Regardin The UPDATE statement

Hi There,
I wanted to know, whether , When we do a UPDATE , is the record locked until the COMMIT is issued? If yes what happens when UPDATE fails
Thanx in Advance

http://download-west.oracle.com/docs/cd/B10501_01/server.920/a96524/c17trans.htm#5610
http://download-west.oracle.com/docs/cd/B10501_01/server.920/a96524/c16sqlpl.htm#1549

Similar Messages

  • When the update statement will check the constraint violation ?

    Hello all,
    i am working on data masking of production data using oracle Translate function.i have created a function otis_mask using translate function to mask sensitive values .For this i am tesitng on a small table. i have created a table with single primary key column SSN.
    sql>desc SSN_MASK
    Name Null? Type
    SSN NOT NULL NUMBER(10)
    1) i have inserted the value 9949577766. if resulted mask value exist in table it should throw the constraint violation error.But it is not throwing any error.rows are properly updating .
    Eg:-
    Table contains below values.
    PA_DATA_SUB @qdsrih30 >select *from SSN_MASK;
    SSN
    7727399911
    9949577766
    9989477700
    UPDATE SSN_MASK SET SSN=otis_mask(SSN);
    if above update statement process 7727399911 first then resulted mask value is 9989477700.This value is already in the table.
    if the update statement process 9949577766 first then resulted mask value is 7727399911.This value is already in the table.
    in any of the above scenario update statement should have to throw constraint violation error. But its not happening. rows are properly updating . when the update statement checking the constraint violation ? after processing all the rows or processing of each row ?
    Please help me in understandding the update statement processing ?
    Thanks,
    Venkat Vadlamudi.

    1)created a function as below.
    CREATE OR REPLACE Function otis_mask(incol varchar2) return varchar2 is
    random_str varchar2(20);
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    select (translate(incol,'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890','qwertyuiopasdfghjklzxcvbnmQWERTYUIOPASDFGHJKLZXCVBNM0842319576')) INTO random_str FROM DUAL;
    return random_str;
    end;
    2. create a table ssn_mask.
    create table ssn_mask(ssn number(10) primary key);
    3) inserted 3 rows as below.
    insert into ssn_mask values(9949577766);
    insert into ssn_mask values(7727399911);
    insert into ssn_mask values(9989477700);
    4)UPDATE SSN_MASK SET SSN=otis_mask(SSN);
    5) Table contains below rows.
    Sql >select *from SSN_MASK;
    SSN
    9949577766
    7727399911
    9989477700.
    6)UPDATE SSN_MASK SET SSN=otis_mask(SSN);
    If the above statement process first row 9949577766,then otis_mask function will return 7727399911 and update statement will update the value of 9949577766 to 7727399911 .At this case 7727399911 is already in the table.So update statement should have to throw primary key constraint violation error.
    If the above statement process second row 7727399911 first ,then otis_mask function will return 9989477700.and update statement will update the value of 7727399911 to 9989477700.At this case 9989477700 is already in the table.So update statement should have to throw primary key constraint violation error.
    But its not throwing any integrity constraint violation error.
    i just want to know when update statement will check the constraint ?
    is update statement will first process all records and kepp in handy the new values then update the table with new values (or) process the first row and update the new value with old value then process second row and update with new value so on ?
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  • What lock does the Update Statement use?

    Hi All,
    Does the below statement will put a row level lock or exclusive lock.
    update employee set emp_name='Emp1' where emp_id=1;
    Regards
    W

