Using Regular Expressions To Remove Characters JDK 1.4

I want to write a regular expression to remove all commas in a string of text.
string is:
1,000
or 1,000,000
I want it to return 1000 and 1000000.
I have tried some but I am just starting with Regular Expressions.
Please Help!

Try this tutorial: Linux : Education : Tutorials
Using regular expressions
David Mertz
President, Gnosis Software, Inc.
September 2000
http://www-105.ibm.com/developerworks/education.nsf/linux-onlinecourse-bytitle/6C2B4863702F592B8625696200589C5B?OpenDocument

Similar Messages

Use Regular Expressions to remove open/close anchor tags but leave the text contained within alone

I have a large file with lots of anchor tags. Many of the anchor tags have no HREF specified and do nothing. They aren't hurting anything, either, but I'd like to get rid of them, leaving the anchor tags that do have HREF alone, and leaving the text between the tags alone. Here's an example: <a>A resident or municipality may seek to vacate 25.01.01</a>.
I've come up with this to identify those tags: <\a>(.)*</\a> and it works, it finds them, but what should I put in the Replace area in order to remove the open/close tags but leave the text as it is?

I'm a reg ex idiot. So I use the Search Specific Tag feature whenever I can. See screenshot, hit Replace All. But please do this on a backed-up document to be sure it does what you want.
Nancy O.

Changeparticular characters in a string by using regular expressions ...

Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you

SSU wrote:
Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you
SQL> SELECT
2 regexp_replace('sdfsdf Sdfdfs Sdfd','s|S','X') from dual;
REGEXP_REPLACE('SD
XdfXdf XdfdfX XdfdRegards,
Achyut

Trying to use regular expressions to convert names to Title Case

I'm trying to change names to their proper case for most common names in North America (esp. the U.S.).
Some examples are in the comments of the included code below.
My problem is that *retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");* does not work as I expect. It seems that the toUpperCase method call does not actually do anything to the identified group.
Everything else works as I expect.
I'm hoping that I do not have to iterate through each character of the string, upshifting the characters that follow spaces.
Any help from you RegEx experts will be appreciated.
{code}
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* DAN MARINO --> Dan Marino
* old macdonald --> Old Macdonald <-- Can't capitalize the 'D" because of Ernst Mach
* ROY BLOUNT, JR. --> Roy Blount, Jr.
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* Tom Jones --> Tom Jones
* ST.LOUIS --> St. Louis
* ST.LOUIS, MO --> St. Louis, Mo <-- Avoid City Names plus State Codes
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
* Basic plan:
* 1. Strategically create double spaces in front of characters to be capitalized
* 2. Capitalize characters with preceding spaces
* 3. Remove double spaces.
// Make the string all lower case
String retName = name.trim().toLowerCase();
// Collapse strings of spaces to single spaces
retName = retName.replaceAll("[ ]+", " ");
// "mc" names
retName = retName.replaceAll("( mc)", " $1");
// Ensure there is one space after periods and commas
retName = retName.replaceAll("(\\.|,)([^ ])", "$1 $2");
// Add 2 spaces after periods, commas, hyphens and apostrophes
retName = retName.replaceAll("(\\.|,|-|')", "$1 ");
// Add a double space to the front of the string
retName = " " + retName;
// Upshift each character that is preceded by a space
// For some reason this doesn't work
retName = retName.replaceAll("( [^ ])([^ ]+)", "$1".toUpperCase() + "$2");
// Remove double spaces
retName = retName.replaceAll(" ", "");
return retName;
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:56 AM
Edited by: FuzzyBunnyFeet on Jan 17, 2011 10:57 AM

