       complaint,
       date
  from a_table t
where account in (select account
                     from first_complaints
   and date >= (select date
                  from first_complaints
                 where account = t.account
Regards
Etbin
Message was edited by: Etbin
rereading: If the same account logged in a complaint next day or any day after i want to show that as well.
The query above is just select * from a_table
Now:
if you want to show just the first complaints in a day for any following date, John answered that already (it's just the first_complaints of mine)
if you want to show all the complaints in any following date, you have to exclude all the complaints logged the first day except the first one
select account,
       complaint,
       date
  from (select account,
               complaint,
               date,
               row_number() over (partition by account order by date) rn
          from a_table
       ) t
where date != (select min(date)
                  from a_table
                 where account = t.account
   or rn = 1