Regular expression alarm url

Hi,
I have a problem with regular expression. I would like to filter only the name of a dsc alarm url: \\EW-MONITOR\monitor\000_t-ist_STB-M1-AS.Alarms.HI should be 000_t-ist_STB-M1-AS . Has somebody an hint for me?
Best Regards,
Joachim
Solved!
Go to Solution.

Joachim082 wrote:
Hi,
I have a problem with regular expression. I would like to filter only the name of a dsc alarm url: \\EW-MONITOR\monitor\000_t-ist_STB-M1-AS.Alarms.HI should be 000_t-ist_STB-M1-AS . Has somebody an hint for me?
Best Regards,
Joachim
What will be constant in the name? Will it always be between "monitor/" and ".Alarms"? Will the format always be "###_<some text>_<other text>"?
This will be easy once I know what to look for.
Jim
You're entirely bonkers. But I'll tell you a secret. All the best people are. ~ Alice

Similar Messages

Regular expression in url-pattern in web.xml

hi,
could any tell me the is web.xml accepts regexp(except wild card) in it's url-pattern attribute. I want to put regular expression (except wildcard, i know it supports) as [a-zA-Z]+ like in url-pattern in servlet-mapping. I tried this :
<servlet-mapping>
<servlet-name>AppDnldMain</servlet-name>
<url-pattern>/[a-zA-Z]+/?</url-pattern>
</servlet-mapping>
But it dint work.. I dont know whether i processed in right way. Any suggestion are most welcome..

No it does not accept wild card.
Servlet specification section SRV.11.2
In theWeb application deployment descriptor, the following syntax is used to define
mappings:
A string beginning with a / character and ending with a /* suffix is used
for path mapping.
A string beginning with a *. prefix is used as an extension mapping.
A string containing only the / character indicates the "default" servlet of
the application. In this case the servlet path is the request URI minus the context
path and the path info is null.
All other strings are used for exact matches only.
If you want regex matching, you can match all urls to a single servlet, and then use request.getRequestURI and do regex on that in your code.
Cheers,
evnafets

Regular expressions for URLs

Hi everyone,
I have a question about regular expressions.
Let's say I want my program to extract last 10-digits from any URL that will be found (every found URL will end up on 10digit number!) and insert that number in the middle of other URL.
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I am not sure how to do that either...
Actually I just figured out that there is no garantee that the URL will be ended on 10-digit number.
Ok, my program is meant to search for the movie info on Yahoo (user enters keyword to search and chooses either 'title', 'actor', 'trailer', 'review' in drop-down menu). After the 'search' button is clicked the appropriate page is supposed to be found.
For example, if the user types in 'shrek' and chooses 'trailer', the result is supposed to be this link http://movies.yahoo.com/movie/1808405861/trailer and not the
following ones:
http://movies.yahoo.com/mv/search?p=shrek
or
http://movies.yahoo.com/shop?d=hv&cf=info&id=1808405861
So in my program the line for the 'title' search is
url = "http://movies.yahoo.com/mv/search?type=all&p=";and it works for the titles. I thought if the found link has 10 -digit number on the end I can somehow 'catch' that number and insert into another link -so the page with trailers would be pulled up (it's an ID number in yahoo database) .
But now since I am not sure if 10-digit number is going to be in the found link at all, I have no idea how to 'catch' that number.
Does anyone have any ideas for my case?

