Range Partitioning for the day of the week

I have a logging table which i want to partition into 7 partition, each one for the day of the week, eg MON,TUE, WED. I am aware and I can do a list partition by creating a parition key which stores 'DY' of the week and this means that I need to add another column to the existing table.
I wanted to explore the option of creating a range parition based on the timestamp column that already exists. Can anyone let me know if this option is possible?
Example
create table test_partition
( log_id number,
log_date TIMESTAMP(6),
log_value varchar2(100)
PARTITION BY RANGE (log_date)
PARTITION p1_mon VALUES LESS THAN (), ---- Not sure what can be used here to create this parition.
PARTITION p2_tue VALUES LESS THAN (),
PARTITION p3_wed VALUES LESS THAN (),
PARTITION p4_thu VALUES LESS THAN (),
PARTITION p5_fri VALUES LESS THAN (),
PARTITION p6_sat VALUES LESS THAN (),
PARTITION p7_sun VALUES LESS THAN ()
Any oracle guru with some suggestion for this would be highly appreciated..
Cheers,
VJ

VJ,
Here is an example of daily partitioning , let me know if this is what you want or you can modify this even to weekly, monthly, quarterly and yearly partitions.
CREATE TABLE YY_EVENT
  PART_KEY       DATE                           NOT NULL,
  SUBPART_VALUE  NUMBER                             NULL,
  EVENT_NAME     VARCHAR2(30 BYTE)                  NULL,
  EVENT_VALUE    NUMBER                             NULL
TABLESPACE TEST_DATA
PARTITION BY RANGE (PART_KEY)
  PARTITION Y_EVENT_20090310 VALUES LESS THAN (TO_DATE(' 2009-03-11 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN'))
    LOGGING
    NOCOMPRESS
    TABLESPACE TEST_DATA, 
  PARTITION Y_EVENT_20090311 VALUES LESS THAN (TO_DATE(' 2009-03-12 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN'))
    LOGGING
    NOCOMPRESS
    TABLESPACE TEST_DATA
)Regards

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  • Is there a way to change the start day for the week?

    So I really like the "Insert Categories from the following" functionality of the Reorganize tool, and I fell in love with it's ability to break down by date automagically. I've encountered one problem with my use of it, though: I start my "work week" on Sunday, and it defaults to Monday as the first day of a week without any seeming way to change it to Sunday. Is there a way to do this?

    Hi Christopher,
    The WEEKDAY function allows specifying either Sunday or Monday as the first day of the week:
    WEEKDAY
    The WEEKDAY function returns a number that is the day of the week for a given date. WEEKDAY(date, first-day)
      date:  The date the function should use. date is a date/time value. The time portion is ignored by this function.
      first-day: An optional value that specifies how days are numbered.
    Sunday is 1 (1 or omitted):  Sunday is the first day (day 1) of the week and Saturday is day 7.
    Monday is 1 (2):  Monday is the first day (day 1) of the week and Sunday is day 7. Monday is 0 (3):  Monday is the first day (day 0) of the week and Sunday is day 6.
    But I think you are referring to the first day of the 'workweek', for which I do not see a means of defining a custom value.
    Since you want to 'insert categories', though, you could easily define your own, using WEEKDAY(date) or WEEKDAY(date,1), plus an IF statement to return the category label appropriate to the day. Here's one for a Sunday to Thursday work week. Dates are in column A, the formula is in whichever column you want as the Category column. For the example, I've placed it in column B.
    B2, and filled down: =IF(WEEKDAY(A)<6,"Work","Off")
    The top table shows the weekday numbers returned for each day of the week for each of the three permitted values for the optional second argument. The bottom table shows the results from the formula above, used to define a category label for each date:
    A10 was left blank intentionally, to determine if the lack of data resulted in an error. The Warning message, flagged by the blue 'warning' triangle, is "The formula uses a number in place of a date." The 'date' assigned to this numerical value of zero was a Friday, but I'm not certain when. Probably best to avoid extra rows with no date shown.
    Regards,
    Barry

  • Find the partition for the fact table

    Oracle version : Oracle 10.2
    I have one fact table with daily partitions.
    I am inserting some test data in this table for old date 20100101.
    I am able to insert this record in this table as below
    insert into fact_table values (20100101,123,456);
    However I observed that the partition for this date does not exist in the table (all_tab_partitions) morever I am not able to select the data using
    select * from facT_table partition(d_20100101)
    but I am able to extract the data using
    select * from facT_table where date_id=20100101
    could some one please let me know the way to find the partition in which this data might be inserted
    and if the partition for date 20100101 is not present then why insert for that date is working ?

    user507531 wrote:
    However I observed that the partition for this date does not exist in the table (all_tab_partitions) morever I am not able to select the data using
    select * from facT_table partition(d_20100101)Wrong approach.
    but I am able to extract the data using
    select * from facT_table where date_id=20100101Correct approach.
    could some one please let me know the way to find the partition in which this data might be inserted
    and if the partition for date 20100101 is not present then why insert for that date is working ?Who says that the date is invalid..? This is a range partition - which means that each partition covers a range. And if you bothered to read up in the SQL Reference Guide on how a range partition is defined, you will notice that each partition is defined with the end value of the range it covers. There is no start value - as the previous partition's end value is the "+border+" between this and the prior partition.
    I suggest that before you use a database feature you first familiarise yourself with it. Else incorrectly using it, and making the wrong assumptions about it, more than likely results.

