REGEXP_SUBSTR and OR !!!

Question

Hi Al,
i would like to know how can i used the OR "|" with REGEXP_SUBSTR
SELECT  REGEXP_SUBSTR('500.90 Oracle Parkway, 12-12-2000 78 Redwood Shores, CA','([0-9]{1,2})-([0-9]{1,2})-([0-9]{4})') "REGEXPR_SUBSTR"  FROM DUAL;this two condition
([0-9]{1,2})  ([0-9]{1,2}) ([0-9]{4})
or this i did it like this
SELECT  REGEXP_SUBSTR('500.90 Oracle Parkway, 12-12-2000 78 Redwood Shores, CA','([0-9]{1,2}) ([0-9]{1,2}) ([0-9]{4} | ([0-9]{1,2})  (JANUARY|FEBRUARY|MARCH|APRIL|JUNE|JULY|AUGUST|SEPTEMBER|OCTOBER|NOVEMBER|DECEMBER))') "REGEXPR_SUBSTR"  FROM DUAL; 
but not correct regards
Edited by: Ayham on Jan 10, 2013 2:33 AM
Edited by: Ayham on Jan 10, 2013 2:34 AM

Answer 1

Ayham wrote:
WHY THIS IS NOT WORKING....
with t as (select '500.90 Oracle Parkway, 12-12-2000 78 Redwood Shores, CA' as txt from dual union all
select '500.90 Oracle Parkway, 12 December 2000 78 Redwood Shores, CA' from dual union all
select '500.90 Oracle Parkway, February 2008 78 Redwood Shores, CA' from dual union all
     select '500.90 Oracle Parkway, 2 February 78 Redwood Shores, CA' from dual union all
select '500.90 Oracle Parkway, 3 05 2010 78 Redwood Shores, CA' from dual
select regexp_substr(txt,'([0-9]{1,2}[ -])?([0-9]{1,2}|January|February|March|April|May|June|July|August|September|October|December)([ -][0-9]{4})?') result
from t;the output
50
50
50
50i already put just "?" in case of the years not thereIt's because of your "?" after the years. In that case the day of the month is optional (as it has a "?") and the year is optional (as you added a "?") so the only bit that needs to match is the middle part which is looking for 2 numeric digits or the month names. The start of each string has two numeric digits 50 so that's the first match it finds and that's what you're getting.