Regular expressions for URLs to match extensions

I am working on a simple method that will assign a specific extension
(e.g. ".jsp", ".php", ".cfm", etc.) to the end of a URL if it doesn't
find anything marking a valid extension, however, I do not want to add
an extension if one is found.
Consider my code:
import java.util.regex.Pattern;
public static final String urlEndSlashPattern = "/?";
public static final String urlQSPattern = "\\??([a-zA-Z0-9\\-_\\.]
+=[^&]*&?)*";
public static final String urlAnchorPattern = "#[^#]*$";
public static void addExtToUrl(String url, String myExt, String[]
exts) {
   StringBuffer sb = new StringBuffer();
   boolean hasExt = false;
   for (int i = 0; i < exts.length; i++) {
sb.append(".").append(exts).append(urlEndSlashPattern).append(urlQSPatte�rn).append(urlAnchorPattern);
if (Pattern.matches(sb.toString(), url)) {
hasExt = true;
sb = new StringBuffer();
if (!hasExt) {
url += "." + myExt;
The issue I want to bring up is the regular expression pattern I'm
using appears to fail. I want to check and see if the URL I provide
ends with a valid extension, followed by optional "/" or a query
string or an anchor or any combination of these.
Like say if I have
http://www.blah.com/index.html
Then don't add the ".jsp" extension
But if I have
http://www.blah.com/registration/
Then I *want* to add the ".jsp" extension:
http://www.blah.com/registration.jsp
Or if I have:
http://www.blah.com/registration/?foo=bar#baz
Then it needs to change to
http://www.blah.com/registration.jsp?foo=bar#baz
But if I have
http://www.blah.com/registration/index.php?foo=bar#baz
Then I do *not* add the ".jsp" extension.
Hope that makes sense now. Bottom line is that the pattern above
doesn't seem to work. Ideas?
Thanks

Ok, just for fun, let's try it.
URL: http://www.blah.com/?bar=baz#anchor
Absolutely valid URL and something possible (remember, Balus, this is from a database entry, thus, it can be anything at all!)
Let's split onto the last /
Your last entry will be
?bar=baz#anchor
So if I re-insert the .jsp that it would not find I get
http://www.blah.com/.jsp?bar=baz#anchor
INVALID URL
Now let's try this one, BalusC:
http://www.blah.com/index.jsp?forwardURL=http://www.wee.com/gotcha_balus/
Now we split according to the ... last /
http://www.blah.com/index.jsp?forwardURL=http://www.wee.com/gotcha_balus.jsp
Valid URL, but possibly wrong when the query string value for "forwardURL" is read, thus, making the URL ultimately wrong.
Two examples that show that splitting by the last / can't work here.

Need a regular expression for URL

Regular expression: ^(udp|norm)://(?:(?:25[0-5]|2[0-4]\\d|[01]\\d\\d|\\d?\\d)(?(?=\\.?\\d)\\.)){4}:(6553[0-5]|655[0-2][0-9]\\d|65[0-4](\\d){2}|6[0-4](\\d){3}|[1-5](\\d){4}|[1-9](\\d){0,3})$
Source: udp://125.3.4.121:23456
Getting error:java.util.regex.PatternSyntaxException: Unknown inline modifier near index 54
^(udp|norm)://(?:(?:25[0-5]|2[0-4]\d|[01]\d\d|\d?\d)(?(?=\.?\d)\.)){4}:(6553[0-5]|655[0-2][0-9]\d|65[0-4](\d){2}|6[0-4](\d){3}|[1-5](\d){4}|[1-9](\d){0,3})$

paulcw wrote:
I can't help wondering if a simpler solution would involve creating a java.net.URL object, passing it the string to be checked, and let URL do the parsing and an initial pass at checking the syntax. Then you could query URL for individual components for further checking (e.g., getting the transfer type to make sure it's one of the kinds you want). This approach would probably be more self-documenting, if nothing else.Nice idea, but java.net.URL doesn't actually do much work at all. It basically takes the protocol part, looks up a handler for it, and delegates everything else to that. The handlers themselves are down in the sun packages (or whatever your Java impl is) and since there isn't one for the OPs protocol, he'd have to write and register his own anyway, which kind-of negates the entire purpose of leveraging it.
@OP: Paul's suggestion can still be of use. Apache, Codehaus and the like will have written their own protocol handlers, it's worth grabbing the source code for, say, Apache HttpClient, and seeing if they've got anything useful in there. Then again, who's to say that what's a valid URL for this 'norm' protocol, other than whoever designed the protocol?

