REMOVE LAST 4 CHARCTER

HI ALL
I HAVE ONE FIELD, ITS VALUE IS '500632732008' AND ITS DATA TYPE IS CHAR.
I WANT TO REMOVE '2008' FROM THE VALUE.
WHAT SHOULD I DO?
PLZ HELP ME.

Hey try this
w_level_03 = strlen( W_STRING ).
lv_offset = w_level_03 - 4.
w_string2 = w_string +(lv_offset).
or
w_string2 = w_string +0(lv_offset).
Eg:-
str = "testing1234".
int offset = strlen( str ) - 4.
str = str+0(offset).
Write : str.
Then the output would be testing.
Regards,
Chandru

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Best way to remove last line-feed in text file

What is the best way to remove last line-feed in text file? (so that the last line of text is the last line, not a line-feed). The best I can come up with is: echo -n "$(cat file.txt)" > newfile.txt
(as echo -n will remove all trailing newline characters)

What is the best way to remove last line-feed in text file? (so that the last line of text is the last line, not a line-feed). The best I can come up with is: echo -n "$(cat file.txt)" > newfile.txt
(as echo -n will remove all trailing newline characters)
According to my experiments, you have removed all line terminators from the file, and replaced those between lines with a space.
That is to say, you have turned a multi-line file into one long line with no line terminator.
If that is what you want, and your files are not very big, then your echo statement might be all you need.
If you need to deal with larger files, you could try using the 'tr' command, and something like
tr '
' ' ' <file.txt >newfile.txt
The only problem with this is, it will most likely give you a trailing space, as the last newline is going to be converted to a space. If that is not acceptable, then something else will have to be arranged.
However, if you really want to maintain a multi-line file, but remove just the very last line terminator, that gets a bit more complicated. This might work for you:
perl -ne '
chomp;
print "
" if $n++ != 0;
print;
' file.txt >newfile.txt
You can use cat -e to see which lines have newlines, and you should see that the last line does not have a newline, but all the others still do.
I guess if you really did mean to remove all newline characters and replace them with a space, except for the last line, then a modification of the above perl script would do that:
perl -ne '
chomp;
print " " if $n++ != 0;
print;
' file.txt >newfile.txt
Am I even close to understanding what you are asking for?

Remove last selection for parameters

Hello expert,
I have a webi report with multiple parameter inherited from store procedure on which universe is built up. how can I remove last select variant for all parameters ? I mean for every running, I want to select parameters from scratch. but currently in my report, parameters display last selection.
Many Thanks,

Hello,
I believe if you go into the universe and right click on the stored procedure, it should give you an edit option. Then you should be able to select the parameter and change it to "Prompt for a value" or something like that. There are probably some other posts regarding how to do this. I am not sure I have it all correct since I don't have BO up right now, but pretty sure I have done it before.
Thanks

Remove Last part

i have this data
ELECT [item_id] ,[f2] from [Regions]
1. ُEgypt
1.1. Cairo
1.1.21. New Cairo
i want to remove last part
like in Egypt remove 1.
and on Cairo remove last 1.
and on New Cairo last 21.

