Re: how to sort an array of type string

Question

thanks bina and turing pest. well i can't use collections.sort or arrays.sort i need to create a method to sort. stupid instructor dont want to take advantage of this good java language. anyways i am able to do the sort but now OMG the whole data is crappy. formatting is gone everything is fukedd up. excuse my language.
public void getSort(String[] A)
          String temp= A[0];
               for(int i=0; i<A.length; i++)
               for (int j=0; j<A.length-1-i; j++)
                    if(A[j].compareTo(A[j+1])>0)
                         temp = A[j];
                         A[j] = A[j+1];
                         A[j+1] = temp;
     }and here is my output if i dont use the sort before it was not giving me an exception of arraysoutofbound and now it is
Item          Number      Cost_unit     Sale_unit        TotalSale       profit          Totalprofit
Binder          500             4       7               3300            1500            1500
Bookbag         350             5       10              3300            1750            3250
Calendar        300             3       8               2400            1500            4750
Shirt           800             4       6               4600            1600            6350
Notebook        400             1       2               800             400             6750
Schedule        876             1       2               1752            876             7626and if i turn my sort function on this is what i getg
Item          Number      Cost_unit     Sale_unit        TotalSale       profit          Totalprofit
4       500             7       Binder                  3300            1500            1500
10              350             5       Bookbag                 3300            1750            3250
3       300             8       Calendar                2400            1500            4750
4       6       800             Shirt                   4600            1600            6350
1       2       400             Notebook                800             400             6750
1       2       876             Schedule                1752            876             7626
Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 1
        at BookStore.main(BookStore.java:62)at this line it is giving me an exception
totalsale = test.totalSales(Integer.parseInt(str[1].trim()), Integer.parseInt(str[3].trim()));why is it all messed up?

Answer 1

you create bean for your data like this
class Person {
   private String name;
   private int age;
   public Person(String name, int age) {
      this.name = name;
      this.age = age;
   public String getName() {
      return name;
   public void setName(String name) {
      this.name = name;
   public int getAge() {
      return age;
   public void setAge(int age) {
      this.age = age;
   public String toString() {
      return "Name : " + name + "\n" + "Age : " + age;
}after that, just sort it
public class Sample {
   public static void main(String[] args) {
      Person[] array = new Person[3];
      array[0] = new Person("Dewi", 20);
      array[1] = new Person("Agus", 21);
      array[2] = new Person("Cindy", 18);
      sortByName(array);
      printOut(array);     
   private static void printOut(Person[] array) {
      for(Person person : array){
         System.out.println(person);
         System.out.println();
   private static void sortByName(Person[] array) {
      for (int i = 0; i < array.length; i++) {
         for (int j = array.length - 1; j > i; j--) {
            if (array[j].getName().compareTo(array[j - 1].getName()) < 0) {
               Person temp = new Person(array[j].getName(), array[j].getAge());
               array[j].setName(array[j - 1].getName());
               array[j].setAge(array[j - 1].getAge());
               array[j - 1].setName(temp.getName());
               array[j - 1].setAge(temp.getAge());
}