Regex for RDF parsing

Hi.
I need help with parsing a rdf-format input stream. I want to use regex for parsing.
The stream looks like this:
<?xml version="1.0" encoding="ISO-8859-1" ?><rdf:RDFxmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#"xmlns="http://my.netscape.com/rdf/simple/0.9/"><channel> <title>heise online news</title><link>http://www.heise.de/newsticker/</link><description>Nachrichten aus der Welt des Computers</description></channel><item><title>Scharfe Regeln f?r Chinas Cybercafes</title><link>http://www.heise.de/newsticker/data/gr-12.10.02-004/</link></item>.........</item></rdf:RDF>
The information i need is placed between the <item></item> tags.
I have wrote following code to get all subsequences like "<item>...</item>":
String rval = new String("");
Pattern p = Pattern.compile("<item[ >](.*)</item>");
Matcher m = p.matcher(retval);
while (m.matches()) {
rval = rval + m.group() + "<br>\n";
But this loop only once and the output is one large String from the first "<item>" to the last "</item>" like "<item>......</item><br>\n". The <item>...</item> combos within are ignored. Maybe the regex must be change?
Thanks for answer,
sushiprinz

You need to use the non-greedy star:Pattern p = Pattern.compile("<item>(.*?)</item>");Also, I think you want to use find() instead of matches().

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Dani3ll3 wrote:
Thanks a lot after I did that the regular expression worked. :)Good. But remember that in real life, you would then have to apply the XML rules to get the actual contents of the text node. For example it might be a CDATA section or it might include characters like ampersands which have been escaped and which you need to unescape. That's why it's better to use a proper parser, as already suggested.
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Sorry about that. Here's the correctly formatted post:
So, with a simple arithmetic expression like:
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