Query to Table with two relation

Dear All,
I have MasterUnit (UnitCode,unitItem,SRunitTypeID,unitItemValue, SRUnitGroupID).
MasterUnit table will join with Table SRMaster ( SRCode,SRItemID,SRName ) to get SRName.
I want show SRName from MasterUnit.SRunitTypeID, MasterUnit.SRUnitGroupID
I just try: select * from MasterUnit left join SRMaster on MasterUnit.SRunitTypeID=SRMaster.SRItemID
I only got SRName of SRunitTypeID.
How that i can show SRName of SRunitTypeID and SRUnitGroupID ?
Please Help.
Best regards,
Surbakti

you need another join... 
select * from MasterUnit
left join SRMaster
on MasterUnit.SRunitTypeID=SRMaster.SRItemID
left join SRMaster SR
on MasterUnit.SRUnitGroupID =Sr.SRItemID
Thanks,
Saurabh 
http://www.linkedin.com/in/sbhadauria http://www.experts-exchange.com/M_6313078.html

Similar Messages

  • Dynamic Table with two columns

    Hi!
    i have to create a Dynamic Table with two columns having 5-5 links each with some text...... three links r based on certain conditions....they r visible only if condition is true...
    if the links r not visible in this case another links take it's place & fill the cell.
    links/text is coming from database.
    i am using Struts with JSP IDE netbeans
    Please help me
    BuntyIndia

    i wanna do something like this
    <div class="box_d box_margin_right">
              <ul class="anchor-bullet">
              <c:forEach items="${data.faqList}" var="item" varStatus="status"
                        begin="0" end="${data.faqListSize/2-1}">
                        <li>${item}</li>
                   </c:forEach>
              </ul>
              </div>
              <div class="box_d">
              <ul class="anchor-bullet">
              <c:forEach items="${data.faqList}" var="item" varStatus="status"
                        begin="${data.faqListSize/2}" end="${data.faqListSize}">
                        <li>${item}</li>
                   </c:forEach>
              </ul>
              </div>
    wanna divide table in two columns....if one link got off due to condition other one take it's position...
    I have created a textorderedlist
    Bunty

  • ORA-00604 ORA-00904 When query partitioned table with partitioned indexes

    Got ORA-00604 ORA-00904 When query partitioned table with partitioned indexes in the data warehouse environment.
    Query runs fine when query the partitioned table without partitioned indexes.
    Here is the query.
    SELECT al2.vdc_name, al7.model_series_name, COUNT (DISTINCT (al1.vin)),
    al27.accessory_code
    FROM vlc.veh_vdc_accessorization_fact al1,
    vlc.vdc_dim al2,
    vlc.model_attribute_dim al7,
    vlc.ppo_list_dim al18,
    vlc.ppo_list_indiv_type_dim al23,
    vlc.accy_type_dim al27
    WHERE ( al2.vdc_id = al1.vdc_location_id
    AND al7.model_attribute_id = al1.model_attribute_id
    AND al18.mydppolist_id = al1.ppo_list_id
    AND al23.mydppolist_id = al18.mydppolist_id
    AND al23.mydaccytyp_id = al27.mydaccytyp_id
    AND ( al7.model_series_name IN ('SCION TC', 'SCION XA', 'SCION XB')
    AND al2.vdc_name IN
    ('PORT OF BALTIMORE',
    'PORT OF JACKSONVILLE - LEXUS',
    'PORT OF LONG BEACH',
    'PORT OF NEWARK',
    'PORT OF PORTLAND'
    AND al27.accessory_code IN ('42', '43', '44', '45')
    GROUP BY al2.vdc_name, al7.model_series_name, al27.accessory_code

    I would recommend that you post this at the following OTN forum:
    Database - General
    General Database Discussions
    and perhaps at:
    Oracle Warehouse Builder
    Warehouse Builder
    The Oracle OLAP forum typically does not cover general data warehousing topics.

  • Table with two header rows

    Hello, i have a table in that table i have a header row which has another table with two header rows
    When form spans more then one page on page2 the color and border are showing up outside of table see example below.
    Anyone have any ideas how I can fix this?
    I am using Livecycle designer ES2 9.***
    THanks

    Hi,
    If the table spans to Next page then if you want to move whole table to other page then uncheck the allow page breaks with content option which is under Object Tab.
    Thanks
    Vjay.