Try:
DECLARE @City TABLE ( CityName varchar(100));
INSERT @City VALUES
('1. Egypt'),
('1.1. Cairo'),
('1.1.21. New Cairo'),
('1.1.21.5. Alexandria')
-- SELECT STUFF('abcdef', 2, 3, 'ijklmn');
SELECT
CityName, RenumberedCityName=
LTRIM(STUFF(REVERSE(SUBSTRING(SUBSTRING(REVERSE(CityName), CHARINDEX('.', REVERSE(CityName),1)+1,LEN(CityName))+'.',
CHARINDEX('.',SUBSTRING(REVERSE(CityName), CHARINDEX('.', REVERSE(CityName),1)+1,LEN(CityName))+'.'),len(CityName))),1,1,'')+SPACE(1)+
REVERSE(LTRIM(RTRIM(LEFT (REVERSE(CityName), CHARINDEX('.', REVERSE(CityName),1)-1)))))
FROM @City WHERE CHARINDEX('.',CityName) > 0;
CityName RenumberedCityName
1. Egypt Egypt
1.1. Cairo 1. Cairo
1.1.21. New Cairo 1.1. New Cairo
1.1.21.5. Alexandria 1.1.21. Alexandria
-- USING hierarchyid method
SELECT
CityName, RenumberedCityName=
LTRIM(REPLACE(STUFF(CONVERT(hierarchyid,'/'+REPLACE(LEFT(CityName, CHARINDEX(' ', CityName)-1),'.','/')).GetAncestor(1).ToString(),1,1,''),'/','.')
+SPACE(1)+REVERSE(LTRIM(RTRIM(LEFT (REVERSE(CityName), CHARINDEX('.', REVERSE(CityName),1)-1)))))
FROM @City WHERE CHARINDEX('.',CityName) > 0;
CityName RenumberedCityName
1. Egypt Egypt
1.1. Cairo 1. Cairo
1.1.21. New Cairo 1.1. New Cairo
1.1.21.5. Alexandria 1.1.21. Alexandria
Kalman Toth Database & OLAP Architect
SQL Server 2014 Design & Programming
New Book / Kindle: Exam 70-461 Bootcamp: Querying Microsoft SQL Server 2012

Remove last 4 digits

Hi all,
I want to remove last 4 digits from my numerical no. how can i do this?
Plz help me.

hi
good
w_level_03 = strlen( W_STRING ).
lv_offset = w_level_03 - 4.
w_string2 = w_string +(lv_offset).
or
w_string2 = w_string +0(lv_offset).
Eg:-
str = "testing1234".
int offset = strlen( str ) - 4.
str = str+0(offset).
thanks
mrutyun^

Remove last 3 char ..

Hi ,
I need to remove last 3 char from my varible which is char 30.
For example : WERKS = 1000 and .
I need to remove last 3 char (and) from the above varibale .Kindly guide this
Regards,
VC

Hi veerachamy,
Just copy this code..it will work fine even if the field changes dynamically..
I took w_char as 30 char..u can give ur field name there...
data:
w_char(30) type c value 'asdfghjklpoiu',
w_tmp(30) type c,
w_tmp1 type i.
w_tmp1 = strlen( w_char ).
w_tmp1 = w_tmp1 - 3.
w_tmp = w_char+0(w_tmp1).
write: w_tmp.
Hope it resolves the issue...
Regards
Kiran

How to replace or remove last 500 bytes of a file without rewriting all the file?

