Removing Weekends in between two dates

Hi,
I need to get the number of days in between two dates excluding the weekends.
Does anyone know how to do this?
Thanks.

Here's a search of the forum for "difference dates". At least the first three questions are identical to yours.
http://search.java.sun.com/Search/java?col=javafrm&qp=%2Bforum%3A31&qt=difference+dates&x=12&y=10

Similar Messages

Calculate the Difference Between two dates excluding weekends and Holidays

Hi,
We need to calculate the difference between the two dates by excluding the Local public holidays (It is global and varies across countries) and weekends should not be included in calculation for a business day in OBIEE.
We have two dates: Open date and close date when ever close date is null we are calculating age based on taking the current timestamp and need to exclude the weekends and Holidays when ever the close date is null.
Ex:
Col1 col2 Total
11/9/2010 2:46:38 PM Null 13
11/2/2010 8:06:26 PM 11/3/2010 5:37:03 PM 1
(In the Total we shouldn't include the weekends,holidays)
Please let me know how to calculate the difference between two dates by excluding the weekends and holidays.
Thanks
Edited by: user10441472 on Nov 22, 2010 3:14 PM

You already asked this question and I answered it...
Re: calculation of Business day in OBIEE

Count days between two dates without weekend

Hi,
I need a solution in query or another thread, that returns the count of days between two dates without consider weekend (saturday and sunday) , I have the columns of type Date, and the return need in format of hours in one column hh:mm:ss and days in another column.
Regards
Jonas

Hi and welcome to the forum.
Keep in mind that you can do a search on this forum.
Your question has been asked before.
Some other pointers:
http://asktom.oracle.com/pls/asktom/ASKTOM.download_file?p_file=6551242712657900129
http://asktom.oracle.com/pls/asktom/f?p=100:11:0::::P11_QUESTION_ID:185012348071

Working days between two date fields and Changing Factory Calendar

Hi,
I have to calculate working days between two date fields excluding the weekends and public holidays for Switzerland.
I have written the routine using factory calender and its working fine except for two problems now:
1. If any one of the date field is empty then teh rsult should be zero.
2. And the below code is working from 1996 but my cleints wants it to work for years before 1996 as well.
I also tried to change the Start date in SCAL for factory calendar but it says enter values between 1995 to 2020.
I am new to ABAP. Please help me how i can achieve these for below code.
DATA: IT_HOLIDAYS type TABLE OF ISCAL_DAY,
      IS_HOLIDAYS TYPE ISCAL_DAY.
DATA: T_DATE TYPE SY-DATUM,
      P_DATE TYPE SY-DATUM.
DATA : X_DATE(4) TYPE C.
DATA: CNT TYPE I.
REFRESH : IT_HOLIDAYS.
CLEAR : IT_HOLIDAYS.
T_DATE = SOURCE_FIELDS-/BIC/ZCCCHP812.
P_DATE = SOURCE_FIELDS-/BIC/ZCCCHP810.
CALL FUNCTION 'HOLIDAY_GET'
EXPORTING
HOLIDAY_CALENDAR = 'CH'
FACTORY_CALENDAR = 'CH'
DATE_FROM = P_DATE
DATE_TO   = T_DATE
TABLES
HOLIDAYS = IT_HOLIDAYS
EXCEPTIONS
FACTORY_CALENDAR_NOT_FOUND = 1
HOLIDAY_CALENDAR_NOT_FOUND = 2
DATE_HAS_INVALID_FORMAT = 3
DATE_INCONSISTENCY = 4
OTHERS = 5.
DESCRIBE TABLE IT_HOLIDAYS LINES CNT.
X_DATE = T_DATE - P_DATE - CNT.
RESULT = X_DATE.
Please help
Regards
Zabina
Edited by: Syed786 on Nov 2, 2011 9:15 AM

Hi Zabina,
Try this function module 'DURATION_DETERMINE'.
Give the factory calendar and unit as DAY
With regards,
Rajesh

Fucntion to Calculate business days (exclude weekends & holidays) between two days

Hello,
I need to be able to calculate business days between two dates excluding weekends and holidays. I do have a date dimension and also flags which denote weekday, holiday. Would really appreciate help in building a udf for the business days calculation.
Thanks,

