Regular expression to get substring from string

Hi,
I’m having the following problem:
SELECT REGEXP_SUBSTR(';first field;ir-second field-02;ir-second field-01; third field','.*ir-(.*)-01.*’)FROM dual
[\CODE]
This is the select that I have with a java expression!
In java I’m able to do find the right expression to retrieve what I want, but I don’t know how to adapt this for oracle!
In oracle I was trying to do something like this:
NVL(SUBSTR(REGEXP_SUBSTR(CONCAT(';', list),';ir-[^01;]+'),LENGTH(';ir-')+1,LENGTH(REGEXP_SUBSTR(CONCAT(';',list),';ir-[^01;]+'))), ' ') AS result
[\CODE]
But it doesn’t work because “ir” can repeat in other parameters.
“ir-something-01” only appears once.
Is it in oracle a logic similar to result groups in oracle?
best regards,
Ricardo Tomás

rctomas wrote:
Hi,
In java I’m able to do find the right expression to retrieve what I wantWell, would be nice to tell us what that right expression would be :). Anyway, is this what you are looking for:
SQL> SELECT REGEXP_SUBSTR(';first field;ir-second field-02;ir-second field-01; third field',';ir-([^;]*)-01')
2 from dual
3 /
REGEXP_SUBSTR(';FIR
;ir-second field-01
SQL> SY.

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