  • Populating a table with two columns using a custom bean

    hello,
    Can someone provide me or give me a link to an example of populating a table (with two columns) with a custom bean?
    thank you
    fwu

    1)create a java class
    2)have a list as a class variable
    3) populate the list in the constructor..
    4) map the values in the af:table
    //Employee pojo
    public class Employee {
        public Employee() {
            super();
        private String empName;
        private String empManager;
        private String job;
        public void setEmpName(String empName) {
            this.empName = empName;
        public String getEmpName() {
            return empName;
        public void setEmpManager(String empManager) {
            this.empManager = empManager;
        public String getEmpManager() {
            return empManager;
        public void setJob(String job) {
            this.job = job;
        public String getJob() {
            return job;
    //maanged bean
    public class Bean {
    private List<Employee> employee;
        public Bean() {
            super();
            employee = new ArrayList<Employee>();
          Employee e1 = new Employee();
          e1.setEmpName("xxxxx");
          e1.setEmpManager("xxxxxxxx");
          e1.setJob("xxxxxxx");
          Employee e2 = new Employee();
          e2.setEmpName("yyyyyyy");
          e2.setEmpManager("yyyyyyy");
          e2.setJob("yyyyyyt");
          Employee e3 = new Employee();
          e3.setEmpName("zzzzzz");
          e3.setEmpManager("zzzzzzz");
          e3.setJob("zzzzzzzz");
          employee.add(e1);
          employee.add(e2);
          employee.add(e3);
          employee.add(e4);
        public void setEmployee(List<Employee> employee) {
            this.employee = employee;
        public List<Employee> getEmployee() {
            return employee;
        }in the table map like
    <af:table value="#{Bean.employee}" var="row" rowBandingInterval="0"
                        id="t1">
    <af:column headerText="Employee Name" id="c1">
                  <af:inputText value="#{row.empName}" id="it5"/>
                </af:column>
                <af:column headerText="Employee Manager" id="c2">
                  <af:inputText value="#{row.empManager}" id="it2"/>
                </af:column>
    </af:table>

  • Master table with two child tables in ADF Framework

    Hi,
    I'm trying to implement single master with two detail tables using oracle adf framework of Jdev 11.1.1.4.0. I'm able to do single master-detail by using view link but unable to achieve nested details block i.e., master with nested child blocks.
    I created Query based view object of Master and two query based view objects as details. Then I created two view link for master with first child and another view link for master with second child. Even then in my data controls I see as two different components which is incorrect.
    Please let me know how to create a data control for an example shown below:
    Fruits [MASTER]
    --- Details of Fruits as adf table
    -- Apples [FIRST CHILD]
    ---- Details of Apples as adf table
    -- Oranges [SECOND CHILD]
    ---- Details of Oranges as adf table
    Regards,
    Amar.

    You need two viewLinks
    Fruits->Apples
    Fruits->Oranges
    Then in the data model you pick the Fruits entry that has:
    Fruits
    |--->Apples
    You stand on Fruits and you shuttle the Oranges to be under it from the left.
    If you'll use the default HR schema you'll see this type of relation for Employees:
    https://blogs.oracle.com/shay/entry/master_with_two_details_on_the

  • How can i build table with two user name columne  ?

    How can I build view with two columns for user name ( one create and the other
    Can change also ) 
    And to display full name ( the user name is the key but not display  ) ?

    Hi,
    Creating View
    •     From initial screen of data dictionary(T.Code: SE11), enter the name of object i.e. view.
    •     Select view radio button and click on the push button.
    •     Dialog box is displayed for types of views.
    •     Select the view type.
    •     On the next screen, you have to pass following parameters.
    •     Short text
    •     In the table box you need to enter the table names, which are to be related.
    •     In join table box you need to join the two tables.
    •     Click on the TABFIELD. System displays the dialog box for all the table fields and user can select the fields from this screen. These fields are displayed in the view fields box.
    •     Save and Activate: When the view is activated, view is automatically created in the underlying database system. As long as the table exists in the database, the view also exists (Unless you delete it).
    Regards,
    Bhaskar