Hi, Please take a look and tweak accordingly. Best of luck.
--Assuming data dimension table something like the following
--tblDateDim (DT date primary key,
flagHoliday bit,
flagWeekday bit
CREATE FUNCTION fnBusinessDays (
@StartDate DATE,
@EndDate DATE
RETURNS INT
AS
BEGIN
DECLARE @Days INT ;
SELECT @Days = count(*)
FROM tblDateDim --// date dimension
WHERE
( DT BETWEEN @StartDate AND @EndDate) --// dt is date column in the table.
AND --// also flags which denote weekday, holiday
flagHoliday = 0 --// flagHoliday= 1--Holiday;= 0 --workingday/businessday
AND
flagWeekday = 1 --// FlagWeekday = 1--businessday ; =0 --weekend (Saturday and Sunday)
RETURN (@Days)
END
GO

Compare n kyf and m chanm of Top 10 Document-No.s between two dates

Dear BW-Gurus,
Our Customer want´s a query, which shows in the TOP 10 of some sales-doc´s and marks a line, if the key figures or a characteristic has changed from one date to an other date (Comparision of a sales document between two dates).
We now created a query with all of the key figures restricted to the one date and to the compare date and to get an info, if something has changed extra key figures build by a forumular subtracting one kyf from another.
We only want to show a TOP 10 list of the doc´s - but we have a very poor performance now.
1) is it possible to build a kind of aggregate containing only the top10 doc´s ? - this will speed up the query enormously.
2) We intend to compare the characterstics and kyfs by using virtual characeristic, which will do the comparison - do you think this is the right way?
How would you solve such a problem?
many thanks for your support.
regards
Jürgen

Post Author: V361
CA Forum: Formula
I modified your formula and added /0
else (HalfDays := ((BusinessEndTime - time(FDay)) / 3600 + (time(LDay) - BusinessStartTime) / 3600); FullDays := (FinalDays - 2) * 9; Hours := HalfDays + FullDays /0;
This causes the formula to fail, but in my version, it will show you the numbers it used during the calc.
For 2007-10-01 to 2007-10-10 the variables are as below
FDay: #2007-10-01 08:00:00#
LDay: #2007-10-09 17:00:00#
BusinessStartTime: #08:00:00#
BusinessEndTime: #17:00:00#
BSTime : 8
BETime: 17
Days:9
Weekends: 2
FinalDays: 7
StartDate: #2007-10-01#
EndDate: #2007-10-09#
HalfDays: 18
FullDays: 45
Hours: 0
For 2007-10-01 to 2007-10-11 the variables are as below
FDay: #2007-10-01 08:00:00#
LDay: #2007-10-10 17:00:00#
BusinessStartTime: #08:00:00#
BusinessEndTime: #17:00:00#
BSTime : 8
BETime: 17
Days:10
Weekends: 2
FinalDays: 8
StartDate: #2007-10-01#
EndDate: #2007-10-10#
HalfDays: 18
FullDays: 54
Hours: 0
FullDays, looks wrong for sure, I assume it is supposed to be hours, but I don't think it is supposed to be subtracting 2 either. Anyway, your hours is actually the sum of your halfdays and fulldays.
Hope that helps,

Find Exact number of days between two dates

How can get the exact number of days between two dates?

An example of business days calculation in SQL */
/* The algorythm is: */
/* 1) Take the absolute difference between the dates */
/* to_date('&todate') - to_date('&frdate') */
/* 2) Subtract the weekends (number of weeks in the range */
/* TRUNC(to_date('&todate'),'D') = 1st day of week that */
/* end of period is in */
/* TRUNC(to_date('&frdate'),'D') = Last day of week that */
/* start of period is in */
/* So subtracting these two gives the number of days */
/* between the two dates but including all of the days in */
/* the weeks that the dates start and end in. When this */
/* number is divided by 7 it gives the number of weeks. */
/* Multiplying by 2 gives the number of weekend days.     */
/* 3) Subtract 1 day if the ending date is on a saturday */
/* DECODE(to_char(to_date('&todate'),'D'),7,-1,0) */
/* --> If the day of the week is saturday (7), returns -1 */
/* 4) Subtract 1 day if the start date is on a sunday */
/* DECODE(to_char(to_date('&frdate'),'D'),1,-1) */
/* --> If the day of the week is sunday (1), returns 1 */
/* 5) Add one day to make the range inclusive (The '1 + ' ) */
/* Author: Kenneth Atkins ([email protected]) */
/* http://www.olywa.net/katkins/oratip */
define frdate = '&1'
define todate = '&2'
set verify off
select
     '&frdate' From_Date
     ,'&todate' To_Date,
     1 + to_date('&todate') - to_date('&frdate') -
     ((TRUNC(to_date('&todate'),'D') - TRUNC(to_date('&frdate'),'D'))/7)*2
     + DECODE(to_char(to_date('&todate'),'D'),7,-1,0)
+ DECODE(to_char(to_date('&frdate'),'D'),1,-1,0) Business_Days
from dual
Here is an example of running the script:
SQL> @busdays 01-AUG-96 15-AUG-96
FROM_DATE TO_DATE BUSINESS_DAYS
01-AUG-96 15-AUG-96 11

