Questions about jdk nio charset

During load test, work threads all wait for reading charset classes from Classloader. Why not keep the stable result in cache? Thanks a lot!
"ExecuteThread: '25' for queue: 'weblogic.kernel.Default'" daemon prio=1 tid=0x5c941800 nid=0x38ee waiting for monitor entry [5d697000..5d6988c8]
     at sun.net.www.protocol.jar.JarFileFactory.get(JarFileFactory.java:49)
     - waiting to lock <0x5113ebe0> (a sun.net.www.protocol.jar.JarFileFactory)
     at sun.net.www.protocol.jar.JarURLConnection.connect(JarURLConnection.java:85)
     at sun.net.www.protocol.jar.JarURLConnection.getInputStream(JarURLConnection.java:107)
     at java.net.URL.openStream(URL.java:913)
     at sun.misc.Service.parse(Service.java:203)
     at sun.misc.Service.access$100(Service.java:111)
     at sun.misc.Service$LazyIterator.hasNext(Service.java:257)
     at java.nio.charset.Charset$1.getNext(Charset.java:303)
     at java.nio.charset.Charset$1.hasNext(Charset.java:318)
     at java.nio.charset.Charset$2.run(Charset.java:361)
     at java.security.AccessController.doPrivileged(Native Method)
     at java.nio.charset.Charset.lookupViaProviders(Charset.java:358)
     at java.nio.charset.Charset.lookup(Charset.java:385)
     at java.nio.charset.Charset.isSupported(Charset.java:407)
     at java.lang.StringCoding.lookupCharset(StringCoding.java:82)
     at java.lang.StringCoding.encode(StringCoding.java:363)
     at java.lang.StringCoding.encode(StringCoding.java:380)
     at java.lang.String.getBytes(String.java:590)

who can tell me how to avoid this? Thanks a lot!

Similar Messages

Question about JDK 5.0 and Eclipse

Hello,
As there are no forums about Eclipse I ask my question here: what version of Eclipse -if any- supports JDK 5.0 without any plugins?
Thanks in advance,
Julien Martin.

The unreleased 3.1.
http://www.eclipse.org/eclipse/development/eclipse_project_plan_3_1.html

Questions about JDK and SQLJ?

i use JDK 1.3 . from FAQ of SQLJ , i should used sqlj 9.0.1 .
But i never see this version of sqlj .
Is there this version product ?
And how can i get it ?

from command line type:
sqlj -version-long
This should show:
Oracle SQLJ Release 8.1.7.0.0 Production
Build version: 2.0.0.0 - Built on May 31, 2000
IDE interface version: 8.1.7.0.0/2.0.0.0
JDBC version: Oracle JDBC driver version 8.1 (8.1.7.0.0)
SQLJ runtime: Oracle 8.1.7 for JDBC 8.1.7 or later/JDK 12EE -
Built on Aug 18, 2
000
Java version: 1.3 (1.3.0)
i use JDK 1.3 . from FAQ of SQLJ , i should used sqlj 9.0.1 .
But i never see this version of sqlj .
Is there this version product ?
And how can i get it ?

Question about character encoding

Hey everyone,
I've been trying to read about character encodings and how Java IO uses them, however, there is something I still don't understand:
I am trying to read an HTML file encoded in UTF-8 and which contain some Arabic characters.
I used this code to save it on a file:
URL u = new URL("http://www.fatafeat.com");    // some Arabic website
URLConnection connection = u.openConnection();
BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream(), "UTF-8"));
OutputStreamWriter writer = new OutputStreamWriter(new FileOutputStream("datat.txt"));
int c;
while ((c = reader.read())!=-1)
writer.write(c);However, the output on the file is always "??????"
I used another version of the code
URL u = new URL("http://www.fatafeat.com");     //some Arabic website
URLConnection connection = u.openConnection();
InputStream reader = connection.getInputStream();
FileOutputStream writer = new FileOutputStream("datat.txt");
int c;
while ((c = reader.read()) != -1)
writer.write(c);And I get on the file something like this " ÇáæÍíÏÉ áÝä "
I tried to open the file from a browser using a UTF-8 encoding, but still the same display. What am I missing here? Thanks

