Rank function code

Does anybody know where I can find the code of rank function in Oracle 8.1.6 Enterprise Edition
Thanks

If you want to look at the proprietary source code for any Oracle function you have to get yourself employed by Oracle Corp as a kernel developer. This is not an open source gig.
Chhers, APC

Similar Messages

  • RANK Function in AIX vs Windows

    I am facing an issue where when I run my report using my windows machine I am able to get the right results with the RANK function. However, when I ran the same report in my AIX machine, I got the following error:
    Odbc driver returned an error (SQLExecDirectW).
    Error Details
    Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
    State: HY000. Code: 378077472. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 46008] Internal error: File server/Query/Optimizer/ServiceInterfaceMgr/Src/SQOIGeneratorBuiltIn.cpp, line 3403. (HY000)
    If anyone has run into this, please let me know.
    Thanks.

    One point to make is the Rank function works if you create 1 column with the RANK function in Answers(i.e. Rank(Fact.Sales) ). The issue comes up when you try to create a BIN column to bucket the RANKs in a seperate column.
    Here's the SQL:
    SELECT Location.Location saw_0, case WHEN RANK(Metrics.Sales) BETWEEN 1 AND 5 then '1-5' WHEN RANK(Metrics.Sales) BETWEEN 5 AND 10 then '5-10' else 'other' end saw_1, Metrics.Sales saw_2, RANK(Metrics.Sales) saw_3 FROM "Rank Prototype" ORDER BY saw_0
    So Basically, the issue is when you have a Bucketed Rank Sales Column and a simple Rank Column in the same request. (In AIX the issue exists, in Windows there is no issue.)

  • Error using Rank function in Answers

    Hi All,
    Am trying to generate a report in Answers which lists Top Accounts with Revenue.
    I Ranked the Revenue field and it is returning me correct values. ( Rank(account.revenue) )
    But, when I try to filter on this field and restrict the rows which shows only top 10 Accounts, it is returning the following error:
    State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 17001] Oracle Error code: 1792, message: ORA-01792: maximum number of columns in a table or view is 1000 at OCI call OCIStmtExecute. [nQSError: 17010] SQL statement preparation failed. (HY000)
    Can any one help me on this.
    Thanks in Advance,
    Imtiaz.