Difference between two dates in hours

hi
i want to write the procedure which will give me the difference of two dates in hours.
there are two columns start_dt and end_dt and i want to calculate the difference between them in hours.
morever i want to add functionality like if the start or end date falls on weekend(saturday & sunday) i want to subtract that whole period(which obviously will be in hours) from the total hours elapsed between two dates.
could anyone please help me in this?
regards,
PD

nicolas..
thanks for bringing this into my notice..
i used ur one of the reply..
select
to_char(sysdate,'dd-mm-yyyy hh:mi:ss') d1,
to_char(sysdate-45.4,'dd-mm-yyyy hh:mi:ss') d2,
trunc(sysdate-(sysdate-45.4)) "Days",
trunc(((sysdate-(sysdate-45.4))-trunc(sysdate-(sysdate-45.4)))*24) "Hours",
trunc(((((sysdate-(sysdate-45.4))-trunc(sysdate-(sysdate-45.4)))*24)-trunc(((sysdate-(sysdate-45.4))-trunc(sysdate-(sysdate
-45.4)))*24))*60) "Minutes",
trunc((((((sysdate-(sysdate-45.4))-trunc(sysdate-(sysdate-45.4)))*24)-trunc(((sysdate-(sysdate-45.4))-trunc(sysdate-(sysdat
e-45.4)))*24))*60)-trunc(((((sysdate-(sysdate-45.4))-trunc(sysdate-(sysdate-45.4)))*24)-trunc(((sysdate-(sysdate-45.4))-tru
nc(sysdate-(sysdate-45.4)))*24))*60)) "Second"
from dual
it's working but the problem is that i also have to give functionality like if the start_dt or end_dt is on holiday(i.e. weekend or holiday) i need to subtract the hours spent during holiday period from total hours.
any help?
regards,
PD!!

How to calculate the month difference between two date char. in Query?

Customers would like to see how many months passed between two date type of characteristics (e.g., the month difference between the current date and the scheduled delivery date in the record) and put the result into the column as KF.
We would have to grab the fiscal year/period kind of value and then do the subtraction, e.g., if the current date value is 2/28/2008 and the scheduled delivery date value in the record is 12/01/2007, the correct result should be 2 month difference between these two date values, but could someone here give us the technical light on how to make this happen in query design?
Thanks and we will give you reward points for the correct anwsers!

Hi Kevin,
The Badi is RSR_OLAP_BADI.
You can create an implementation using Transaction SE18.
The implementation is per cube and is defined in the filters.
In the Implementation you have the following methods :
1. Define : Here you will provide the Keyfigure you need as a virtual one.
2. Initilialize : Any Init Function you want to do.
3. Compute. This is called per datarecord and here you can cimpute your value.
Hope this helps.
Pralay Ahluwalia

As to the data type of the data type of the difference between two date type of datas

Hi,
I have a question about the data type of the difference between two date type of datas.
There are two date type of datas as:
SSHIPMENTS.RECEIVEDATETIME
SSHIPMENTS.PROMISEDATETIME
I try to use the following SQL Script in Oracle SQL*Plus as:
SELECT CASE
WHEN (SSHIPMENTS.RECEIVEDATETIME - SSHIPMENTS.PROMISEDATETIME) < '000 01:00:00.000' THEN 'OnTime'
WHEN (SSHIPMENTS.RECEIVEDATETIME - SSHIPMENTS.PROMISEDATETIME) < '000 01:30:00.000' THEN '60-89 Minutes'
ELSE '3+ Hours'
END
FROM SSHIPMENTS;
The error message of "Invalid Number" for the '000 01:30:00.000' happens.
I don't know if the data type of the interval is wrong.
Many Thanks,
Cathy