Upon further investigation, my initial hunch appears to be correct. The page in question is not correctly encoded UTF-8, so the Java decoder fails. By default, the java decoder fails silently and replaces malformed input with the character "\uFFFD". If you want more control over the decoding process, you need to read the data as bytes and use the CharsetDecoder class to convert to characters. Here is small example to illustrate:
import java.io.ByteArrayOutputStream;
import java.io.CharArrayWriter;
import java.io.IOException;
import java.io.InputStream;
import java.net.URL;
import java.nio.ByteBuffer;
import java.nio.CharBuffer;
import java.nio.charset.Charset;
import java.nio.charset.CharsetDecoder;
import java.nio.charset.CoderResult;
import java.nio.charset.CodingErrorAction;
public class FatafeatToy3
    private static final Charset UTF8 = Charset.forName("UTF-8");
    private static final Charset DEFAULT_DECODER_CHARSET = UTF8;
    private final CharsetDecoder decoder;
    public FatafeatToy3(final Charset cs)
        this.decoder = cs.newDecoder();
        this.decoder.onMalformedInput(CodingErrorAction.REPORT);
        this.decoder.onUnmappableCharacter(CodingErrorAction.REPORT);
    public FatafeatToy3()
        this(DEFAULT_DECODER_CHARSET);
    public ByteBuffer pageSlurp (URL url) throws IOException
        ByteArrayOutputStream pageBytes = new ByteArrayOutputStream ();
        InputStream is = url.openStream();
        int ch;
        while ((ch = is.read()) != -1)
            pageBytes.write(ch);
        is.close();
        return ByteBuffer.wrap(pageBytes.toByteArray());
    public CoderResult decodeSome(ByteBuffer in, CharBuffer out)
        decoder.reset();
        CoderResult result = decoder.decode(in, out, true);
        if (result.isMalformed())
            System.err.printf("Malformed input detected at pos 0x%x%n", in.position());
        else if (result.isUnmappable())
            System.err.printf("Unmappable input detected at pos 0x%x%n", in.position());
        else if (result.isUnderflow())
            result = decoder.flush(out);
        return result;
    public static void main(String[] args) throws Exception
        FatafeatToy3 ft = new FatafeatToy3();
        ByteBuffer in = ft.pageSlurp(new URL("http://www.fatafeat.com"));
        System.out.printf("Page slurped contains %d bytes%n", in.capacity());
        CharBuffer out = CharBuffer.allocate(1); // one character at a time
        CharArrayWriter pageChars = new CharArrayWriter();
        CoderResult result = CoderResult.UNDERFLOW;
        while ( (! result.isError()) && in.remaining() > 0)
            result = ft.decodeSome(in, out);
            if (result.equals(CoderResult.OVERFLOW))
                out.flip();
                pageChars.append(out);
                out.clear();
}

