Regular expression - removing emails

Hi,
How to use regular expressions to remove email addresses from
html files ?
Thanks in advance.
Maxcx

maxcx wrote:
> Hi,
> How to use regular expressions to remove email addresses
from html files ?
> Thanks in advance.
> Maxcx
Do you want to remove the email address, or to remove the
whole <a>
tag containing same?
Mick

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Regular expression for email

Hi all,
Can anyone help me to create a regular expression validation for email id? I have tried many combinations from internet regarding this validation, but everyone fails on APEX, although it runs fine in .NET or JAVA.
Expressions i tried was "^([\w\-\.]+)@((\[([0-9]{1,3}\.){3}[0-9]{1,3}\])|(([\w\-]+\.)+)([a-zA-Z]{2,4}))$", i want to validate email address such as "[email protected]". Can anyone help me in this regard?
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Hello Sunil,
>> Can anyone help me to create a regular expression validation for email id?
If you are talking about an email address, it’s not clear to me why you include the ‘http’ string in your regular expression. In any case, I’m using the following:
^[a-zA-Z0-9]{1}[a-zA-Z0-9\.\-]{1,}@[a-zA-Z0-9]{1}[a-zA-Z0-9\.\-]{1,}\.{1}[a-zA-Z]{2,4}$Regards,
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Please remember to mark appropriate posts as correct/helpful. For the long run, it will benefit us all.

Regular expression for email address formats

I have the following regulare expression which I am using to validate email address format.
This allows addresses of the form
[email protected]
^[-a-zA-Z0-9._]+\@[-a-zA-Z0-9]+\.[-a-zA-Z0-9]+\.[-a-zA-Z0-9]+$
And of course this allows addresses of the form
[email protected]
^[-a-zA-Z0-9._]+\@[-a-zA-Z0-9]+\.[-a-zA-Z0-9]+$
What I'm looking for is something which will allow both.

This way
'^[-a-zA-Z0-9._]+\@[-a-zA-Z0-9.]+$' would allow both. :-)
with test_data as
( select '[email protected]' as val from dual union all
select '[email protected]'   as val from dual union all
select 'no#good'              as val from dual
select
val ,
case
    when regexp_like( val, '^[-a-zA-Z0-9._]+\@[-a-zA-Z0-9.]+$' ) then 'Y'
    else 'N'
    end
    as good
from test_data ;
VAL                  G
[email protected] Y
[email protected]   Y
no#good              NBut then again, it would also allow "[email protected]" and "[email protected]" too. So I suspect you don't really want something that simply allows your two cases to pass validation. If you want to allow only those two cases then try something like this.
with test_data as
( select '[email protected]'     as val from dual union all
select '[email protected]'       as val from dual union all
select '[email protected]' as val from dual union all
select '[email protected]'      as val from dual union all
select 'no#good'                  as val from dual
select
val ,
case
    when
      regexp_like
      ( val
      , '^[-a-zA-Z0-9._]+\@[-a-zA-Z0-9]+\.[-a-zA-Z0-9]+(\.[-a-zA-Z0-9]+)?$'
      ) then 'Y'
    else 'N'
    end
    as good
from test_data ;
VAL                      G
[email protected]     Y
[email protected]       Y
[email protected] N
[email protected]      N
no#good                  N--
Joe Fuda
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Message was edited by SnippetyJoe - added clarification.

Regular expression: remove quotes except where there is a pipe in the middle

input file:
Column1|"Column | 2"|Column 3|Column 4
Column 1|"Column" 2|Column 3|Column 4
require a sed/awk command to end up with
Column1|"Column | 2"|Column 3|Column 4
Column 1|Column 2|Column 3|Column 4
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input file:
Column1|"Column | 2"|Column 3|Column 4 -->1
Column 1|"Column" 2|Column 3|Column 4
testfile:
Column1|"Column | 2"|Column 3|Column 4
Column 1|2 "Column 2|Column 3|Column 4 -->2

Help me! Give me a Regular Expressions for Email and URL!

see title!
Thank you very much!

