Reference to parent record in Tree view
Dear Jheadstart Team,
When creating a Tree which I intend to use to insert child records, it is indeed possible to insert these records, unfortunately the key that identifies the relationship with the parent (in the child record) is always set to null and has to be inserted manually. How can I modify my application in order to let the application fill in the above specified value?
Kind regards
Double-click the Create button to create a managed bean method where you can add custom code after the new row has been created. In the custom code, you can set the parent key attribute.
Then move the new button code in the jspx page to a custom template.
Steven Davelaar,
JHeadstart Team.
Similar Messages
-
Post Back Tree view when tree node check changed
Hi everyone,
I have a tree view, both child and parent have check box. I want to check all the child on the parent selection.
I try "SelectedNodeChanged" but the page doesn't post back to fire my function.
I know I can use javascript to post back the page, but is there any other way to post back my page without javascript???
Thnaks in advance.Hi everyone,
I have a tree view, both child and parent have check box. I want to check all the child on the parent selection.
I try "SelectedNodeChanged" but the page doesn't post back to fire my function.
I know I can use javascript to post back the page, but is there any other way to post back my page without javascript???
Thnaks in advance.
Assuming this is a WinForm application (it looks like it may not be), the following works pretty well:
Option Strict On
Option Explicit On
Public Class Form1
Private Sub Form1_Load(ByVal sender As System.Object, _
ByVal e As System.EventArgs) _
Handles MyBase.Load
With TreeView1
.CheckBoxes = True
.ShowLines = True
.ShowPlusMinus = True
.ShowRootLines = True
.ExpandAll()
End With
End Sub
' Updates all child tree nodes recursively.
Private Sub CheckAllChildNodes(ByVal treeNode As TreeNode, ByVal nodeChecked As Boolean)
Dim node As TreeNode
For Each node In treeNode.Nodes
node.Checked = nodeChecked
If node.Nodes.Count > 0 Then
' If the current node has child nodes, call the CheckAllChildsNodes method recursively.
Me.CheckAllChildNodes(node, nodeChecked)
End If
Next node
End Sub
' NOTE This code can be added to the BeforeCheck event handler instead of the AfterCheck event.
' After a tree node's Checked property is changed, all its child nodes are updated to the same value.
Private Sub node_AfterCheck(ByVal sender As Object, ByVal e As TreeViewEventArgs) Handles TreeView1.AfterCheck
' The code only executes if the user caused the checked state to change.
If e.Action <> TreeViewAction.Unknown Then
If e.Node.Nodes.Count > 0 Then
' Calls the CheckAllChildNodes method, passing in the current
' Checked value of the TreeNode whose checked state changed.
Me.CheckAllChildNodes(e.Node, e.Node.Checked)
End If
End If
End Sub
End Class
The reference for that is this MSDN document.
If you're looking for a true tri-state operation though, honestly you might want to look at some third-party controls.
I hope that helps. :)
Please call me Frank :) -
I have a HTML page with an IFrame. Inside the Iframe there is a table with a tree view
<iframe>
<table>
<tr>
<td>
<treeview id="tv1"></treeview>
</td>
</tr>
</table>
</iframe>
In UIA, i am able to traverse till the tree view but not able to see it.
I have used the TreeWalker.RawViewWalker Field to traverse the node from the desktop Automation.RootElement.
I tried to use AutomationElement.FromPoint method to check whether i am able to get that element. Fortunately i was able to get the automation element.
i tried to get the path to root element from the node element using the TreeWalker.RawViewWalker. I was able to get the parent path to the root element.
But trying the reverse way like navigating from root element to tree node, was not getting the element for me.