Few questions about apex + epg and cookie blocked by IE6

Hi,
I would like to ask a few questions about apex and epg.
I have already installed and configured apex 3.2 on oracle 10g (on my localhost - computer name 'chen_rong', ip address -192.168.88.175 ), and enable anonymous access xdb http server.
now,
1. I can access 'http://chen_rong' , 'http://localhost' , 'http://192.168.88.175' without input username / password for realm 'XDB' in IE6;
2. I can access 'http://localhost/apex/apex_admin' , 'http://192.168.88.175/apex/apex_admin' , and I can be redirected into apex administation page after input admin/<my apex admin password> for realm 'APEX' in IE6;
3. I can access 'http://chen_rong/apex/apex_admin' in IE6, but after input admin/password , I can not be redirected into administation page, because the cookie was blocked by IE6.
then, the first question is :
Q1: What is the difference among 'http://chen_rong' , 'http://localhost' , 'http://192.168.88.175' ? I have already include site 'chen_rong' into my trusted stes! why the cookie was blocked by IE6. I have already tried firefox and google browser, both of them were ok for 'chen_rong', no cookie blocked from site 'chen_rong'!
and,
1. I have tried to use the script in attachment to test http authentication and also want to catch the cookie by utl_http .
2. please review the script for me.
3. I did:
SQL> exec show_url('http://localhost/apex/apex_admin/','ADMIN','Passw0rd');
HTTP response status code: 401
HTTP response reason phrase: Unauthorized
Please supplied the required Basic authentication username/password for realm XDB for the Web page.
Web page http://localhost/apex/apex_admin/ is protected.
MS-Author-Via: DAV
DAV: 1,2,<http://www.oracle.com/xdb/webdav/props>
Server: Oracle XML DB/Oracle Database
WWW-Authenticate: Basic realm="XDB"
Date: Tue, 04 Aug 2009 02:25:15 GMT
Content-Type: text/html; charset=GBK
Content-Length: 147
======================================
PL/SQL procedure successfully completed
4. I also did :
SQL> exec show_url('http://localhost/apex/apex_admin/','ANONYMOUS','ANONYMOUS');
HTTP response status code: 500
HTTP response reason phrase: Internal Server Error
Check if the Web site is up.
PL/SQL procedure successfully completed
SQL> exec show_url('http://localhost/apex/apex_admin/','SYSTEM','apexsite');
HTTP response status code: 401
HTTP response reason phrase: Unauthorized
Please supplied the required Basic authentication username/password for realm APEX for the Web page.
Web page http://localhost/apex/apex_admin/ is protected.
Content-Type: text/html
Content-Length: 147
WWW-Authenticate: Basic realm="APEX"
======================================
PL/SQL procedure successfully completed
my second questions is :
Q2: After I entered into realm 'XDB', I still need went into realm'APEX'. how could I change the script show_url to accomplish these two tasks and successfully get the cookie from site.
the show_url script is as following:
CREATE OR REPLACE PROCEDURE show_url
(url IN VARCHAR2,
username IN VARCHAR2 DEFAULT NULL,
password IN VARCHAR2 DEFAULT NULL)
AS
req UTL_HTTP.REQ;
resp UTL_HTTP.RESP;
name VARCHAR2(256);
value VARCHAR2(1024);
data VARCHAR2(255);
my_scheme VARCHAR2(256);
my_realm VARCHAR2(256);
my_proxy BOOLEAN;
cookies UTL_HTTP.COOKIE_TABLE;
secure VARCHAR2(1);
BEGIN
-- When going through a firewall, pass requests through this host.
-- Specify sites inside the firewall that don't need the proxy host.
-- UTL_HTTP.SET_PROXY('proxy.example.com', 'corp.example.com');
-- Ask UTL_HTTP not to raise an exception for 4xx and 5xx status codes,
-- rather than just returning the text of the error page.
UTL_HTTP.SET_RESPONSE_ERROR_CHECK(FALSE);
-- Begin retrieving this Web page.
req := UTL_HTTP.BEGIN_REQUEST(url);
-- Identify yourself.
-- Some sites serve special pages for particular browsers.
UTL_HTTP.SET_HEADER(req, 'User-Agent', 'Mozilla/4.0');
-- Specify user ID and password for pages that require them.
IF (username IS NOT NULL) THEN
UTL_HTTP.SET_AUTHENTICATION(req, username, password, 'Basic', false);
END IF;
-- Start receiving the HTML text.
resp := UTL_HTTP.GET_RESPONSE(req);
-- Show status codes and reason phrase of response.
DBMS_OUTPUT.PUT_LINE('HTTP response status code: ' || resp.status_code);
DBMS_OUTPUT.PUT_LINE
('HTTP response reason phrase: ' || resp.reason_phrase);
-- Look for client-side error and report it.
IF (resp.status_code >= 400) AND (resp.status_code <= 499) THEN
-- Detect whether page is password protected
-- and you didn't supply the right authorization.
IF (resp.status_code = UTL_HTTP.HTTP_UNAUTHORIZED) THEN
UTL_HTTP.GET_AUTHENTICATION(resp, my_scheme, my_realm, my_proxy);
IF (my_proxy) THEN
DBMS_OUTPUT.PUT_LINE('Web proxy server is protected.');
DBMS_OUTPUT.PUT('Please supply the required ' || my_scheme ||
' authentication username/password for realm ' || my_realm ||
' for the proxy server.');
ELSE
DBMS_OUTPUT.PUT_LINE('Please supplied the required ' || my_scheme ||
' authentication username/password for realm ' || my_realm ||
' for the Web page.');
DBMS_OUTPUT.PUT_LINE('Web page ' || url || ' is protected.');
END IF;
ELSE
DBMS_OUTPUT.PUT_LINE('Check the URL.');
END IF;
-- UTL_HTTP.END_RESPONSE(resp);
-- RETURN;
-- Look for server-side error and report it.
ELSIF (resp.status_code >= 500) AND (resp.status_code <= 599) THEN
DBMS_OUTPUT.PUT_LINE('Check if the Web site is up.');
UTL_HTTP.END_RESPONSE(resp);
RETURN;
END IF;
-- HTTP header lines contain information about cookies, character sets,
-- and other data that client and server can use to customize each
-- session.
FOR i IN 1..UTL_HTTP.GET_HEADER_COUNT(resp) LOOP
UTL_HTTP.GET_HEADER(resp, i, name, value);
DBMS_OUTPUT.PUT_LINE(name || ': ' || value);
END LOOP;
-- Read lines until none are left and an exception is raised.
--LOOP
-- UTL_HTTP.READ_LINE(resp, value);
-- DBMS_OUTPUT.PUT_LINE(value);
--END LOOP;
UTL_HTTP.GET_COOKIES(cookies);
dbms_output.put_line('======================================');
FOR i in 1..cookies.count LOOP
IF (cookies(i).secure) THEN
secure := 'Y';
ELSE
secure := 'N';
END IF;
-- INSERT INTO my_cookies
-- VALUES (my_session_id, cookies(i).name, cookies(i).value,
-- cookies(i).domain,
-- cookies(i).expire, cookies(i).path, secure, cookies(i).version);
dbms_output.put_line('site:'||url);
dbms_output.put_line('cookies:');
dbms_output.put_line('name:'||cookies(i).name);
dbms_output.put_line('value:'||cookies(i).value);
dbms_output.put_line('domain:'||cookies(i).domain);
dbms_output.put_line('expire:'||cookies(i).expire);
dbms_output.put_line('path:'||cookies(i).path);
dbms_output.put_line('secure:'||secure);
dbms_output.put_line('version:'||cookies(i).version);
END LOOP;
UTL_HTTP.END_RESPONSE(resp);
EXCEPTION
WHEN UTL_HTTP.END_OF_BODY THEN
UTL_HTTP.END_RESPONSE(resp);
END;
/

I use oracle database enterprise edtion 10.2.0.3. I have already figured out the epg on 10.2.0.3 to support apex 3.2.
And as I described above, the apex site works fine for ip address , and localhost. but the cookie will be blocked by IE6, if I want to access the site by 'http://computername:port/apex/apex_admin'. This problem does not occured in firefox and google browser. Could someone give me answer?