URL pattern:
String proto="(\\w+)";
String userPassAt=":(\\w+)(?::(\\w+))?@";
String host="([^\\s:/\\<>]+)";
String port=":(\\d+)\\b";
String file="/([^\\s:?]*)"; //backslash not included
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Email validation using Regular Expression.

Hi,
I am in need of using a regular expression for email valiatino. ^[a-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+(?:[A-Z]{2}|com|org|net|edu|gov|mil|biz|info|mobi|name|aero|asia|jobs|museum)$ which is gotten from http://www.regular-expressions.info/email.html .
This works fine in a regular expression test tool http://regexpal.com/ , but when I use in Oracle, it does not.
DECLARE
v_exp VARCHAR2(4000);
BEGIN
   --v_exp := '^[a-z0-9!#$%&''*+/=?^_`{|}~-]+(?:\.[a-z0-9!#$%&''*+/=?^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+(?:[A-Z]{2}|com|org|net|edu|gov|mil|biz|info|mobi|name|aero|asia|jobs|museum)$';
   v_exp := '^[a-z0-9!#\$%&''*+/=?\^_`{|}~-]+(?:\.[a-z0-9!#\$%&''*+/=?\^_`{|}~-]+)*@(?:[a-z0-9](?:[a-z0-9-]*[a-z0-9])?\.)+(?:[A-Z]{2}|com|org|net|edu|gov|mil|biz|info|mobi|name|aero|asia|jobs|museum)$';
   dbms_output.put_line(v_exp);
   FOR v_rec IN (
      with test_data as
( select '[email protected]'     as val from dual union all
select '[email protected]'       as val from dual union all
select 'ad{[email protected]' as val from dual union ALL
select '[email protected]' as val from dual union all
select '[email protected]' as val from dual union all
select '[email protected]'      as val from dual union all
select 'no#good'                  as val from dual
select
val ,
case
    when
      regexp_like
      (val, v_exp,'i') then 'Y'
    else 'N'
    end
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from test_data ) LOOP
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END LOOP;
END;   and the results are
[email protected], N
[email protected], N
ad{[email protected], N
[email protected], N
[email protected], N
[email protected], N
no#good, N
The expected result should be Y for all but for the last two.
I am not sure why it is not working in Oracle.
Can any body please help me to find the mistake and to have it correctly?
Advance Thanks,
Natarajan
Edited by: Nattu on Dec 4, 2012 1:31 AM

Try this regular expression:
>> ^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,4})$
>> [email protected], *Y*
>> [email protected], *Y*
>> ad{[email protected], N
>> [email protected], *Y*
>> [email protected], *Y*
>> [email protected], N
>> no#good, N
[Using a regular expression to validate an email address|http://stackoverflow.com/questions/201323/using-a-regular-expression-to-validate-an-email-address]
Edited by: stefan nebesnak on 4.12.2012 2:25

Problem with email regular expression

I found the following regular expression from this website : http://www.regular-expressions.info/email.html
\b[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}\bor
^[A-Z0-9._%+-]+@[A-Z0-9.-]+\.[A-Z]{2,4}$I am using the following website to check its success, as well as my java app. : http://www.regexplanet.com/simple/index.html
of course java has a problem with the illegal escape character so i add another "/".
In both of my testing scenarios the regex value seems to fail. Am I missing something here?
If anyone could also test this regex and verify or correct my problem I would be very grateful.
Edited by: rico16135 on Jun 5, 2010 4:01 PM
Edited by: rico16135 on Jun 5, 2010 4:02 PM

rico16135 wrote:
of course java has a problem with the illegal escape character so i add another "/".I seem to be missing the distinction between a forward slash / which is not an escape character, and a backslash \ which is.
Also, if you show your actual Java code (in code tags, of course), and describe clearly and precisely what's going wrong--pasting in the exact, complete error message and indicating clearly which line caused it, if there is one--people will be in a better position to help you.

