Replace function in xslt for BPEL 2.0

Question

Hi,
We have a requirement where special characters (e.g. \, ., &, @) will be replaced with ' ' .  As the position of the special characters are not fixed, I believe I won't be able to do it by substring function.
Got some link suggesting this  <xsl:value-of select="replace(description, '\n', '<p/>')" disable-output-escaping="yes" />  with <xsl:stylesheet> ='2.0' but its not working for me. I would appreciate your help .Thanks in advance.
Source: 65\Road No.1,Glasgow,Scotland
Required o/p:  65 Road No 1 Glasgow Scotland
Thanks,
Abhishek

Answer 1

when i test the replace in xmlspy it works, maybe you forgot to escape all the "special" characters which need to be replaced ?
xslt tested in xmlspy
[code]
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions">
  <xsl:template match="/">
  <xsl:variable name="test" select="string('65\Road No.1,Glasgow,Scotland')"/>
  <root>
  <debug1>
  <xsl:value-of select="$test"/>
  </debug1>
  <xsl:variable name="debug2" select="replace($test,'\\',' ')"/>
  <debug2>
  <xsl:value-of select="$debug2"/>
  </debug2>
  <xsl:variable name="debug3" select="replace($debug2,'\.',' ')"/>
  <debug2>
  <xsl:value-of select="$debug3"/>
  </debug2>
  <xsl:variable name="debug4" select="replace($debug3,'\,',' ')"/>
  <debug2>
  <xsl:value-of select="$debug4"/>
  </debug2>
  </root>
  </xsl:template>
</xsl:stylesheet>
[/code]
output
[code]
<root xmlns:fn="http://www.w3.org/2005/xpath-functions" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema">
  <debug1>65\Road No.1,Glasgow,Scotland</debug1>
  <debug2>65 Road No.1,Glasgow,Scotland</debug2>
  <debug2>65 Road No 1,Glasgow,Scotland</debug2>
  <debug2>65 Road No 1 Glasgow Scotland</debug2>
</root>
[/code]