A question about compatiblilty of JDBC

Hi, there,
I have a question about JDBC 3.0 in JDK1.4.1.
We build a .jar using JDK1.4.1 and this .jar file
provides JDBC 3.0 interface.
I then tried to call the interface under JDK1.3.1
but it keeps asking me about the getParameterMetaData()
in PreparedStatement.
(The error message like this:
Exception in thread "main" java.lang.NoClassDefFoundError: java/sql/ParameterMetaData dbmaker.sql.JdbcOdbcConnection.prepareStatement(JdbcOdbcConnection.java:257)
I did implement the getParameterMetaData() method,
but I didn't call this method in my testing program.
It's quite strange since when JDK1.2 was release,
we implemented the getBlob() method in
ResultSet class and there's no problem when we
use JDK1.1 run time to call this ResultSet object.
Could any one tell me why? Is this caused by a
compatibility problem between JDK1.4 and the
older versions of JDK?

Hi, there,
Let me outline the condition by examples so that maybe you can help me. PLEASE! Could somebody tell us what's wrong?
- CASE 1:
In JDK1.2, we implemented a new method getBlob which returns the type of Blob (this is done according to JDBC 2.0 specification.) in ResultSet class. We can use the .jar compiled by jdk1.2 in jdk1.1 environment.
e.g. We make a xyz.jar by jdk1.2 and the xyz.jar includes new method getBlob in ReaultSet class. Then, one java application including ResultSet class CAN run under jdk1.1 with xyz.jar, if the method ResultSet.getBlob() is not called.
- CASE 2:
BUT, the following case which is the same as in the above condition will fail in jdk1.3 environment.
In JDK 1.4, we implemented a new method getParameterMetaData() which returns the type of ParameterMetaData. (BTW, this is done according to JDBC 3.0 specification.) in PreparedStatement class. We CANNOT use the .jar compiled by jdk1.4 in jdk1.3 environment.
e.g. We make a ttt.jar by jdk1.4 and ttt.jar includes the new method getParameterMetaData() in PreparedStatement class. Then, one java application including PreparedStatement class CANNOT be run under jdk1.3 with ttt.jar, even when the method PreparedStatement.getParameterMetaData() is not called.

Newbie question about loading servlets on tomcat

I have what is probably a very basic question about loading simple servlets on to tomcat to test its installation. I have followed instructions from numerous tutorials to the letter but still I can't get it to work.
I have installed tomcat on win2k in c:\tomcat. I set up the jdk, environment vars (JAVA_HOME, CATALINA_HOME, TOMCAT_HOME) which all point at the correct dirs. I can compile a servlet without errors. I can also place a test jsp and html file into the root directory and they both work fine.
However, now I am trying a test servlet and no matter what I do it gives me a 404. I have a servlet class file called "HelloServlet.class" which I placed into the %install_dir%\webapps\ROOT\WEB-INF\classes directory. I try to reference it using this url:
http://localhost/servlet/HelloServlet
Tomcat is configured to use port 80 and has been restarted after adding the servlet class file. Does anyone have a clue why this is not working for me?
Many thanks
Marc

You have to add in the web.xml file that it is in the WEB-INF dir, the information about your servlet. An example:
<web-app>
<servlet>
<servlet-name>HelloServlet</servlet-name>
<servlet-class>HelloServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>HelloServlet</servlet-name>
<url-pattern>/HelloServlet</url-pattern>
</servlet-mapping>
</web-app>

Question about reading a very big file into a buffer.

Hi, everyone!
I want to randomly load several characters from
GB2312 charset to form a string.
I have two questions:
1. Where can I find the charset table file? I have used
google for hours to search but failed to find GB2312 charset
file out.
2. I think the charset table file is very big and I doubted
whether I can loaded it into a String or StringBuffer? Anyone
have some solutions? How to load a very big file and randomly
select several characters from it?
Have I made myself understood?
Thanks in advance,
George