    Hi Joe,
    This is the Physical query generated when I use Rank function and the report is fine.
    select distinct D1.c1 as c1,
    D1.c2 as c2,
    D1.c3 as c3,
    D1.c4 as c4,
    D1.c5 as c5,
    D1.c6 as c6,
    D1.c7 as c7,
    D1.c8 as c8,
    D1.c9 as c9,
    D1.c10 as c10,
    D1.c11 as c11,
    D1.c12 as c12,
    D1.c13 as c13,
    D1.c14 as c14,
    D1.c15 as c15
    from
    (select D1.c1 as c1,
    D1.c2 as c2,
    D1.c3 as c3,
    D1.c4 as c4,
    D1.c5 as c5,
    D1.c6 as c6,
    D1.c7 as c7,
    D1.c8 as c8,
    D1.c9 as c9,
    D1.c10 as c10,
    D1.c11 as c11,
    D1.c12 as c12,
    D1.c13 as c13,
    D1.c14 as c14,
    D1.c15 as c15
    from
    (select Case when D1.c1 is not null then Rank() OVER ( ORDER BY D1.c1 DESC NULLS LAST ) end as c1,
    D1.c2 as c2,
    D1.c3 as c3,
    D1.c1 as c4,
    D1.c4 as c5,
    D1.c5 as c6,
    D1.c6 as c7,
    D1.c7 as c8,
    D1.c8 as c9,
    D1.c9 as c10,
    D1.c10 as c11,
    D1.c11 as c12,
    D1.c12 as c13,
    D1.c13 as c14,
    D1.c14 as c15,
    ROW_NUMBER() OVER (PARTITION BY D1.c1, D1.c2, D1.c3, D1.c4, D1.c5, D1.c6, D1.c7, D1.c8, D1.c9, D1.c10, D1.c11, D1.c12, D1.c13, D1.c14 ORDER BY D1.c1 ASC, D1.c2 ASC, D1.c3 ASC, D1.c4 ASC, D1.c5 ASC, D1.c6 ASC, D1.c7 ASC, D1.c8 ASC, D1.c9 ASC, D1.c10 ASC, D1.c11 ASC, D1.c12 ASC, D1.c13 ASC, D1.c14 ASC) as c16
    from
    (select distinct T690.SUM_REVN_AMT as c1,
    T690.NAME as c2,
    T2216.NAME as c3,
    T690.X_PETROFAC_REVN as c4,
    T690.SUM_WIN_PROB as c5,
    T690.X_PERCENT_GET as c6,
    T690.SUM_WIN_PROB * T690.X_PERCENT_GET / nullif( 100, 0) as c7,
    T690.X_EC_PRIORITY as c8,
    T19028.LOGIN as c9,
    T690.X_COUNTRY as c10,
    T690.X_REGION as c11,
    T18311.NAME as c12,
    T18641.NAME as c13,
    T18238.NAME as c14
    from
    SIEBEL.S_BU T18238 left outer join (
    SIEBEL.S_USER T19028 left outer join (
    SIEBEL.S_OPTY T690 left outer join SIEBEL.S_STG T2216 On T690.CURR_STG_ID = T2216.ROW_ID) left outer join SIEBEL.S_ORG_EXT T1189 On T690.PR_DEPT_OU_ID = T1189.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18311 /* Competitor */ On T690.PR_CMPT_OU_ID = T18311.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18641 /* Partner */ On T690.PR_PRTNR_ID = T18641.ROW_ID) left outer join SIEBEL.S_POSTN T19114 On T690.PR_POSTN_ID = T19114.PAR_ROW_ID) left outer join SIEBEL.S_OPTY_BU T18280 On T690.ROW_ID = T18280.OPTY_ID) left outer join SIEBEL.S_OPTY_X T19415 On T690.ROW_ID = T19415.PAR_ROW_ID) On T19028.PAR_ROW_ID = T19114.PR_EMP_ID) On T18238.ROW_ID = T18280.BU_ID
    ) D1
    ) D1
    where ( D1.c16 = 1 )
    ) D1
    order by c1 desc
    But When I apply Filter on this Rank column then it gives me the error. THis is the Physical query for that
    select distinct Case when D1.c1 is not null then Rank() OVER ( ORDER BY D1.c1 DESC NULLS LAST ) end as c1,
    D1.c2 as c2,
    D1.c3 as c3,
    D1.c1 as c4,
    D1.c4 as c5,
    D1.c5 as c6,
    D1.c6 as c7,
    D1.c7 as c8,
    D1.c8 as c9,
    D1.c9 as c10,
    D1.c10 as c11,
    D1.c11 as c12,
    D1.c12 as c13,
    D1.c13 as c14,
    D1.c14 as c15
    from
    (select D1.c1 as c1,
    D1.c2 as c2,
    D1.c3 as c3,
    D1.c4 as c4,
    D1.c5 as c5,
    D1.c6 as c6,
    D1.c7 as c7,
    D1.c8 as c8,
    D1.c9 as c9,
    D1.c10 as c10,
    D1.c11 as c11,
    D1.c12 as c12,
    D1.c13 as c13,
    D1.c14 as c14
    from
    (select T690.SUM_REVN_AMT as c1,
    T690.NAME as c2,
    T2216.NAME as c3,
    T690.X_PETROFAC_REVN as c4,
    T690.SUM_WIN_PROB as c5,
    T690.X_PERCENT_GET as c6,
    T690.SUM_WIN_PROB * T690.X_PERCENT_GET / nullif( 100, 0) as c7,
    T690.X_EC_PRIORITY as c8,
    T19028.LOGIN as c9,
    T690.X_COUNTRY as c10,
    T690.X_REGION as c11,
    T18311.NAME as c12,
    T18641.NAME as c13,
    T18238.NAME as c14,
    Case when T690.SUM_REVN_AMT is not null then Rank() OVER ( ORDER BY T690.SUM_REVN_AMT DESC NULLS LAST ) end as c15
    from
    SIEBEL.S_BU T18238 left outer join (
    SIEBEL.S_USER T19028 left outer join (
    SIEBEL.S_OPTY T690 left outer join SIEBEL.S_STG T2216 On T690.CURR_STG_ID = T2216.ROW_ID) left outer join SIEBEL.S_ORG_EXT T1189 On T690.PR_DEPT_OU_ID = T1189.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18311 /* Competitor */ On T690.PR_CMPT_OU_ID = T18311.ROW_ID) left outer join SIEBEL.S_ORG_EXT T18641 /* Partner */ On T690.PR_PRTNR_ID = T18641.ROW_ID) left outer join SIEBEL.S_POSTN T19114 On T690.PR_POSTN_ID = T19114.PAR_ROW_ID) left outer join SIEBEL.S_OPTY_BU T18280 On T690.ROW_ID = T18280.OPTY_ID) left outer join SIEBEL.S_OPTY_X T19415 On T690.ROW_ID = T19415.PAR_ROW_ID) On T19028.PAR_ROW_ID = T19114.PR_EMP_ID) On T18238.ROW_ID = T18280.BU_ID
    ) D1
    where ( D1.c15 <= 10 )
    ) D1
    order by c2, c3, c4, c5, c6, c7, c8, c9, c10, c11, c12, c13, c14, c15
    Thanks,
    Imtiaz