PHP Regular Expression of URL in text

I have some text that is displaying from a database table and
inside
that text is a web address (i.e.,
http://www.whateverthisaddressis.com).
I'd like to know if anyone has a code out there to where php
can find
text with a
http:// or www. and change it into a link
automatically. I
know there's many out there, but I don't have a clue what I'm
looking at
and where to put it.
Any help would be greatly appreciated!
Toad78

You might find something here:
http://ca3.php.net/preg_replace

Url pattern tag and regular expression

I am trying to set up my web.xml in Tomcat 4.1.3 container to go to one page if letters are entered in last part of url or go to another page if numbers are entered in the last part of a url.
For example if here is how the url would be set up where the url will go to either the all numbers location or the non numbers location:
Any number entry for last part of url which could be something like 343
http://127.0.0.1:8080/theapp/pack/weburl/343
Any non number entry for last part of url which could be something like abec
http://127.0.0.1:8080/theapp/pack/weburl/abec
My attempt below is not working because it doesnt seem to take the regular expressions. But if I manually put in letters such as: <url-pattern>/pack/weburl/ab</url-pattern> it would take me to the correct page. How does web.xml work with regular expressions inthe url-pattern tag??
<servlet>
<servlet-name>Number</servlet-name>
<servlet-class>pack.Number</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Number</servlet-name>
<url-pattern>/pack/weburl/\d*</url-pattern>
</servlet-mapping>
<servlet>
<servlet-name>NotNumber</servlet-name>
<servlet-class>pack.NotNumber</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>NotNumber</servlet-name>
<url-pattern>/pack/weburl/[A-Za-z]</url-pattern>
</servlet-mapping>

Sorry, this pattern can't take regular expressions.
Referring to the servlet spec section 11.2 which defines these mappings
In the web application deployment descriptor, the following syntax is used to define
mappings:
� A string beginning with a �/� character and ending with a �/*� postfix is used
for path mapping.
� A string beginning with a �*.� prefix is used as an extension mapping.
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application. In this case the servlet path is the request URI minus the context
path and the path info is null.
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URL paths and regular expressions in ASDM

Some background info - I've recently switched to an ASA 5510 on 8.4(3) coming from a Checkpoint NGX platform (let's say fairly quickly and without much warning ). I have a couple questions and they're kind of similar so I'll post them up. I've read docs about regex and creating them both via command line and ASDM, but the examples always seem to include info I don't need or honestly something I don't understand yet (mainly related to defining class\inspect maps). If someone could provide a simple example of how to do these in ASDM that would help a lot in understanding how regular expressions are properly configured. So here we go.
I know this is basic but I need to make sure I understand this properly - I have a single web server (so this won't be a global policy) where I need to allow access to a specific URL path\file and that's it. So we'll call it \test\testfile.doc. Any other access to any other path should be dropped. What's the best way to do this in ASDM (6.4)? I think if I saw a basic example for this I could figure out next few questions but I'll post them as well just in case.
I have another single public web server (again this won't be a global policy) where I'd like to specify blocking file types, like .php, .exe., etc... again a basic example would be great.
Lastly, and this is kind of related, but we have a single office/domain and sometimes we get spam from forged addresses appearing to be from our domain. On Checkpoint I used to use its built-in SMTP security server and could define if it received mail from *@mydomain.com to drop it because we would never receive mail externally from our own domain name. I saw something similar with ESMTP in ASDM and it looks kind of like how you set up the URL access mentioned above. Can I configure this in ASDM as well, and if so how?
TIA for your help,
Jordan

/bump

Finding URLs using regular expression.

I have an requirement where user will type some text containing URLs like "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747. Thank you". This text has to be modified as below before saving it to the database.
"Please visit this site <a href='http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747'>http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747</a>. Thank you"
I am using regular expression (http|https)://.+?\\s which marks the end of the url with a white space character.This pattern doesn't work if the URL is located at the end of the string since there will be no space at the end.
For example if the string is "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747" the regex will fail.
My acutal problem is to find the URL irrespective its position within the string.
Pattern urlPattern = Pattern.compile("(http|https)://.+?\\s", Pattern.CASE_INSENSITIVE);
Matcher matcher = urlPattern.matcher(plainText);
Map stringIndexMap = new HashMap();
//Searching the input string for urlPattern...
while(matcher.find()) {
String urlString = matcher.group();
//Storing the urls in a hashmap with their indices as keys....
stringIndexMap.put(new Integer(matcher.start()), urlString.trim());
Set keySet = stringIndexMap.keySet();
Iterator it = keySet.iterator();
//Iterating over the hashmap containing urls...
while(it.hasNext()) {
String urlString = (String) stringIndexMap.get(it.next());
* Replacing the url string in the input text with <a href="#" onclick="window.open('<urlString>')"
* using String index
clickableURLString.replace(clickableURLString.indexOf(urlString),
clickableURLString.indexOf(urlString) + urlString.length(),
"<a href=\"#\" onclick=\"window.open('" + urlString
+ "')\">" + urlString + "</a>");
return clickableURLString.toString();