Please help me with suggestions or inputs to resolve this issue.Thanks Bernard,
It works fine with JInitiator but not working with
the JPI. For JPI what settings I need to do ??hi TKARIM and Bernard, i am having similar problem even with the Bernard's recommended setup. could you post the webutiljini.htm (i presume you are using config=test) ?
i am actually using jinitiator 1.3.1.28 with Oracle HTTP Server of OAS 10gR2) calling Forms Server 6i (f60cgi). After setting up according to Bernard's recommended setup steps, the java console showed that it loaded the icon jar file when it could not read the form, but it skipped the loading of the icon jar file once it read and started the form. How do we specify in the form to pick up the icon from the jar file instead from a directory ? Or do we need to specify ? Any ideas ?
Thx and Regards
dkklau -
Build XML for Custom Nested Accordian (like Tree View Structure) for SharePoint List Data
Expected output in Xml:
<?xml version="1.0" encoding="utf-8" ?>
- <TopRoot>
- <Root id="1" Name="Department">
- <Type id="2" Name="IT">
- <SubType id="3" Name="Technology">
<SubSubType id="4" Name="Sharepoint" />
<SubSubType id="5" Name="ASP.NET" />
<SubSubType id="6" Name="HTML 5" />
</SubType>
</Type>
</Root>
</TopRoot>
List Details:
list details for storing category / sub category data and code to build tree structure for the same.
1.Create Custom List named “CategoryDetails”:
2.Create Column “Category Name” of type single line of text. Make it as required field and check Yes for Enforce Unique values.
3.Create column “Parent Category” of type lookup. under Additional Column Settings.
Get information dropdown, select “CategoryDetails”.
4.Choice column ["SRTypeName"] 1.Root,2.SRTYPE,3.SubSRTYPE, 4.SUBSUBSRTYPE
In this column dropdown, select “Category Name”:
Referance:
http://www.codeproject.com/Tips/627580/Build-Tree-View-Structure-for-SharePoint-List-Data -fine but don't want tree view just generate xml string
i just follwed above link it work perferfectly fine for building tree view but i don't want server control.
Expected Result:
My ultimate goal is to generate xml string like above format without building tree view.
I want to generate xml using web service and using xml i could convert into nested Tree View Accordian in html.
I developed some code but its not working to generate xml /string.
My modified Code:
public const string DYNAMIC_CAML_QUERY =
"<Where><IsNull><FieldRef Name='{0}' /></IsNull></Where>";
public const string DYNAMIC_CAML_QUERY_GET_CHILD_NODE =
"<Where><Eq><FieldRef Name='{0}' /><Value Type='LookupMulti'>{1}</Value></Eq></Where>";
protected void Page_Load(object sender, EventArgs e)
if (!Page.IsPostBack)
string TreeViewStr= BuildTree();
Literal1.Text = TreeViewStr;
StringBuilder sbRoot= new StringBuilder();
protected string BuildTree()
SPList TasksList;
SPQuery objSPQuery;
StringBuilder Query = new StringBuilder();
SPListItemCollection objItems;
string DisplayColumn = string.Empty;
string Title = string.Empty;
string[] valueArray = null;
try
using (SPSite site = new SPSite(SPContext.Current.Web.Url))
using (SPWeb web = site.OpenWeb())
TasksList = SPContext.Current.Web.Lists["Service"];
if (TasksList != null)
objSPQuery = new SPQuery();
Query.Append(String.Format(DYNAMIC_CAML_QUERY, "Parent_x0020_Service_x0020_Id"));
objSPQuery.Query = Query.ToString();
objItems = TasksList.GetItems(objSPQuery);
if (objItems != null && objItems.Count > 0)
foreach (SPListItem objItem in objItems)
DisplayColumn = Convert.ToString(objItem["Title"]);
Title = Convert.ToString(objItem["Title"]);
int rootId=objItem["ID"].ToString();
sbRoot.Append("<Root id="+rootId+"
Name="+Title+">");
string SRAndSUBSRTpe = CreateTree(Title, valueArray,
null, DisplayColumn, objItem["ID"].ToString());
sbRoot.Append(SRAndSUBSRTpe);
SRType.Clear();//make SRType Empty
strhtml.Clear();
SRType.Append("</Root>");