  • @Rank function using EVALUATE

    Hi short question,
    I'm trying to get the @rank function to work in combination with OBIEE 10.1.3.4 (using EVALUATE). Anyone here already tried using this with Essbase version 9.2? In some of the documentation it states this can not be done using anything below Essbase 9.3 but the @Rank function is available within v9.2 Is there any limit on using this from the OBIEE side?
    I used this reference:
    (how to:) http://oraclebizint.wordpress.com/2008/04/28/oracle-bi-ee-101332-handling-sort-order-in-hyperion-essbase-931-evaluate-and-mdx/
    (Essbase 9.2 doc --> @Rank available) http://download.oracle.com/docs/cd/E12032_01/doc/epm.921/html_techref/techref.htm
    Evaluate function I'm trying to launch is:
    EVALUATE(’RANK(%1.dimension.currentmember,%2.members)’ AS INTEGER,Period."PeriodGen4",Period."PeriodGen4")
    Am I doing something wrong here, or am I trying to do things which can't be done?
    Thanks in advance,
    Mathijs

    I tried the syntax
    EVALUATE ('RANK(%1,%2)' as integer,"Account"."Gen4,Account Default","Account"."Gen4,Account Default")
    but still i am getting the error as:-
    Error Codes: OPR4ONWY:U9IM8TAC:OI2DL65P
    State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error has occurred. [nQSError: 43113] Message returned from OBIS. [nQSError: 96002] Essbase Error: Syntax error in input MDX query on line 6 at token 'RANK' (HY000)
    SQL Issued: SELECT s_0, s_1, s_2, s_3, s_4, s_5, s_6, s_7 FROM ( SELECT 0 s_0, "FINRPTC#1"."Account"."Gen3,Account Default" s_1, "FINRPTC#1"."Account"."Gen4,Account Default" s_2, "FINRPTC#1"."FinancialYear"."Gen2,FinancialYear" s_3, "FINRPTC#1"."Period"."Gen3,Period" s_4, EVALUATE ('RANK(%1,%2)' as integer,"FINRPTC#1"."Account"."Gen4,Account Default","Account"."Gen4,Account Default") s_5, "FINRPTC#1"."FINRPTC"."Actual" s_6, REPORT_AGGREGATE("FINRPTC#1"."FINRPTC"."Actual" BY "FINRPTC#1"."Account"."Gen3,Account Default","FINRPTC#1"."Account"."Gen4,Account Default","FINRPTC#1"."FinancialYear"."Gen2,FinancialYear","FINRPTC#1"."Period"."Gen3,Period") s_7 FROM "FINRPTC#1" WHERE (("FinancialYear"."Gen2,FinancialYear" = 'FY12') AND ("Period"."Gen3,Period" = 'Nov') AND ("Account"."Gen3,Account Default" = 'Net Cost of Services')) ) djm

  • Retruning rows which have same value return by RANK function

    Hi, what I wanna acheive is to use a DENSE RANK function to identify the same value of the data, if rank values are same then extra out. Here is the code
    WITH CTE AS
    SELECT SalesPersonID,
    SalesQuota,
    DENSE_RANK() OVER (ORDER BY SalesQuota DESC) as DENSE_RANK
    FROM Sales.SalesPersonQuotaHistory
    WHERE SalesQuota BETWEEN 266000.00 AND 319000.00
    )This retrun
    SalesPersonID SalesQuota DENSE_RANK
    280 319000.00 1
    287 304000.00 2
    280 301000.00 3
    282 288000.00 4
    283 284000.00 5
    287 281000.00 6
    278 280000.00 7
    283 280000.00 7
    283 267000.00 8
    278 266000.00 9How could I select those rank value which are same value ??
    The result should be
    278 280000.00 7
    283 280000.00 7

    with cte as
    select salespersonid,
         salesquota,
         dense_rank() over (order by salesquota desc) as dr
       from sales.salespersonquotahistory
      where salesquota between 266000.00 and 319000.00
    select *
      from (
         select cte.*, count(*) over(partition by dr) ct
           from cte
    where ct > 1