The end of the input is '$' as a regex.
import java.util.regex.*;
public class Prasanna{
public static void main(String[] args){
    String text
= "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747";
//    String regex = "(http|https)://.+?(?:\\s|$)"; // this works
    String regex = "(http|https)://[^ ]+";          // this also works
    Pattern pat = Pattern.compile(regex, Pattern.CASE_INSENSITIVE);
    Matcher mat = pat.matcher(text);
    while (mat.find()){
      System.out.println(mat.group());
}

Regular Expression for website Url the format of

Hi All,
I am new to Regular Expression in java.
I want to validate the web site url.That format is should be like
"www.sun.com".
Please help me.
Thanks.
Saravanan.P

Hi Sandeep,
you can use the below code for website validation.
<af:inputText label="" id="time" simple="true" value="" contentStyle="width:100px;" maximumLength="100">
      <af:validateRegExp pattern="^www[.][a-z]{1,15}[.](com|org)$"
                     messageDetailNoMatch="Website must be like www.google.com"
                                                                                               hint="Website Format: www.google.com"/>
    </af:inputText>
as per your requirement you can change the pattern.
Thanks
Prabhat

URL validation - regular expression

Hello,
I searched but didn´t find.
I need a simple method: isValidUrl
I tried "new URL(url)", getting error, but it allows a simple url with space... I tried too org.apache.validator but it brought me problems with related .jar...
I got one validation for e-mail, that work very well using regex. Does anyone have URL validation using regular expression?
Thanks.

^(http|https|ftp)\\://[a-zA-Z0-9\\-\\.]+\\.[a-zA-Z]{2,3}(:[a-zA-Z0-9]*)?/?([a-zA-Z0-9\\-\\._\\?\\,\\'/\\\\\\+&%\\$#\\=~])*$
It seems to work.Are you sure?

Strange regular expression difference when using an URL

Hello all,
I took some time and finally was able to come up with a regular expression that express the condition of a parameter in a URL. Baiscally, I want to remove the parameter and everything that belongs to this parameter in the URL so I can construct another link free from this parameter.
I want it to match either a number(todeletetable=10) or a list of numbers seperated with a comma (todeletetable=10,11,12,13,) in the URL
I used the following pattern :
Pattern.compile("&todeletetable=(\\d+,)+&|&todeletetable=\\d+&");When testing this locally, it works very well.
String toMatch = "method=allocate&todeletetable=153622,153623,153579,&sortDirection=asc"
matcher.replaceAll("&") -> returns "method=allocate&sortDirection=asc"However, when playing with HTML links, the comma is encoded into %2C. Therefore, I added this expression to the pattern :
Pattern.compile("&todeletetable=(\\d+,)+&|&todeletetable=(\\d+%2C)+&|&todeletetable=\\d+&");
String toMatch = "method=allocate&todeletetable=153622%2C153623%2C153579%2C&sortDirection=asc"
matcher.replaceAll("&") ->returns "method=allocate&sortDirection=asc" locally but over the web, I get "method=allocate&%2C153623%2C153579%2C&sortDirection=asc"It seems that the %2C is not detected in the regular expression in the case of an URL. I don't know what to do to avoid this.
Please help me if you can with any hint or solution.
Thank you
Raphas

Use your original pattern but URL decode the URL first using class URLDecoder.
P.S. I have not checked your regex BUT it looks over complicated.

Need help with regular expression

I'm trying to use the java.util.regex package to extract URLs from html files.
The URLs that I am interested in extracting from the HTML look like the following:
<font color="#008000">http://forum.java.sun.com -
So, the URL is always preceeded by:
<font color="#008000">
and then followed by a space character and then a hyphen character. I want to be able to put all these URLs in a Vector object. This doesn't seem like it should be too difficult but for some reason I can't get anywhere with it. Any help would be greatly appreciated. Thanks!

hi gupta am not sure of the java syntax but i can tell u about the regular expression...try this....
<font color="#008000">(http:\/\/[a-zA-Z0-9.]+) [-]
i dont know the java methods to call...just the reg exp...
Sanjay Acharya

Introduction to regular expressions ... last part.

