Using regular expressions to get a customized output

Hi,
I have a string/varchar variable with the data ',a,b,c,' in it.
I want the display as follows:
a
b
c
I would like to get the similar output using regular expressions.
How do I get this output using REGEXP_REPLACE or REGEXP_SUBSTR?
Please do the needful.
Thanks & Regards,
Rakshit

I remember that, however if we look closer, that one has a little flaw: The 2nd row should be null, because ",," indicates an empy field. The MODEL clause solution works just fine in this case:
with t as (select 'aaaa,,bbbb,cccc,dddd,eeee,ffff' col1 from dual)
-- end of sample data
SELECT col_new
FROM t
MODEL
 PARTITION BY (ROWNUM rn)
 DIMENSION BY (0 dim)
 MEASURES(col1, col1 col_new)
 RULES ITERATE(99) UNTIL (ITERATION_NUMBER = LENGTH(REGEXP_REPLACE(col1[0], '[^,]')))
 (col_new[ITERATION_NUMBER] = REPLACE(REGEXP_SUBSTR(col1[0], '(^|,)[^,]*', 1, ITERATION_NUMBER+1), ','))
COL_NEW
aaaa
bbbb
cccc
dddd
eeee
ffff
7 Zeilen ausgewählt.Update: I had this nagging feeling that I missed something, and there it was. If you want to see what the problem with my solution is, change the example to
with t as (select ',aaaa,,bbbb,cccc,dddd,eeee,ffff' col1 from dual)So I went back and tried to fix BlueShadows approach. Here it is:
with t as (select 'aaaa,,bbbb,cccc,dddd,eeee,ffff' txt from dual)
-- end of sample data
SELECT REPLACE(REGEXP_SUBSTR(',' || txt, ',[^,]*', 1, level), ',') col_new
FROM t
CONNECT BY level <= length(regexp_replace(txt,'[^,]*'))+1
;C.

Similar Messages

One for the Tekkies: How to get this output using REGULAR EXPRESSIONS?

How to get the below output using REGULAR EXPRESSIONS??
SQL> ed
Wrote file afiedt.buf
1* CREATE TABLE cus___addresses (full_address VARCHAR2(200 BYTE))
SQL> /
Table created.
SQL> PROMPT Address Format is: House #/Housename, street, City, Zip Code, COUNTRY
House #/Housename, street, City, Zip Code, COUNTRY
SQL> INSERT INTO cus___addresses VALUES('1, 3rd street, Lansing, MI 49001, USA');
1 row created.
SQL> INSERT INTO cus___addresses VALUES('3B, fifth street, Clinton, OK 74103, USA');
1 row created.
SQL> INSERT INTO cus___addresses VALUES('Rose Villa, Stanton Grove, Murray, TN 37183, USA');
1 row created.
SQL> SELECT * FROM cus___addresses;
FULL_ADDRESS
1, 3rd street, Lansing, MI 49001, USA
3B, fifth street, Clinton, OK 74103, USA
Rose Villa, Stanton Grove, Murray, TN 37183, USA
SQL> The REG EXP query shouLd output the ZIP codes: i.e. 49001, 74103, 37183 in 3 rows.Edited by: user12240205 on Jun 18, 2012 3:19 AM

Hi,
user12240205 wrote:
... Frank, ʃʃp's method, I understand. But your method, although correct, I find it difficult to understand.
Could you explain how you did this?? What does '.*(\d{5})\D*' and '\1' mean???
Your method is better because it uses only ONE reg expression function. ʃʃp's uses 2.In Oracle 10.2 (I believe) and higher, '\d' is equivalent to '[[:digit:]]', and '\D' is equivalent to '[^[:digit:]]'. I find '\d' and '\D' easier to type, but there's nothing wrong with using '[[:digit:]]' and '[^[:digit:]]'.
'.*' means "0 or more of any character".
'\D*' means "0 or more non-digits".
The whole expression, '.*(\d{5})\D*' means:
a. 0 or more characters (any characters)
b. 5 digits
c. 0 or more non-digits.
'\1' is a Backreference . It means the sub-string that matched the pattern after the 1st '(', up to (but not including) its matching ')'. In this case, that means the sub-string that matched '\d{5}', or b. using the explanation immediately above.
So the entire REGEXP_REPLACE call means "When you see a sub-string consisting of a., follwed immediately by b., followed immedately by c., replace that sub-string with b. alone."