  • Compile forms error because using rank function

    Hi,
    Oracle Form 9i don't known rank function in my SQL statement. When compile forms, it alerts err message: "Encountered the symbol "(" when expecting one ..."
    code:
    select * from (
    select group_id, acct_no, acct_desc, rank() over(order by acct_no desc) rank_no from customer
    where group_id='002'
    ) where rank_no< 10000
    Help me ASAP.
    Many thank,
    Bum.

    Where is INTO clause ? Plz provide the actual code you are writing.
    I think this type of queries not supported in Forms 9i.....try forms 10g or above.

  • Function Code can not be selected

    Dear expert,
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    Message NO: 00255
    Diagnosis
    You entered an Inactive function code
    You can trigger this by:
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    inputting the fastpath of an inactive menu function
    choosing an inactice function key, or even by
    choosing enter, if enter has an inactive function
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    As well as activating function codes stastically in the menu painter(Transaction SE41), they can also be deactivated dynamically using the excluding addition with PF-STATUS.
    Now one more thing i want to tell you is when user just open MIGO directly and try to enter some data and get back before saving and then Execute uploader then user can upload data without any error,
    Kindly tell me what shoul i do to remove this error permanently
    Thanks in advance
    Regards
    Shelly Malik

    There is an error in this uploader, it should not call this command which is not available on that screen. What is this uploader? If it's a custom abap program, you must debug it.

  • How to track the standard function code eg. PRI

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    Atanu

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    santhosh reddy

  • How to find function code for buttons on toolbar in oops alv

    Hi experts,
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    ENDFORM.                    "PF_STATUS}
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    *-->Then doble click on that pf status,
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          i_callback_user_command           = 'COMM'
    And make a subroutine of the name 'COMM'i.e,
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      DATA: okcode TYPE sy-ucomm.
      okcode = ucomm.
      CASE okcode.
        WHEN 'REF'.
        CALL FUNCTION 'POPUP_TO_INFORM'
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            titel         = 'MANSI'
            txt1          = 'CREATED BY'
            txt2          = SY-UNAME
          TXT3          = ' '
          TXT4          = ' '
    endcase.
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  • How to translate function codes from GUI-status into other language ?

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  • Assigning a function code to radio button in 4.5B

    I’ve a requirement wherein I need to trigger the PAI event in a module pool program when I select a particular radiobutton in a group and do some processing subsequently.
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    I am able to assign function codes to radio button groups in esuides(4.6C) and other systems.
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    If so, please tell me how to do this.
    With regards,
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    Hi,
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    if RAD1 = 'X'.
    xxxxxxxxxxx.
    xxxxxxxxx.
    elseif RAD2 = 'X'.
    xxxxxxxxx.
    xxxxxxxxxxxx.
    endif.
    regards,
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  • "Function code cannot be selected" error while uploading a document.

    Hi,
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    No batch input data for screen SAPLF040 0300
    Message no. 00344
    Diagnosis
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    Possible reasons:
    1. The batch input session was created incorrectly. The sequence of screens was recordly incorrectly.
    2. The transaction behaves differently in background processing in a batch work process than when running in dialog (SY-BATCH is queried and changes the screen sequence).
    3. The transaction has undergone user-specific Customizing and therefore certain screens may be skipped or processed differently, according to the current user. If the person who created a batch input session is not the same as the person now processing it, this problem may occur frequently.
    System Response
    None.
    Procedure
    For 1: Either re-create the session or process it in expert mode. Correct the batch input program.
    For 2. It is very difficult to analyze this problem, particularly in the case that the screen sequence or the display-only options of fields differ according to whether the transaction is being processed in the background or as an online dialog. It could also be that this kind of transaction cannot run with batch input.
    For 3: Have the creator of the session process it. If no error occurs now, then this is a program with user-specific Customizing.

    Hi Amar,
    I am facing the same issue while processing Vendor master inbound idocs, Few Idocs gone in error with error message "Function code cannot be selected".
    Could you please suggest any solution found for the same.
    Thanks in advance
    Shivam

  • How to use "Rank" function  in Oracle?