Hi everyone,
Usually I only ask for help when I can't find a solution for several days or weeks... And guess what? That just happen!
So, this is what i am trying to do:
I have a program to ZIP folder and protect them with password, then it encrypts the zip file.
That it's working fine, until the user forgets his password.
So, what I want to do is give the user a Recovery Password option for each ZIP file created. I can't use the Windows Registry because the idea is to be able to recover the password in any computer.So i came up with an idea...
In simple terms, this will work like this:
0 - Choose folder to ZIP
1 - Ask user for recover details (date of birth, email etc)
2 - ZIP folder with password
3 - Encrypt ZIP file
4 - Encrypt recover details and convert it to HEX
5 - Add recover details (in HEX) to the end of the ZIP file (last bytes)
6 - Add "5265636F76657244657461696C73" which is the text "RecoverDetails" in HEX
7 - Add "504B0506000000000000000000000000000000000000" this is the final bytes of a ZIP file and will make the Operating System think that is a ZIP file (i know that will give an error when we try to open it.. the ideia is to change the
extension later and use my software to do all the work to access this ZIP/folder again)
So, explaining what it's here, I want to say that I managed how to do all of this so far. The point number 6 will help us to determine where the recover details are in the file, or if they actually exist because user can choose not to use them.
In order to unlock this ZIP and extract it's contents, I need to reverse what I've done. That means, that need to read only the last 500 bytes (or less if the file is smaller) of the ZIP and remove those extra bytes I added so the program can check
if the user is inputing a correct password, and if so decrypt contents and extract them.
But, if the user insert a wrong password I need to re-add those bytes with the recover details again to the ZIP file.
The second thing is, if the user forgets his password and asks to recover it, a form will be shown asking to insert the recover detail (date of birth, email etc), so we need to reed the last 500 bytes of the ZIP, find the bytes in number 6 and remove the
bytes before number 6, remove bytes in number 6 and number 7, and we will have the recover details to match against the user details input.
I have all done so far with the locking process. But i need help with the unlocking.
I am not sure if it's possible, but this what i am looking for:
Read last 500 bytes of a file, remove the bytes with recover details and save the file. Without reading the whole file, because if we have a 1GB file that will take a very long time. Also, i don't want to "waste" hard drive space creating a new
clone file with 1GB and then delete the original.
And then add them back "in case user fails the password" which should be exactly the same.
This sounds a bit confusing I know, even to me, I am writing and trying to explain this the better I can.. Also my English is not the best..
Here it goes some code to better understanding:
'READ LAST 500 BYTES OF ZIP FILE TO CHECK IF IT CONTAINS RECOVER DETAILS
Dim oFileStream As New FileStream(TextBox_ZIP_to_Protect.Text & ".zip", FileMode.Open, FileAccess.Read)
Dim oBinaryReader As New BinaryReader(oFileStream)
Dim lBytes As Long = oFileStream.Length
oBinaryReader.BaseStream.Position = lBytes - 500
Dim fileData As Byte() = oBinaryReader.ReadBytes(500)
oBinaryReader.Close()
oFileStream.Close()
Dim txtTemp As New System.Text.StringBuilder()
For Each myByte As Byte In fileData
txtTemp.Append(myByte.ToString("X2"))
Next
Dim RecoveryDetailsPass_Holder = txtTemp.ToString()
'Dim Temp_2 = txtTemp.ToString()
'RichTextBox1.Text = txtTemp.ToString()
If txtTemp.ToString.Contains("505245434F47414653") Then
'we have password recovery details(the numbers mean RecoverDetails in HEX)
'next we will get rid of everything before and after of string "cut_at"
Dim mystr As String = RecoveryDetailsPass_Holder 'RichTextBox1.Text
Dim cut_at As String = "505245434F47414653"
Dim x As Integer = InStr(mystr, cut_at)
' Dim string_before As String = mystr.Substring(0, x - 1)
Dim string_after As String = mystr.Substring(x + cut_at.Length - 1)
RecoveryDetailsPass_Holder = RecoveryDetailsPass_Holder.Replace(string_after.ToString, "")
RecoveryDetailsPass_Holder = RecoveryDetailsPass_Holder.Replace("505245434F47414653", "") ' this is RecoverDetails in HEX
RecoveryDetailsPass_Holder = RecoveryDetailsPass_Holder.Replace("504B0506000000000000000000000000000000000000", "") ' this is the bytes of an empty zip file
'AT THIS POINT WE HAVE ONLY THE RECOVER PASSWORD DETAILS (date of birth, email etc) IN THE VARIABLE "RecoveryDetailsPass_Holder"
'////////////////////////////////////////////////////// TO DEBUG
'MsgBox(string_after.ToString & "505245434F47414653")
'InputBox("", "", string_after.ToString)
'\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\ TO DEBUG
'Temp_2 = Temp_2.Replace(RecoveryDetailsPass_Holder.ToString, "")
Now that we have the recover details, we need to remove them from ZIP in order to the software try to unzip it with the password provided by the user on the GUI.
If the user needs to recover the password we have the details already in RecoveryDetailsPass_Holder variable and just need to match them against user input details.
If the user fails, we need to put the RecoveryDetailsPass_Holder back on the file.
Any question just ask, it's a bit trick to explain i think, but please ask.
Anyone know how to do this?
Many thanks in advanced.
Nothing is impossible!
@ Portugal
Vote if it's helpfull :)

