Replace new line from xml string

hi,
I am getting an input string as given below
<div class="titleBar">
          <h1>sssPRIVACY POLICY AND YOUR CALIFORNIA PRIVACY RIGHTS</h1>
     </div>
     <div class="txtPod"> And I want to replace all the blank lines and the output should be like
<div class="titleBar">
          <h1>sssPRIVACY POLICY AND YOUR CALIFORNIA PRIVACY RIGHTS</h1>
     </div>
     <div class="txtPod"> I tried replaceAll("\n",""), but that doesn't seem to work.
Can somebody help me on this

str = str.replaceAll("(?m)^[ \t]*\r?\n", "");

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How to remove new line from string

I have a string say following
String line = "one\ntwo\nthree";Now i am trying to remove new line from string. For this i did following
String txt = line.replaceAll("\\n","");But i see still new line is occuring. Is it correct way. Please advice me.

Ok. I was just using \n instead of \r\n. And i am in windows. I will give a try with \r\n
Ok i tried using following , but it doesnt work.
line = line.replaceAll("\\r\n","");Am i missing anything here. Please guide me.
Edited by: ArpanaK on Oct 8, 2007 4:44 PM

Setting the name of a new object from a string

Is there anyway I can set the object name of a newly created
object from a string?
eg.
(the code below generates a compile time error on the
variable declaration)
public function addText(newTxt:String, txt:String,
format:TextFormat):void {
var
this[newTxt]:TextField = new TextField();
this[newTxt].autoSize = TextFieldAutoSize.LEFT;
this[newTxt].background = true;
this[newTxt].border = true;
this[newTxt].defaultTextFormat = format;
this[newTxt].text = txt;
addChild(this[newTxt]);
called using>
addText("mytxt", "test text", format);
I could then reference the object later on without using
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There are many a time when I want to set the name of a new
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In this example I have a function that adds a new text object
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The problem is, if I call the function more than once then
two textfield objects will exist, both with the same name. (either
that or the old one will be overwritten).
I need a way of setting the name of the textfield object from
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using
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ReferenceError: Error #1056: Cannot create property newTxt on
Box.
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Thanks

Using:
var this[newTxt]:TextField = new TextField()
is the right approach.
You can either incrment an instance variable so that the name
is unique:
newTxt = "MyName" + _globalCounter;
var this[newTxt]:TextField = new TextField();
globalCounter ++;
Or store the references in an array:
_globalArray.push(new TextField());
Tracy

Create Business Partner from XMl String not a file

Hi,
Is it possible to create a BP from an XML string.
I know about GetBusinessPartnerFromXml(string FileName, int index)
but I dont want to save the string in a file before creating a BP from it
Hope there's a method to do that

Marc,
This looks like it is a duplicate of this post, so I am closing this thread as it looks like you answered your own question!
Create Business Partner from XMl String not a file
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Adding New Line character to String

Hi,
I want to add a new line while concatenating strings.
I am getting some string objects and put them together. while concatenating them i want new string to be displayed in new line.
The purpose of this is i am displaying this bunch of strings on a mouse over finction using javascript. Hence i want the different values to be displayed on a new line.
Any help is appreciated.

You normally use \r\n or System.getProperty("line.separator") to get a newline in Java.
But since you're talking about Javascript, the whole question makes really no sense here at a Java forum. Don't you just mean a linebreak in HTML? If so, it is just
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Replacing New Line character in a hexadecimal string in ECC5.0

Hi,
I am trying to create an XML document using ABAP.
I have created one DOM and later used the DOM to get the XML content into an internal table in form of Hexadecimal String. In that internal table(which contains XML in form of hexadecimal content), I want to search for the new line character and replace it by Space.
I have used class CL_XML_DOCUMENT to create such document.
Now, the keyword 'SEARCH' which searches the New Line character, works on the hexadecimal content of the internal table in 46C and I get an XML document. I get the position of the New Line in SY-FDPOS and can do whatever I want. But SEARCH on hexadecimal content is not permitted in ECC 5.0. I get a syntax error when I try to do so. Tried many options but could not succed.
Would apreciate if anyone can help in finding and replacing characters like new line, tab etc in a hexadecimal string.
Thanks.
Can anyone

Hi!
When you say hexadecimal string, you mean variable - otherwise string (= character) operations would work?
Then you have to go for hex handling -> do it yourself. Make something like
data: lf type x value '0A',
      sp type x value '20',
      i type i.
I = 0.
while sy-subrc = 0.
if hex_string+i(1) = lf.
    hex_string+i(1) = sp.
endif.
add 1 to i.
endwhile.
Regards,
Christian