How to get year value using regular expression

Hi,
I have a different format of date such as 2004-01-03, 2003/01, 05/06/2005, 06-05-2007
How can I get only the year value using regular expression? The year value is always in 4 digits
Thanks in advance

sabre150 wrote:
JosAH wrote:
\d{4}Is this the Jos I knew who poured scorn on anything to do with regex? Is this the Jos I knew who said that the 'pimping lemon' stopped regex being of any real use?It wasn't me; honest, I'm innocent: one of my parrots walked over my keyboard; I wouldn't be able to type such nonsense; naughty parrot! No cookie!
kind regards,
Jos
ps. regexes can only survive the baby-pumping-lemma; they all die a horrible death with the real-men-pumping lemma! So there.

Help in query using regular expression

HI,
I need a help to get the below output using regular expression query. Please help me.
SELECT REGEXP_SUBSTR ('PWRPKG(P/W+P/L+CC)', '[^+]+', 1, lvl) val, lvl
FROM DUAL,(SELECT LEVEL lvl FROM DUAL
CONNECT BY LEVEL <=(SELECT MAX ( LENGTH ('PWRPKG(P/W+P/L+CC)') - LENGTH (REPLACE ('PWRPKG(P/W+P/L+CC)','+',NULL))+ 1) FROM DUAL));
I need the output as
correct result:
==============
val lvl
P/W 1
P/L 2
CC 3
But i tried the above it is not coming the above result. Please help me where i did a mistake.
Thanks in advance

Frank gave you a solution in your other thread. You could simplify it if you are on 11g:
SQL> select * from table_x
2 /
TXT
TECHPKG(INTELLI CC+FRT SONAR)
PWRPKG(P/W+P/L+CC)
select txt,
 regexp_substr(
 txt,
 '(.*\()*([^+)]+)',
 1,
 column_value,
 null,
 2
 ) element,
 column_value element_number
from table_x,
 table(
 cast(
 multiset(
 select level
 from dual
 connect by level <= regexp_count(txt,'\+') + 1
 as sys.OdciNumberList
order by rowid,
 column_value
TXT ELEMENT ELEMENT_NUMBER
TECHPKG(INTELLI CC+FRT SONAR) INTELLI CC 1
TECHPKG(INTELLI CC+FRT SONAR) FRT SONAR 2
PWRPKG(P/W+P/L+CC) P/W 1
PWRPKG(P/W+P/L+CC) P/L 2
PWRPKG(P/W+P/L+CC) CC 3
SQL> SY.

How to fetch substring using regular expression

Hi,
I am new to using regular expression and would like to know some basic details of how to use them in Java.
I have a String example= "http://www.google.com/foobar.html#*q*=database&aq=f&aqi=g10&fp=c9fe100d9e542c1e" and would like to get the value of "q" parameter (in bold) using regular expression in java.
For the same example, when we tried using javascript:
match = example.match("/^http:\/\/(?:(?!mail\.)[^\.]+?\.)?google\.[^\?#]+(?:.*[\?#&](?:as_q|q)=([^&]+))?/i}");
document.write('
' + match);
We are getting the output as: http://www.google.com/foobar.html#q=database,*database* where the bold text is the value of "q" parameter.
In Java we are trying to get the value of the q parameter separately or atleast resembles the output given by JavaScript. Please help me resolving this issue.
Regards
Praveen

BalusC wrote:
Regex is a cumbersome solution for fixed patterns like URL's. String#substring() in combination with String#indexOf would most likely already suffice.I usually agree, although, in this case, finding the exact parameter might be difficult without a small regex, perhaps:
"\\wq=\\s*"in conjunction with Pattern/Matcher, used similarly to an indexOf() to find the start of the parameter value.
Winston

Item Validation using Regular Expression

Hi,
I am trying to apply a Validation to a text field item, with the type as Regular Expression.
The text input into the field should be in a HH:MM:SS format, ie 05:30:00 (for 5:30am).
The text I am placing in the 'Validation Expression 2' box is:
[0-2][0-9]\:[0-5][0-9]\:[0-5][0-9]
This doesn't seem to work and I get an error message when I enter text in the correct format.
I have even tried to use other comparisons, for example:
or
.{8}
but these still give me an error message.
Anyone have any ideas?

