Regular expression and line break problem

Question

Hi friends,
I was trying out one regular expression in java but, for some reasons its not working. The test string looks something like this in the eclipse watch window:-
Test string:-*
Content-Disposition: form-data; name="name"\n\nOmkar\n|
In the above test string the last character is a pipe symbol.
And the java code i have written is: -
code:
    public static void getParameterValue(String paramName, String testParameter) {
              String parameterRegex = "name=\""+paramName+"\"(.*)|";
              Pattern pattern = Pattern.compile(parameterRegex,Pattern.DOTALL);
              Matcher matcher = pattern.matcher(testParameter);
              boolean isFound = matcher.find();
              if (isFound) {
                   System.out.println("The parameter value is : "+matcher.group(1));
         }After, the debug line moves over the first line in this method, the value contained in the "parameterRegex" string variable is:-
Regex:-*
name="name"(.*)|
However, my SOP statement, prints null....even though, "isFound" variable is true....can someone please explain me what could be the problem, where i am going wrong ?....
I have even, set the DOTALL option for the regex.
please some one help me!
Thanks and Regards
Omkar Patkar

Answer 1

zomkar wrote:
Sorry, folks, i did not mention the fact that i had posted the my query, in Java ranch also. But my problem lead to another problem of CROSS - POSTING !
Apologies, for that !....but please, does any one have a solution to my regex ? .... any one ? please ?
The value i get in paramaname is :- name
which is present in double quotes in test string.
is my regex incorrect ?The discussion at JavaRanch seems to be pretty alive, so why not leave this thread and continue there? That way, people won't have to first read two different threads on two different forums before trying to help you.