The following can give the correspondence between GB2312 encoded byte arrays and characters (in hexadecimal integer expression).
import java.nio.charset.*;
import java.io.*;
public class GBs{
static String convert() throws java.io.UnsupportedEncodingException{
StringBuffer buffer = new StringBuffer();
String l_separator = System.getProperty("line.separator");
Charset chset = Charset.forName("EUC_CN");// GB2312 is an alias of this encoding
CharsetEncoder encoder = chset.newEncoder();
int[] indices = new int[Character.MAX_VALUE+1];
for(int j=0;j<indices.length;j++){
       indices[j]=0;
for(int j=0;j<=Character.MAX_VALUE;j++){
    if(encoder.canEncode((char)j)) indices[j]=1;
byte[] encoded;
String data;
for(int j=0;j<indices.length;j++) {
     if(indices[j]==1) {
            encoded =(Character.toString((char)j)).getBytes("EUC_CN");
                      for(int q=0;q<encoded.length;q++){
                      buffer.append(Byte.toString(encoded[q]));
                      buffer.append(" ");
            buffer.append(": 0x");buffer.append(Integer.toHexString(j));
            buffer.append(l_separator);
    return buffer.toString();
//the following is for testing
/*public static void main(String[] args) throws java.lang.Exception{
   String str = GBs.convert();
   System.out.println(str);*/

I hava a question about RMI,please help me!

Ladys and Gentleman,I hava a question about RMI.I wirte four little programs in java that is about RMI on my PC.
import java.rmi.*;
public interface AddServerIntf extends Remote{
double add(double d1,double d2) throws RemoteException;
import java.rmi.*;
import java.rmi.server.*;
public class AddServerImpl extends UnicastRemoteObject implements AddServerIntf{
public AddServerImpl() throws RemoteException{
public double add(double d1,double d2)throws RemoteException{
return d1+d2;
import java.net.*;
import java.rmi.*;
public class AddServer{
public static void main(String args[]){
try{
AddServerImpl addServerImpl=new AddServerImpl();
Naming.rebind("AddServer",addServerImpl);
}catch(Exception e){
e.printStackTrace();
import java.rmi.*;
public class AddClient
     public static void main(String args[]){
     try{
     String addServerURL="rmi://"+args[0]+"/AddServer";
     AddServerIntf addServerIntf=(AddServerIntf) Naming.lookup(addServerURL);
     System.out.println("The first number is: "+args[1]);
     double d1=Double.valueOf(args[1]).doubleValue();
     System.out.println("The second number is: "+args[2]);
     double d2=Double.valueOf(args[2]).doubleValue();
     System.out.print("The sum is: "+addServerIntf.add(d1,d2));
     }catch(Exception e){
     System.out.println("Exception: "+e);
And I compiled these files,so I got 4 class files(AddServer.class,AddServerIntf.class,AddServerImpl.class,AddServerClient.class).Then I use "rmic AddServerImpl" got another two files(AddServerImpl_Skel.class and AddServerImpl_Stub.class).Then I input command:rmiregistry,in another window,I input command:java AddServer,I got some exceptions,I was confused by these exceptions.The exception is:
D:\MyJava\rmi_3>java AddServer
java.rmi.ServerException: RemoteException occurred in server thread; nested exception is:
java.rmi.UnmarshalException: error unmarshalling arguments; nested exception is:
java.lang.ClassNotFoundException: AddServerImpl_Stub
java.rmi.UnmarshalException: error unmarshalling arguments; nested exception is:
java.lang.ClassNotFoundException: AddServerImpl_Stub
java.lang.ClassNotFoundException: AddServerImpl_Stub
at sun.rmi.transport.StreamRemoteCall.exceptionReceivedFromServer(Unknown Source)
at sun.rmi.transport.StreamRemoteCall.executeCall(Unknown Source)
at sun.rmi.server.UnicastRef.invoke(Unknown Source)
at sun.rmi.registry.RegistryImpl_Stub.rebind(Unknown Source)
at java.rmi.Naming.rebind(Unknown Source)
at AddServer.main(AddServer.java:8)
But some times this exception will not appeared.Who can give me answer or suggestion,thanks a lot.
By the way,when I run shutdown.bat in tomcat_root\bin,I can get some exceptions:
C:\Tomcat\bin>shutdown
Using CATALINA_BASE: ..
Using CATALINA_HOME: ..
Using CATALINA_TMPDIR: ..\temp
Using JAVA_HOME: C:\JDK
Catalina.stop: java.net.ConnectException: Connection refused: connect
java.net.ConnectException: Connection refused: connect
at java.net.PlainSocketImpl.socketConnect(Native Method)
at java.net.PlainSocketImpl.doConnect(PlainSocketImpl.java:350)
at java.net.PlainSocketImpl.connectToAddress(PlainSocketImpl.java:137)
at java.net.PlainSocketImpl.connect(PlainSocketImpl.java:124)
at java.net.Socket.<init>(Socket.java:268)
at java.net.Socket.<init>(Socket.java:95)
at org.apache.catalina.startup.Catalina.stop(Catalina.java:579)
at org.apache.catalina.startup.Catalina.execute(Catalina.java:402)
at org.apache.catalina.startup.Catalina.process(Catalina.java:180)
at java.lang.reflect.Method.invoke(Native Method)
at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:203)
I use Windows server 2000+JDK 1.3.1_04+tomcat 4.1.7