    I need to display Top 15 records by using rank function.
    Here is my query...I need to pull top 15 FAQ's using the below query.. How can I use RANK function to display the Top 15 FAQ"s in the list.
    Select  distinct SUb1.FAQ,Sub1.FAQ_Hits,GU.display_Name_FMLS as displayname,ev.ParentLinkrecordid,ev.userid from User GU
    Join Event ev
    ON LOWER (ev.userid) IN (LOWER (GU.lanid), LOWER (Gu.racfid))
    Join (Select distinct sm.stem as FAQ,Sum(ev.Eventresults) as FAQ_Hits,ev.ParentLinkrecordid as Topic_ID from Event ev
    Join SubjectMatter sm
    ON (TO_CHAR (sm.smrecordid) = ev.eventdetail1) AND ev.eventdetail1 IS NOT NULL AND sm.smtype = 1
    Where (Upper(ev.eventsubtype) in (Upper('FAQ'),Upper('OPENFAQ')))
    AND TO_DATE (eventdatetime, 'yyyy-mm-dd hh24:mi:ss') >= TO_DATE ('20100601', 'yyyymmdd')
    and TO_DATE (eventdatetime, 'yyyy-mm-dd hh24:mi:ss') <= TO_DATE ('20100831', 'yyyymmdd')
    Group by sm.stem,ev.Parentlinkrecordid
    order by FAQ )sub1
    ON Sub1.Topic_ID = ev.ParentLinkrecordid)

    A few bits that I noticed in the query ...
    in (Upper('FAQ'),Upper('OPENFAQ'))1) Do you really a upper for a string which is already in upper case.
    Select distinct sm.stem as FAQ,Sum(ev.Eventresults) as FAQ_Hits,ev.ParentLinkrecordid as Topic_ID2) Do you need a distinct when you are using a GROUP function viz. SUM ?
    You rank query is as follows, I am not very good at the ANSI style JOIN so changed it slightly ... :-)
    Also notice the usage rank function in the "sub1" query.
    select distinct sub1.faq,
                    sub1.faq_hits,
                    gu.display_name_fmls as displayname,
                    ev.parentlinkrecordid,
                    ev.userid
    from user gu, event ev,
      (select rank() over (order by sum(ev.eventresults) desc) rnk,
              sum(ev.eventresults) as faq_hits,
              sm.stem as faq,         
              ev.parentlinkrecordid as topic_id
         from event ev, subjectmatter sm
        where (to_char(sm.smrecordid) = ev.eventdetail1)
          and ev.eventdetail1 is not null
          and sm.smtype = 1
          AND upper(ev.eventsubtype) in ('FAQ', 'OPENFAQ')
          and to_date(eventdatetime, 'yyyy-mm-dd hh24:mi:ss') >= to_date('20100601', 'yyyymmdd')
          and to_date(eventdatetime, 'yyyy-mm-dd hh24:mi:ss') <= to_date('20100831', 'yyyymmdd')
        group by sm.stem, ev.parentlinkrecordid
        order by faq) sub1
    where lower(ev.userid) in (lower(gu.lanid), lower(gu.racfid))
      and sub1.topic_id = ev.parentlinkrecordid)
      and sub1.rnk <= 15;Like mentioned above, some sample data would have helped.