Thanks for your help Flavio, the Regular Expression tool is really helpful.
When I use this tool to compare strings with my regular expression, I get output = TRUE, which means I'm getting it right, but for some reason when I copy the same Regular Expression syntax into APEX, it doesn't work.
I try to input correct strings into the field that is validated by the Reg Expr, but it still gives me an error.
It seems to be something I am doing wrong within the application, but I can't figure out what I'm missing.
I am creating an Item Level Validation with details:
Type: Regular Expression
Validation Expression 1: P23_BUS_DAY_COVERAGE_START
Validation Expression 2: ^(([0-1][0-9])|(2[0-3])):[0-5][0-9]:[0-5][0-9]$
Has anyone had similar problems using regualr expression validation in APEX?

Regular expression not giving the required output.

Hi , I have msgs that look like this :
dear john smith you Bought 500 shares of Nile Cotton Ginning at 14.9 L.E On 21/01/10
Im using the Regular expression to get 4 substrings of this msg
1-Bought|Sold
2-Quantity of shares (ex: 500)
3-Name of the stock (ex:Nile Cotton Ginning)
4-price (ex:14.9)
Here is my code , but the output returns the whole msg back :
select SMSID,SMSNO,CUSTOMERACCOUNTID,SENDDATE,ENTRYDATE,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\1')),'(watheeqa)') buy_sell
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\2')),'(watheeqa)') amount ,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\3')),'(watheeqa)') company ,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at ([0-9]*\.[0-9]*|[0-9][^A-Z][^a-z]) .*','\4')),'(watheeqa)') price
from SMSOUTMSG@bimsic s
where trunc(SENDDATE) = trunc(sysdate) -1
and exists (select 1 from PHONEDETAIL@bimsic p
where s.CUSTOMERACCOUNTID = p.CUSTOMERACCOUNTID
and SMSFLAG = 1);Thanks.

It does check it out
with t
as
select 'dear john smith you Bought 500 shares of Nile Cotton Ginning at 14.9 L.E On 21/01/10' smstext from dual
select
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\1')),'(watheeqa)') buy_sell,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\2')),'(watheeqa)') amount ,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at (.*)','\3')),'(watheeqa)') company ,
regexp_replace(trim(regexp_replace(SMSTEXT,'^.* you (Sold|Bought)(.*) of (.*) at ([0-9]*\.[0-9]*|[0-9][^A-Z][^a-z]) .*','\4')),'(watheeqa)') price
from t

Rplacing space with &nbsb; in html using regular expressions

Hi
I want to replace space with &nbsb; in HTML.
I used the below method to replace space in my html file.
var spacePattern11:RegExp =/(\s)/g;
str= str.replace(spacePattern," "
Here str varaible contains below html file.In this html file i want to replace space present between " What number does this represents" with &nbsb;
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this Roman numeral represents MDCCCXVIII ?</TEXTFORMAT>
</body>
</html>
But by using the above regular expression i am getting like this.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head><body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this represents</TEXTFORMAT>
</body>
</html>
Here what happening means it was replacing space with &nbsb; in HTML tags also.But want to replace space with &nbsb; present in the outside of the HTML tags.I want like this using regular expressions in FLEX
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>What number does this represents</body>
</html>
Hi,Please give me the solution to slove the above problem using regular expressions
Thanks in Advance to all
Regards
ssssssss

sorry i missed some information in above,The modified information was in red color
Hi
I want to replace space with &nbsb; in HTML.
I used the below method to replace space in my html file.
var spacePattern11:RegExp =/(\s)/g;
str= str.replace(spacePattern," "
Here str varaible contains below html file.In this html file i want to replace space present between " What number does this represents" with &nbsb;
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this Roman numeral represents MDCCCXVIII ?</TEXTFORMAT>
</body>
</html>
But by using the above regular expression i am getting like this.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head><body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADIN G="2"> What number does this represents</TEXTFORMAT>
</body>
</html>
Here what happening means it was replacing space with &nbsb; in HTML tags also.But want to replace space with &nbsb; present in the outside of the HTML tags.I want like this using regular expressions in FLEX
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>What&nbsb;number&nbsb;does&nbsb;this&nbsb;represents</body>
</html>
Hi,Please give me the solution to slove the above problem using regular expressions
Thanks in Advance to all
Regards
ssssssss