Hopefully someone will still be able to provide a RegEx solution, but until that time here is a working method.
Also, if people have suggestions of other rules for letter capitalization in names, I am interested in those too.
* Converts names in some random case into proper Name Case. This method does not have the
* extra processing that would be necessary to convert street addresses.
* This method does not add or remove punctuation.
* Examples:
* CAROL mosely-BrAuN --> Carol Mosely-Braun
* carol o'connor --> Carol O'Connor
* DAN MARINO --> Dan Marino
* eD mCmAHON --> Ed McMahon
* joe amcode --> Joe Amcode <-- Embedded "mc"
* mr.t --> Mr. T <-- Inserted space
* OLD MACDONALD --> Old Macdonald <-- Can't capitalize the 'D" because of Ernst Mach
* old mac donald --> Old Mac Donald
* ROY BLOUNT,JR. --> Roy Blount, Jr.
* ST.LOUIS --> St. Louis
* ST.LOUIS,MO --> St. Louis, Mo <-- Avoid City Names plus State Codes
* Tom Jones --> Tom Jones
* This is a work in progress that will need to be updated as new exceptions are found.
public static String toNameCase(String name) {
 * Basic plan:
 * 1. Strategically create double spaces in front of characters to be capitalized
 * 2. Capitalize characters with preceding spaces
 * 3. Remove double spaces.
 // Make the string all lower case
 String workStr = name.trim().toLowerCase();
 // Collapse strings of spaces to single spaces
 workStr = workStr.replaceAll("[ ]+", " ");
 // "mc" names
 workStr = workStr.replaceAll("( mc)", " $1 ");
 // Ensure there is one space after periods and commas
 workStr = workStr.replaceAll("(\\.|,)([^ ])", "$1 $2");
 // Add 2 spaces after periods, commas, hyphens and apostrophes
 workStr = workStr.replaceAll("(\\.|,|-|')", "$1 ");
 // Add a double space to the front of the string
 workStr = " " + workStr;
 // Upshift each character that is preceded by a space and remove double spaces
 // Can't upshift using regular expressions and String methods
 // workStr = workStr.replaceAll("( [^ ])([^ ]+)", "$1"toUpperCase() + "$2");
 StringBuilder titleCase = new StringBuilder();
 for (int i = 0; i < workStr.length(); i++) {
 if (workStr.charAt(i) == ' ') {
 if (workStr.charAt(i+1) == ' ') {
 i += 2;
 while (i < workStr.length() && workStr.charAt(i) == ' ') {
 titleCase.append(workStr.charAt(i++));
 if (i < workStr.length()) {
 titleCase.append(workStr.substring(i, i+1).toUpperCase());
 } else {
 titleCase.append(workStr.charAt(i));
 return titleCase.toString();
{code}

Regular Expression to remove space in HTML Tag

Hello All,
My HTML string is like below.
select '<CityName>RICHMOND</CityName>
<StateCd>ABCD CDE
<StateCd/>
<CtryCd>CAN</CtryCd>
<CtrySubDivCd>BC</CtrySubDivCd>' Str from dual
Desired Output is
<CityName>RICHMOND</CityName><StateCd>ABCD CDE
<StateCd/><CtryCd>CAN</CtryCd><CtrySubDivCd>BC</CtrySubDivCd>
i.e. want to remove those spaces from tag value area having only spaces otherwise leave as it is. Please help to implement the same using Regular expression.

Hi,
It's unclear what you want. This site seems to be formatting your message in some odd way.
Post a statement like
SELECT '...' FROM dual;
without any formatting, to show your input, and post the exact output you want friom that, with as little formatting as possible. It might help if you use some character like ~ instead of spaces (just for posting; we'll find a solution that works for spaces).
To remove the text that consists of spaces and nothing else between the tags, you can say
REGEXP_REPLACE ( str
, '> +<'
, '><'
How is this string being generated? Maybe there's some easier, more efficient way to keep the bad sub-wrtings out of the string in the first place.

Regular Expression for Removing a space after the a... tag?

Hi there,
I'm fairly new to using Regular Expressions, but am in need of one that will help me find all <a...> tags that have a space immediately following that tag and replace it with the exact same tag, but no space following the <a...> tag.
So, for example, a regular expression that will find:
<a href="somelink.html"> Somelink</a>
as well as:
<a href="#" onmouseout="MM_swapImgRestore()" onmouseover="MM_swapImage('sub-nav_button_professional_portal','','images/sub-nav_button_ professional_portal_f2.png',1)"> Somelink</a>
And just remove the space appearing as part of the hyperlink. Does anyone know how to accomplish this?

Thought of that, but it would remove spaces from crucial areas of my pages. For example, conditional logic within a script, like:
for (i = 0; i > (a.length - 2); i += 3)
would become:
for (i = 0; i >(a.length - 2); i += 3)
While that wouldn't pose a huge problem, I'm messing up the syntax in order to fix something else, which is why I wanted to go the route of a regular expression. I need to replace all "<a ...> " (space included) tags with "<a ...>" and make sure that the properties within the <a> tag stay in tact.

Validate cfinput using regular expression

Hi,
can somebody help me valditing an cfinput field using regular expressions?
First digit must be a number or "R".
Digit 2-15 can be everything without special characters. Digit 2-15 can also be empty.
I try this, but it doesn't work (Sorry I'm a beginner using regex).
<cfinput type="text" name="field1" required="yes" validate="regular_expression" pattern="[0-9Rr][0-9a-zA-Z]*" maxlength="15">
Thank you in advice!
Claudia

You haven't told your regex to match the entire string, so it will "pass"
any string that has your match anywhere within it, so like as long as it's
got an R or a digit in it: it's OK.
To tell it to match the entire string, anchor it to the start and end of the
string with ^ and $ respectively.
Regular expression syntax: Using special characters
http://help.adobe.com/en_US/ColdFusion/9.0/Developing/WSc3ff6d0ea77859461172e0811cbec0a38f -7ffb.html#WSc3ff6d0ea77859461172e0811cbec0a38f-7fef
Adam