catch (Exception ex)
throw ex;
return SRType.ToString();
StringBuilder strhtml = new StringBuilder();
private string CreateTree(string RootNode, string[] valueArray,
List<SPListItem> objNodeCollection, string DisplayValue, string KeyValue)
try
strhtml.Appends(GetSRType(KeyValue, valueArray, objNodeCollection);
catch (Exception ex)
throw ex;
return strhtml;
StringBuilder SRType = new StringBuilder();
private string GetSRType(string RootNode,
string[] valueArray, List<SPListItem> objListItemColn)
SPQuery objSPQuery;
SPListItemCollection objItems = null;
List<SPListItem> objNodeListItems = new List<SPListItem>();
objSPQuery = new SPQuery();
string objNodeTitle = string.Empty;
string objLookupColumn = string.Empty;
StringBuilder Query = new StringBuilder();
SPList objTaskList;
SPField spField;
string objKeyColumn;
string SrTypeCategory;
try
objTaskList = SPContext.Current.Web.Lists["Service"];
objLookupColumn = "Parent_x0020_Service_x0020_Id";//objTreeViewControlField.ParentLookup;
Query.Append(String.Format
(DYNAMIC_CAML_QUERY_GET_CHILD_NODE, objLookupColumn, RootNode));
objSPQuery.Query = Query.ToString();
objItems = objTaskList.GetItems(objSPQuery);
foreach (SPListItem objItem in objItems)
objNodeListItems.Add(objItem);
if (objNodeListItems != null && objNodeListItems.Count > 0)
foreach (SPListItem objItem in objNodeListItems)
RootNode = Convert.ToString(objItem["Title"]);
objKeyColumn = Convert.ToString(objItem["ID"]);
objNodeTitle = Convert.ToString(objItem["Title"]);
SrTypeCategory= Convert.ToString(objItem["SRTypeName"]);
if(SrTypeCategory =="SRtYpe")
SRType.Append("<Type id="+objKeyColumn+" Name="+RootNode+ ">");
if (!String.IsNullOrEmpty(objNodeTitle))
SRType.Append(GetSRType(objKeyColumn, valueArray, objListItemColn));
if(SrTypeCategory =="SRSubTYpe")
SRType.Append("<SRSubType id="+objKeyColumn+" Name="+RootNode+
">");
if (!String.IsNullOrEmpty(objNodeTitle))
SRType.Append(GetSRType(objKeyColumn, valueArray, objListItemColn));
if(SrTypeCategory =="SubSubTYpe")
SRType.Append("<SubSubType id="+objKeyColumn+" Name="+RootNode +"
></SubSubType");
SRType.Append("</SubType>");
SRType.Append("</Type>");
catch (Exception ex)
throw ex;
return SRType.ToString();
// Call method again (recursion) to get the child itemsHi,
According to your post, my understanding is that you want to custom action for context menu in "Site Content and Structure" in SharePoint 2010.
In "SiteManager.aspx", SharePoint use MenuItemTemplate class which represent a control that creates an item in a drop-down menu.
For example, to create or delete the ECB menu for a list item in
"Site Content and Structure", we can follow the steps below:
To add the “My Like” menu, we can add the code below:
<SharePoint:MenuItemTemplate
UseShortId=false
id="OLListItemLike"
runat="server"
Text="My Like"
ImageUrl="/_layouts/images/DelItem.gif"
ClientOnClickNavigateUrl="https://www.google.com.hk/"
/>
To remove the “Delete” menu, we can comment the code below:
<SharePoint:MenuItemTemplate
UseShortId=false
id="OLListItemDelete"
runat="server"
Text="<%$Resources:cms,SmtDelete%>"
ImageUrl="/_layouts/images/DelItem.gif"
ClientOnClickScript="%SmtObjectDeleteScript%"
/>
The result is as below:
More information:
MenuItemTemplate Class (Microsoft.SharePoint.WebControls)
MenuItemTemplate.ClientOnClickScript property (Microsoft.SharePoint.WebControls)
Best Regards,
Linda Li
Linda Li
TechNet Community Support -
Tree view control - populating speed - over 100 nodes
I have a few questions about a tree view control:
1. If you put more than approximately 100 nodes in a tree, it populates too slow. There is no change if you try with query or record group. I figured that the populating of the record group makes all problems, but there is no chance to enlarge the array siye of the record group. Developer 6 has some built-ins which can do that, bu after many unsuccesful tries I don't see a solution.