Tab And New Line in XML data

I have a formatted text which I store as a text node. By default the new line char's are converted into white spaces. I read elsewhere on this forum, that we should use the charecter entity reference equivalent &#A; for new line. I did not understand this idea clearly, so I tried this out:
In my formatted string, I replaced all instances of '\n' with '&#A;'. I create my text node as follows:
script.replaceAll("\n","&#A;");
scriptElement = document.createTextNode(script);
As expected when the XML is written the &#A10; is further encoded into "&#A10". And when I read back my XML from the parser, I get my string back with all the "&#A10;". I again need to do a replace all to get the new line charecters back.
My question is : Is there any other standard solution to this problem or the bottom line is to replace the new line and tabs with "MUMBOJUMBO" or a standard charecter entity ref and look for the same while reading back.
Is there anyway I could tell my XMLwriter to convert '\n' into "&#A;" and get back '\n' when I parse the XML?

by default, all white spaces collapse: http://www.w3.org/TR/xsl/slice7.html#white-space-collapse
you can use xml:space="preserve" in your XML elements (tags) or
you can use <fo:block white-space-collapse="false" linefeed-treatment="preserve"> in XSL if you use XSL to format the XML.

How to remove empty lines from xml files after removing nodes from document

<pre>
Hi
<b>i have xml document, which is shown below
after removing some nodes from the document ,i am getting empty lines in place of removed nodes,how to resolve this and get the proper xml document without any errors</b>
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<!DOCTYPE Message SYSTEM "TRD01.dtd">
<Message>
<Header>
<CounterPartyType>CLIENT</CounterPartyType>
<CreationTime>20134455</CreationTime>
<ErrorCode>363 </ErrorCode>
<ErrorEnterPriseId>N</ErrorEnterPriseId>
<ErrorStatus>1</ErrorStatus>
<ErrorSystemId>STL</ErrorSystemId>
<ErrorTimes>31</ErrorTimes>
<MessageType>T</MessageType>
<RecipientEnterpriseId>N</RecipientEnterpriseId>
<RecipentSystemId>EXM</RecipentSystemId>
<Remarks>REMARSK</Remarks>
<SenderEnterpriseId>N</SenderEnterpriseId>
<SenderSystemId>TR</SenderSystemId>
</Header>
</Message>
<ErrorCode>363 </ErrorCode>
<ErrorEnterPriseId>NIHK</ErrorEnterPriseId>
<ErrorStatus>1</ErrorStatus>
<ErrorSystemId>STL</ErrorSystemId>
<ErrorTimes>31</ErrorTimes>
XPathExpression expression5 = xpath.compile(xmlpath5);
Object result5 = expression5.evaluate(doc, XPathConstants.NODE);
Node node5 = (Node) result5;
node5.getParentNode().removeChild(node5);
XPathExpression expression6 = xpath.compile(xmlpath6);
Object result6 = expression6.evaluate(doc, XPathConstants.NODE);
Node node6=(Node) result6;
node6.getParentNode().removeChild(node6);
XPathExpression expression7 = xpath.compile(xmlpath7);
Object result7 = expression7.evaluate(doc, XPathConstants.NODE);
Node node7=(Node) result7;
node7.getParentNode().removeChild(node7);
doc.normalize();
doc.normalizeDocument();
TransformerFactory tf = TransformerFactory.newInstance();
Transformer t = tf.newTransformer();
t.setOutputProperty(OutputKeys.INDENT, "yes");
t.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");
t.setOutputProperty(OutputKeys.METHOD,"xml");
t.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
the xml output i am getting is
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<Message>
<Header>
<CounterPartyType>CLIENT</CounterPartyType>
<CreationTime>20134455</CreationTime>
<MessageType>TRD01</MessageType>
<RecipientEnterpriseId>N</RecipientEnterpriseId>
<RecipentSystemId>STL</RecipentSystemId>
<Remarks>REMARSK</Remarks>
<SenderEnterpriseId>N</SenderEnterpriseId>
<SenderSystemId>T</SenderSystemId>
</Header>
</Message>
<b>could you please let me know how to avoid empty lines in the xml doucment output</b>
this is the method i am using to get the result
public void ValidateRecord(String xml){
try{
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder db = factory.newDocumentBuilder();
//parse file into DOM
/*DOMParser parser = new DOMParser();
parser.setErrorStream(System.err);
parser.setValidationMode(DTD_validation);
parser.showWarnings(true);*/
System.out.println ("HI THIS xml is validation "+xml);
Resolver res = new Resolver();
db.setEntityResolver(res);
Document doc = db.parse(new InputSource(new StringReader(xml)));
XPathFactory xpf = XPathFactory.newInstance();
XPath xpath = xpf.newXPath();
// XPathExpression expression = xpath.compile("//A/B[C/E/text()=13]");
String xmlpath="/Message/Header/CounterPartyType/text()";