String Regular Expression for uncommon characters

Hi,
I am trying to get text out of HTML file for which I am using EditorKit and Document classes. After I obtain the text, the text (String) contains some characters like �. This character looks like a with French style acute accent . My problem is how to use regular expression to find and replace (replaceAll method) these unwanted characters.
Is there a regular expression pattern for such characters?
Thanks!
Rahul.

hrm I would recommend looking at the specific patterns,
a simplified site would be here http://www.p3m.org/wiki?regex
as a refernce . If you dont know regular expression, use
http://www.perl.com/doc/manual/html/pod/perlre.html
The only way I could think of constructing the regex is to use the \s and add the characters you want in that regex :s you could look into regex look ahead and look behind methods...

Regular Expression Exclude Certain Characters

I am building this with Apex 3.2
I have a validation on a page item of type regular expression
Validation Expression 1 :   P13_TARGET_BMI
Validation Expression 2:    ^[[:alnum:]-]*$
This allows all characters, number and the - symbol
Now I need to exclude certain alpha characters, ie German letters Ä Ü Ö
and spaces if possible
Basically if the user types in Ä, Ü, Ö, the validation should fail
Cheers
Gus

Hi, Gus,
The most efficient thing would be to list all the acceptable characters instead of using [:alnum:].
REGEXP_LIKE ( str
            , '^[a-z0-9A-Záéíóúæ... -]+$'
If you can't do that, then use a separate test to check for the exceptional alphabetic characters
     REGEXP_LIKE ( str
                 , '^[[:alnum:] -]+$'
AND str = TRANSLATE ( str
                     , 'xÄÜÖ'
                     ,'x'
You can use regular expressions for the Ä Ü Ö testing, if you want to.
There's nothing tricky about spaces; by default, they have no special meaning in regular expressions, and they never have any special meaning inside square brackets.

One for the Tekkies: How to get this output using REGULAR EXPRESSIONS?

How to get the below output using REGULAR EXPRESSIONS??
SQL> ed
Wrote file afiedt.buf
1* CREATE TABLE cus___addresses (full_address VARCHAR2(200 BYTE))
SQL> /
Table created.
SQL> PROMPT Address Format is: House #/Housename, street, City, Zip Code, COUNTRY
House #/Housename, street, City, Zip Code, COUNTRY
SQL> INSERT INTO cus___addresses VALUES('1, 3rd street, Lansing, MI 49001, USA');
1 row created.
SQL> INSERT INTO cus___addresses VALUES('3B, fifth street, Clinton, OK 74103, USA');
1 row created.
SQL> INSERT INTO cus___addresses VALUES('Rose Villa, Stanton Grove, Murray, TN 37183, USA');
1 row created.
SQL> SELECT * FROM cus___addresses;
FULL_ADDRESS
1, 3rd street, Lansing, MI 49001, USA
3B, fifth street, Clinton, OK 74103, USA
Rose Villa, Stanton Grove, Murray, TN 37183, USA
SQL> The REG EXP query shouLd output the ZIP codes: i.e. 49001, 74103, 37183 in 3 rows.Edited by: user12240205 on Jun 18, 2012 3:19 AM

Hi,
user12240205 wrote:
... Frank, ʃʃp's method, I understand. But your method, although correct, I find it difficult to understand.
Could you explain how you did this?? What does '.*(\d{5})\D*' and '\1' mean???
Your method is better because it uses only ONE reg expression function. ʃʃp's uses 2.In Oracle 10.2 (I believe) and higher, '\d' is equivalent to '[[:digit:]]', and '\D' is equivalent to '[^[:digit:]]'. I find '\d' and '\D' easier to type, but there's nothing wrong with using '[[:digit:]]' and '[^[:digit:]]'.
'.*' means "0 or more of any character".
'\D*' means "0 or more non-digits".
The whole expression, '.*(\d{5})\D*' means:
a. 0 or more characters (any characters)
b. 5 digits
c. 0 or more non-digits.
'\1' is a Backreference . It means the sub-string that matched the pattern after the 1st '(', up to (but not including) its matching ')'. In this case, that means the sub-string that matched '\d{5}', or b. using the explanation immediately above.
So the entire REGEXP_REPLACE call means "When you see a sub-string consisting of a., follwed immediately by b., followed immedately by c., replace that sub-string with b. alone."