I tried to make fetches from cursor into a record group (30 nodes on a "page", but it looses a real hierarchy and you should do a lot of programming). If anybody knows how to make the population of the tree faster or have some template / please forward.
2. After we put the patch 5 of developer6, tree view control is totally unpredictable. Usually its when you programmaticaly try to select a node (ftree.set_tree_selection)...Anybody have the same problems?<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by Natasa Stojovska ([email protected]):
I have a few questions about a tree view control:
1. If you put more than approximately 100 nodes in a tree, it populates too slow. There is no change if you try with query or record group. I figured that the populating of the record group makes all problems, but there is no chance to enlarge the array siye of the record group. Developer 6 has some built-ins which can do that, bu after many unsuccesful tries I don't see a solution.
I tried to make fetches from cursor into a record group (30 nodes on a "page", but it looses a real hierarchy and you should do a lot of programming). If anybody knows how to make the population of the tree faster or have some template / please forward.
<HR></BLOCKQUOTE>
Try taking out the 'start with' and 'connect by' clauses in your select statement if you're using them. However, this will mean that you will have to determine the levels of the tree manually and ensure that the data comes out in the same order each time you execute the select statement.
null -
Is there a way to open SSRS 2005 tree view in a table in a Details row upward?
Hi.
I building some reports with SSRS, and showing data in a table. The table has one Details row that forms at the end multiple rows with the tree view (+ and -).
Is there a way to open the tree view upwards and not downwards so that the children of level 2, 3 etc come over the parent row?
I've goggled it everywhere, but I don't seem to find the answer. If anyone could help me out, I would appreciated.
Thanks
NoviHi again.
And by the way, this is a parent child hierarchy. I have made a group details row with a "ParentUniqeName" on Parent Group text box and "UniqueName" on the Group On expression box by using Edit Group menu.
In addition, there is a drill down functionality on the table.
Now, it seems that the order of the items is correct, I just want it to have the opposite order.
Thanks again...
Novi -
How to add Icon in Tree View in Forms 6.0 (URGENT..!)
Hello All,
I want to add icons in tree view (hierarchical tree) by using
forms 6.0.
So pls. help me to find out the solution for the same.
thanks
Pradeep
nullPradeep (guest) wrote:
: Hello All,
: I want to add icons in tree view (hierarchical tree) by using
: forms 6.0.
: So pls. help me to find out the solution for the same.
: thanks
: Pradeep
hello pradeep,
for adding icons in the tree, u willhave to look closely to the
data format for the tree.in the data format used for populating
the tree we are supplying 5 fields. the state of the tree node
(expanded or collapsed), the depth of the node w.r.t the parent
node, the node value, the node label(what we see on the tree)
and the node icon which we want to use. for the node icon we
have to provide the entire path of the icon file. that's it.
hope this will solve the problem
null -
Pragmaticobjects : Tree view in the JSP page
I have to understand Tree view Generation in the JSP page by using pragmaticobjects jar file.
Can any body please help me from where I got the details of pragmaticobjects.
I am not able to fined appropriate link in Google.
com.pragmaticobjects.taglibs.tree.util some of the used package .a tree model
wrap <ul> <ul> around all his childeren + wrap the String representation with <li> </li>
that should provide you with the structure in html.
