Remove repeated row in 2D array

Hi,
How can I remove the row for second repeated data in my 2D array regardless of the 2D array size.

Try this...
There are many variations possible.
LabVIEW Champion . Do more with less code and in less time .
Attachments:
RemoveExtraRowsWithDuplicateFirstTwoElements.png ‏31 KB

Similar Messages

  • How to remove a row from a rowset

    HI,
    I am trying to do a very simple thing, but I got stuck.
    The problem:
    I want to remove a row from a rowset, without removing the row itself. Especially I do not want to remove any entities.
    I need this functionality in several situations, for example when I want to move a row from one rowset to another.
    Another situation is when I have a viewlink not based on an association. When a row is modified so it does not fit to the viewlink's where clause anymore, I need a way to remove it manually (without removig any associated entities),
    I hope someon can help me on this,
    thanks,
    Frank

    Sascha:
    The only workaround I can think of is a true hack, and you'd be entering into a unchartered territory. But, it may be worth a try.
    First, you need to create a subclass of oracle.jbo.server.ViewObjectImpl in the oracle.jbo.server package. This is because you need to override one of the package private methods. Suppose you define oracle.jbo.server.TempBaseViewObjectImpl which extends ViewObjectImpl.
    Override the following method:
    int[] getDeleteParticipants()
    This method returns an array of EO bases for which ViewRow's delete should cause deletion of EntityRow's.
    So, before you remove a ViewRow, you should set some flag in your TempBaseViewObjectImpl, so that getDeleteParticipants() would return "new int[0];" This will cause no EntityRow's to be deleted. Only the ViewRow will be removed from the collection.
    Note that you should reset this flag after the operation, so that you can delete the EntityRow's (when necessary).
    Your real VO should then subclass TempBaseViewObjectImpl.
    Once we fix this problem and provide a real API, you should remove TempBaseViewObjectImpl and extend your real VO from ViewObjectImpl instead of TempBaseViewObjectImpl.
    Thanks.
    Sung

  • First attempt to remove duplicate rows from a table...

    I have seen many people asking for a way to remove duplicate rows from data. I made up a fairly simple script. It adds a column to the table with the cell selected in it, and adds the concatenation of the data to the left into that new column. then it reads that into a list, and walks through that list to find any that are listed twice. Any that are it marks for DELETE.
    It then walks through to find each one marked for delete and removes them (you must go from bottom to top to do this, otherwise your row markings for delete don't match up to the original rows anymore). Last is to delete the column we added.
    tell application "Numbers"
    activate
    tell document 1
    -- DETERMINE THE CURRENT SHEET
    set currentsheetindex to 0
    repeat with i from 1 to the count of sheets
    tell sheet i
    set x to the count of (tables whose selection range is not missing value)
    end tell
    if x is not 0 then
    set the currentsheetindex to i
    exit repeat
    end if
    end repeat
    if the currentsheetindex is 0 then error "No sheet has a selected table."
    -- GET THE TABLE WITH CELLS
    tell sheet currentsheetindex
    set the current_table to the first table whose selection range is not missing value
    end tell
    end tell
    log current_table
    tell current_table
    set list1 to {}
    add column after column (count of columns)
    set z to (count of columns)
    repeat with j from 1 to (count of rows)
    set m to ""
    repeat with i from 1 to (z - 1)
    set m to m & value of (cell i of row j)
    end repeat
    set value of cell z of row j to m
    end repeat
    set MyRange to value of every cell of column z
    repeat with i from 1 to (count of items of MyRange)
    set n to item i of MyRange
    if n is in list1 then
    set end of list1 to "Delete"
    else
    set end of list1 to n
    end if
    end repeat
    repeat with i from (count of items of list1) to 1 by -1
    set n to item i of list1
    if n = "Delete" then remove row i
    end repeat
    remove column z
    end tell
    end tell
    Let me know how it works for y'all, it worked good on my machine, but I know localization is causing errors sometimes when I post things.
    Thanks,
    Jason
    Message was edited by: jaxjason