@ ALL
Thank you very much for you help. I know that if I'm "playing" with bytes you should assume that I know a lot of VB.net, but I don't know that much unfortunately. I am not a beginner but I am still very fresh and I probably do stuff that work but
probably not in the best way...
Anyway, I will explain the idea of this little software I'm making. Once I wanted to create a program to protect folders with password, and I came up with something to change folder permissions to lock access to them, and that actually worked fine and quickly.
However, I managed how to "crack" the protection by going to folder properties, security tab and then give permissions back to my username. So that, to me, wasn't a safer system to protect folders, also I want the ability to use passwords. So I search
and search online for a way to do it, and someone replied (to someone with the same question as me) that the best option would be to create a zip with all contents of the folder, with password and then change the extension from .zip to .whatever and register
the new extension .whatever on the Windows Registry, so that file will have an icon and open with my software.
So I did...The program zips everything, change the extension and I added the encryption to avoid people changing the extension to ZIP or trying to open with 7-Zip or similar and be able to see the protected files names in the .zip/.whatever
Answering to all of you now:
@Armi
"System.IO.FileStream.SetLength"
I know I tried that but I erased the code because it didn't work for some reason, I don't remember why sorry, was long time before I created this post.
The last code I was trying to use was this:
' Set the stream position to the desired location of the stream.
Dim fileStream As IO.FileStream = _
New IO.FileStream(TextBox_ZIP_to_Protect.Text & ".zip", IO.FileMode.Append)
Try
' Set the stream (OFFSET) position to the desired location of the stream.
fileStream.Seek(210, IO.SeekOrigin.Current)
Dim Bytes_do_ZE As Byte() = HexStringToByteArray(Temp_2.ToString)
'Write Characters ASCII
For Each Byte_Do_Zeca As Byte In Bytes_do_ZE
fileStream.WriteByte(Byte_Do_Zeca)
Next
Finally
fileStream.Close()
End Try
and we need this:
Private Shared Function HexStringToByteArray(ByRef strInput As String) As Byte()
Dim length As Integer
Dim bOutput As Byte()
Dim c(1) As Integer
length = strInput.Length / 2
ReDim bOutput(length - 1)
For i As Integer = 0 To (length - 1)
For j As Integer = 0 To 1
c(j) = Asc(strInput.Chars(i * 2 + j))
If ((c(j) >= Asc("0")) And (c(j) <= Asc("9"))) Then
c(j) = c(j) - Asc("0")
ElseIf ((c(j) >= Asc("A")) And (c(j) <= Asc("F"))) Then
c(j) = c(j) - Asc("A") + &HA
ElseIf ((c(j) >= Asc("a")) And (c(j) <= Asc("f"))) Then
c(j) = c(j) - Asc("a") + &HA
End If
Next j
bOutput(i) = (c(0) * &H10 + c(1))
Next i
Return (bOutput)
End Function
That code, as I understand, is to search for the OFFSET of the bytes in the file and start to write from there... That OFFSET should be the beginning of the 500 bytes read on the code before. I got the OFFSET position "210" reading the file with
the HEX editor "HxD - Hexeditor v1.7.7.0" but using the OFFSET won't work because every file, password, recover details and so on, are different and so the file size, changing the OFFSET I
think.
@Reed Kimble
Does that sound like something which might work for you?
Thanks for your help. That might be some solution, however it seams a bit of the same problem where we need to read the bytes again to get the recover details. But, as I said in this post, because this is meant to password protect folders, do you think that
will apply as well?
@Crazypennie
Thanks for your reply.
All this appears really weak. The user has your application since he need it to open the file .... and the code in the application contain the code to read the file without knowing the password. Therefore anyone can read your code and retrieve the
data without the password ... if he knows VB.
The application can only open the file if the user didn't use a password to protect the file. Because the file is encrypted and needs to be unencrypted first.
When the application tries to open/read the file, will need to decrypt it first and then check for a password and do the validation. Also the application is with the code masked/protected which i think it might not be easy for reverse engineering.
- You need to use a web server and a symmetric key encryption
This a good idea, besides I don't know how to implement it. However the idea is to be able to:
1 - Protect a folder anywhere in any Windows computer (portable app)
2 - Recover password details (security question) in any computer, online and offline
And I think we need a computer always connected to the Internet to use that method, right?
@ Mr. Monkeyboy
Thank you very much for your effort.
I just wanted to let you know that the zip method you are using is no longer supported.
I didn't actually knew that. Thanks for letting me know.
Do you require the compressed encrypted files to actually be Zip files or could they just be compressed files that have nothing to do with Zip?
No, it doesn't need to be a .zip extension. I am actually using my own extension. It starts as a Zip but then I changed to my own extension which I have registered on the Windows Registry.
@ ALL
Thanks again to all for trying and spending time helping me.
By the way, I might not be able to answer or try any code during the weekend... It's easter break and family is around. Have a nice easter everyone. :)
Nothing is impossible! Imagination is the limit!

