RegEx to ID file path that uses Wildcard appropriately

Question

I am looking for a Regex expression to identify paths with wildcards, but pilchards only allowed in the file name and extension portion of the path. So both of these should return true
C:\Path\*.*
\\SRV\Path\*.txt
However, \\*\Path\*.* should return false since a wildcard anywhere but the end is invalid.
My Google Fu has failed me, as all my searches are coming up with discussions of wild cards in the RegEx, rather than * occurring in a specific pattern. 
To give some context, I have a Copy function that is going to take Source and Destination arguments, as well as optional Breadcrumb and Overwrite arguments, and it will handle the actual copy differently depending on the source being a file, folder or wildcard
and destination being a file or folder. And of course it will return an error in the log if the destination is a wildcard.

Answer 1

I couldn't figure out a way to do it with regex, although I did learn a lot about regex in the process.  For anyone else that might find this thread, here is the best link I've found explaining regex:
http://www.freeformatter.com/regex-tester.html
Unfortunately, it wasn't good enough (or I'm just not smart enough) to puzzle this one out.  The following code works, but is obviously much less elegant than a straight up regex.  I post it only because I spent the time on it and if it can ever
possibly help anyone, it was worth the effort:
$a = "\\path\folder\job*.*","\\path\fo*lder\star.tar","c:\path\folder\bo*lder\f*","c:\blah\blah.txt","\\blah\blagaa\blahgahah\a\f\*"
Foreach ($target in $a) {
$flag = $null
$path = $target -split ("\\")
$count = $path.count
If ($path[$path.count -1] -match "\*") {
Foreach ($index in 0..($path.count -2)) {
If ($path[$index] -match "\*") {$flag = 1}
If (!($flag)){$target}
PS C:\Users\user> $a = "\\path\folder\job*.*","\\path\fo*lder\star.tar","c:\path\folder\bo*lder\f*","c:\blah\blah.txt","\\blah\blagaa\blahgahah\a\f\*"
PS C:\Users\user> Foreach ($target in $a) {
>> $flag = $null
>> $path = $target -split ("\\")
>> $count = $path.count
>> If ($path[$path.count -1] -match "\*") {
>> Foreach ($index in 0..($path.count -2)) {
>> If ($path[$index] -match "\*") {$flag = 1}
>> }
>> If (!($flag)){$target}
>> }
>> }
>>
\\path\folder\job*.*
\\blah\blagaa\blahgahah\a\f\*
That being said, I'm eager to see the 10 character or less regex expression to do it that someone is sure to post soon and make me feel silly.
I hope this post has helped!