Query with CTE solution - Predecessor

Well, my problem started with the following challenge:
I have a table where
I have a field I call 'JOB'and
the otherI call 'predecessor'. Predecessor, as the name says, is
the father of JOB beside him, for example:
JOB - PREDECESSOR - POSITION
  A   -    '       '        -   NULL 
  B   -      A             -   NULL
'A' is the root job, the first one..
and 'B' is just below the
'A', then 'A' is father of 'B'.
I has the following Query, I have the followingquery,where my
query defines a table where there are
random insertions.I want to
organize it in an order from the first job
to be executed. I created
a CTE but it doesnt work for this order,but I was wondering
if you can optimize it to organize
my table correctly.
CREATE
TABLE CTRL_M2
Job
varchar(50),
Antecessor
varchar(50),
Posicao
int
insert
into CTRL_M2
values
('B',
'A',
null)
insert
into CTRL_M2
values
('C',
'B',
null)
insert
into CTRL_M2
values
('B',
'AB',
null)
insert
into CTRL_M2
values
('XB',
'A',
null)
insert
into CTRL_M2
values
('XC',
'A',
null)
insert
into CTRL_M2
values
('E',
'D',
null)
insert
into CTRL_M2
values
('ZB',
null)
insert
into CTRL_M2
values
('ZA',
null)
insert
into CTRL_M2
values
('D',
'C',
null)
insert
into CTRL_M2
values
('A',
null)
insert
into CTRL_M2
values
('AB',
null)
select
from CTRL_M2
with
CTE as
SELECT s.Job,
s.Antecessor,
Posicao
=
CASE
WHEN s.Antecessor
like
THEN 1
END
FROM CTRL_M2 s
UNION
ALL
SELECT s.Job,
s.Antecessor,
Posicao
=
CASE
WHEN s.Antecessor
like
THEN 1
END
FROM CTRL_M2 s
join cte
as x
on x.Job
= s.Antecessor
WHERE s.Antecessor
is
not
null
select
distinct Job,
Antecessor,Posicao
from CTE
order
by Posicao
DESC 

Hi, Jayakumaur.
I tried but I noticed that
still does not solve my problem. Here's why:
I
insert that order:
insert into CTRL_M2 values ('B', 'A', null)
insert into CTRL_M2 values ('C', 'B', null)
insert into CTRL_M2 values ('B', 'AB', null)
insert into CTRL_M2 values ('XB', 'A', null)
insert into CTRL_M2 values ('XC', 'A', null)
insert into CTRL_M2 values ('E', 'D', null)
insert into CTRL_M2 values ('ZB', '-', null)
insert into CTRL_M2 values ('ZA', '-', null)
insert into CTRL_M2 values ('D', 'C', null)
insert into CTRL_M2 values ('A', '-', null)
insert into CTRL_M2 values ('AB', '-', null)
As you can see, my table is totally out of order.
When I used your
CTE, I had
the following result:
JOB - PREDECESSOR - POSITION
A    -    '-'      -      1
AB    -    '-'      -      1
B    -    A     -      0
B    -    AB      -      0
C    -    B     -      0
D    -    C      -      0
E    -    D      -      0
XC    -    A      -      0
XB  -    A      -      0
ZA  -    '-'      -      1
ZB  -    '-'      -      1
The last four
jobs are out of
order.The last two
should be first to be
run as they have no
predecessors.The two
above them should be
well above
the job because they have
'A' as a predecessor, so
could not be in
the end.

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                      ELSE rgt END
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      FROM OrgChart AS E
           LEFT OUTER JOIN
           OrgChart AS B
           ON B.lft
              = (SELECT MAX(lft)
                   FROM OrgChart AS S
                  WHERE E.lft > S.lft
                    AND E.lft < S.rgt);
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      FROM Personnel AS P1, Personnel AS P2
     WHERE P1.lft BETWEEN P2.lft AND P2.rgt 
       AND P1.emp_name = @my_emp_name;
    I have a book on TREES & HIERARCHIES IN SQL which you can get at Amazon.com right now. It has a lot of other programming idioms for nested sets, like levels, structural comparisons, re-arrangement procedures, etc. 
    --CELKO-- Books in Celko Series for Morgan-Kaufmann Publishing: Analytics and OLAP in SQL / Data and Databases: Concepts in Practice Data / Measurements and Standards in SQL SQL for Smarties / SQL Programming Style / SQL Puzzles and Answers / Thinking
    in Sets / Trees and Hierarchies in SQL

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