    Hi jason
    I hope that with the added comments it will be clear.
    Ask if something is always opaque.
    set {current_Range, current_table, current_Sheet, current_Doc} to my getSelection()
    tell application "Numbers09"
    tell document current_Doc to tell sheet current_Sheet to tell table current_table
    set list1 to {}
    add column after column (count of columns)
    set z to (count of columns)
    repeat with j from 1 to (count of rows)
    set m to ""
    tell row j
    repeat with i from 1 to (z - 1)
    set m to m & value of cell i
    end repeat
    set value of cell z to m
    end tell
    end repeat
    set theRange to value of every cell of column z
    repeat with i from (count of items of theRange) to 1 by -1
    (* As I scan the table backwards (starting from the bottom row),
    I may remove a row immediately when I discover that it is a duplicate *)
    set n to item i of theRange
    if n is in list1 then
    remove row i
    else
    set end of list1 to n
    end if
    end repeat
    remove column z
    end tell
    end tell
    --=====
    on getSelection()
    local _, theRange, theTable, theSheet, theDoc, errMsg, errNum
    tell application "Numbers09" to tell document 1
    set theSheet to ""
    repeat with i from 1 to the count of sheets
    tell sheet i
    set x to the count of tables
    if x > 0 then
    repeat with y from 1 to x
    (* Open a trap to catch the selection range.
    The structure of this item
    «class
    can't be coerced as text.
    So, when the instruction (selection range of table y) as text
    receive 'missing value' it behaves correctly and the lup continue.
    But, when it receive THE true selection range, it generates an error
    whose message is errMsg and number is errNum.
    We grab them just after the on error instruction *)
    try
    (selection range of table y) as text
    on error errMsg number errNum (*
    As we reached THE selection range, we are here.
    We grab the errMsg here. In French it looks like:
    "Impossible de transformer «class
    The handler cuts it in pieces using quots as delimiters.
    item 1 (_) "Impossible de transformer «class » "
    item 2 (theRange) "A2:M25"
    item 3 (_) " of «class NmTb» "
    item 4 (theTable) "Tableau 1"
    item 5 (_) " of «class NmSh» "
    item 6 (theSheet) "Feuille 1"
    item 7 (_) " of document "
    item 8 (theDoc) "Sans titre"
    item 9 ( I drop it ) " of application "
    item 10 ( I drop it ) "Numbers"
    item 11 (I drop it ) " en type string."
    I grab these items in the list
    {_, theRange, _, theTable, _, theSheet, _, theDoc}
    Yes, underscore is a valid name of variable.
    I often uses it when I want to drop something.
    An alternate way would be to code:
    set ll to my decoupe(errMsg, quote)
    set theRange to item 2 of ll
    set theTable to item 4 of ll
    set theSheet to item 8 of ll
    set theDoc to item 10 of ll
    it works exactly the same but it's not so elegant.
    set {_, theRange, _, theTable, _, theSheet, _, theDoc} to my decoupe(errMsg, quote)
    exit repeat (*
    as we grabbed the interesting datas, we exit the lup indexed by y.*)
    end try
    end repeat -- y
    if theSheet > "" then exit repeat (*
    If we are here after grabbing the datas, theSheet is not "" so we exit the lup indexed by i *)
    end if
    end tell -- sheet
    end repeat -- i
    (* We may arrive here with two kinds of results.
    if we grabbed a selection, theSheet is something like "Feuille 1"
    if we didn't grabbed a selection, theSheet is the "" defined on entry
    and we generate an error which is not trapped so it stops the program *)
    if theSheet = "" then error "No sheet has a selected table."
    end tell -- document
    (* Now, we send to the caller the interesting datas :
    theRange "A2:M25"
    theTable "Tableau 1"
    theSheet "Feuille 1"
    theDoc "Sans titre" *)
    return {theRange, theTable, theSheet, theDoc}
    end getSelection
    --=====
    on decoupe(t, d)
    local l
    set AppleScript's text item delimiters to d (*
    Cut the text t in pieces using d as delimiter *)
    set l to text items of t
    set AppleScript's text item delimiters to "" (*
    Resets the delimiters to the standard value. *)
    (* Send the list to the caller *)
    return l
    end decoupe
    --=====
    Have fun
    And if it's not clear enough, you may ask for more explanations.
    Yvan KOENIG (from FRANCE mardi 27 janvier 2009 21:49:19)