String xmlpath1="/Message/Header/RecipentSystemId/text()";
String xmlpath2="/Message/Header/ErrorSystemId/text()";
XPathExpression expression = xpath.compile(xmlpath);
XPathExpression expression1 = xpath.compile(xmlpath2);
Object result = expression.evaluate(doc, XPathConstants.NODE);
Object result1 = expression1.evaluate(doc, XPathConstants.NODE);
Node node = (Node) result;
Node node1 = (Node) result1;
System.out.println("the values of the string is " +node.getNodeValue());
System.out.println("the values of the string is " +node1.getNodeValue());
// for (int i = 0; i < nodes.getLength(); i++) {
//System.out.println(nodes.item(i).getNodeValue());
// CAHNGING THE RECEIPENT NODE
XPathExpression expression2 = xpath.compile(xmlpath1);
Object result2 = expression2.evaluate(doc, XPathConstants.NODE);
Node node2 = (Node) result2;
System.out.println(node2);
node2.setNodeValue(node1.getNodeValue());
System.out.println(node2);
//removing the nodes from document
String xmlpath3="/Message/Header/ErrorCode";
String xmlpath4="/Message/Header/ErrorEnterPriseId";
String xmlpath5="/Message/Header/ErrorStatus";
String xmlpath6="/Message/Header/ErrorSystemId";
String xmlpath7="/Message/Header/ErrorTimes";
XPathExpression expression3 = xpath.compile(xmlpath3);
Object result3 = expression3.evaluate(doc, XPathConstants.NODE);
Node node3 = (Node) result3;
node3.getParentNode().removeChild(node3);
XPathExpression expression4 = xpath.compile(xmlpath4);
Object result4 = expression4.evaluate(doc, XPathConstants.NODE);
Node node4 = (Node) result4;
System.out.println("node value");
System.out.println(node4.getParentNode().getNodeName());
node4.getParentNode().removeChild(node4);
XPathExpression expression5 = xpath.compile(xmlpath5);
Object result5 = expression5.evaluate(doc, XPathConstants.NODE);
Node node5 = (Node) result5;
node5.getParentNode().removeChild(node5);
XPathExpression expression6 = xpath.compile(xmlpath6);
Object result6 = expression6.evaluate(doc, XPathConstants.NODE);
Node node6=(Node) result6;
node6.getParentNode().removeChild(node6);
XPathExpression expression7 = xpath.compile(xmlpath7);
Object result7 = expression7.evaluate(doc, XPathConstants.NODE);
Node node7=(Node) result7;
node7.getParentNode().removeChild(node7);
// Node b13Node = (Node) expression.evaluate(doc, XPathConstants.NODE);
//b13Node.getParentNode().removeChild(b13Node);
doc.normalize();
doc.normalizeDocument();
TransformerFactory tf = TransformerFactory.newInstance();
Transformer t = tf.newTransformer();
t.setOutputProperty(OutputKeys.INDENT, "yes");
t.setOutputProperty("{http://xml.apache.org/xslt}indent-amount", "4");
t.setOutputProperty(OutputKeys.METHOD,"xml");
t.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
t.transform(new DOMSource(doc), new StreamResult(System.out));
catch (Exception e) {
e.printStackTrace();
System.out.println(e.getMessage());
</pre>
Edited by: user12185243 on Apr 6, 2013 6:38 AM
Edited by: user12185243 on Apr 6, 2013 6:41 AM
Edited by: user12185243 on Apr 6, 2013 6:43 AM
Edited by: user12185243 on Apr 6, 2013 6:45 AM
Edited by: user12185243 on Apr 6, 2013 9:00 AM

either this way we can do this
1)
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
<b> factory.setIgnoringElementContentWhitespace(true); </b>
DocumentBuilder db = factory.newDocumentBuilder();
or
2)
java.io.StringWriter sw = new java.io.StringWriter();
StreamResult sr = new StreamResult(sw);
t.transform(new DOMSource(doc), sr);
String xml1 = sw.toString().trim();
<b> xml1=xml1.replaceAll("\\s",""); </b>
System.out.println(xml1.trim());

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iam using JSTL EL expression in my JSP.
iam printing a string in JSP as ${vobject.rmessage} where rmessage is a string .
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Can anyone please guide me on writing EL expression for the above problem?

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Kudos are always welcome if you got solution to some extent.
I need my difficulties because they are necessary to enjoy my success.
--Ranjeet

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Hello.
I have a textstring in which there are New Line characters. These cause problems when inserting the data.
An example is as follows (assume a table test exists with one column col1 VARCHAR2(2000):
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How about this:
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<SORT_FIELD1_INV>110
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Hi,
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