  • How to build a table with two For Loop

    Hi,
    I have two Loop For and I want to build a table with N columm (N = a loop + b loop)
    You can see my example.
    Thank's a lot
    Attachments:
    help_table.zip ‏10 KB

    I think this is the solution that you are going for.
    -Jim
    Attachments:
    help_table.vi ‏26 KB

  • Table with two headers

    i have a designed a table with 2 headers(say H1 AND H2), and  dynamic body rows (with three columns)
    the issue is when the table is oveflowing in to next page only one of the header is showing on the next page,
    i have noticed that the option 
    " INCLUDE HEADER ROW IN SUBSEQUENT PAGES" would not check for both the header rows , if i check it for say H1 then that option for H2 gets deselected. How do i resolve it..?
    Thanks in advance

    Hi Paul,
    Thanks for your suggestion
    so,
    now i am looking in to combining two headers together , but i am not sure how to do,
    right now i had wrapped the whole table in to  a subform , say S5
    and there are now two header rows
    Header row[0]
    header row[1]
    and
    body row
    i am trying to wrap the two headers as you suggested , but not sure how to proceed on. i have attached the pdf, can you please suggest me the changes. The table :"Table2"  is  Page 3 of the form.
    Thank you

  • How to define form within a table with two columns?

    Hallo,
    i want to design a form with two columns side by side.
    My way is to define a table within the form:
    <af:panelForm>
    <afh:tableLayout width="100%">
    <afh:rowLayout halign="left">
    <af:inputText value="#{bindings.StsNr.inputValue}"
    label="#{bindings.StsNr.label}"
    required="#{bindings.StsNr.mandatory}"
    columns="#{bindings.StsNr.displayWidth}"
    readOnly="true">
    <af:validator binding="#{bindings.StsNr.validator}"/>
    <f:convertNumber groupingUsed="false"
    pattern="#{bindings.StsNr.format}"/>
    </af:inputText>
    <af:selectOneChoice value="#{bindings.StammsaetzeStsEmpfangsart.inputValue}"
    label="#{bindings.StammsaetzeStsEmpfangsart.label}"
    tip="Brief, Fax, Mail">
    <f:selectItems value="#{bindings.StammsaetzeStsEmpfangsart.items}"/>
    </af:selectOneChoice>
    </afh:rowLayout>
    </afh:tableLayout>
    </af:panelForm>
    Is there a better way to do it?

    Hi reiasmus ,
    Try <af:panelForm row="X">, that specifies the number of fields by columns. If you have ten fields and you fix row="5", you will obtain two columns with 5 rows on each.
    Regards,
    Tif

  • Filling temporary table with two other tables.

    Hi everyone,
    In an start routine, I would like to do the following :
    read values in an internal table, save it in temporary table tab1.
    read values in an internal table (the same with a different request) and save it in temporary table tab2.
    save with no duplicate keys and in a sorted table tab3 the result of the two tables.
    I have coded like this, but it doesn't work, since the final table is empty.
    Indeed, the system says it is tried to insert a duplicate key. How is it possible using instruction INSERT ?
        DATA : t_agence_1 TYPE SORTED TABLE OF ty_agence
                       WITH UNIQUE KEY /BIC/C_AGENCE2
                       WITH HEADER LINE.
        DATA : t_agence_2 TYPE SORTED TABLE OF ty_agence
                       WITH UNIQUE KEY /BIC/C_AGENCE2
                       WITH HEADER LINE.
        DATA : t_agence TYPE SORTED TABLE OF ty_agence
                       WITH UNIQUE KEY /BIC/C_AGENCE2
                       WITH HEADER LINE.
    SELECT * FROM /BIC/PC_AGENCE2
          INTO CORRESPONDING FIELDS OF TABLE t_agence_1
          FOR ALL ENTRIES IN DATA_PACKAGE
               WHERE CALMONTH = DATA_PACKAGE-CALMONTH
               AND /BIC/C_AGENCE2 = DATA_PACKAGE-/BIC/C_AG1
               AND objvers = 'A'.
         IF sy-subrc = 0.
           INSERT LINES OF t_agence_1 INTO TABLE t_agence.
         endif.
       SELECT * FROM /BIC/PC_AGENCE2
          INTO CORRESPONDING FIELDS OF TABLE t_agence_2
          FOR ALL ENTRIES IN DATA_PACKAGE
               WHERE CALMONTH = DATA_PACKAGE-CALMONTH
               AND /BIC/C_AGENCE2 = DATA_PACKAGE-/BIC/C_AG2
               AND objvers = 'A'.
       IF sy-subrc = 0.
              INSERT LINES OF t_agence_2 INTO TABLE t_agence.
       endif.
    Thanks if you can help !
    regards
    fred
    Edited by: Christophe BELIN on Dec 5, 2008 3:43 PM