    UKJA@ukja102> drop table t1 purge;
    Table dropped.
    Elapsed: 00:00:00.93
    UKJA@ukja102> create table t1(c1 int);
    Table created.
    Elapsed: 00:00:00.09
    UKJA@ukja102>
    UKJA@ukja102> insert into t1 values(1);
    1 row created.
    Elapsed: 00:00:00.00
    UKJA@ukja102> commit;
    Commit complete.
    Elapsed: 00:00:00.03
    UKJA@ukja102>
    UKJA@ukja102> update t1 set c1 = 2;
    1 row updated.
    Elapsed: 00:00:00.00
    UKJA@ukja102>
    UKJA@ukja102> set serveroutput on
    UKJA@ukja102>
    UKJA@ukja102> col sid new_value my_sid
    UKJA@ukja102>
    UKJA@ukja102> select sid
      2  from v$mystat where rownum = 1
      3  ;
           SID                                                                                                                                                                                             
           139                                                                                                                                                                                             
    Elapsed: 00:00:00.03
    UKJA@ukja102>
    UKJA@ukja102> exec print_table('select * from v$lock where sid = &my_sid');
    ADDR                          : 695C4224                                                                                                                                                               
    KADDR                         : 695C423C                                                                                                                                                               
    SID                           : 139                                                                                                                                                                    
    TYPE                          : TM                                                                                                                                                                     
    ID1                           : 74212                                                                                                                                                                  
    ID2                           : 0                                                                                                                                                                      
    LMODE                         : 3                                                                                                                                                                      
    REQUEST                       : 0                                                                                                                                                                      
    CTIME                         : 0                                                                                                                                                                      
    BLOCK                         : 0                                                                                                                                                                      
    ADDR                          : 69612444                                                                                                                                                               
    KADDR                         : 69612560                                                                                                                                                               
    SID                           : 139                                                                                                                                                                    
    TYPE                          : TX                                                                                                                                                                     
    ID1                           : 458787                                                                                                                                                                 
    ID2                           : 13053                                                                                                                                                                  
    LMODE                         : 6                                                                                                                                                                      
    REQUEST                       : 0                                                                                                                                                                      
    CTIME                         : 0                                                                                                                                                                      
    BLOCK                         : 0                                                                                                                                                                      
    PL/SQL procedure successfully completed.
    Elapsed: 00:00:00.14DML acquires TX lock in exclusive(6) mode(row level lock) and TM lock in row exclusive(3) mode.
    =======================================
    Oracle Performance Storyteller
    Dion Cho
    http://ukja.tistory.com
    http://wiki.ex-em.com/index.php/performance_in_depth
    http://wiki.ex-em.com/index.php/optimizing_oracle_optimizer
    =======================================

  • How to tune the Update statement for 20 million rows

    Hi,
    I want to update 20 million rows of a table. I wrote the PL/SQL code like this:
    DECLARE
    v1
    v2
    cursor C1 is
    select ....
    BEGIN
    Open C1;
    loop
    fetch C1 bulk collect into v1,v2 LIMIT 1000
    exit when C1%NOTFOUND;
    forall i in v1.first..v1.last
    update /*+INDEX(tab indx)*/....
    end loop;
    commit;
    close C1;
    END;
    The above code took 24 mins to update 100k records, so for around 20 million records it will take 4800 mins (80 hrs).
    How can I tune the code further ? Will a simple Update statement, instead of PL/SQL make the update faster ?
    Will adding few more hints help ?
    Thanks for your suggestions.
    Regards,
    Yogini Joshi

    Hello
    You have implemented this update in the slowest possible way. Cursor FOR loops should be absolute last resort. If you post the SQL in your cursor there is a very good chance we can re-code it to be a single update statement with a subquery which will be the fastest possible way to run this. Please remember to use the {noformat}{noformat} tags before and after your code so the formatting is preserved.
    David                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                           

  • How To Insert a Row If The Update Statement Fails?

    Hi folks,
    For some reason I just can't get this working and wanted to throw it out to everyone, very simple one so won't take much of your time up.
    Going through each row of the cursor, and wanting to update a table, if the record doesn't exist, then I want to insert it.....but nothing is happening.
    IF v_related_enrolement < 1
    THEN
    BEGIN
    -- Record NOT found in Study_block_associations
    -- Insert Student record into ADM_EVER_REGISTERED table
    -- Set Ever_Registered column to 'N'
    UPDATE adm_ever_registered
    SET ever_registered = 'N'
    WHERE personal_id = v_personal_id
    AND appl_code = v_appl_code;
    EXCEPTION
    WHEN NO_DATA_FOUND THEN
    INSERT INTO adm_ever_registered VALUES(v_personal_id, v_appl_code, v_choice_no, 'N');
    END;
    ELSE

    It's better to use a merge statement in this case.
    Your code doesn't work because of the false assumption that an update statement that doesn't update a single row fails with a no_data_found exception, where it's a successful update statement that just doesn't update a single row. So instead of the exception, use a "if sql%rowcount = 0 then" construct to make your current code work. Best option, as said, is to switch to the merge statement.
    Regards,
    Rob.

  • How to test the update statement in SQLJ - Im lost and cant figure it out!