  • RANK FUNCTION IN ORACLE 8I

    제품 : PL/SQL
    작성날짜 : 2001-09-11
    RANK FUNCTION IN ORACLE 8I
    ==========================
    EXPLANATION
    oracle 8i(8.1.6) 부터 가능한 rank function 입니다.
    8.1.5 에서는 ora-923 error 가 납니다.
    plsql 내에서는 oracle 9i 부터 가능합니다.
    8.1.6에서는 ora-900 error가 납니다.
    EXAMPLE
    <RANK() OVER ( query_partition_clause ORDER_BY clause) >
    - 중복 rank 값만큼 다음 순위는 생략
    SQL>SELECT deptno, ename, sal, comm,
    RANK() OVER (PARTITION BY deptno ORDER BY sal DESC, comm) as rk
    FROM emp;
    DEPTNO ENAME SAL RK
    10 KING 5000 1
    10 CLARK 2450 2
    10 MILLER 1300 3
    20 3500 1
    20 SCOTT 3000 2
    20 FORD 3000 2
    20 JONES 2975 4
    20 ADAMS 1100 5
    20 SMITH 800 6
    30 BLAKE 2850 1
    30 ALLEN 1600 2
    30 TURNER 1500 3
    30 WARD 1250 4
    30 MARTIN 1250 5
    40 JAMES 777 1
    9 1
    <DENSE_RANK( ) OVER ( query_partition_clause ORDER_BY clause ) >
    - 중복 rank 의 수와 무관하게 numbering
    SQL>SELECT dname, ename, sal, DENSE_RANK()
    OVER (PARTITION BY dname ORDER BY sal) as drank
    FROM emp, dept
    WHERE emp.deptno = dept.deptno
    AND dname IN ('SALES', 'RESEARCH');
    DNAME ENAME SAL DRANK
    RESEARCH SMITH 800 1
    RESEARCH ADAMS 1100 2
    RESEARCH JONES 2975 3
    RESEARCH SCOTT 3000 4
    RESEARCH FORD 3000 4
    RESEARCH 3500 5
    SALES WARD 1250 1
    SALES MARTIN 1250 1
    SALES TURNER 1500 2
    SALES ALLEN 1600 3
    SALES BLAKE 2850 4
    plsql 내에서 사용 가능 :oracle 9i 부터
    SQL> create table
    rank_emp(deptno number(2), ename varchar2(20), sal number(5), rk number(2));
    테이블이 생성되었습니다.
    SQL> create or replace procedure window_plsql AS
    query_str VArchar2(1000);
    begin
    query_str := 'insert into rank_emp
    SELECT deptno, ename, sal,
    RANK() OVER (PARTITION BY deptno ORDER BY sal DESC, comm) as rk
    FROM emp' ;
    Execute Immediate query_str;
    end;
    2 /
    프로시저가 생성되었습니다.
    SQL> exec window_plsql
    PL/SQL 처리가 정상적으로 완료되었습니다.
    SQL> select * from rank_emp;
    DEPTNO ENAME SAL RK
    10 KING 5000 1
    10 CLARK 2450 2
    10 MILLER 1300 3
    20 SCOTT 3000 1
    20 FORD 3000 1
    20 JONES 2975 3
    20 ADAMS 1100 4
    20 SMITH 800 5
    30 BLAKE 2850 1
    30 ALLEN 1600 2
    30 TURNER 1500 3
    DEPTNO ENAME SAL RK
    30 WARD 1250 4
    30 MARTIN 1250 5
    30 JAMES 950 6
    14 개의 행이 선택되었습니다.

    That's correct
    The differences between Standard and Enterprise Edition are listed here:
    http://www.oracle.com/technology/products/oracle8i/pdf/8i_fam.pdf

  • Prob in using rank in pl/sql ,need logic same of rank function in any way

    I have a query as of the following <br>
    <br>
    SELECT sr_no,cod_acct_no,dat_arrears_due,amt_arrear_due<br>
    FROM ( select cod_acct_no,dat_arrears_due,sum(amt_arrears_due) <br>amt_arrear_due,rank() over (partition by cod_acct_no order by <br>dat_arrears_due asc) sr_no<br>
              from arrears_table <br>
              where amt_arrears_due > 0<br>
    and dat_arrears_due <= to_date('31/10/2006','dd/mm/yyyy')<br>
    and COD_ARREAR_TYPE = 'C'<br>
         group by cod_acct_no,dat_arrears_due<br>
         ) Z <br>
    WHERE z.sr_no <=5 <br>
    <br>
    I have to use this in a cursor in pl/sql but because i have rank analytic function <br>
    I am facing a compilation error ORA-06550: error <br>
    <br>
    Can you give me a logic which gives same output as of above <br>
    <br>
    Regards<br>
    vamsi krishna<br>
    <br>
    <br>

    [1]: (Error): ORA-06550: line 5, column 28: PLS-00103: Encountered the <br>symbol "(" when expecting one of the following: , from <br>
    <br>
    My oracle version is <br>
    Oracle8i Enterprise Edition Release 8.1.6.0.0 - Production<br>
    PL/SQL Release 8.1.6.0.0 - Production<br>
    CORE 8.1.6.0.0 Production<br>
    TNS for 32-bit Windows: Version 8.1.6.0.0 - Production<br>
    NLSRTL Version 3.4.1.0.0 - Production<br>
    <br>I think it is comming for rank function it self <br>
    <br> will this version support analytic (rank) function's in pl/sql cursors<br>
    Regards<br>
    vamsi krishna<br>

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