<ol class="tree">
<li>parent
<ul>
<li>child1.1
<ul>
<li>child1.1.2</li>
<li>child1.1.2</li>
</ul>
</li>
<li>child1.2
<ul>
<li>child1.2.1</li>
<li>child1.2.2</li>
</ul>
</li>
</ul>
</li>
<ul>then it's css time
<html>
<head>
<style>
<!--
.tree {
list-style-type: none;
list-style-image: none;
list-style-position: outside;
.tree ul {
margin: 0em;
padding: 0em;
.tree li{
border: 1px black solid;
text-align: center;
float: left;
-->
</style>
</head>
<body>
<ul class="tree">
<li>parent
<ul>
<li>child1.1
<ul>
<li>child1.1.2</li>
<li>child1.1.2</li>
</ul>
</li>
<li>child1.2
<ul>
<li>child1.2.1</li>
<li>child1.2.2</li>
</ul>
</li>
</ul>
</li>
<ul>
</body>
</html>from here well there are differend solutions, but I think a little too CSS orientated to discuss it here. if you need more details email I'm not sure if I check this topic again.
Mr_Light
stuurff [at] hotmail.com -
How to update child record when item from parent record changes
Hi, I have a master and detail form with two regions on the same page.
Region one references parent record, one of column in the parent record is also in the child record. And is one to many relation
between parent record and child record. How can I have the column on the child record updated when the column of the parent record is being modified?
For exemple; Parent record has two columns : ID and Program.
Child record has Program, goal# and status. I have two pages established, page 27 and page 28.
Page 27 list out all programs from parent record, by clicking on edit to a program, it braches to page 28 with program listed as editable field in region one, and mulitple records list in region two from the child record with the same program.
The problem that I am having is once the program in region one got modified using ApplyMRU, the program in child record did not get updated with the new value and therefore those record become orphan records. I need a way to update all current child records with the new program value.
Thanks in advance for anyone who can hlep out on this problem.
Julie
Edited by: JulieHP on May 24, 2012 4:57 PMOne Idea is
If possible create a after update database trigger on the parent table to update the relevant child record.
Next one
Create a PL/SQL process on the parent page with process sequence next to ApplyMRU, so when the ApplyMRU is seccessfull it goes not to your process where you can have your update statement -
Hello,
(LabVIEW 8.0): I have found that the font size of the tree view items can be set at design time from the drop down list on the menu bar. However, is it possible to make each "level" (i.e. parent = a level, child = different level, grandchild = still another level) have a different font size to clearly differentiate one level from the next?
Thanks,
Christry a property node...
Attachments:
Clipboard-2.jpg 76 KB -
Basic Requirement to create Tree View
Hi gurus.
While creating Custom Tree View, I am getting following error when i click the Search button in search page..
**An error occurred during event processing in view ASSEG.htm of UI Component ZHIER_VIEW**
**An exception has occurred Exception Class CX_SY_REF_IS_INITIAL - Dereferencing of the NULL reference**
**Method: ZL_ZHIER_VI_ASSEG_IMPL=>EH_ONSEARCH**
**Source Text Row: 109**
please help me if any one done tree view..
helpful if provide correct procedure to create tree view..
Regards.
Ashok.Hi Lakshmi and Raj
The answer was correct, i was able to resolve that exception...
But the thing is when i click on the search button it is not displaying the result.. i mean it is not triggering the event...
what will be the answer for this please help me .. urgent requirement..
let me explain the scenario here i am taking one advance search page and if u click on search button result should display in tree format...
I done all correctly but i am now unable to point the error... my requirement similar to the standard component SEGAS_SEG.
Thanks
Ashok.. -
Hi all
I want to set a print option for the tree view control along with back,exit etc options.please help me to do this.
Thanks in regards
Regards
Giri<BLOCKQUOTE><font size="1" face="Verdana, Arial">quote:</font><HR>Originally posted by Natasa Stojovska ([email protected]):
I have a few questions about a tree view control:
1. If you put more than approximately 100 nodes in a tree, it populates too slow. There is no change if you try with query or record group. I figured that the populating of the record group makes all problems, but there is no chance to enlarge the array siye of the record group. Developer 6 has some built-ins which can do that, bu after many unsuccesful tries I don't see a solution.