Help in query using regular expression

HI,
I need a help to get the below output using regular expression query. Please help me.
SELECT REGEXP_SUBSTR ('PWRPKG(P/W+P/L+CC)', '[^+]+', 1, lvl) val, lvl
FROM DUAL,(SELECT LEVEL lvl FROM DUAL
CONNECT BY LEVEL <=(SELECT MAX ( LENGTH ('PWRPKG(P/W+P/L+CC)') - LENGTH (REPLACE ('PWRPKG(P/W+P/L+CC)','+',NULL))+ 1) FROM DUAL));
I need the output as
correct result:
==============
val lvl
P/W 1
P/L 2
CC 3
But i tried the above it is not coming the above result. Please help me where i did a mistake.
Thanks in advance

Frank gave you a solution in your other thread. You could simplify it if you are on 11g:
SQL> select * from table_x
2 /
TXT
TECHPKG(INTELLI CC+FRT SONAR)
PWRPKG(P/W+P/L+CC)
select txt,
 regexp_substr(
 txt,
 '(.*\()*([^+)]+)',
 1,
 column_value,
 null,
 2
 ) element,
 column_value element_number
from table_x,
 table(
 cast(
 multiset(
 select level
 from dual
 connect by level <= regexp_count(txt,'\+') + 1
 as sys.OdciNumberList
order by rowid,
 column_value
TXT ELEMENT ELEMENT_NUMBER
TECHPKG(INTELLI CC+FRT SONAR) INTELLI CC 1
TECHPKG(INTELLI CC+FRT SONAR) FRT SONAR 2
PWRPKG(P/W+P/L+CC) P/W 1
PWRPKG(P/W+P/L+CC) P/L 2
PWRPKG(P/W+P/L+CC) CC 3
SQL> SY.

Rplacing space with &nbsb; in html using regular expressions

Hi
I want to replace space with &nbsb; in HTML.
I used the below method to replace space in my html file.
var spacePattern11:RegExp =/(\s)/g;
str= str.replace(spacePattern," "
Here str varaible contains below html file.In this html file i want to replace space present between " What number does this represents" with &nbsb;
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this Roman numeral represents MDCCCXVIII ?</TEXTFORMAT>
</body>
</html>
But by using the above regular expression i am getting like this.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head><body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this represents</TEXTFORMAT>
</body>
</html>
Here what happening means it was replacing space with &nbsb; in HTML tags also.But want to replace space with &nbsb; present in the outside of the HTML tags.I want like this using regular expressions in FLEX
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>What number does this represents</body>
</html>
Hi,Please give me the solution to slove the above problem using regular expressions
Thanks in Advance to all
Regards
ssssssss

sorry i missed some information in above,The modified information was in red color
Hi
I want to replace space with &nbsb; in HTML.
I used the below method to replace space in my html file.
var spacePattern11:RegExp =/(\s)/g;
str= str.replace(spacePattern," "
Here str varaible contains below html file.In this html file i want to replace space present between " What number does this represents" with &nbsb;
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this Roman numeral represents MDCCCXVIII ?</TEXTFORMAT>
</body>
</html>
But by using the above regular expression i am getting like this.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head><body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADIN G="2"> What number does this represents</TEXTFORMAT>
</body>
</html>
Here what happening means it was replacing space with &nbsb; in HTML tags also.But want to replace space with &nbsb; present in the outside of the HTML tags.I want like this using regular expressions in FLEX
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>What&nbsb;number&nbsb;does&nbsb;this&nbsb;represents</body>
</html>
Hi,Please give me the solution to slove the above problem using regular expressions
Thanks in Advance to all
Regards
ssssssss

Regular Expressions to Omit Characters

I am new to Java. I am trying to use regular expressions to omit a pattern. The construct [^abc] can be used to omit a or b or c, but how can I omit the string abc from a regular expression? Many thanks.

Why not use the regular expression "abc" and see if it doesn't match? Or even use this:
boolean matches = (targetString.indexOf("abc") == -1); // == -1 means "not found", so matches become true if abc is not in targetString
if (matches) System.out.println("Yay, no abc in " + targetString + "!");
else System.out.println("Eek, get that abc out of my sight!");

Using regular expressions in java

Does anyone of you know a good source or a tutorial for using regular expressions in java.
I just want to look at some examples....
Thanks

thanks a lot... i have one more query
Boundary matchers
^      The beginning of a line
$      The end of a line
\b      A word boundary
\B      A non-word boundary
\A      The beginning of the input
\G      The end of the previous match
\Z      The end of the input but for the final terminator, if any
\z      The end of the input
if i want to use the $ for comparing with string(text) then how can i use it.
Eg if it is $120 i got a hit
but if its other than that if should not hit.

Using Regular Expressions in Numbers 09?

Is there any way to use regular expressions in Numbers 09 in Find & Replace?

kilowattradio wrote:
Is there any way to use regular expressions in Numbers 09 in Find & Replace?
NO !
_Go to "Provide Numbers Feedback" in the "Numbers" menu_, describe what you wish.
Then, cross your fingers, and wait _at least_ for iWork'10
Yvan KOENIG (VALLAURIS, France) vendredi 25 septembre 2009 14:49:49

Using Regular Expressions To Remove Characters JDK 1.4

Similar Messages

Maybe you are looking for