  • Only Monday and important lesson for the week.

    Yeah it's like one small change can set off a chain reaction of mishaps in the most unanticipated, yet in 20/20 hindsight makes sense, ways.One of my business partners asked me to stop by a 3-person company run by one of her friends. They have zero tech support and have problems dealing with Western Digital external hard drive solution. I go there, and the device just is not working. I told the guy "Well hate to this, but it's just not working" And the guy is like "I can't accept that as an answer", and I chuckle to myself "as if the device cares what you will accept", so I take him to google and type out his problem and let him see all the people struggling with it and he's like "Oh I guess there is something wrong with it" And I tell him "Welcome to my job.. googling problems and working out which solutions might work and might not...

    I have a client that has this odd industry app that I guess is always a PITA. I had a small fix to do a few weeks back. He mentions a rep from this software vendor will be coming and installing some new software features to this app and some special hardware. He said I don't know, but we may need you on that day.
    I replied okay, you have all the logins you should need, I think you'll be set. Guy comes, I guess that all goes off without a hitch. The next week though I get email he's like I'mlogging in with this account, I don't recall what we used before.
    This account was for the owner and had a roaming profile setup, and printers had changed from default because this vendors work. He tried changing, but they kept resetting. I told him I think it was probably related to so many profiles on this account being open and they weren't all the...
    This topic first appeared in the Spiceworks Community

  • Search help for the "Week Select option"

    Hi Experts,
    My selection screen is like this:
    Article:  .............. to ..............
    Week  .............    to ...............
    I am taking article EKPO-MATNR field.and week S012-SPWOC field
    Now there is there search help for the S012-SPWOC field. How can I create the seach help for this fields.
    Regards
    Krishan

    hi,
    try this way.
    tables: ekpo, s012.
    select-options:article for EKPO-MATNR,
                    week for S012-SPWOC.
    Regards,
    Shankar.

  • Here's why Adobe closed for the week

    June 30, 2009
    Adobe is closed this week (and what that means)
    http://blogs.adobe.com/jnack/2009/06/adobe_is_closed_this_week.html

    Could anyone object to getting four weeks' holiday in a country where that could seem generous? The problem is that Adobe's reasons for the shutdowns – its attempts to cope with the economic slowdown that has, in turn, reduced demand from its core customer base in the "creative knowledge worker business" – don't mean that it's easing up on staff.The office closures didn't mean that deadlines were pushed back by a week for those developing software. And for those preparing for a conference, such as the RSA conference in April, which came immediately after one of Adobe's one-week breaks, there was simply no let-up.
    People in the UK, of course, may have a better reason than any for pausing, as the – an increase that was announced earlier in June but that is still not documented on the company's UK website. That has pushed the disparity between the pricing of CS4 in the UK and US to 39.7%.
    Hmmmmmm.

  • Range Size for the Iterator

    Hi
    I have set the iterator range size for a VO in an UIX page as "10". Can I change the range size dynamically in the code....(i.e) in one view I want the 10 records to be listed and in another view i want 20 records to be displayed.
    Thanks
    Shoba

    Try setRangeSize() after executeQuery(), like this
    try
    panelBinding.getRowIterBinding("CubTicsView3", null, "CubTicsView1Iterator").getViewObject().setWhereClause(currentWhere);
    panelBinding.getRowIterBinding("CubTicsView3", null, "CubTicsView1Iterator").getViewObject().executeQuery();
    panelBinding.getRowIterBinding("CubTicsView3", null, "CubTicsView1Iterator").setRangeSize(-1);
    callRedrawChart();
    catch (DMLException ex)
    ex.printStackTrace();
    }

  • Account was paid in full for 90 days but several weeks later it was deleted.

    I paid $30 on May 16 so I would get the 90-day plan. I received two emails within a few hours saying that it had gone through and my $30 was accepted. It also said my account was paid up through August 16th. Several weeks later I got an email saying my account was not paid up and my initial $25 payment would expire in a few days. About a week ago I got another email saying my account had been deleted since I had never paid. So, I have paid and I have emails stating such, and my credit card account shows the $30 was accepted by AT&T. My account should be paid in full from May 16 through August 16. I have needed to use the device for internet but cannot as my account has been deleted. Help!

    Hi BillProblemo,
    Your issue has been escalated to a Verizon agent. Before the agent can begin assisting you, they will need to collect further information from you. Please go to your profile page for the forum and look at the top of the middle column where you will find an area titled "My Support Cases". You can reach your profile page by clicking on your name beside your post, or at the top left of this page underneath the title of the board.
    Under "My Support Cases" you will find a link to the private board where you and the agent may exchange information. This should be checked on a frequent basis, as the agent may be waiting for information from you before they can proceed with any actions. Please keep all correspondence regarding your issue in the private support portal.

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