Re: Four data guard on the same machine

Hi Hemant
i am finding much difficulty in using this updated form now.i have asked question but not able to see.So i am asking my question here.please reply
i have a query regarding directory structure.What i did is i kept exactly the same directory structure on both primary and standby..please clear me on that
Its what i did
Primary SID- PROD
Directory--- D:\oracle\product\10.2.0\PROD\abc.dbf(all datafiles,redo,control are in this directory)
Archive location on Primary D:\PROD\ARCHIVE\.arc(all archives)
Now what i did on standby.i created different sid--PROD2
But i have kept exactly the same directory structure on standby too as
datafiles in D:\oracle\product\10.2.0\PROD\abc.dbf(all datafiles)
Archive location on standby D:\PROD\ARCHIVE\.arc(all archives).
As i kept the same directory structure so i didnot set parameters db_file_name_convert and log_file _name_convert
Please clear me on this before i move forward to check for archive shipping because i get confused that may be i followed wrong and i should have kept as
Standby datafiles = d:\oracle\product\10.2.0\prod2\.dbf
standby archives = d:\prod2\archive
please tell.i really need your reply urgently
can this approach of same directory structure affect the primary in bad way or is that fine

i have taken the same directory structure as it was on primary even the sid name in directory is same.
PRIMARY SID= PROD
STANDBY SID =PROD2
but datafiles,redo,control and archive location i have kept the same sid as of primary.
D:\oracle\product\10.2.0\PROD\.dbf
D:\oracle\product\10.2.0\PROD\.ctl
D:\oracle\product\10.2.0\PROD\.redo
i just changed control file with standby and also i did not created standby redo's as i read in document its needed for switchover.so i thought i 'll create later on

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