Continued from Introduction to regular expressions ... continued., here's the third and final part of my introduction to regular expressions. As always, if you find mistakes or have examples that you think could be solved through regular expressions, please post them.
Having fun with regular expressions - Part 3
In some cases, I may have to search for different values in the same column. If the searched values are fixed, I can use the logical OR operator or the IN clause, like in this example (using my brute force data generator from part 2):
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE data IN ('abc', 'xyz', '012');There are of course some workarounds as presented in this asktom thread but for a quick solution, there's of course an alternative approach available. Remember the "|" pipe symbol as OR operator inside regular expressions? Take a look at this:
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(abc|xyz|012)$')
;I can even use strings composed of values like 'abc, xyz , 012' by simply using another regular expression to replace "," and spaces with the "|" pipe symbol. After reading part 1 and 2 that shouldn't be too hard, right? Here's my "thinking in regular expression": Replace every "," and 0 or more leading/trailing spaces.
Ready to try your own solution?
Does it look like this?
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(' || REGEXP_REPLACE('abc, xyz , 012', ' *, *', '|') || ')$')
;If I wouldn't use the "^" and "$" metacharacter, this SELECT would search for any occurence inside the data column, which could be useful if I wanted to combine LIKE and IN clause. Take a look at this example where I'm looking for 'abc%', 'xyz%' or '012%' and adding a case insensitive match parameter to it:
SELECT data
FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE REGEXP_LIKE(data, '^(abc|xyz|012)', 'i')
; An equivalent non regular expression solution would have to look like this, not mentioning other options with adding an extra "," and using the INSTR function:
SELECT data
FROM (SELECT data, LOWER(DATA) search
          FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE search LIKE 'abc%'
    OR search LIKE 'xyz%'
    OR search LIKE '012%'
SELECT data
FROM (SELECT data, SUBSTR(LOWER(DATA), 1, 3) search
          FROM TABLE(regex_utils.gen_data('abcxyz012', 4))
WHERE search IN ('abc', 'xyz', '012')
; I'll leave it to your imagination how a complete non regular example with 'abc, xyz , 012' as search condition would look like.
As mentioned in the first part, regular expressions are not very good at formatting, except for some selected examples, such as phone numbers, which in my demonstration, have different formats. Using regular expressions, I can change them to a uniform representation:
WITH t AS (SELECT '123-4567' phone
             FROM dual
            UNION
           SELECT '01 345678'
             FROM dual
            UNION
           SELECT '7 87 8787'
             FROM dual
SELECT t.phone, REGEXP_REPLACE(REGEXP_REPLACE(phone, '[^0-9]'), '(.{3})(.*)', '(\1)-\2')
FROM t
;First, all non digit characters are beeing filtered, afterwards the remaining string is put into a "(xxx)-xxxx" format, but not cutting off any phone numbers that have more than 7 digits. Using such a conversion could also be used to check the validity of entered data, and updating the value with a uniform format afterwards.
Thinking about it, why not use regular expressions to check other values about their formats? How about an IP4 address? I'll do this step by step, using 127.0.0.1 as the final test case.
First I want to make sure, that each of the 4 parts of an IP address remains in the range between 0-255. Regular expressions are good at string matching but they don't allow any numeric comparisons. What valid strings do I have to take into consideration?
Single digit values: 0-9
Double digit values: 00-99
Triple digit values: 000-199, 200-255 (this one will be the trickiest part)
So far, I will have to use the "|" pipe operator to match all of the allowed combinations. I'll use my brute force generator to check if my solution works for a single value:
SELECT data
FROM TABLE(regex_utils.gen_data('0123456789', 3))
WHERE REGEXP_LIKE(data, '^(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$')
; More than 255 records? Leading zeros are allowed, but checking on all the records, there's no value above 255. First step accomplished. The second part is to make sure, that there are 4 such values, delimited by a "." dot. So I have to check for 0-255 plus a dot 3 times and then check for another 0-255 value. Doesn't sound to complicated, does it?
Using first my brute force generator, I'll check if I've missed any possible combination:
SELECT data
FROM TABLE(regex_utils.gen_data('03.', 15))
WHERE REGEXP_LIKE(data,
                   '^((25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$'
; Looks good to me. Let's check on some sample data:
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
            UNION
           SELECT '256.128.64.32'
             FROM dual
SELECT t.ip
FROM t WHERE REGEXP_LIKE(t.ip,
                   '^((25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})\.){3}(25[0-5]|2[0-4][0-9]|[01]?[0-9]{1,2})$'
; No surprises here. I can take this example a bit further and try to format valid addresses to a uniform representation, as shown in the phone number example. My goal is to display every ip address in the "xxx.xxx.xxx.xxx" format, using leading zeros for 2 and 1 digit values.
Regular expressions don't have any format models like for example the TO_CHAR function, so how could this be achieved? Thinking in regular expressions, I first have to find a way to make sure, that each single number is at least three digits wide. Using my example, this could look like this:
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
SELECT t.ip, REGEXP_REPLACE(t.ip, '([0-9]+)(\.?)', '00\1\2')
FROM t
; Look at this: leading zeros. However, that first value "00127" doesn't look to good, does it? If you thought about using a second regular expression function to remove any excess zeros, you're absolutely right. Just take the past examples and think in regular expressions. Did you come up with something like this?
WITH t AS (SELECT '127.0.0.1' ip
             FROM dual
SELECT t.ip, REGEXP_REPLACE(REGEXP_REPLACE(t.ip, '([0-9]+)(\.?)', '00\1\2'),
                            '[0-9]*([0-9]{3})(\.?)', '\1\2'
FROM t
; Think about the possibilities: Now you can sort a table with unformatted IP addresses, if that is a requirement in your application or you find other values where you can use that "trick".
Since I'm on checking INET (internet) type of values, let's do some more, for example an e-mail address. I'll keep it simple and will only check on the
"[email protected]", "[email protected]" and "[email protected]" format, where x represents an alphanumeric character. If you want, you can look up the corresponding RFC definition and try to build your own regular expression for that one.
Now back to this one: At least one alphanumeric character followed by an "@" at sign which is followed by at least one alphanumeric character followed by a "." dot and exactly 3 more alphanumeric characters or 2 more characters followed by a "." dot and another 2 characters. This should be an easy one, right? Use some sample e-mail addresses and my brute force generator, you should be able to verify your solution.
Here's mine:
SELECT data
FROM TABLE(regex_utils.gen_data('a1@.', 9))
WHERE REGEXP_LIKE(data, '^[[:alnum:]]+@[[:alnum:]]+(\.[[:alnum:]]{3,4}|(\.[[:alnum:]]{2}){2})$', 'i'); Checking on valid domains, in my opinion, should be done in a second function, to keep the checks by itself simple, but that's probably a discussion about readability and taste.
How about checking a valid URL? I can reuse some parts of the e-mail example and only have to decide what type of URLs I want, for example "http://", "https://" and "ftp://", any subdomain and a "/" after the domain. Using the case insensitive match parameter, this shouldn't take too long, and I can use this thread's URL as a test value. But take a minute to figure that one out for yourself.
Does it look like this?
WITH t AS (SELECT 'Introduction to regular expressions ... last part. URL
             FROM dual
            UNION
           SELECT 'http://x/'
             FROM dual
SELECT t.URL
FROM t
WHERE REGEXP_LIKE(t.URL, '^(https*|ftp)://(.+\.)*[[:alnum:]]+(\.[[:alnum:]]{3,4}|(\.[[:alnum:]]{2}){2})/', 'i')
Update: Improvements in 10g2
All of you, who are using 10g2 or XE (which includes some of 10g2 features) may want to take a look at several improvements in this version. First of all, there are new, perl influenced meta characters.
Rewriting my example from the first lesson, the WHERE clause would look like this:
WHERE NOT REGEXP_LIKE(t.col1, '^\d+$')Or my example with searching decimal numbers:
'^(\.\d+|\d+(\.\d*)?)$'Saves some space, doesn't it? However, this will only work in 10g2 and future releases.
Some of those meta characters even include non matching lists, for example "\S" is equivalent to "[^ ]", so my example in the second part could be changed to:
SELECT NVL(LENGTH(REGEXP_REPLACE('Having fun with regular expressions', '\S')), 0)
FROM dual
;Other meta characters support search patterns in strings with newline characters. Just take a look at the link I've included.
Another interesting meta character is "?" non-greedy. In 10g2, "?" not only means 0 or 1 occurrence, it means also the first occurrence. Let me illustrate with a simple example:
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^.* +')
FROM dual
;This is old style, "greedy" search pattern, returning everything until the last space.
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^.* +?')
FROM dual
;In 10g2, you'd get only "Having " because of the non-greedy search operation. Simulating that behavior in 10g1, I'd have to change the pattern to this:
SELECT REGEXP_SUBSTR('Having fun with regular expressions', '^[^ ]+ +')
FROM dual
;Another new option is the "x" match parameter. It's purpose is to ignore whitespaces in the searched string. This would prove useful in ignoring trailing/leading spaces for example. Checking on unsigned integers with leading/trailing spaces would look like this:
SELECT REGEXP_SUBSTR(' 123 ', '^[0-9]+$', 1, 1, 'x')
FROM dual
;However, I've to be careful. "x" would also allow " 1 2 3 " to qualify as valid string.
I hope you enjoyed reading this introduction and hope you'll have some fun with using regular expressions.
C.
Fixed some typos ...
Message was edited by:
cd
Included 10g2 features
Message was edited by:
cd