Maybe I am off base here but it seems to me the problem is the way in which you bind your server. The server must be bound to the same address and you are looking up from, i.e. "rmi://" host "/AddServer"
so
Naming.rebind("AddServer",addServerImpl);should be
Naming.rebind("rmi://127.0.0.1/AddServer", addServerImpl);to match
String addServerURL="rmi://"+args[0]+"/AddServer";
AddServerIntf addServerIntf=(AddServerIntf)
Naming.lookup(addServerURL);Hopefully this will solve your problem, if not it is a problem with your classpath. An easy way to make sure it can see your files is to set the java.rmi.server.codebase to point to where your classes are, e.g.
java -Djava.rmi.server.codebase=file:"c:\\cygwin\\home\\tweak\\keck_folder\\cmsi401\\RMIGalaxySleuth\\classes\\" AddServer
I had to set the codebas for my rmi stuff to work no matter how much I messed with the classpath.
Hope this helps,
Will

A question about Enumeration()

i am a beginner in java,resently i met a question about Enumeration(),and i hope someone can help me.
my question is that in the package of java.util there is an interface called Enumeration and there are two method hasMoreElements()��nextElemen() in it.
but in general we do not realize them before we use them.for example:
first we defined a new class Vector
Vector myVector = new Vector();
then when after we add some objects to it,we can do like this:
Enumeration e = myVectior.elements();
e.nextElemen();
i want to know where the method nextElemen is realized? incording to java's grammar,it is impossible to be realized in Enumeration for it is an interface,but
both class Vector and the my own class do not realize it too.so i am confused.

The class that implements the Enumeration returned by elements is hidden in the Vector class implementation. In fact, the class is anonymous. Here's the code from java.util.Vector (JDK 1.4).
   public Enumeration elements() {
        return new Enumeration() {
            int count = 0;
            public boolean hasMoreElements() {
                return count < elementCount;
            public Object nextElement() {
                synchronized (Vector.this) {
                    if (count < elementCount) {
                        return elementData[count++];
                throw new NoSuchElementException("Vector Enumeration");
    }

Questions about your new HP Products? HP Expert Day: January 14th, 2015

Thank you for coming to Expert Day! The event has now concluded.
To find out about future events, please visit this page.
On behalf of the Experts, I would like to thank you for coming to the Forum to connect with us. We hope you will return to the boards to share your experiences, both good and bad.
We will be holding more of these Expert Days on different topics in the months to come. We hope to see you then!
If you still have questions to ask, feel free to post them on the Forum – we always have experts online to help you out.
So, what is HP Expert Day?
Expert Day is an online event when HP employees join our Support Forums to answer questions about your HP products. And it’s FREE.
Ok, how do I get started?
It’s easy. Come out to the HP Support Forums, post your question, and wait for a response! We’ll have experts online covering our Notebook boards, Desktop boards, Tablet boards, and Printer and all-in-one boards.
We’ll also be covering the commercial products on the HP Enterprise Business Community. We’ll have experts online covering select boards on the Printing and Digital Imaging and Desktops and Workstations categories.
What if I need more information?
For more information and a complete schedule of previous events, check out this post on the forums.
Is Expert Day an English-only event?
No. This time we’ll have experts and volunteers online across the globe, answering questions on the English, Simplified Chinese, and Korean forums. Here’s the information:
Enterprise Business Forum: January 14th 7:00am to 12:00pm and 6:00pm to 11:00pm Pacific Time
Korean Forum: January 15th 10am to 6pm Korea Time
Simplified Chinese Forum: January 15th 10am to 6pm China Time
Looking forward to seeing you on January 14th!
I am an HP employee.

My HP, purchased in June 2012, died on Saturday. I was working in recently installed Photoshop, walked away from my computer to answer the phone and when I came back the screen was blank. When I turned it on, I got a Windows Error Recovery message. The computer was locked and wouldn't let me move the arrow keys up or down and hitting f8 didn't do anything.
I'm not happy with HP. Any suggestions?

Have questions about your Creative Cloud or Subscription Membership?

You can find answers to several questions regarding membership to our subscription services. Please see Membership troubleshooting | Creative Cloud - http://helpx.adobe.com/x-productkb/policy-pricing/membership-subscription-troubleshooting- creative-cloud.html for additional information. You can find information on such topics as:
I need help completeing my new purchase or upgrade.
I want to change the credit card on my account.
I have a question about my membership price or statement charges.
I want to change my membership: upgrade, renew, or restart.
I want to cancel my membership.
How do I access my account information or change update notifications?

Branching to new discussion.
Christym16625842 you are welcome to utilize the process listed in Creative Cloud Help | Install, update, or uninstall apps to install and evaluate the applications included with a Creative Cloud Membership. The software is fully supported on recent Mac computers. You can find the system requirements for the Creative Cloud at System requirements | Creative Cloud.