I tried to make fetches from cursor into a record group (30 nodes on a "page", but it looses a real hierarchy and you should do a lot of programming). If anybody knows how to make the population of the tree faster or have some template / please forward.
<HR></BLOCKQUOTE>
Try taking out the 'start with' and 'connect by' clauses in your select statement if you're using them. However, this will mean that you will have to determine the levels of the tree manually and ensure that the data comes out in the same order each time you execute the select statement.
null -
Tree View Second level is not displaying bind parameter
Studio Edition Version 11.1.2.2.0appears this problem is addressed in
http://dailydevfixes.blogspot.com/2011/07/setting-bind-parameters-on-hierarchy-of.html
unfortunately I must be missing something.
as a test using the hr schema
I was doing a tree view with hire date as the first level then the employee id, last name and first name as the second level.
I hard coded employee id of 187 on a bean called by a button.
the first level is updated unfortunately the second level is not (employee id 107 should not show up)
--1999-02-07
----- 187 Cabrio Anthony
----- 107 Lorentz Dianahere is my bean the first level is updated but the second level is not not quite sure what I am missing
public void ButtonClick(ActionEvent actionEvent) {
BindingContext bindingctx = BindingContext.getCurrent();
BindingContainer bindings = bindingctx.getCurrentBindingsEntry();
DCBindingContainer bindingsImpl = (DCBindingContainer) bindings;
DCIteratorBinding dciter = bindingsImpl.findIteratorBinding("ParentVO1Iterator");
ViewObject Parentvo =dciter.getViewObject();
Parentvo.setNamedWhereClauseParam("empid",187);
Parentvo.executeQuery();
AttributeDef attrDef = Parentvo.findAttributeDef("ChildVO");
ViewObject childvo = attrDef.getAccessorVO(Parentvo);
childvo.setNamedWhereClauseParam("empid",187);
childvo.executeQuery();
AdfFacesContext adfFCtx = AdfFacesContext.getCurrentInstance();
adfFCtx.addPartialTarget(treeupdate);
}here is the query for the parent view object.
select trunc(hire_date) hire_dt
from employees
where :empid is null or employee_id = :empid
group by trunc(hire_date)here is the query for the child view object
select trunc(hire_date) hire_dt, employee_id, employee_id||' '||last_name||' '||first_name nm
from employees
where :empid is null or employee_id = :empid
order by trunc(hire_date)here is the view link
<?xml version="1.0" encoding="windows-1252" ?>
<!DOCTYPE ViewLink SYSTEM "jbo_03_01.dtd">
<!---->
<ViewLink
xmlns="http://xmlns.oracle.com/bc4j"
Name="ParentToChildViewLink"
Version="11.1.2.61.83">
<Properties>
<SchemaBasedProperties>
<LABEL
ResId="model.view.link.ParentToChildViewLink_LABEL"/>
</SchemaBasedProperties>
</Properties>
<ViewLinkDefEnd
Name="ParentVO"
Cardinality="1"
Source="true"
Owner="model.view.ParentVO">
<DesignTime>
<Attr Name="_accessor" Value="true"/>
<Attr Name="_finderName" Value="ParentVO"/>
<Attr Name="_isUpdateable" Value="true"/>
</DesignTime>
<AttrArray Name="Attributes">
<Item Value="model.view.ParentVO.HireDt"/>
</AttrArray>
</ViewLinkDefEnd>
<ViewLinkDefEnd
Name="ChildVO"
Cardinality="-1"
Owner="model.view.ChildVO">
<DesignTime>
<Attr Name="_finderName" Value="ChildVO"/>
<Attr Name="_isUpdateable" Value="true"/>
</DesignTime>
<AttrArray Name="Attributes">
<Item Value="model.view.ChildVO.HireDt"/>
</AttrArray>
</ViewLinkDefEnd>
<ResourceBundle>
<PropertiesBundle
PropertiesFile="model.ModelBundle"/>
</ResourceBundle>
</ViewLink>and here is the tree
<af:tree value="#{bindings.ParentVO1.treeModel}" var="node"
selectionListener="#{bindings.ParentVO1.treeModel.makeCurrent}" rowSelection="single"
id="t1" binding="#{myBean.treeupdate}">
<f:facet name="nodeStamp">
<af:outputText value="#{node}" id="ot1"/>
</f:facet>
</af:tree>thanks I am working through that example unfortunately I ran into a problem
previously (in my real application) I was using bind parameters and my query had the following where clause.