Can I write this condition with only one reg expr in Oracle (regexp_substr in my example)?I meant to use only regexp_substr in select clause and without regexp_like in where clause.
but for better understanding what I'd like to get
next example:
a have strings of two blocks separated by space.
in the first block 5 symbols of [01] in the second block 3 symbols of [01].
In the first block it is optional to meet one (!), in the second block it is optional to meet one (>).
The idea is to find such strings with only one reg expr using regexp_substr in the select clause, so if the string does not satisfy requirments should be passed out null in the result set.
with t as (select '10(!)010 10(>)1' num from dual union all
select '1112(!)0 111' from dual union all --incorrect because of '2'
select '(!)10010 011' from dual union all
select '10010(!) 101' from dual union all
select '10010 100(>)' from dual union all
select '13001 110' from dual union all -- incorrect because of '3'
select '100!01 100' from dual union all --incorrect because of ! without (!)
select '100(!)1(!)1 101' from dual union all -- incorrect because of two occurencies of (!)
select '1001(!)10 101' from dual union all --incorrect because of length of block1=6
select '1001(!)10 1011' from dual union all) --incorrect because of length of block2=4
select '10110 1(>)11(>)0' from dual union all)--incorrect because of two occurencies of (>)
select '1001(>)1 11(!)0' from dual)--incorrect because (!) and (>) are met not in their blocks
--end of test data