Using regular expressions for validating time fields

Similar to my problem with converting a big chunk of validation into smaller chunks of functions I am trying to use Regular Expressions to handle the validation of many, many time fields in a flexible working time sheet.
I have a set of FormCalc scripts to calculate the various values for days, hours and the gain/loss of hours over a four week period. For these scripts to work the time format must be in HH:MM.
Accessibility guidelines nix any use of message box pop ups so I wanted to get around this by having a hidden/visible field with warning text but can't get it to work.
So far I have:
var r = new RegExp(); // Create a new Regular Expression Object
r.compile ("^[00-99]:\\] + [00-59]");
var result = r.test(this.rawValue);
if (result == true){
true;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "visible";
else (result == false){
false;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "hidden";
Any help would be appreciated!

Date and time fields are tricky because you have to consider the formattedValue versus the rawValue. If I am going to use regular expressions to do validation I find it easier to make them text fields and ignore the time patterns (formattedValue). Something like this works (as far as my very brief testing goes) for 24 hour time where time format is HH:MM.
// form1.page1.subform1.time_::exit - (JavaScript, client)
var error = false;
form1.page1.subform1.errorMsg.rawValue = "";
if (!(this.isNull)) {
var time_ = this.rawValue;
if (time_.length != 5) {
    error = true;
else {
    var regExp = /^([01]?[0-9]|2[0-3]):[0-5][0-9]$/;
    if (!(regExp.test(time_))) {
      error = true;
if (error == true) {
form1.page1.subform1.errorMsg.rawValue = "The time must be in the format HH:MM where HH is 00-23 and MM is 00-59.";
form1.page1.subform1.errorMsg.presence = "visible";
Steve

How to use regular expression to delete a character?

Hello,
I have a query,
select partition_name from dba_tab_partitions where table_owner='xxx'and num_rows <>0 and table_name = 'xxx';
P5
P6
P7
P12
P13
P14
P17
P18
P19
P20
P24
How can I use regular expression in above SQL query to get result without letter 'P', like..
5
6
7
12
13
14
17
18
19
20
24
thank you

I find answer...
select regexp_replace(partition_name,'P','')
thanks anyway

Finding URLs using regular expression.

I have an requirement where user will type some text containing URLs like "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747. Thank you". This text has to be modified as below before saving it to the database.
"Please visit this site <a href='http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747'>http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747</a>. Thank you"
I am using regular expression (http|https)://.+?\\s which marks the end of the url with a white space character.This pattern doesn't work if the URL is located at the end of the string since there will be no space at the end.
For example if the string is "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747" the regex will fail.
My acutal problem is to find the URL irrespective its position within the string.
Pattern urlPattern = Pattern.compile("(http|https)://.+?\\s", Pattern.CASE_INSENSITIVE);
Matcher matcher = urlPattern.matcher(plainText);
Map stringIndexMap = new HashMap();
//Searching the input string for urlPattern...
while(matcher.find()) {
String urlString = matcher.group();
//Storing the urls in a hashmap with their indices as keys....
stringIndexMap.put(new Integer(matcher.start()), urlString.trim());
Set keySet = stringIndexMap.keySet();
Iterator it = keySet.iterator();
//Iterating over the hashmap containing urls...
while(it.hasNext()) {
String urlString = (String) stringIndexMap.get(it.next());
* Replacing the url string in the input text with <a href="#" onclick="window.open('<urlString>')"
* using String index
clickableURLString.replace(clickableURLString.indexOf(urlString),
clickableURLString.indexOf(urlString) + urlString.length(),
"<a href=\"#\" onclick=\"window.open('" + urlString
+ "')\">" + urlString + "</a>");
return clickableURLString.toString();