( I did this to turn a comma separated list into an in statement)
WHERE :Bind_Batch_NM_Comma_Sep_List IS NULL
OR batch_nm IN
( SELECT REGEXP_SUBSTR (:Bind_Batch_NM_Comma_Sep_List,
'[^,]+',
1,
LEVEL)
batch_nm
FROM DUAL
CONNECT BY LEVEL <=
REGEXP_COUNT (:Bind_Batch_NM_Comma_Sep_List,
+ 1)however in the example presented you are to create view criteria and there is a panel on the right called view object where clause but I can not figure out how to type into it directly
and I find it unlikely I can recreate this where clause using the add item button.
is there a way to manually type the where clause in the view object where clause box? -
Issue in Tree View Enhancement
Hello Experts,
I have a Tree View and its related Context Node Class. Due to some requirement I need to enhance the same.
I have done the following steps:
1. Enhance the View which eventually enhanced the CTXT class to Z_CTXT as well.
2. I am trying to enhance the Tree View context node( say IBASE in my example).
When I do the same, it is giving me an error saying that
Method CTXT - CREATE_IBASE does not exist.
Just to recheck I went to the parent class of Z_CTXT which is CTXT and found the method was very much there.
Refer standard component ICCMP_IBASE View: IBTreeResultList Context Node: IBASE. My question is related to this context node.
Thanks in advance.
Best Regards,
Vinamra.Hi Vinamra,
When you enhance the view by default CTXT class also will be enhanced, when you enhance the context node then only system will create corresponding method create_"context node name" in your Z_CTXT class.
Did you check Z_CTXT class for the create_ibase method, This class should have added this method with code like this
model = owner->create_model(
class_name = 'ZCLICCMP_IB_IBTREERESULTL_CN00' "cl_crm_ic_ibase_constants=>gc_ibtree_firstlevel_class "#EC NOTEXT
model_id = cl_crm_ic_ibase_constants=>gc_ibtree_node_name ). "#EC NOTEXT
ibasetree ?= model.
Best Regards,
Dharmakasi. -
Are workmanagers visible in the jndi tree viewer?
Hi, I'm trying to setup a workmanager, and I'm having a few problems, but I'm just wondering if I'm falling at the first hurdle. I've tried creating workmanagers at the global and application level, but looking in the admin console for my server they never show up in the jndi tree viewer. Should I expect to see my workmanager there? If I look in the deployment then I do see that the workmanager exists, alongside default.
Thanks.If you create a workmanager at the application level, you'll see the work manager in the console under Deployments -> your app -> Monitoring ->Workload.
If you create a workmanager at the domain / server level and reference it within your app's deployment descriptors ( wl-dispatch-policy ), you can look under Servers ->your app's targeted server -> Deployments -> your app -> Monitoring -> Workload. In this case, you'll see all the workmanagers targeted to that server, but you can confirm your app's usage of the correct wm by submitting a request to your app and seeing an increase in the completed requests column of the display.
A work manager configured at the domain / server level doesn't have a JNDI name attribute that you enter. You just use the same workmanager name in your deployment descriptor <wl-dispatch-policy>someWM</wl-dispatch-policy>.
The handling of stuck threads seems to be a trouble point for application defined workmanagers, so we've decided to stick with individual server level work managers for each app.
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