Regular Expressions

I am trying to use a regular expression to filter out certain urls from getting aliased in my httpd.conf file.
I currently have
ScriptAliasMatch /someDir/ "C:/myCGIBin/"
which redirects any urls starting with someDir.
Ex. http://www.mySite.com/someDir/someApp.exe maps internally to c:/myCgiBin/someApp.exe
The catch is that there is 1 subdirectory which should not point to the cgi-bin
/someDir/specialDir/*
So any requests to this special directory should fail the ScriptAliasMatch, while all others pass.
ex.
/someDir/somefile.exe PASS
/someDir/someOtherDir/* PASS
/someDir/specialDir/* FAILI am not sure how to build a regular expression to achieve this.

public static void test3() {
    // (?!XXXXX) is negative look ahead,
    // so the regex does not match XXXXX right after /dirA/
    String str = "/dirA/(?!dirB/).*";
    Pattern pat = Pattern.compile(str);
    String [] testCases = { "/dirA/file.exe",
                            "/dirA/goodDir/*",
                            "/dirA/dirB/*",
                            "/dirA/dirB.txt"}; // this last one is valid!
    Matcher m = pat.matcher("");
    for (int i = 0, maxi = testCases.length; i < maxi; i++)
        m.reset(testCases);
System.out.println(testCases[i] + " passes: " + m.find());

Regular expression alarm url

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