Questions about using the Voice Memos app

I'm currently an Android user, but will be getting an iPhone 6 soon. My most used app is the voice memos app on my Android phone. I have a couple questions about the iPhone's built-in voice memos app.
-Am I able to transfer my voice memos from my Android phone to my iPhone, so my recordings from my Android app will show up in the iPhone's voice memos app?
-When exporting voice memos from the iPhone to computer, are recordings in MP3 format? If not, what format are they in?
-In your opinion, how is the recording quality of the voice memos app?

You cannot import your Android voice memos to your iPhone's voice memo app. You might be able to play the Android memos and have the iPhone pick up the audio and record it.
Here is the writeup about sending voice memos from the iPhone to your computer (from the iPhone User Guide):
App quality is excellent.

Re: Question about the Satellite P300-18Z

Hello everyone,
I have a couple of questions about the Satellite P300-18Z.
What "video out" does this laptop have? (DVI, s-video or d-sub)
Can I link the laptop up to a LCD-TV and watch movies on a resolution of 1080p? (full-HD)
What is the warranty on this laptop?

Hello
According the notebook specification Satellite P300-18Z has follow interfaces:
DVI - No DVI port available
HDMI - HDMI-out (HDMI out port available)
Headphone Jack - External Headphone Jack (Stereo) available
.link - iLink (Firewire) port available
Line in Jack - No Line in Jack port available
Line out Jack - No Line Out Jack available
Microphone Jack - External Micrphone Jack
TV-out - port available (S-Video port)
VGA - VGA (External monitor port RGB port)
Also you can connect it to your LCD TV using HDMI cable.
Warranty is country specific and clarifies this with your local dealer but I know that all Toshiba products have 1 year standard warranty and also 1 year international warranty. you can of course expand it.