Need to remove LAST NAME only in merged letter

Here's my quandry. Client supplied a mail list with full name in column one. It's okay for the addressing portion, but in the salutation she wants to remove just the last name. I already merged my 2900 name list.
So I have:
Mary and John Smith
123 Main St.
Your Town, State Zip
Dear Mary and John Smith,
Then body of letter.
I would need a way to search for any space and word before the comma and return in this one line only. Remove the space and last name so the comma slides over after John. I don't want to strip out any other words before a comma. I checked and I believe no line in the letter has a hard return following a comma.
Doable? If so, how?

Or you could search for \s[\l\u|\-]+(,)$ and replace with $1 to remove the last name and leave the comma next to the last word in the first name. this must be done as a find/change rather than a GREP style.
Colin's method is nice in it can be a style, but it leaves "space" between the last visible name and the comma because the text is still present. Colin "escaped" the comma in his version, too, but is seems to make no difference in my test.

FCP5 removes last frame from any 23.98fps movie

I'm having an issue with 23.98fps Quicktimes in FCP. When I play the clip in Quicktime, the frame count is correct. When the same movie is opened in the FCP viewer or dropped in a bin, FCP removes the last frame. For example, say I have 2 clips, identical in every way except for frame rate:
Clip A - 720p Photo-JPEG 120 frames 24fps
Clip B - 720p Photo-JPEG 120 frames 23.98fps
In QT7, both clips play correctly, contain all frames, and are reported in the info window to be 5 seconds exactly. In FCP Clip A, plays correctly, contains all frames, and has a reported length of 00:00:05:00. Clip B is missing the last frame and has a reported length of 00:00:04:23.
I have done this same test with a 480 frame clip as well with the same results. QT7 reports 20 seconds, FCP reports 00:00:19:23.
I have had this problem with quicktime movies from different sources as well, not just QT movies I have created. It is imperative that I find out what is causing this issue. If anyone can offer any suggestions/answers at all, it would be much appreciated.
PowerMac Dual G5 Mac OS X (10.4)

hello anthony.
i can't offer any explanation, but i can offer what might be a work around. i am assuming you need to work at 23.98 and that you are receiving exact frame count files.
if you receive files @ 24fps which are correct, try using cinema tools to "conform" these files to 23.98 ... just open the file from within cinema tools and hit the conform button. i'd be interested to know if these conformed files maintain the correct frame count.
a guess might be that the export or transcode process might be the source of the error.
R.

How to remove last char in a string by space

I have to implement backspace application(remove a last char in a string , when we pressed a button).
for ex: I enter the no
1234
instead of 1236
So when i press a button on the JWindow... it should display
123
so that i can enter 6 now.
I tried to display the string "123 " instead over "1234" but it is not working when the no background is specified. but works fine when a background color is specified.
The string is displayed as
Graphics2D g = (Graphics2D)window.getGraphics();
AttributedString as = new AttributedString(string, map);
g.drawString(as.getIterator(),x,y);
In the map, the background is set to NO_BACKGROUND.
Thanks and regards

Deja vu. I saw this kind of post before, and I'm sure
it was today.http://forum.java.sun.com/thread.jspa?threadID=588110&tstart=0
Here it is.