  • Delete unwanted rows in 2D array when not knowing the index of which to delete

    Hi!
    I am kind of new to Labview and I hope that someone can help me with my problem.
    First I import a spreadsheet from Excel into a 2-D array of string. For each row in the array I then want to compare the data in a specific column (which is a date (time stamp)) with today's date. Rows containing a date with lower number than today's date I want to put into a new array and the rest I have no need for.
    I have succeeded in creating a time stamp for today's date so that it is consistent with the Excel time stamp. But for the comparing and creating a new array part I have no idea about how to do it. I have tried numerous ways with no luck at all (probably because I don't understand all of the VIs that I need to use).
    Happy for all help that I can get!
    Solved!
    Go to Solution.

    You're on the right track! (although your attempt will only list the datetime values)
    What you'll need to add/change is the resulting array need to be connected to the loop as Shift register (with an initial empty array), and in the Case you'll either use Build array to add the current line or send the unmodified through.
    You'll probably want to send the full array through and not only the datetime.
    You'll probably need some tweak to only use date, but similar to this:
    /Y
    LabVIEW 8.2 - 2014
    "Only dead fish swim downstream" - "My life for Kudos!" - "Dumb people repeat old mistakes - smart ones create new ones."
    G# - Free award winning reference based OOP for LV

  • Remove Second Row From CSV

    I've got a group of small CSV files - only about 15 and with about 30 rows each in. I'm running a script against them once a month so because they're so small and being processed infrequently they can read-in and treated as a string. I need to remove the
    second row of the file though and I've got nowhere with it so far.
    Sample data:
    TimeIndex,CPU,FCP,NFS,CIFS,ISCSI,NetworkIn,NetworkOut,NetworkTotal,Filername
    TimeIndex,CPU,FCP,NFS,CIFS,ISCSI,NetworkIn,NetworkOut,NetworkTotal,000-samplehostname
    So the header is correct, but the sample hostname on the second row would be different for each file and that row shouldn't be there. The simplest thing to do is just wipe that row entirely.
    Any ideas?
    Thanks in advance
    Adam

    I have two ideas :-)
    You mentioned that you are just reading in the files and treating them as strings.  In this case, you'd want to split it to a collection of objects and remove the second row...like this:
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    Test
    Test"
    $arrlines = {$strMultiLineString -split "`r"}.INvoke() #Force it into an object collection
    $null = $arrlines.Remove($arrlines[1])
    If you are importing the file as a csv, you could do something like this:
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    Here is more information on adding and removing items from arrays/collections:
    http://www.jonathanmedd.net/2014/01/adding-and-removing-items-from-a-powershell-array.html
    That should remove the line in question, but is only done in memory, sounds to me the OP wants it removed from the file, so you would need to save the changes back to the actual file
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    Don't Retire Technet

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    hi
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    many thanks
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    - (q3) Is the default configuration of RangeSize="25" on the iterator intended behaviour (for an interator supporting an executeWithParams action)?
    regards
    Jan

  • Repeatable row disabled by default. Need to enable all rows based on value in XML.

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        adffacesctx.addPartialTarget(this.getQueryTable()); In this post, I believe Frank sums up what I should do: Remove row from af:table
    >
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    I don't understand your problem. If your "Delete" button is
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