Some questions about Muse

First of all, I would like to say that I am very impressed with how well Muse works and how easy it was to create a website that satisfies me. Before I started a daily updated website I thought I would encounter many problems I will not be able to solve. I have only had a few minor issues which I would like to share with you.
The most problems I have with a horizontal layouts (http://www.leftlane.pl/sty14/dig-t-r-3-cylindrowy-silnik-nissana-o-wadze-40-kg-i-mocy-400- km.html). Marking and copying of a text is possible only on the last (top) layer of a document. The same situation is with widgets or anything connected with rollover state - it does not work. In the above example it would be perfect to use a composition/tooltip widget on the first page. Unfortunately, you cannot even move the cursor into it.
It would be helpful to have an option of rolling a mouse to an anchor (like in here http://www.play.pl/super-smartfony/lg-nexus-5.html and here http://www.thepetedesign.com/demos/onepage_scroll_demo.html). I mean any action of a mouse wheel would make a move to another anchor/screen. It would make navigation of my site very easy.
Is it possible to create a widget with a function next anchor/previous anchor? Currently, in the menu every button must be connected to a different anchor for the menu to be functional.
A question about Adobe Muse. Is it possible to create panels in different columns? It would make it easier to go through all the sophisticated program functions.
The hits from Facebook have sometimes very long links, eg.
(http://www.leftlane.pl/sty14/mclaren-p1-nowy-krol-nurburgring.html?fb_action_ids=143235557 3667782&fb_action_types=og.likes&fb_source=aggregation&fb_aggregation_id=288381481237582). If such a link is activated, the anchors in the menu do not work on any page. I mean the backlight of an active state, which helps the user to find out where on page they currently are. The problem also occurs when in the name of a html file polish fonts exist. And sometimes the dots does not work without any reason, mostly in the main page, sometimes in the cooperation page either (http://www.leftlane.pl/wspolpraca/). In the first case (on main page), I do not know why. I have checked if they did not drop into a state button by accident, moved them among the layers, numbered them from scratch and it did not help. In the cooperation page, the first anchor does not work if it is in Y axle set at 0. If I move it right direction- everything is ok.
The text frame with background fill does not change text color in overlay state (http://www.leftlane.pl/sty14/nowe-mini-krolestwo-silnikow-3-cylindrowych.html). I mean a source button at the beginning of every text. I would like a dark text and a light layer in a rollover, but the text after export and moving cursor into it does not change color for some reason.
I was not sure whether to keep everything (whole website) in one Muse file (but I may be mistaken?). I have decided to divide it into months. Everyone is in a different Muse file. If something goes wrong, I will not have any trouble with an upload of a whole site, which is going to get bigger and bigger.
The problem is that every file has two master pages. Everything works well up to the moment when I realize how many times I have to make changes in upper menu when I need to add something there. I have already 5 files, every with 2 masters. Is there any way to solve this problem? Maybe something to do with Business Catalyst, where I could connect a menu to every subpage independently, deleting it from Muse file? Doing so I would be able to edit it everywhere from one place. It would make my work much easier, but I have no idea jendak how to do it.
The comments Disqus do not load, especially at horizontal layouts (http://www.leftlane.pl/sty14/2014-infiniti-q50-eau-rouge-concept.html). I have exchanged some mails and screenshots with Disqus help. I have sent them a screenshot where the comments are not loaded, because they almost never load. They have replied that it works at their place even with attached screenshot. I have a hard time to discuss it, because it does not work with me and with my friends either. Maybe you could fix it? I would not like to end up with awful facebook comments ;). The problem is with Firefox on PC and Mac. Chrome, Safari and Opera work ok.
YouTube movie level layouts do not work well with IE11 and Safari 7 (http://www.leftlane.pl/sty14/wypadki-drogowe--004.html). The background should roll left, but in the above mentioned browsers it jumps up. Moreover the scrolling with menu dots is not fluent on Firefox, but I guess it is due to Firefox issues? The same layout but in vertical version rolls fluently in Firefox (http://www.leftlane.pl/sty14/polskie-wypadki--005.html).
Now, viewing the website on new smartphones and tablets. I know it is not a mobile/tablet layout, but I tried to make it possible to be used on mobile hardware with HD (1280) display. I mean most of all horizontal layouts (http://www.leftlane.pl/sty14/2015-hyundai-genesis.html), where If we want to roll left, we need to roll down. Is there a way to make it possible to move the finger the direction in which the layout goes?
On Android phones (Nexus 4, Android 4.4.2, Chrome 32) the fade away background effect does not work, although I have spent a lot of time over it (http://www.leftlane.pl/lut14/koniec-produkcji-elektrycznego-renault-fluence-ze!.html). It is ok on PC, but on the phone it does not look good. A whole picture moves from a lower layer instead of an edge which spoils everything.
This layout does not look good on Android (http://www.leftlane.pl/sty14/nowe-mini-krolestwo-silnikow-3-cylindrowych.html#a07). The background does not fill the whole width of a page. There are also problems with a photo gallery, where full screen pictures should fill more of a screen.
Is it possible to make an option of scroll effects/motions for a fullscreen slideshow widget thumbnails (http://www.leftlane.pl/sty14/2014-chevrolet-ss%2c-rodzinny-sedan-z-415-konnym-v8.html#a06)? It would help me with designing layouts. Currently, it can go from a bottom of a page at x1 speed or emerge (like in this layout) by changing opacity. Something more will be needed, I suppose.
Sometimes the pictures from gallery (http://www.leftlane.pl/sty14/2014-chevrolet-ss%2c-rodzinny-sedan-z-415-konnym-v8.html#a06 download very slowly. The website is hosted at Business Catalyst. I cannot state when exactly it happens, most of the time it works ok.
I really like layouts like this (http://www.leftlane.pl/sty14/2014-chevrolet-ss%2c-rodzinny-sedan-z-415-konnym-v8.html#a03). On the top is a description and a main text, and the picture is a filled object with a hold set at the bottom edge. That is why there is a nice effect of a filling a whole screen- nevertheless the resolution that is set. It works perfect on PC, but on Android the picture goes beyond the screen. You can do something about it?
In horizontal layouts (http://www.leftlane.pl/sty14/dig-t-r-3-cylindrowy-silnik-nissana-o-wadze-40-kg-i-mocy-400- km.html) holding of a filling object does not work. Everything is always held to upper edge of a screen regardless the settings. Possibility of holding the picture to the bottom edge or center would make my work much easier.
According to UE regulations we have to inform about the cookies. I do not know how to do it in Muse. I mean, when the message shows up one time and is accepted, there would be no need to show it again and again during another visit on the website. Is there any way to do it? Is there any widget for it maybe?
The YouTube widget sometimes changes size just like that. It is so when the miniature of the movie does not load, and the widget is set to stroke (in our case 4 pixels, rounded to 1 pixel). As I remember ( in case of a load error) it extends for 8 pixels wide.
Last but not least - we use the cheapest hosting plan in Business Catalyst. The monthly bandwidth is enough, although we have a lot of pictures and we worried about it at first. Yet we are running out of the disk storage very quickly. We have used more than a half of a 1 GB after a month. We do not want to change BC for a different one, because we like the way it is connected with Muse. But we do not want to buy the most expensive package - but only this one has more disk space. We do not need any other of these functions and it would devastate our budget. Do we have any other option?
I’m using Adobe Muse 7.2 on OS X 10.9.1.
and I'm sending Muse file to <[email protected]>

Unfortunatley, there is no way to get a code view in Muse. I know quite a few people requested it in the previous forum, but not really sure where that ended up. Also, you may not want to bring the html into DW unless you only have 1 or 2 small changes 2 make. Two reasons. First, it isnt backwards compatible, so if you are planning on updating that site in Muse, you will need to make those changes in DW everytime you update. Second, by all accounts the HTML that Muse puts out is not pretty or easy to work with. Unlike you, I am code averse, but there was a lenghty discussion on the previous forum on this topic. I know they were striving to make it better with every release, just not sure where it is at this point.
Dont think I am reading that second question right, but there was a ton of info on that old site. You may want to take a look there, people posted a ton of great unique solutions, so it worth a look.
Here is the link to the old forums- http://support.muse.adobe.com/muse

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