Removing Last Word in Columns in Numbers '09

I've got a column full of names. Some names are multiple words, like, "Bob & Nancy Smith", while others are 2 words, first and last name. I just want to remove the final word, the last name, in each cell. Formulas I've found on this forum only apply if there are 2 words. Can you help me??
Message was edited by: phillipsler

EDIT: I took "remove" as meaning you wanted the last name, not that you wanted the last name gone. Rereading your post I think I got that backwards.
I can think of a brute force method which requires a few columns. You can reduce it to fewer columns by combining formulas together. Or maybe someone else has a more elegant approach
Column B = the names
Column C = 0 (zero)
Column D =IFERROR(FIND(" ",$B,C+1),"")
Drag-fill or copy/paste D into columns E-J
K2 =COUNT(D2:J2) drag-fill to the rest of the column
Column L =OFFSET(C,0,K)
Column M =RIGHT(B,LEN(B)-L)
Columns D through J locate all the spaces. K and L together find the position of the last space in the string. M returns everything to the right of that last space. You can combine K through M into one formula but I don't know of a more elegant way to find the last space than by finding each one, one at a time.
There are, I'm sure, other ways than this to do the same basic thing but the ones I can think of also require multiple columns.
Message was edited by: Badunit
Message was edited by: Badunit

Removing last 2 characters from string field

I am trying to remove the last 2 characters of a string field.
there is no consistant length in the field
316R1
12364R1
i want to remove everything after R
i tried instrrev but i that didnt do it.
is there a way to say
start position1 and go the R
thanks

formula,
left (field, length_formula) is the solution
the length_formula is the number of chars form left
f.i
left(field, length (field)-2)
left (field, InstrRev, field,"R")
of course a combination with Right is also possible

Bulk remove last action stop

Hi,
I have around 3000 fla files that I need to remove the last action stop in their actionscript.
I have meanwhile found no way to do this. Any ideas?
Much apprecaited!

Thank you both for your replys...
I have a software that enables people to add animations to IM softwares. In this case, the flash is sent to the recepient and run once.
Now we are building a directory for the animations online and it makes sense that when browsing an animation, the animation will loop and not stop after 1 view.
Any help would be greatly apprecaited as it will save me weeks of work
thanks!

To remove last '/' character

I need to remove '/' character and string comes after it. I will give an example.
CREATE TABLE TAB (COL1 VARCHAR2(50));
INSERT INTO TAB VALUES ('hIA/SS/TTTT/FFFF');
INSERT INTO TAB VALUES ('hDFF/AA/S/AAAAAAAA');
I should remove the last '/' and string comes after it so when i query , i should get result as
hiA/SS/TTTT
hDFF/AA/S
Please help me

Hi,
Welcome to the forum!
Here's one way:
SELECT     col1    -- if wanted
,     REGEXP_REPLACE ( col1
                 , '/[^/]*$'
                 )     AS up_to_last_slash
FROM     tab
;Regular expressions can be very convenient, but they can also be slow. If performance is a problem, try this instead:
SELECT     col1    -- If wanted
,     NVL ( SUBSTR ( col1
                      , 1
                      , INSTR (col1, '/', -1) - 1
         , col1
         )                  AS up_to_last_slash
FROM     tab
;This is basically what Chris posted earlier, except that it returns col1 unchanged when col1 does not contain a '/'.
Thanks for posting the CREATE TABLE and INSERT statements; that's very helpful!
Edited by: Frank Kulash on Oct 8, 2012 7:32 AM

Remove last frame after live stream

Hi,
How can I remove/reset the last frame sent by a live streaming client? I'm using FMS 3.5.
It can be a server or client side solution. any ideas?
tks.

Hi,
What do you mean by removing the last frame from live stream?
A live stream that is published to the server and there is a client which is subscribing to that live stream. And you dont want to send the last frame of the stream to the subscriber, is it? Or something else?
Regards,
Janaki L

REMOVE LAST 4 CHARCTER

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