SELECT CASE
WHEN (to_char(SSHIPMENTS.RECEIVEDATETIME,'hhmiss') - to_char(SSHIPMENTS.PROMISEDATETIME,'hh24miss')) < '010000' THEN 'OnTime'
WHEN (to_char(SSHIPMENTS.RECEIVEDATETIME,'hhmiss') - to_char(SSHIPMENTS.PROMISEDATETIME,'hh24miss'))< '000 01:30:00.000' THEN '60-89 Minutes'
ELSE '3+ Hours'
END
FROM SSHIPMENTS;
just try it out..

No of Fridays in between two date

Hi all
What is the Qucikest and easy way to retreive the NO of fridyas in betwen two dates
Thanks & Regards
Vivek

vivekvm wrote:
Hi all
What is the Qucikest and easy way to retreive the NO of fridyas in betwen two dates
Make sure you test the boundary conditions for any solution you get.
Have you defined exactly what you mean by "in between two dates", for example. do you want to count the end points if one, or both, of them is a friday ?
Regards
Jonathan Lewis
http://jonathanlewis.wordpress.com
http://www.jlcomp.demon.co.uk
To post code, statspack/AWR report, execution plans or trace files, start and end the section with the tag {noformat}{noformat} (lowercase, curly brackets, no spaces) so that the text appears in fixed format.
"Science is more than a body of knowledge; it is a way of thinking"
Carl Sagan

How can I remove all content between two tags using Find/Replace regular expressions?

This one is driving me bonkers... I'm relatively new to regular expressions, but I'm trying to get Dreamweaver to remove all content between two tags in an XML document. For example, let's say I have the following XML:
<custom>
<![CDATA[<p>Some text</p>
<p>Some more text</p>]]>
</custom>
I'd like to do a Find/Replace that produces:
<custom>
</custom>
In essence, I'd like to strip all of the content between two tags. Ideally, I'd like to know how to strip the CDATA content as well, to return the following:
<custom>
<![CDATA[]]>
</custom>
I'd much appreciate any suggestions on accomplishing this.
Many thanks!

Thanks much for your response. I found David's article to be a little thin with respect to examples using quantifiers in coordination with the wildcard metacharacters; however, I was able to cobble together a working expression through trial and error using the information he presented. For posterity, here’s the solution:
Find:
<custom>[\d\D]*?</custom>
Replace:
<custom>
<![CDATA[]]>
</custom>
I believe this literally translates to:
[] = find anything in this range/character class
\d = find any digit character (i.e. any number)
\D = find any non-digit character (i.e. anything except numbers)
*? = match zero or more times, but as few times as possible (i.e. match multiple characters per instance, but only match one instance at a time, or none at all)
I’m still not sure how to effectively utilize the . wildcard. For example, the following expression will not find content that ends with a number:
<custom>.*?[\D]*?</ custom >
I'm presuming this is because numbers aren't included in the \D metacharacter; however, shouldn't numbers be picked up by the .*? expression?

How can i get report between two dates?

Hi
how can i get report between two dates?
for example i want get reports between 20/4/2002 & 27/4/2002.
my table has date column and i can get first date( exam : .... where date:=a and/or ....i don't know this part)
thanks alot.
Regards
The Oracle Reports Team
http://otn.oracle.com/

where exam_date between :from_date and :to_date
from_date and to_date are user_parameter

Difference between two date ,according to office time.

hi,
How can I get diffrence between two date.
If I select from-date 20-03-2012 09:30AM and to-date 20-03-2012 06:30PM then output should be 1 day(as it is office time from 09:30 AM TO 06:30 PM).
ACCORDINGLY If I select from-date 20-03-2012 09:30AM and to-date 21-03-2012 02:00PM then output should be 1.5 day
select 24*(to_date(:P2_TO_DATE,'DD-MM-YYYY HH:MIPM') - to_date(:P2_FROM_DATE,'DD-MM-YYYY HH:MIPM'))"date" from dual;