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  • Need help on the update statement

    Hi,
    I have a small requirement. I have a table called test1 and it has 2 columns, nam and seq. nam is a VARCHAR2(100) and seq is a NUMBER.
    In the seq I have values like, 2, 3, 7, 9, 25. I would like to update the seq value in an order such that it will be modifed like, 1, 2, 3, 4 and 5.
    Here is the scripts, I have used.
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    (nam VARCHAR2(100),
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    INSERT INTO test1 VALUES('AAA', 2);
    INSERT INTO test1 VALUES('BBB', 3);
    INSERT INTO test1 VALUES('CCC', 7);
    INSERT INTO test1 VALUES('DDD', 9);
    INSERT INTO test1 VALUES('EEE', 25);
    COMMIT;
    And, I would like to achive this in a simple single DML statement. (The required output would be something like, AAA - 1, BBB - 2 etc,...)
    I have tried the following query. It is working fine. But If I have a better solution to it, I would to implement the same.
    UPDATE test1 a
      SET seq =
      (SELECT rn
      FROM (SELECT ROW_NUMBER() OVER(ORDER BY seq) rn FROM test1) x
      WHERE a.rowid = x.rowid);
    PS: I am using Oracle 11.2.0.2.0 (11g)
    Thanks In Advance!
    With Regards,
    VST

    SQL> CREATE TABLE test1 
      2   (nam VARCHAR2(100), 
      3    seq NUMBER); 
    Table created.
    SQL>  INSERT INTO test1 VALUES('AAA', 2); 
    1 row created.
    SQL>  INSERT INTO test1 VALUES('BBB', 3); 
    1 row created.
    SQL>  INSERT INTO test1 VALUES('CCC', 7); 
    1 row created.
    SQL>  INSERT INTO test1 VALUES('DDD', 9); 
    1 row created.
    SQL>  INSERT INTO test1 VALUES('EEE', 25); 
    1 row created.
    SQL>  COMMIT; 
    Commit complete.
    SQL> select * from test1;
    NAM                                                                                                         SEQ
    AAA                                                                                                           2
    BBB                                                                                                           3
    CCC                                                                                                           7
    DDD                                                                                                           9
    EEE                                                                                                          25
    5 rows selected.
    SQL> update test1 set seq = rownum;
    5 rows updated.
    SQL> select * from test1;
    NAM                                                                                                         SEQ
    AAA                                                                                                           1
    BBB                                                                                                           2
    CCC                                                                                                           3
    DDD                                                                                                           4
    EEE                                                                                                           5
    5 rows selected.

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            14            3 n
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        USERID NEWSLETTERID D
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            14            2 y
            14            3 y
    SQL> HTH,
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    882300 wrote:
    Hello everyone,
    I'm trying to write a query where I can update a pastdue_fees column in a book_trans table based on a difference between return_dte and due_dte columns.
    I am using Oracle SQL. This is what I have so far for my decode function:
    SQL> SELECT
    2 DECODE(SIGN((return_dte - due_dte)*2),
    3 '-1', '0',
    4 '1', '12', 'Null')
    5 FROM book_trans;
    DECO
    Null
    12
    Null
    0
    So the logic is that if the sign is -1, the value in return_dte column should be 0; if it's +1 then it's 12 and everything else is Null.
    So now, I need to enter my decode function into the update statement to update the columns. However, I get error messages.
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    UPDATE book_trans SET PastDue_fees = decode(expression)
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    SQL> UPDATE book_trans
    2 SET pastdue_fees = SELECT
    3 DECODE(SIGN((return_dte - due_dte)*2),
    4 '-1', '0',
    5 '1', '12', 'Null')
    6 FROM book_trans;
    SET pastdue_fees = SELECT
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    ORA-00936: missing expression
    SQL> UPDATE book_trans
    2 SET pastdue_fees =
    3 DECODE(SIGN((return_dte - due_dte)*2),
    4 '-1', '0',
    5 '1', '12', 'Null')
    6 FROM book_trans;
    FROM book_trans
    ERROR at line 6:
    ORA-00933: SQL command not properly ended
    Any help or tips would be greatly appreciated as I've been taking SQL for about six weeks and not very proficient!
    Thanks!If you really really really want to update the entire table, the syntax would be...
    UPDATE book_trans
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          pastdue_fees  = DECODE(SIGN((return_dte - due_dte)*2), -1, 0, 1, 12, Null);I took out all the single quotes. If you actually have a string column and you're storing entirely numbers in it then it should be declared as a NUMBER column and not a character (varchar2) column.
    ALWAYS use the proper data type, it'll save you a ton of headaches in the future.
    Also, since you're new to the forum, please read the FAQ so you learn the etiquette and what not.
    http://wikis.sun.com/display/Forums/Forums+FAQ

  • Error while schedulingg update stat in db13

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    Hi,
    Check the owner for BRBACKUP, BRARCHIVE, and BRCONNECT in kernel,
    these files should be with SIDADM, if not change the owner to SIDADM and rerun the update stats.
    and also Refer the note 446172
    Regards,
    Ram

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