How to use Regular expression

Hi,
I have a file that contains this format (separated by ;(semicolon) ):
user id;user name;email address;password;integer;list of integer(separated by ,(comma))
below is the example data :
abc;Abc;[email protected];password1;1;1,2
def;Def;[email protected];password;2;1,2,3
ghi;Ghi;[email protected];password;2;1
my question is how to verify the valid input for each row using regular expression..? TQ

@Op. Doing a correct validation of e-mailaddresses
is very hard using regular expressions (doingbasic
validation is however easy)
http://www.regular-expressions.info/email.html
I like the RFC 822 compliant regexp :)

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Hello All,
My HTML string is like below.
select '<CityName>RICHMOND</CityName>
<StateCd>ABCD CDE
<StateCd/>
<CtryCd>CAN</CtryCd>
<CtrySubDivCd>BC</CtrySubDivCd>' Str from dual
Desired Output is
<CityName>RICHMOND</CityName><StateCd>ABCD CDE
<StateCd/><CtryCd>CAN</CtryCd><CtrySubDivCd>BC</CtrySubDivCd>
i.e. want to remove those spaces from tag value area having only spaces otherwise leave as it is. Please help to implement the same using Regular expression.

Hi,
It's unclear what you want. This site seems to be formatting your message in some odd way.
Post a statement like
SELECT '...' FROM dual;
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REGEXP_REPLACE ( str
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, '><'
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<custom>
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<custom>
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<custom>
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Thanks much for your response. I found David's article to be a little thin with respect to examples using quantifiers in coordination with the wildcard metacharacters; however, I was able to cobble together a working expression through trial and error using the information he presented. For posterity, here’s the solution:
Find:
<custom>[\d\D]*?</custom>
Replace:
<custom>
<![CDATA[]]>
</custom>
I believe this literally translates to:
[] = find anything in this range/character class
\d = find any digit character (i.e. any number)
\D = find any non-digit character (i.e. anything except numbers)
*? = match zero or more times, but as few times as possible (i.e. match multiple characters per instance, but only match one instance at a time, or none at all)
I’m still not sure how to effectively utilize the . wildcard. For example, the following expression will not find content that ends with a number:
<custom>.*?[\D]*?</ custom >
I'm presuming this is because numbers aren't included in the \D metacharacter; however, shouldn't numbers be picked up by the .*? expression?

Regular expression in java -- specifically email

Does anyone know how I can do a regular expression with java that is going to retrieve an email address pattern.
For example, let's say i have a huge string
this is a sample test. perhaps someoen can tell me how to retrieve my [email protected] from this string. sincerely yours [email protected]
could someone explain to me how to retrieve these emai addresses most efficiently using java's regular expressions
thanks
stev

A citing (http://jregex.sourceforge.net/examples-email.html):
String someValidChars="[\\w.\\-]+";
String someAlphaNums="\\w+";
String dot="\\.";
Pattern email=new Pattern(someValidChars + "@" + someValidChars + dot + someAlphaNums);

Using Regular Expressions To Remove Characters JDK 1.4

I want to write a regular expression to remove all commas in a string of text.
string is:
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or 1,000,000
I want it to return 1000 and 1000000.
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Please Help!

Try this tutorial: Linux : Education : Tutorials
Using regular expressions
David Mertz
President, Gnosis Software, Inc.
September 2000
http://www-105.ibm.com/developerworks/education.nsf/linux-onlinecourse-bytitle/6C2B4863702F592B8625696200589C5B?OpenDocument

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According to RFC-2822 and RFC-2821 specifications the local part of email addresses are allowed to contain a whitespace character as long as it is within quotations. The rest of my regular expression works fine I am battling to find out how to match the above mentioned pattern. Here is the first part of my expression...
([\"(\\w|\\s|\\p{Punct}){1,}\"])
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AmitChalwade123456 wrote:
it's client side validation ( java script regex) must be used ! Since when are client side validations recommended above server side validations?
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i think
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Regular expression - removing emails

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