    Shanon,
    You would handle the parent with two child tables exactly the same way you would a parent with one child.
    1) Bring in all 3 tables through the Database Expert.
    2) On the Links Tab, place the parent table on the left of the window and the two child tables to the right (yes there is a reason for doing this).
    3) Delete any CR generated links between the tables.
    4) "Draw" a link that starts from the parent table to the 1st child table and then again, from the parent to the 2nd child.
    a. I'm assuming that you know which fields to link on.
    b. No links between children.
    5) Once you have both links in place right click them and change the "Link Type" to "Left Outer Join"
    a. The reason for doing this: It allows ALL of the parent records to come through, even if they do not have any matching records in
    one or both of the child tables.
    Hope this helps,
    Jason

  • Is it possible to query an Item with two or more conditions in OOB Update List Item WF Step

    In SharePoint Designer 2010, in Workflows, is it possible to give more then one condition when querying items? Let me explain, it is fairly easy to drop Update item in this list step, and say, for example, Update item with ID X. However, if is it possible
    to do something along this lines with OOB steps, Update an item in this list where Title is Equal to "abc" and Modify date no older then 3 days.
    Update: Workflow is started when the item is added to the list. What I would like is to update some fields on this item depending on information in this item and in external list. For example
    Current Item Field 1 has value "abc"
    Current Item Field 2 has value "123"
    Current Item Field 3 has value "456"
    External List has Item with value in Field 1 "123"
    External List has Item with value in Field 2 "abc"
    External List has Item with value in Field 3 "xyz"
    Update Current Item Field 3 with value "xyz"
    In short I would need following query - Update Current_Item_Field_3 with value from External_List_Field_3 where Field 1 is equal to Current_Item_Field_2 and Field 2 is equal to Current_Item_Field_1

    Hi,
    From your description, I understand you want to update list item with workflow based on two or more conditions.
    To resolve your issue, you need to use “If current item field equals value” condition. Use this condition to compare a field in the current item that the list or reusable list workflow is currently running on to a value. Values can be static text, dynamic
    strings, and lookups to variables, context information, or other SharePoint fields. And you can learn more about each condition by referring to the article:
    https://support.office.com/en-in/article/Workflow-conditions-in-SharePoint-Designer-2010-A-quick-reference-guide-d8e33ac7-9336-487f-a60b-388c4ea497ff?ui=en-US&rs=en-IN&ad=IN
    I assume your External List is called “ListB”, and Current List is called “ListA”, You can follow the steps below:
    1. Add “If current item field equals value" for condition that ListB Field2 equals to ListA Field1, then set the second condition “ListB Field1 equal to ListA Field2” as the “Find the List Item” in the “Lookup for Single line of text”
    as the screenshot below:
    2. Add “Update List Item” as the screenshot below for updating Current_Item_Field_3 with value from External_List_Field_3. In addition, you should set “Find the List Item” in “Lookup for Single line of text” same to the “Find the List Item” in step 1:
    In addition, if you have more conditions, you could add “If current item field equals value” condition, and you should set each “Find the List Item” in “Lookup for Single line of text” same to the “Find the List Item” in step 1.
    Regards,
    Rebecca Tu
    TechNet Community Support

  • Sort a table with two columns based on the first

    I have a powershell table with the columns 'Used Perc' and 'ID'.
    This was formed from the following 
    $a = @{Expression={[System.Math]::Round(($_.nUsed_Avg/$_.nSize)*100,1)};Label="Used Perc";width=25}, @{Expression={$_.nStatisticalDiskIdentificationID};Label="ID";width=15}
    $GLOBAL:CSV2 = Import-CSV $STATDISKOUT | Format-Table $a
    Before this, the file $STATDISKOUT had the columns 'nUsed_Avg', 'nSize', and 'nStatisticalIdentificationID'.
    My question is, how would I sort the new table based on 'Used Perc' but keeping the corresponding 'ID' column lined up to the right value?

