Question about bit operation

1/ I know I can use << to translate from number of index to the binary number.
But how can I translate from binary number to number of index? (e.g. 1024 translates to 10)
2/ How can I separate two bits in a number? (e.g. 144 translates to 128+16)
3/ How can I know that the number exists a required bit? (e.g. check 144 if there exists 4th bit)
Currently, I translate to binary number string first and then use indexOf and lastIndexOf methods to get the location of the bits.
3rd question I use number==(number|10000)
Is it any other more efficient methods to achieve that?
Thanks.

nwoedf wrote:
1/ I know I can use << to translate from number of index to the binary number.
But how can I translate from binary number to number of index? (e.g. 1024 translates to 10)Convert the number to a binary String and go through it keeping track of the 1 bit positions.
You can use Integer.toString(1024, 2); to convert for example.
2/ How can I separate two bits in a number? (e.g. 144 translates to 128+16)Same as the first one, then you just need to go through the bits again and translate the indices into the values.
3/ How can I know that the number exists a required bit? (e.g. check 144 if there exists 4th bit)The & operator can be used for that for example.
Currently, I translate to binary number string first and then use indexOf and lastIndexOf methods to get the location of the bits.
3rd question I use number==(number|10000)
Is it any other more efficient methods to achieve that?Why, is your computer not doing this fast enough?

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