The end of the input is '$' as a regex.
import java.util.regex.*;
public class Prasanna{
public static void main(String[] args){
 String text
= "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747";
// String regex = "(http|https)://.+?(?:\\s|$)"; // this works
 String regex = "(http|https)://[^ ]+"; // this also works
 Pattern pat = Pattern.compile(regex, Pattern.CASE_INSENSITIVE);
 Matcher mat = pat.matcher(text);
 while (mat.find()){
 System.out.println(mat.group());
}

Searching for a substring using Regular Expression

I have a lengthy String similar to repetetion of the one below
String str="<option value='116813070'>Something1</option><option value='ABCDEF' selected>Something 2</option>"I need to search for the Sub string "<option value='ABCDEF' selected>" (need to get the starting index of sub string) and but the value ABCDEF can be anything numberic with varying length.
Is there any way i can do it using regular expressions(I have no other options than regular expression)?
thanks in advance.

If you go through the tutorial then you will find this on the second page:
import java.io.Console;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class RegexTestHarness {
 public static void main(String[] args){
 Console console = System.console();
 if (console == null) {
 System.err.println("No console.");
 System.exit(1);
 while (true) {
 Pattern pattern =
 Pattern.compile(console.readLine("%nEnter your regex: "));
 Matcher matcher =
 pattern.matcher(console.readLine("Enter input string to search: "));
 boolean found = false;
 while (matcher.find()) {
 console.format("I found the text \"%s\" starting at " +
 "index %d and ending at index %d.%n",
 matcher.group(), matcher.start(), matcher.end());
 found = true;
 if(!found){
 console.format("No match found.%n");
}It's does everything you need and a bit more. Adapt it to your needs then write a regular expression. Then if you have problems by all means come back and post them up here, but first at least attempt to solve it yourself.

Format string using Regular Expression

Input string output format...
SELECT q'<select ab_c "ABC", efg "EFG" from dual>' str FROM DUAL
Output:
STR
select ab_c "ABC", efg "EFG" from dual
Required output format using regular expression...
STR
select 'ab_c' "ABC", 'efg' "EFG" from dual

Regular expressions have many limitations as parsing tools, and you didn't specify the rules you wanted. This expression puts quotes around the non blank string before a quoted string:
SELECT regexp_replace(q'<select ab_c "ABC", efg "EFG" from dual>',
 '([^" ]+)( +"[^ ]*")' , '''\1''\2' ) str FROM DUAL;
STR
select 'ab_c' "ABC", 'efg' "EFG" from dual
{code}
It is not robust - a missing " will confuse it, and you should be using bind variables anyway.

Find text using regular expression and add highlight annotation

Hi Friends
Is it possible to find text using regular expression and add highlight annotation using plugin

A plugin can use the PDWordFinder to get a list of the words on a page, and their location. That's all that the API offers for searching. Of course, you can use a regular expression library to work with that word list.

Creating regular expression to get desired info

Hi all!!!
I have a little problem. I need to get the line below, but i NEED to use regular expression. I am useing java.text.regex correctly, but I dont really know how to create a regex pattern. my line is :
[2004/01/06 12:43:58.735] [info] br.com.organox.web.aggregator.servlet.struts.action.LoginEmbeddedAction: User 'TESTER12345678' with ticket 'acLBF9a6ZiY41073400238626' logged in.
and i need to get these two values
'TESTER12345678' and 'logged in'
can anyone help me?

You could try this:
String line = "[2004/01/06 12:43:58.735] [info] br.com.organox.web.aggregator.servlet.struts.action.LoginEmbeddedAction: User 'TESTER12345678' with ticket 'acLBF9a6ZiY41073400238626' logged in.";
String pattern = "User '(.+?)'.+' (.+)";
Pattern p = Pattern.compile(pattern);
Matcher m = p.matcher(line);
String user = null;
String status = null;
if (m.find())
user = m.group(1);
status= m.group(2);
System.out.println("user=" + user + ", status=" + status);By the way, next time post at the "Jave programming" forum instead.

Using regular expressions to get a customized output

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