    We use a select statement to reorder columns and recalculate,  The formatters just go at the end to adjust the display.
    Import-Csv <file> | select <column order format> | Format-Table
    or you can do it in the table:
    Import-Csv <file | Format-Table -Properties ,f1.,f2.,,f3....Here is how to inset a sort inline:
    $a=@{
    L='ID';
    E={$_.nStatisticalDiskIdentificationID};
    L='Used Perc';
    E={[System.Math]::Round(($_.nUsed_Avg/$_.nSize)*100,1)}
    Import-CSV $STATDISKOUT | Select $a | Sort 'Used Perc' | Format-Table -Auto
    ¯\_(ツ)_/¯

  • Master advance table with two detail advanced tables

    Hi All,
    I have this in mind..please let me know if that is possible.
    I want to have two detail advanced tables within a master advance table.
    The two detail advance tables will be wrapped in a subtab layout.
    My questions are:
    Can a master table have two details tables?
    Can a advance table have two inner advance tables?
    Your help or ideas would be valuable to me.
    Thank you,
    Arun

    Hi OAF Gurus
    I just want to know whether this is possible or not.
    I have created two view links and three view objects
    Table in Table in Table
    Table1--> Table2 --> Table3
    One problem i am facing when i click on Show link of Table1,it displays details of Table2 and when i click Show link of Table2,it displays details of Table3.
    but when i click on Hide of Table1, it says
    oracle.jbo.NoDefException: JBO-25002: Definition <Table3 View Object> of type Attribute not found
    Could you please anybody throw some pointers on this?
    Thanks
    Hitesh

  • SQL query - 2 tables with no relationship

    I'm fairly new to SQL, but I'm trying to put together a query using 2 tables. They have no relationship. I'm using this information in a C# app and I'm trying to pull it as clean as possible to use in a class.
    For example, I have a table called Server where I am selecting 2 columns,
    ServerID and Type. The second table called
    App I am selecting the AppVersion column.
    Question is how can output the data without duplicate AppVersion values? I would rather see null or empty.
    I have tried below along with a CROSS JOIN and I get duplicates in the AppVersion. 
    SELECT ServerID, Type, AppVersion
    FROM Server, App;
    I know that is wrong as it outputs duplicates for AppVersion in the results.
    Thanks in advance. 
    A

    I didn't get your question. When you cross join two different tables the output is a Cartesian product of the two tables.
    The Record (A, 1, 1.1) is different from (B, 1, 1,1).
    You can use a distinct to eliminate if you have duplicates in data and you don't want to see them.
    SELECT DISTINCT ServerID, Type, AppVersion
    FROM Server, App;
    Please mark as answer, if this has helped you solve the issue.
    Good Luck :) .. visit www.sqlsaga.com for more t-sql code snippets and BI related how to articles.

Maybe you are looking for

  • Wireless Printing with a linksys wireless print server

    I am new to Mac and I am trying to install my printer Via wireless, I am totally lost I can't even get my printer model into the printer list, I know this is a vague question but any help would be appreciated.

  • IC Webclient - Chat

    Dear All, i have configured the web chat in the communication channels, assigned it to the IC client profile. but somehow, when i send chat request through the contact center simulator, it does not alert the webclient IC that there's an incoming webc

  • BUG : Compressor 3.5 crashing when adding files?

    Fcs 2 worked just fine under tiger. Now with leo, fcs3 and compressor 3.5 it is impossible to convert (1080p prores/hq) a bigger batch of materiel without compressor crashing. You can try to add about 45 files (e5markII) but anything over that,the co

  • How Is this Level Problem Even Possible?

    I have a PT HD system with a 96 i/o interface. When I open a Logic 8 session, I have to crank my phones up much louder to hear than I do if I open Pro Tools. The Master Volume and Output faders are at ZERO in Logic, but I really have to crank Logic t

  • Portal Runtime Error after System Refresh

    Did a system refresh and now when I select a BI workbook that executed before the refresh I receive the error "portal runtime error an exception occurred while processing your request exception id:09:27_07/02/11_0018_2780350 see the details for the e