Hello Shirish,
WITH dates AS(
    SELECT TO_DATE ('20-03-2012 09:30AM', 'DD-MM-YYYY HH:MIPM') AS start_date
           ,TO_DATE ('20-03-2012 06:30PM', 'DD-MM-YYYY HH:MIPM') AS end_date
    FROM    dual
    UNION ALL
    SELECT TO_DATE ('20-03-2012 09:30AM', 'DD-MM-YYYY HH:MIPM') AS start_date
           ,TO_DATE ('20-03-2012 04:15PM', 'DD-MM-YYYY HH:MIPM') AS end_date
    FROM    dual
    UNION ALL
    SELECT TO_DATE ('20-03-2012 09:30AM', 'DD-MM-YYYY HH:MIPM') AS start_date
           ,TO_DATE ('21-03-2012 02:00PM', 'DD-MM-YYYY HH:MIPM') AS end_date
    FROM    dual
    UNION ALL
    SELECT TO_DATE ('20-03-2012 09:30AM', 'DD-MM-YYYY HH:MIPM') AS start_date
           ,TO_DATE ('21-03-2012 12:00PM', 'DD-MM-YYYY HH:MIPM') AS end_date
    FROM    dual
    UNION ALL
    SELECT TO_DATE ('20-03-2012 04:30PM', 'DD-MM-YYYY HH:MIPM') AS start_date
           ,TO_DATE ('21-03-2012 02:00PM', 'DD-MM-YYYY HH:MIPM') AS end_date
    FROM    dual
    UNION ALL
    SELECT TO_DATE ('20-03-2012 04:30PM', 'DD-MM-YYYY HH:MIPM') AS start_date
           ,TO_DATE ('22-03-2012 02:00PM', 'DD-MM-YYYY HH:MIPM') AS end_date
    FROM    dual
    UNION ALL
    SELECT TO_DATE ('20-03-2012 04:30PM', 'DD-MM-YYYY HH:MIPM') AS start_date
           ,TO_DATE ('22-03-2012 10:00AM', 'DD-MM-YYYY HH:MIPM') AS end_date
    FROM    dual
,times as(
SELECT start_date
       ,end_date
       ,TRUNC (end_date - start_date) days
       ,MOD (end_date - start_date,1) hours
       ,(start_date - 9.5/24 - TRUNC (start_date))*24 offset_start
       ,(end_date - 9.5/24 - TRUNC (end_date))*24 offset_end
       ,(end_date - 9.5/24 - TRUNC (end_date))*24
        - (start_date - 9.5/24 - TRUNC (start_date))*24 offset_diff
FROM    dates
SELECT TO_CHAR(start_date, 'DD-MM-YYYY HH:MIPM') AS start_date
       ,TO_CHAR(end_date, 'DD-MM-YYYY HH:MIPM') AS end_date
       ,days
       ,ROUND(offset_start,2) offset_start
       ,ROUND(offset_end,2) offset_end
       ,ROUND(offset_diff,2) offset_diff
       ,CASE WHEN offset_diff > 4 THEN
            days + 1
        WHEN offset_diff > 0 THEN
            days + 0.5
        WHEN offset_diff = 0 THEN
            days
        WHEN offset_diff + 9 > 4 THEN
            days + 1
        ELSE
            days + 0.5
        END computed_days
FROM timesThe first step (subquery times) computes the full days and the difference between start_date and end_date, compared to the beginning of the office ours (9.5 /24)
The second step takes the days and according to the possible values of the difference adds a half or a full day.
Regards
Marcus
Edited by: Marwim on 19.03.2012 11:23
CASE offset_diff = 0

Date difference between two dates

hi All,
i have to right a stored proc to find the difference between two dates.
for example of i give
startdate as 4/1/2015 and enddate 14/1/2015
i should get 1 year , 10 days and 0 months .
i have tried the DateDiff function but it does not calculate the leap year.
please help.

DECLARE @from datetime
DECLARE @to datetime
SET @from = '20150104 8:00'
SET @to = '20150114 10:30'
SELECT DATEDIFF(minute,@from, @to) % 60 as Minutes
SELECT (DATEDIFF(minute,@from, @to) / 60) % 24 as Hours
SELECT DATEDIFF(minute,@from, @to) / (60 * 24) as Days
SELECT DATEDIFF(month,@from, @to) as Months
SELECT DATEDIFF(year,@from, @to) as Year
Best Regards,Uri Dimant SQL Server MVP,
http://sqlblog.com/blogs/uri_dimant/
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Removing Weekends in between two dates

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