Regexp to extract text inside braces ?

Hello,
I need to extract a text inside braces. I used this :
select regexp_substr ( 'Churchill Executive, in Business Bay ( Commercial )' , '\(([^)]*)\)' ) from dual ;
But, I got :
( Commercial ) .
I need to get only:
Commercial
Any help please.
Regards,
I use Oracle 11.2.0.3

Hi,
Spaces immediately after the '(' can be ignored the same way the '(' is ignored. The same goes for 0 or more spaces immediately before the ')':
SELECT REGEXP_SUBSTR ( 'Churchill Executive, in Business Bay ( Commercial )'
                      , '\( *([^)]*) *\)'
                      , 1
                      , 1
                      , NULL
                      , 1
FROM    dual

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http://htmlparser.sourceforge.net/ and write the rules to match title, abstract etc.
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import java.io.FileReader;
import java.io.IOException;
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 private String m_filename;
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 List urls = new ArrayList();
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 super();
 m_filename = filename;
 * parses only title and abstract
 public void parse() throws Exception
 lexical = new URLLexicalAnalyzer(m_filename);
 String word = lexical.getNextWord();
 boolean isabstract = false;
 while (null != word)
 if (isTag(word))
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 System.out.println("TITLE: " + lexical.getNextWord());
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 parseAbstract();
 isabstract = true;
 word = lexical.getNextWord();
 lexical.close();
 public static void main(String[] args) throws Exception
 ACMHTMLParser parser = new ACMHTMLParser("./acm_html.html");
 parser.parse();
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 return ( word.startsWith("<") && word.endsWith(">"));
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 return ( "".equals(word));
 private void parseAbstract() throws Exception
 while (true)
 String abs = lexical.getNextWord();
 if (!isTag(abs))
 System.out.println(abs);
 break;
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 private boolean isTag;
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 try
 m_reader = new BufferedReader(new FileReader(filename));
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 m_reader = new BufferedReader(new InputStreamReader(in));
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 catch (IOException ignored) {}
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